To find the error in java code if any

Question

i was learnig java.net package and this is the code i wrote to read the contents directly from a given url using openStream() method of URL class and got the message 'error' from
java.io.IOException which i had given in the catch block. please tell me what is happening & how
could i read the content from an url with url class method.
import java.io.*;
import java.net.*;
public class url
public static void main(String[] args)
throws java.io.IOException,java.java.MalformedURLException
try{
URL yahoo = new URL("http://www.yahoo.com");
BufferedReader read_io = new BufferedReader(new InputStreamReader(yahoo.openStream()));
String line;
while((line =read_io.readLine())!= null)
System.out.println(line);
line.close();}
catch(MalformedURLException e)
System.out.println("error");
catch(IOException e)
System.out.println("error"):
after execution at the terminal
bash-3.00#javac url.java
bash-3.00#java url
error

Answer 1

Please use [code] tags when posting code.
Are you sure String has a close method? I'm not sure your code compiles.
Exceptions have a getMessage method, which can be useful (and a printStackTrace method that can be even more useful.)