To count the number of occurences of a character

Hi All,
Is there a particular function to count the number of occurences of a particular character in a string...?
Let me know if u know the same.
Thanx and regards
Akshat

A method with a test driver:
public class a {
     public static void main(String args[]) {
          System.out.println(howmany(args[0],args[1].charAt(0)));
     public static int howmany(String what,char c) {
          String regexp = "" + c;
          String s=null;
          try     {
               s=what.replaceAll(regexp,"");
          catch (Exception e) {
                regexp = "\\" + c;
               s=what.replaceAll(regexp,"");
          return what.length() - s.length();
}

Similar Messages

How to count the number of occurences of a character

hi
wat command is used to count the number of occurences of a charcter in a line?
i have to count the number of '.' in a line

FIND
Searches for patterns.
Syntax
FIND <p> IN [SECTION OFFSET <off> LENGTH <len> OF] <text>
            [IGNORING CASE|RESPECTING CASE]
            [IN BYTE MODE|IN CHARACTER MODE]
            [MATCH OFFSET <o>] [MATCH LENGTH <l>].
The system searches the field <text> for the pattern <p>. The SECTION OFFSET <off> LENGTH <len> OF addition tells the system to search only from the <off> position in the length <len>. IGNORING CASE or RESPECTING CASE (default) specifies whether the search is to be case-sensitive. In Unicode programs, you must specify whether the statement is a character or byte operation, using the IN BYTE MODE or IN CHARACTER MODE (default) additions. The MATCH OFFSET and MATCH LENGTH additions set the offset of the first occurrence and length of the search string in the fields <p> and <l>.

Count the number of occurence in table with toplink

Hi !
there is no way to build a query with expressionbuilder or .... to count the number of occurences in my table ?
i don't want use query " select count(*) from table "
thanks

Not sure of the question. Are you looking to get the sql "select count(*) from table" from using the TopLink expression framework or are you getting that SQL already and want something else?
If you are looking just to get the count from a table/class, you can use a ReportQuery:
ReportQuery rquery = new ReportQuery(ClassToQueryOn.class);
rquery.addCount(); //equivalent to count(*);
session.executeQuery(rquery);
You can use a report query to return data instead of objects, and use selection criteria just like a normal read query.
Best Regards,
Chris

Count the number of occurences of a pattern in some files

Hi,
I am trying to extract some patterns in files using regex. I can easily extract the patterns using my program. I also wanted to count the number of occurences of the pattern in the files. For that I have written this code:
int count=0;
          while (m.find())
             System.out.println("Found Patterns: "+m.group());
             count++;
       System.out.println(count); //giving error saying identifier expectedUnfortunately I am getting an error saying identifier expected at the count line. What to do?
Thanks

Cheapside-Poultry wrote:
Move the } down one line so the count is in scope.No, it looks like he just forgot the opening { with the while.

I need to WAP to count the number of occurences of an alphabet in a string.

I need to WAP to count the number of occurences of an alphabet in a string.I tried a lot and have surfed a lot regarding this problem.
I m not the most proficient with java.but this is all i could come up with,and would appreciate some help here.I hope you guys would help me find a solution to this.
e.g String : abcabrty
Result should be
a:2
b:2
c:1
r:1
t:1
y:1
public class chkoccurences
     public static void main(String args[ ])
          String user_Data=args[0];
          int counter=0;
          try
               for(int i=0;i<user_Data.length( );i++)
                    for(int j=0;j<user_Data.length( );j++)
                         if(user_Data.charAt(i) == user_Data.charAt(j))
                         counter++;
                    System.out.println(user_Data.charAt(i)+" exists "+counter+" time(s) in the word.");
               System.out.println(" ");
          catch(ArrayIndexOutOfBoundsException e)
               System.out.println("Check the array size.");
}This is the output i get out of the program:
a exists 2 time(s) in the word.
b exists 4 time(s) in the word.
c exists 5 time(s) in the word.
a exists 7 time(s) in the word.
b exists 9 time(s) in the word.
r exists 10 time(s) in the word.
t exists 11 time(s) in the word.
y exists 12 time(s) in the word.What i think is i need an array to store the repeated characters because the repeated characters are getting counted again in the loop,if you know what i mean.
Please, i would appreciate some help here.

