Time String to Timestamp Conversion Problem

Hi,
I attempted to convert time string to timestamp but I failed. What is the wrong with it? I need a timestamp to create waveforms.
Egemen
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Attachments:
Time String to Timestamp.png ‏18 KB

You are right Gogineni, when I got the error, I was using %S in the format string for Format Date/Time String function and %3u in the format string for Scan From String.
I found the solution in this thread - use %S%3u in both places.
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Similar Messages

Timestamp conversion problem.

I work in the development of a LabVIEW program that communicates with a
server (written in Java). All acquired data is sent via TCP and the
server can read everything (waveforms and other information). However,
there is a problem in timestamp conversion. We don't know how to
convert the milliseconds correctly. The timestamp is inside a waveform,
so we cannot convert it to formatted string.
Example:
Original timestamp:
13:37:19,639
11/10/2005
String generated with "Flatten to String":
0000 0000 BF71 9ABF A3D7 0800 0000 0000
Converted value (Java server):
13:37:19,000
11/10/2005
Does anyone know the algorithm to obtain the milliseconds from this value: "A3D7 0800"?
Thanks for attention.
My regards,
Vinicius Falseth
Solved!
Go to Solution.

There is a faster way. You can extract the timestamp from the waveform using Get Waveform Components.
At that point, you can convert it to whatever you want. Attached
is a VI which shows a simple conversion to milliseconds, losing a lot
of resolution (128 bit timestamp goes to 52 bit double) and a more
complex conversion showing the internal structure of the timestamp (it
is a 128 bit fixed point number with the decimal in the middle).
You can modify the second conversion to do such things as throw away
the integer portion to get higher resolution on the fraction. Or
you could just save to Java using a four-integer structure.
This account is no longer active. Contact ShadesOfGray for current posts and information.
Attachments:
timestamp.llb ‏48 KB

String to timestamp conversion

I have a string of the format yyyyMMdd:hh:mm:ss.SSSSS.
I need to convert it to a timestamp value of
the format dd-MMM-yy hh.mm.ss.SSSSS.
I tried the following
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd:hh:mm:ss.SSSSS");
java.util.Date date = sdf.parse(stdate);
java.sql.Timestamp t = new java.sql.Timestamp(date.getTime());
but it didnt work.
Any help will be greatly appreciated.

I have a string of the format
yyyyMMdd:hh:mm:ss.SSSSS.
need to convert it to a timestamp value of
he format dd-MMM-yy hh.mm.ss.SSSSS.
I tried the following
SimpleDateFormat sdf = new
SimpleDateFormat("yyyyMMdd:hh:mm:ss.SSSSS");
java.util.Date date = sdf.parse(stdate);
java.sql.Timestamp t = new
java.sql.Timestamp(date.getTime());
but it didnt work.
Any help will be greatly appreciated.
I have a string of the format
yyyyMMdd:hh:mm:ss.SSSSS.
need to convert it to a timestamp value of
he format dd-MMM-yy hh.mm.ss.SSSSS.Timestamps do not have a format - they are just a point in time. The toString() method will return a String representing the Timestamp in some format but this is not the same as having a format.
I tried the following
SimpleDateFormat sdf = new
SimpleDateFormat("yyyyMMdd:hh:mm:ss.SSSSS");
java.util.Date date = sdf.parse(stdate);
java.sql.Timestamp t = new
java.sql.Timestamp(date.getTime());
but it didnt work.What do you mean by "didn't work"?

Java time to DB2 timestamp conversion

I want to convert current time to following format "2008-01-12 11:46:55.945000". I tried but I an not able to do. Could you pelase hlep me out or is there any easy way to do
          Calendar calendar = Calendar.getInstance();
          //2008-01-12 11:46:55.945000
          int year = calendar.get(Calendar.YEAR);
          int date = calendar.get(Calendar.DATE);
          int month = calendar.get(Calendar.MONTH);
          int hour = calendar.get(Calendar.HOUR);
          int minite = calendar.get(Calendar.MINUTE);
          int second = calendar.get(Calendar.SECOND);
          int millisecond = calendar.get(Calendar.MILLISECOND);
          String timestamp = year+"-"+date+"-"+month+" "+hour+":"+minite+":"+second+"."+millisecond;

have you try like:
java.sql.Timestamp creationdate = new java.sql.Timestamp(new Date().getTime());
prepStmt.setTimestamp(1, creationdate);or format the date as "yyyy-MM-dd HH:mm:ss" like string by using SimpleDateFormat
and use
java.sql.Timestamp creationdate =
               java.sql.Timestamp.valueOf(creationDate);

