Throwing my own exception

Question

I'm trying to throw my own exception but can't seem to do it. the method i'm using has three different exceptions that i need to declare. Heres my code with one exception (not working of course):
     public static String ProcessUserInput(){          
          BufferedReader kbd = new BufferedReader(new InputStreamReader(System.in));
          String line = "";
          BlankException blanke = new BlankException blanke();
          try{
line = kbd.readLine();
catch (IOException ex)
System.out.println( "Error reading keyboard input." );
return line;
I've tried to throw a new exception called BlankException but i get the following error message:
'(' or '[' expected
BlankException blanke = new BlankException blanke();
How do i put three of my own exceptions in this piece of code?

Answer 1

how do i do that if i have three exceptions in the one methodYou can declare your method to throw as many exceptions as you want.
Example:public void method() throws CustomExceptionA, CustomExceptionB, CustomExceptionC {
    if (/* something goes wrong */) {
        throw new CustomExceptionA();
    try {
    catch(IOException ioEx) {
        throw new CustomExceptionB();
    catch(Exception ex) {
        throw new CustomExceptionC();
}