Criticism is welcomed
public class tests {
     final int min = 10;
     final int max = 35;
     final char[] chars = new char[] {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h',
               'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u',
               'v', 'w', 'x', 'y', 'z'};
     public static void main(String[] args){
          tests t = new tests();
          String[] strings = new String[] {"aabcze", "att3%a", ""};
          for(String s : strings){
               System.out.println(t.getAlphaCount(s));
     public String getAlphaCount(String s){
          int[] alphaCount = new int[26];
          int val;
          for(char c : s.toCharArray()){
               val = Character.getNumericValue(c);
               if( (val>=min) && (val<=max)){
                    alphaCount[val-min]++;
          StringBuilder result = new StringBuilder();
          for(int i=0; i<alphaCount.length; i++){
               if(alphaCount[i] > 0){
                    result.append(chars[i] + ":" + alphaCount[i] + ", ");
          if(result.length() != 0){
               result.delete(result.length()-2, result.length());
          return result.toString();
}

Counting the number of occurences in a table column

Hi All
I have a table with a column that contains approx. 5000 6-digit codes. A number of these codes are duplicted in the column, and I want to count the number of occurences of each code. The column looks a bit like -
WCID
940042
920012
940652
940199
188949
155146
155196
174196
152148
151281
196209
174015
182163
195465
195318
182008
189589
150675
There can be mulitple instances of each WCID and I need to count the number of instances of each. I also have access to another table that also has a column of each WCID, but only once - ie no multiple instances. The second table is identical except that there are only single instances of each WCID.
I thought I could either loop through on the table to be counted, from 100000 to 999999 and count each occurence that way, but it would be very inefficient. The other way I thought would be to perhaps select a WCID from the unique table, count the occurence of that, select the next WCID from the unique table, count that and so on, however I'm not sure how to do it in PL/SQL. Perhaps select the WCID from the unique table into a cursor, loop through that and compare it with the original table and count the instances?
I hope this makes some sense, any help would be really appreciated
Thanks
Bill

Hi, Bill,
That sounds like a job for GROUP BY:
SELECT    wcid
,         COUNT (*)       AS num_found
FROM      table_x
GROUP BY wcid
ORDER BY wcid
I hope that answers your question.
If not, post CREATE TABLE and INSERT statements for a little sample data, and the results you want from that data.

Fastest way to count the number of occurences of string in file

I have an application that will process a number of records in a plain text file, and the processing takes a long time. Therefore, I'd like to first calculate the number of records in the file so that I can display a progress dialog to the user (e.g. " 1234 out of 5678 records processed"). The records are separated by the string "//" followed by a newline, so all I need to do to get the number of records is to count the number of times that '//' occurs in the file. What's the quickest way to do this? On a test file of ~1.5 Gb with ~500 000 records, grep manages under 5 seconds, whereas a naive Java approach:
BufferedReader bout = new BufferedReader (new FileReader (sourcefile));
               String ffline = null;
               int lcnt = 0;
               int searchCount = 0;
               while ((ffline = bout.readLine()) != null) {
                    lcnt++;
                    for(int searchIndex=0;searchIndex<ffline.length();) {
                         int index=ffline.indexOf(searchFor,searchIndex);
                         if(index!=-1) {
                              //System.out.println("Line number " + lcnt);
                              searchCount++;
                              searchIndex+=index+searchLength;
                         } else {
                              break;
               }takes about 10 times as long:
martin@martin-laptop:~$ time grep -c '//' Desktop/moresequences.gb
544064
real     0m4.449s
user     0m3.880s
sys     0m0.544s
martin@martin-laptop:~$ time java WordCounter Desktop/moresequences.gb
SearchCount = 544064
real     0m42.719s
user     0m40.843s
sys     0m1.232sI suspect that dealing with the file as a whole, rather than line-by-line, might be quicker, based on previous experience with Perl.

Reading lines is very slow. If your file has single byte character encoding then use something like the KMP algorithm on an BufferedInputStream to find the byte sequence of "//\n".getBytes(). If the file has a multi-byte encoding then use the KMP algorithm on a BufferedReader to find the chars "//\n".getCharacters() .
The basis for this can be found in reply #12 of http://forum.java.sun.com/thread.jspa?threadID=769325&messageID=4386201 .
Edited by: sabre150 on May 2, 2008 2:10 PM

How to find out the number of occurence of special character

Hi ,
I have a string coming coming in I/p which is like '1;2;100;201;'
I need to break up this string and run my process for each value ( i.e for 1,2,100 and 201).
How i can know the count of number of occurences of ';' character?
How i can loop so that it runs once for each value?

