Tree control parent node label

The following code works fine (except the part in caps, which
isn't code). Suggestions?
private function changeEvt(event:Event):void {
var theData:String = ""
if (event.currentTarget.selectedItem.@value) {
theData = " Data: " +
event.currentTarget.selectedItem.@value;
trace(event.currentTarget.selectedItem.@label + theData);
//trace(NEED PARENT NODE LABEL HERE IF IT EXISTS);
}

OK. So I stopped looking too soon. In my case:
trace(browserTree.selectedItem.parent().@label);

Similar Messages

How to Formate the Font of The Tree's Parent Node ?

Hello,
Pls. , how to Formate the Font of The Tree's Parent Node ?
Other Formatting Aspects..etc.
Regards,
Abdetu..

In ur code is HTREE$ is of type varchar2 or ITEM?
Give valid parameter for item_name/item_id.
This code will be usefull to add/change the icon of the node. You can show the 16x16 image (gif, ico based on your forms_home\forms\java\oracle\forms\registry\Registry.dat file) before the tree item's node lebel.
I tried in this way to get the "Favourites" node label as *"Favourites"* (Bold).
I make *"Favourites"* as a gif icon (16 x 270) and added it as a node icon. but it shows 16 x 16 of my image.
So using this code u cannot format the font of the tree's parent node.
Balaji.

Tree control with Nodes in ALV

Hi ABAP Gurus,
I am trying to create tree control with nodes in ALV. I have referred to standard BCALV_TREE* programs but new to OO programming. Not sure as to how I can display my internal table data than the SFLIGHT information in these programs. Can you please let me know how this can be done or if I can use any ALV function modules for the node display.
thanks,
Chaitanya

Maybe you could use this. Call this VI from a Value Change event of the tree.
Attachments:
Check_Tree_Items.vi ‏28 KB

Tree Control Property Node for Accessing "Child Text" String Array

When adding items to a tree control using the EditTreeItems invoke nodes, the inputs include "Child Tag", "Item Indent", "Child Only?", "Glyph Index", "Child Text", and "Left Cell String" as can be seen in this screenshot.
There are property nodes for the tree control for accessing each of these elements, except for the "Child Text", which is an array of strings. It is possible to access this data as outlined in this forum post, but this method is somewhat involved and round about.
I suggest that a property for the Tree class be created to access the Child Text array directly.

The work around only works if you do not have an empty string element some where in the middle.
At lest could the "Active Celltring Property" read return an error when you have gone beyond the end of the array.

Tree control's nodes and ites position

Hello,
Is there a way to get tree's nodes and items position,or
get it by ElementVisualizationMode and Hit event ?
Thanks,
Assaf

Hi
Using the new features, and I think I have found a bug that I was wondering if anyone else can comment on.
GetNodeLeft(BSTR key) ... perfect
GetNodeTop(BSTR Key) ... perfect
GetNodeHeight(BSTR Key) ... perfect
BUT
GetNodeWidth(BSTR Key) ... returns weird values, except for the first item in the tree.
The function then returns what seems to be:
(Control Width - (Height * Absolute Position))
The deeper one goes into the tree, the smaller the width becomes ...
Surely this is a bug ....

Not able to get the database data into the Tree Control

Hi Everybody,
I have to populate the tree control with nodes and items, which is to be populated from the database, and the tree control is dynamic. I mean, there is a toolbar, whenever a pushbutton is clicked, depending on that the tree contents has to be changed.
If anybody had worked with CL_GUI_COLUMN_TREE control to get the data from database, depending upon the pushbutton selected in Toolbar, please paste the seudocode for it.
Regards,
Abdul,
Intelligroup.
P.S: Helpful answers will be rewarded.