String to date conversion problem

Hai braniees,
i am new to java.I have a problem in converting string to date.my code is this
dob="2/05/2005";
SimpleDateFormat sf=new SimpleDateFormat("dd/MM/yyyy");
Date dt=sf.parse(dob);
i this i am getting the error in the last line.the error is
" Unhandled exception type ParseException"
I am not able to getrid of this.
Thanks
anieshuk

I would advise against doing what ranjithcp suggested unless you are such a perfect programmer that you'll never get invalid data into your methods. Also what ranjithcp has failed to mention is that you'll have to put the throws instruction all over your code right up to your main method otherwise your just moving your error message up through your program.
You should always try and handle checked exceptions not throw them.

Problem with String to Int conversion

Dear Friends,
Problem with String to Int conversion
I am having a column where most of the values are numeric. Only 4 values are non numeric.
I have replaces those non numeric values to numeric in order to maintain the data type.
CASE Grade.Grade WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' ELSE Grade.Grade END
This comes the result as down
Grade
_0_
_1_
_10_
_11_
_12_
_13_
_14_
_15_
_16_
_17_
_18_
_19_
_2_
_20_
_21_
_22_
_23_
_24_
_3_
_4_
_5_
_6_
_7_
_8_
_9_
Refresh
Now I want to convert this value to numeric and do some calculation
So I changed the formula as below
cast (CASE Grade.Grade WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' ELSE Grade.Grade END as INT)
Now I get the following error
View Display Error
_ Odbc driver returned an error (SQLExecDirectW)._
Error Details
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
_State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 17001] Oracle Error code: 1722, message: ORA-01722: invalid number at OCI call OCIStmtFetch. [nQSError: 17012] Bulk fetch failed. (HY000)_
SQL Issued: SELECT cast ( CASE Grade.Grade WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' ELSE Grade.Grade END as Int) saw0 FROM "Human Capital - Manpower Costing" WHERE LENGTH(CASE Grade.Grade WHEN 'E1' THEN '20' WHEN 'E2' THEN '21' WHEN 'E3' THEN '22' WHEN 'E4' THEN '23' ELSE Grade.Grade END) > 0 ORDER BY saw_0_
Refresh
Could anybody help me
Regards
Mustafa
Edited by: Musnet on Jun 29, 2010 5:42 AM
Edited by: Musnet on Jun 29, 2010 6:48 AM

Dear Kart,
This give me another hint, Yes you are right. There was one row which returns neither blank nor any value.
I have done the code like following and it works fine
Thanks again for your support
Regards
Code: cast (CASE (CASE WHEN Length(Grade.Grade)=0 THEN '--' ELSE Grade.Grade END) WHEN 'E4' THEN '24' WHEN 'E3' THEN '23' WHEN 'E2' THEN '22' WHEN 'E1' THEN '21' when '--' then '-1' ELSE Grade.Grade END as Int)

Problem converting U8 array to date-time string

Hi All,
How can I convert U8 array (time_t data type from C dll) to date time string?
A dll function that I am calling has a structure of string, integer and time_t as one of the parameters. Instead of passing cluster, I pass an array of U8 of the size that the structure should be. All the members of the strcuture and parsed correctly except the date/time.
Function Parameter:
typedef struct {
Int AlarmState ;
Int AlarmGrade ;
TCHAR AlarmMessage [100] ;
time_t AlarmTimeStamp ;
} WV_ALARM_INFO ;
Total size = 4 + 4 + 100 + 4 = 112
Using Call Library Function, I set the parameter type to Array of U8 and size 112.
After the array is populated when the function is called, I have done the following to interpret date and time.
1) Using Extract Zero Terminated String.VI I converted U8 array (of size 4) to string.
2) Type casted string to integer (I32).
3) Swap bytes
4) Swap Words
5) Format Date/Time String.
Please see the attached screenshot for visual display of the above.
Ideas on why the year is incorrect?
Mimansa
Attachments:
Time.JPG ‏102 KB

Hi Mimansa,
Is it only the year that is incorrect? Also, where did you find that ABC\0 VI that you use 3 times? Did you make it or is it in a labview library somewhere?
Thanks,
Laura