1. Split, pre Oracle 10g...
===========================
with t as (select '10,aaaa,20,vvvvv,30,xxx''xx,12,12,56' txt from dual)
select substr( txt
             , decode(level, 1, 1, instr(txt, ',', 1, level-1)+1)
             , decode(instr(txt, ',', 1, level), 0, length(txt), instr(txt, ',', 1, level)
               - decode(level, 1, 0, instr(txt, ',', 1, level-1))-1)
             ) val
from t
connect by level <= length(txt)-length(replace(txt,','))+1
VAL
10
aaaa
20
vvvvv
30
xxx'xx
12
12
56
9 rows selected.2. Split, 10g onwards using regular expressions
===============================================
with t as (select 'aaaa,,bbbb,cccc,dddd,eeee,ffff' as txt from dual)
-- end of sample data
select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
from t
connect by level <= length(regexp_replace(txt,'[^,]*'))+1
REGEXP_SUBSTR(TXT,'[^,]+',1,LE
aaaa
bbbb
cccc
dddd
eeee
ffff
7 rows selected.example usage with varying IN clause...
SQL> ed
Wrote file afiedt.buf
1 select *
2 from emp
3 where ename in (
4    with t as (select '&input_string' as txt from dual)
5    select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
6    from t
7    connect by level <= length(regexp_replace(txt,'[^,]*'))+1
8*   )
SQL> /
Enter value for input_string: SCOTT,JAMES
old   4:   with t as (select '&input_string' as txt from dual)
new   4:   with t as (select 'SCOTT,JAMES' as txt from dual)
     EMPNO ENAME      JOB              MGR HIREDATE                   SAL       COMM     DEPTNO
      7788 SCOTT      ANALYST         7566 19-04-1987 00:00:00       3000                    20
      7900 JAMES      CLERK           7698 03-12-1981 00:00:00        950                    30
SQL>3. Split 10g onwards using XMLTABLE...
======================================
SQL> ed
Wrote file afiedt.buf
1 with t as (select 'This is some sample text that needs splitting into words' as txt from dual)
2 select x.*
3 from t
4      ,xmltable('x/y'
5                passing xmltype('<x><y>'||replace(t.txt,' ','</y><y>')||'</y></x>')
6                columns word varchar2(20) path '.'
7*              ) x
SQL> /
WORD
This
is
some
sample
text
that
needs
splitting
into
words
10 rows selected.

How to find the number of occurence of a string

String str="The AR tech seeks experienced candidates in java,jsp. The candidates should have atleast 1 year of experience in the specified skills.";
here i need to find the number of occurence of the string "experience".
how to find it out?

String str="The AR tech seeks experienced candidates in java,jsp. The candidates should have atleast 1 year of experience in the specified skills.";
String findStr = "experience";
int count = 0;
int index = 0;
while(index != -1) {
index = str.indexOf(findStr, (count == 0 ? 0 : index + findStr.length()));
if(index != -1) {
count++;

Counting the number of detail records at target side...

Hi
I have a requirement where i need to caluclate the number of detail records formed and add it in trailer section...both at target side...
The output will look like this :
<Detail>
    <Field></Field>
</Detail>
<Detail>
    <Field></Field>
</Detail>
<Detail>
    <Field></Field>
</Detail>
<Trailer>
   <Count> 3 </Count>
</Trailer>
Basically, In trailer the Count field will contain the number of Detail records.
Can this be achived by a UDF?? Please help!!!

Actually teh detail node formation at target depends on a lot of nodes of source side...using Count I have already done it but due to lot of nodes @ source side it becomes kind of a mesh...
Hence I was trying to figure out a way in which if I can count the number of detail nodes at target side I can remove the present mapping...
Corect me if I am wrong but can't we declare this target detail node as global variable and then use 'Count' function to capture its occurence???
P.S : In XI 3.0 we used to have a tab to declare global variables but here in 7.1 we have Functions tab...could anybody tell me how to declare the variable in 7.1?

Is there a way to count the number of times an array moves from positive to negative?

I have an array of values, and I need to find the number of times that the array changes signs (from positive to negative, or vice versa). In other words from a graphical standpoint, how many times a certain line crosses the x-axis. Counting the number of times the array equals zero does not help however, because the array does not always equal exactly zero when it crosses the axis (ie, the points could move from .1 to -.1).
Thanks for you help. Feel free to email me at [email protected] I only have lv 5.1.1 so if you attach any files, they cannot be version 6.0.

