Transform incomplete xml

is it possible to transform a incomplete xml with xsl.
incomplete xml without root tag
+++++++++++++++++++++++++++++++++++++++++++++++++++++++
<log action="NEW_ORDER" time="06.06.2003 12:00:06">
</log>
<log action="NEW_ORDER" time="06.06.2003 12:00:06">
</log>
<log action="NEW_ORDER" time="06.06.2003 12:00:06">
</log>
+++++++++++++++++++++++++++++++++++++++++++++++++++++++
xsl file
+++++++++++++++++++++++++++++++++++++++++++++++++++++++
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text" indent="no" />
<xsl:template match="/">
OrderID, User, Name, Stock, Name, Time, Action, BS, Qty, Price, Source/Ref/MatchID, Memo/CounterParty, Account/OEMID, AccName/Mkt type, ExtKey/Short
<xsl:apply-templates />
</xsl:template>
<xsl:template match="log">
<xsl:value-of select="order/id" />, <xsl:value-of select="userInfo/effectiveUserId" />, <xsl:value-of select="userInfo/userId" />, <xsl:value-of select="order/securityCode" />, <xsl:value-of select="order/securitySymbol" />, <xsl:value-of select="order/completedTime" />, <xsl:value-of select="@action" />, <xsl:choose> <xsl:when test="order/side='1'">B</xsl:when> <xsl:when test="order/side='2'">S</xsl:when> <xsl:when test="order/side='3'">SS</xsl:when> </xsl:choose>, <xsl:value-of select="order/filledQty" />, <xsl:value-of select="order/price" />, <xsl:value-of select="suborder/id" />,, <xsl:value-of select="order/account" />, <xsl:value-of select="order/orderType" />,
</xsl:template>
</xsl:stylesheet>
+++++++++++++++++++++++++++++++++++++++++++++++++++++++
program code
+++++++++++++++++++++++++++++++++++++++++++++++++++++++
public static void main(String [] args) {
try {
StreamSource xslSource = new StreamSource(XSL_FILE);
StreamSource xmlSource = new StreamSource(XML_FILE);
StreamResult xmlResult = new StreamResult(new FileOutputStream(XML_RESULT_FILE));
TransformerFactory tFactory = TransformerFactory.newInstance();
Transformer transformer = tFactory.newTransformer(xslSource);
transformer.transform(xmlSource, xmlResult);
} catch(Exception ex) {
ex.printStackTrace();
+++++++++++++++++++++++++++++++++++++++++++++++++++++++
please help! any work arround?!

No. You can only use well-formed XML.
The workaround in your case is to wrap your XML fragment in a root element and then transform that.

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