Date time string from UME-SPML interface

Hi,
I am using the UME-SPML interface to manage users in SAP UME and using AS ABAP user management as the user store for UME.
I have noticed a problem in the date time string returned in the SPML search response when I search for a user. When you search for a user, normally you get 3 date time strings for "validfrom", "validto" and "lastmodifydate".
These are what have been returned in the SPML response:
<attr name="lastmodifydate"><value>20101019030648Z</value></attr>
<attr name="validfrom"><value>20101019010000Z</value></attr>
<attr name="validto"><value>25001230010000Z</value></attr>
When I check the same user with the user management administration console, I get these:
Date of Account Creation: Oct 19, 2010 2:06:48 PM (Eastern Standard Time (New South Wales))
Start Date of Account Validity: Oct 20, 2010 12:00:00 AM (Eastern Standard Time (New South Wales))
End Date of Account Validity: Dec 31, 2500 12:00:00 AM (Eastern Standard Time (New South Wales))
The timezone I am in is GMT10 (Australia Eastern Standard Time (New South Wales)) and now we in day light saving so effectively we are in GMT11 now.
You can see that the datetime string for "lastmodifydate" correctly reflects what's shown on user management administration console.
But the datetime strings for "validfrom" and "validto" seems to get the conversion wrong: both seem to be using 12 hour format instead of 24 hour format. (2010 10 19 01 00 00Z should be 2010 10 19 13 00 00Z and 2500 12 30 01 00 00Z should be 2500 12 30 13 00 00Z)(I have put in a space in the string to break up the date time components)
Anyone has any idea what went wrong here?
Regards,
GG

Also search service.sap.com for the term "sy-zonlo".
Personally I am a member of the [flat earth society|http://en.wikipedia.org/wiki/Flat_Earth_Society] when it get to this topic, because it causes no end of problems.
Most customers simply stop operations on 31.12.xxxx or before, or alternately use reporting tools to make corrections afterwards.
In the security realm, SAP also respects server side timestamp tolerances (only a few seconds are allowed).
Time is server time in my books. Some people work late, others early - and there is nothing you can control to stop a customer in the US from placing an order via a system in Japan anyway.
Anyway, this is probably a program error with the 12 hour format in the component software or possibly the API interface to user management in your release so you should open a customer message with SAP (my best guess).
Cheers,
Julius

Time string to time stamp

Hi Everyone ,
I have two time strings :
05-06-2009 > 02:00-03:00
13-06-2009 > 05:00-06:00
I want to convert them into timestamp and then i want to compare them to know which one is older.
If its possible without converting to timestamp then that would be good too but I guess the best way would be to convert the string to timestamp first.
Rgs
M Omar Tariq
Solved!
Go to Solution.

Its now working ,
Thanx , I was doing a mistake, the following thread solution works
http://forums.ni.com/t5/LabVIEW/timestamp-conversion/m-p/1283734/highlight/false#M533356
Rgs
Omar

When I run this VI "Waveform Time to Date Time String" in LabView 7.0 it will not pass decimals of seconds.

When I run this VI "Waveform Time to Date Time String" in LabView 7.0 it will not pass decimals of seconds. From decimals of inputline. If i disconnect the input to the subVI "Get Date/Time string vi" it will work propperly, it also doses if I reconnect it. I use LabViev 7.0.
So the problem i solved, but i dosent understund why it works in this way. Does it indicate other problems which will make my researchprogram unrelaible ?
Attachments:
Waveform_Time_to_Date_Time_String.vi ‏18 KB

Hello.
I checked your vi and it fails as you state.
It runs fine if: 1 Convert number to timestamp OR
2 Wire a constant to want seconds?
In labview 7.1, no problems.
I think is a job for NI engeniers.
Hope it helps
Alipio
"Qod natura non dat, Salmantica non praestat"

Increment the number with date/time string. when ever the next date come's it should reset again with initial number

i want to store the number of records in a file. Every time when ever i run the program the record will be incremented well i using forloop with count value 1 as a constant .in the for loop i am using autoincrement with the feedback node . to view the number i have attached the indicatator .the number will be increment every time . i am using number to time time stamp that is connected to get date/time string. from that we can view the date string and time string . so , my issue is when ever i close the code again it is coming with intial value . i should get from that number only where ever i close the code . after the date completed again it should come from intial value . i am attaching the code so that u guys can solve my problem.
Attachments:
record.doc ‏34 KB

here you can see.......the file path in case structure in that i have included my requirement of increment the number
-> if the case is true then it goes in ok file path and the no of records string will pass in the file by seeing these code u will get the clarity
my requirement is the number of records should increase ........ whnever the program runs...that i made it. by the next day again it should begain with the intial value.........that is my requirement. i hope u understand .
suggest me how can i use the intial value .......
Attachments:
code.vi ‏35 KB