Attached is a VI showing the # of Pos and Neg numbers in an array, with 0 considered as non-Pos. It is easily modifiable to other parameters - including using the X-axis value as your compare point versus only Zero.
This is a modified VI from LV (Separate Array.vi)
Compare this with your other responses to find the best fit.
Doug
Attachments:
arraysizesposneg.vi ‏40 KB

How do I count the number of records returned in the CMIS query

How do I count the number of records returned in the query CMIS?
SELECT COUNT(*) FROM ora:t:IDC:GlobalProfile WHERE ora:p:xRegionDefinition = \'RD_PROJETOS_EXCLUSIVOS\''}
Euler Homero

Hi Euler,
interestingly enough, the reference guide for CMIS ( http://wiki.alfresco.com/wiki/CMIS_Query_Language ) that I found does not mention the COUNT function at all. On the other hand it states that: "The SELECT clause identifies which virtual columns to return in the result set. It can be either a comma-separated list of one or more queryNames of properties that are defined by queryable object types or * for all virtual columns."
There are, however, some other posts like e.g. http://alfrescoshare.wordpress.com/2010/01/20/count-the-total-number-of-documents-in-alfresco-using-sql/ which state that they could make it working.
Having asked in the WebCenter Portal forum, I assume that your content repository is WebCenter Content. The CMIS doc for the Content is available here: http://docs.oracle.com/cd/E23943_01/doc.1111/e15813.pdf (no COUNT there either). It does, however, mention explicitly that "CMIS queries return a Result Set where each Entry object will contain only the properties that were specified in the query.". This means your could rather investigate the Result Set. Note that there are also other means than CMIS how to get the requested result set (e.g. calling a search service directly via so-called RIDC).
In the given context I am also interested what your use case is. OOTB CMIS in WebCenter Portal is used, for instance, in Content Presenter, where it is content rather than "parameters" what's displayed.

How to count the number of rows in a cube!!??

Experts,
I can somebody tell me how do I count the number of rows in my cube when i am using listcube???..
Thanks
Ashwin

Hi,
have a look ath this theard too
Number of Records in Cube
regards

How to count the number of rows in a resultser object?

hi there
how to count the number of rows in a resultser object which may contains millions of rows? besides using a while loop? thanks

You don't, you execute a query whose result is the record count of those records that match the search and then you execute the actual query to create your record set. Typically you do
select count(id) from YourTable where [filter]
from the resulting ResultSet do
int res.getInt(1);
which gives you the count and then
select id from YourTable where [filter]
to produce the actual result set.
in the second query the id part can be substituted with the actual fields you want.

How to Count the number of TAB chars value '0A' in a line?

I have a requirement to count the number of TABs in a text file that I am processing (they must equal 75) to ensure that all the fields have been submitted on the file I am reading?
How do I identify the TABs in a line?
I have this so far:
         CONCATENATE gv_unix_file gv_lstfiles-name INTO gv_unix_file.
          OPEN DATASET gv_unix_file for INPUT IN TEXT MODE ENCODING NON-UNICODE.
          IF sy-subrc <> 0 .
            message e000(zz) with 'Cannot access in_uk files'.
          ENDIF.
          CONCATENATE gv_unix_file_arc gv_lstfiles-name INTO gv_unix_file_arc.
          OPEN DATASET gv_unix_file_arc FOR OUTPUT IN TEXT MODE ENCODING NON-UNICODE.
          IF sy-subrc <> 0 .
            message e000(zz) with 'Cannot access in_uk files'.
          ENDIF.
          DO.
            READ DATASET gv_unix_file into lv_str.
            IF sy-subrc <> 0.
              exit. "exit do loop, file is done.
            else.
              TRANSFER lv_str to gv_unix_file_arc.
            ENDIF.
          ENDDO.

Here is a sample code:
DATA: lv_string TYPE string,
      lv_tab TYPE c VALUE cl_abap_char_utilities=>horizontal_tab,
      lv_i TYPE i.
DATA: result_tab TYPE match_result_tab.
DO 3 TIMES.
CONCATENATE 'A' lv_string INTO lv_string SEPARATED BY lv_tab.
ENDDO.
" this is how you need to find how many tabs are in your transfer work area...
FIND ALL OCCURRENCES OF lv_tab IN lv_string RESULTS result_tab.
DESCRIBE TABLE result_tab LINES lv_i.
WRITE:'No. of tabs found:', lv_i.

To count the number of occurences of a character

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