The coherence cluster supports created how much cache?

Question

Hi,
I have runing Oracle Coherence GE 3.6.1 in cluster.
The coherence cluster supports created how much cache? cache type is Distributed Cache.
Cache over-population will affect the performance of the cluster?
Thank you!

Answer 1

Do a test, the code is as follows：
cache code
     public final long removeLike(String regex) {
          long l1 = System.currentTimeMillis();
long result = 0;
Set<String> setKeys = nc.keySet(new LikeFilter(new KeyExtractor(), regex + "%", (char)0, false));
long l2 = System.currentTimeMillis();
System.out.println("removeLike , execute time :" + (l2 - l1));
return result;
public final boolean removeStartWith(String prefix) {
long l1 = System.currentTimeMillis();
int i = 0;
try {
Set<String> keys = nc.keySet();
Iterator<String> iter = keys.iterator();
String v = "";
while (iter.hasNext()) {
v = iter.next();
if (v.startsWith(prefix)) {
++i;
long l2 = System.currentTimeMillis();
System.out.println("removeStartWith , execute time :" + (l2 - l1));
return true;
} catch (Exception e) {
LOG.error(e.getMessage(), e);
return false;
The above 2 methods are computational search KEY time, not to delete operation
test code
     @BeforeClass
public static void init() {
try {
cache = CacheFactory.getCache("testCache");
} catch (CacheException e) {
e.printStackTrace();
cache.clear();
for (int i = 0; i < 100000; i++) {
cache.add("test-" + i,i);
for (int i = 0; i < 100000; i++) {
cache.add("hello-" + i,i);
@Test
public void testReadByDefaultKey1() {
cache.removeLike("test");
@Test
public void testReadByDefaultKey2() {
cache.removeStartWith("test");
The test results show that the:
removeLike , execute time : 637
removeStartWith , execute time :125
Circulating KEY faster than using likeFilter quickly.