The sum function requires 1 argument(s).

Question

---Hi i am trying get all of
(sum(Q.SCTOTAL,0)) as SC,
(sum(Q.SRTOTAL,0)) as SRTOTAL,
(sum(Q.CminusREF,0))as CminusREF,
(sum(Q.SFAT,0))as SFAT,
(sum(Q.SPAT,0))as SPAT,
(sum(Q.SNOTATPT,0))as SNOTATPT,
(sum(Q.SET,0))as SET,
(sum(Q.TOTAV,0))as TOTAV
and for each emp_name?
but it is not wotking for me. the error says: The sum function requires 1 argument(s).
what shoould i change on the code below so mY Query can Run?
thank you
B.
select distinct
G.Emp_name,
upper(G.EMP_case_number) as MIS_EMP_case_NO,
G.Emp_name as Emp,
G.MIS_Emp_id,Radius,
G.address,
G.DC as Emp_DC,
G.Emp_class,
Q.YEAR,
Q.EMP_case_number,
(sum(Q.SCTOTAL,0)) as SC,
(sum(Q.SRTOTAL,0)) as SRTOTAL,
(sum(Q.CminusREF,0))as CminusREF,
(sum(Q.SFAT,0))as SFAT,
(sum(Q.SPAT,0))as SPAT,
(sum(Q.SNOTATPT,0))as SNOTATPT,
(sum(Q.SET,0))as SET,
(sum(Q.TOTAV,0))as TOTAV
FROM tbl_MIS_QC G
LEFT JOIN QCPFA Q ----View
ON upper(Q.EMP_case_number) = upper(G.EMP_case_number)
where DC = '55'
gorup by G.Emp_name
order by G.Emp_name, upper(G.EMP_case_number)

Answer 1

Hi,
It's true: the SUM function only takes one argument. What are you trying to do with the second argument, 0?
When you use aggregate functions (like SUM), everything in the SELECT clause must be an aggregate function, a constant, or one of the GROUP BY columns. Without knowing your tables, your data, or what results you want, I can't tell you exactly what to do. You might want to compute the SUMs in a sub-query before joining them to the other table, something like this:
select  G.Emp_name,
        upper(G.EMP_case_number) as MIS_EMP_case_NO,
        G.Emp_name as Emp,
        G.MIS_Emp_id,Radius,
        G.address,
        G.DC as Emp_DC,
        G.Emp_class,
        Q.YEAR,
        Q.upper_EMP_case_number,
        q.sc,
        q.srtotal,
FROM    tbl_MIS_QC G
LEFT JOIN
        (   -- Begin in-line view q
        SELECT  year,
                UPPER (emp_case_number) AS upper_emp_case_number,
                sum(SCTOTAL) as SC,
                sum(SRTOTAL) as SRTOTAL,
        FROM    QCPFA
        GROUP BY  year,
                  UPPER (emp_case_number)
        )   -- End in-line view q
ON Q.upper_EMP_case_number = upper(G.EMP_case_number)
where DC = '55'
order by G.Emp_name, upper(G.EMP_case_number) Repeat: this is just a wild guess, the best I can do without seeing some test data and the results you want from that data.