To get actual age from sysdate

Question

sir,
i did what syntax u have provided but failed to get the value.
please check my query where had done wrong.
SQL>select trunc((to_char(&sysdate, 'mm/dd/yyyy')-to_char(&birthday, 'mm/dd/yyyy'))/10000)as age
from dual;
Enter value for sysdate: '10/14/2006'
Enter value for birthday: '02/08/1980'
select trunc((to_char('10/14/2006', 'mm/dd/yyyy')-to_char('02/08/1980', 'mm/dd/yyyy'))/10000)as age
ERROR at line 1:
ORA-01722: invalid number

Answer 1

but LAURENT SCHNEIDER is one of oracle certified master, who posted it.
does this syntax wrong????
please revert my question back.
How old are you?
I just come back from holiday, I am quite busy at the moment. Here is a tiny function to get the age
trunc((to_char(sysdate,'YYYYMMDD')-to_char(birthdate,'YYYYMMDD'))/10000)
it is much safer than add_months, because add_months do some conversion at the end of the month, and I would never accept to wait until Feb 29th, 2008 (28-2-1990 + 18*12 months) to be 18 if I were born Feb 28th, 1990.
POSTED BY LAURENT SCHNEIDER AT 5:43 PM
1 COMMENTS:
Anonymous said...
oh greate!!
def birthdate = to_date('2000/02/29','yyyy/mm/dd')
def sys_date = to_date('2003/02/28','yyyy/mm/dd')
select
trunc((to_char(&sys_date,'YYYYMMDD')-to_char(&birthdate,'YYYYMMDD'))/10000) as age from dual;
def sys_date = to_date('2003/03/01','yyyy/mm/dd')
select
trunc((to_char(&sys_date,'YYYYMMDD')-to_char(&birthdate,'YYYYMMDD'))/10000) as age from dual;
thanxx in advance