Missing charsets in STring to FontSet conversion

Hi,
After installed SUn OS 10, I am trying to install SMC and I got a warning error: Missing Charsets in String to FontSet conversion. Cannot convert string "-monotype_arrial-regular-r-normal --*-140-*-*-p-*-iso8859-2" to type FonsStruct
and so on, with different font types. etc....
How can I find out which fontset in the Unix box? How can I permanent set it back to UTF-8 w/o re install OS again?
Thanks
HS

Too bad Lily didn't follow up on TommyReynolds' suggestion. I'm also having the same problem ( I think ).
TommyReynolds does say how to get the installed list, but doesn't say how to find out what's missing.
My settings:
[root@OEL5u4DB11gR2 X11]# rpm -qa 'xorg*font*' | /bin/sort
xorg-x11-fonts-100dpi-7.1-2.1.el5
xorg-x11-fonts-75dpi-7.1-2.1.el5
xorg-x11-fonts-base-7.1-2.1.el5
xorg-x11-fonts-ISO8859-1-100dpi-7.1-2.1.el5
xorg-x11-fonts-ISO8859-1-75dpi-7.1-2.1.el5
xorg-x11-fonts-misc-7.1-2.1.el5
xorg-x11-fonts-truetype-7.1-2.1.el5
xorg-x11-fonts-Type1-7.1-2.1.el5
xorg-x11-font-utils-7.1-2
[root@OEL5u4DB11gR2 X11]# uname -a
Linux OEL5u4DB11gR2 2.6.18-164.el5 #1 SMP Thu Sep 3 02:16:47 EDT 2009 i686 i686 i386 GNU/Linux
[root@OEL5u4DB11gR2 X11]# xclock &
[1] 5950
[root@OEL5u4DB11gR2 X11]# Warning: Missing charsets in String to FontSet conversion
I would greatly appreciate any input.
Kind regards,
UFP1701

Convert String to timestamp

Hi,
I have problem converting the following string to timestamp.
SimpleDateFormat sdf = new SimpleDateFormat(
"MM/dd/yyyy HH:mm");
sdf.setLenient(false);
String date = "200601110300";
long timeInMillis = sdf.parse(date).getTime();
Timestamp timestamp = new Timestamp(timeInMillis);
System.out.println(timestamp);
java.text.ParseException: Unparseable date: "200601110300"
thanks

Hi,
have problem converting the following string to
timestamp.
SimpleDateFormat sdf = new SimpleDateFormat(
"MM/dd/yyyy HH:mm");
setLenient(false);
String date = "200601110300";
long timeInMillis = sdf.parse(date).getTime();
Timestamp timestamp = new
Timestamp(timeInMillis);
System.out.println(timestamp);
Exception: Unparseable date: "200601110300"Of course there is an Exception thrown. The String you passed in doesn't have the expected format. If you want to parse 200601110300 int o a Date, give the formattter the proper format String:
yyyyMMddhhmm

String to TimeDate conversion

Hi,
I have a string like
20041002211500 (14 digit YYYYMMDDHHMMSS)
I want to get the Day of the year. I know I can use Format Date/Time String
with %j and get the output.
But, I cannot convert the string into TimeDate format.
How can I do that?
TIA

The %j will give you the day of the year. Your problem is to convert your string into a time/date format. The attached vi shows how. Basically you need to split your string using Scan From String into the different fields (MM/DD/YY/hh/mm/ss), then bundle these into the time/date cluster, then wiring the cluster into the Date/Time to Seconds function. The output of Date/Time to Seconds is then wired into the Format Date/Time String function. You can create the time/date cluster by right clicking on the input terminal of Date/Time to Seconds and selecting Create Control.
- tbob
Inventor of the WORM Global
Attachments:
DayOfYear.vi ‏30 KB

Strange "Scan From String" to Timestamp Error

hi,
i am trying to parse my time-string into a Time Stamp with "Scan From String" but i get some strange Error(1).
The Code:
The Error:
can anyone confirm? do i have an error in my parser-string?
is it possibly related to this Bug
461196
Scan From String VI returns Error 1 with "%t" as the format string input
http://www.ni.com/product-documentation/52151/en/
that should be fixed?
my labview version is
LV 2014 Service Pack 1 -- Version 14.0.1 (32bit)
with the RealTime addon (but the code in question was not run on RT)
thanks for your time.
Solved!
Go to Solution.

Why do you have the square brackets around the scan from string format string? They are not there when you generate the timestamp string so it will fail when trying to convert it back as they are expected to be there.
Certified LabVIEW Architect, Certified TestStand Developer
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Time String to Timestamp Conversion Problem

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