have you seen this demo program
SAPCOLUMN_TREE_CONTROL_DEMO
Regards
Raja

How to binding incoming xml node list to the tree control as dataProvider

Recently, I faced into one issue: I want to binding incoming xml node (it's not avaliable at start) list to the tree control as a dataProvider.
Since the incoming xml node list is not avaliable at beginning but I needs to bind it to the tree, so I create one virtual one in the xml, and prepare to remove it before the tree is shown. (ready for the actual node adding). But It did not work.
Please see the presudo-code here:
1. Model layer(CsModel.as)
public class CsModel
 [Bindable]
 public var treeXML:XML=<nodes><car label="virtualOne" id="1">
 </car></nodes>;
 (Here, I want to build binding relationship on the <car/> node,
 one 'virtual/stub' node is set here with lable="virtualOne".
 But this node will be deleted after IdTree
 control is created completely.)
 [Bindable]
 public var treeData:XMLList =new XMLListCollection(treeXML.car);
2. view layer(treePage.mxml)
 private var _model:CsModel = new CsModel();
 private function addNode():void
 var newNode:XML=<car/>;
 newNode.@label="newOne";
 newNode.@id=1;
 _model.treeXML.appendChild(newNode);
 private function cleanData():void
 delete _model.treeXML.car;
 <mx:VBox height="100%" width="100%">
 <mx:Button label="AddNode" click="addNode()" />
 <mx:Tree id="IdTree" labelField="@label"
 creationComplete="cleanData()"
 dataProvider="{_model}"/>
 </mx:VBox>
3. Top view layer (App.Mxml)
<mx:application>
 <treePage />
</mx:application>
For method: cleanData()，It's expected that when the treePage is shown, we first delete the virutalOne to provide one 'clear' tree since we don't want show virtualOne to the user. The virutalOne node just for building the relationship between treeData and treeXML at beginning. But the side effect of this method, I found, is that the relationship between treeXML and treeData was cut off. And this leads to that when I added new node (by click the 'addNode' button) to the xmlXML, the xmlData was not affected at all !
So Is there any other way to solve this issue or bind the incoming xml node list to the xmlListCollection which will be used as Tree control's dataProvider ?

If u want to display the name : value then u can do like this
<xsl:eval>this.selectSingleNode("name").nodeName</xsl:eval> : <xsl:value-of select="name" />

Save selected node in Tree control

I'm making this flex form for my school to add a new student
to the DB. When the admin clicks on a button it will open a Tree
control that displays the available courses and sections in the
following heirarchy:
Year>Semester>Course Name>Sections
Now I want that when he clicks on the button Select within
this new window showing the Tree, it will store the current
selected node and the full path to it, so that back in the original
form it will display the Year, Semester, Course name and section.
I've tried using the value and selecteditem methods from the tree
control but they are not working. Any ideas to figure out the full
path of the selected item?

You will need to climb back up the ancestor nodes to build
that path yourself.
"parent()" i believe returns the parent of the current node.
Tracy

Tree's node label disappear?

Guys,
I have the php returned me a xml data to my tree control.
When I expand or collapse a node, one of the children node's label
become empty. However, If I maximize the browser, everything is
back to normal. I am using Adobe Flex builder 3. Any idea?
-Alan

"2JZ" <[email protected]> wrote in message
news:glqtok$8v5$[email protected]..
> Amy,
>
> Here is how I declare teh tree control.
>
> <mx:Tree id="ViewTreeCtrl" width="100%" height="100%"
> horizontalScrollPolicy="auto"
allowMultipleSelection="true"
> color="#000000"
> dataProvider="{ViewXML}" labelField="@name"
borderStyle="none" alpha="1.0"
> selectable="true" iconFunction="TreeIconAssignment"
dropEnabled="true"
> dragEnabled="true" dragDrop="OnViewDragDrop(event)"
> dragEnter="OnDragEnter(event)">
>
> I am not sure if I am indirectly using custom
itemRenderers. When using
> these
> functions:
>
> labelField="@name"
> iconFunction="TreeIconAssignment"
>
> Where TreeIconAssignment() specify which embedded icons
to use base on
> the
> node's type.
That shouldn't cause the problem. I'm not seeing anything in
what you
posted that would cause the problem. Sorry :-(

How to get all items under a parent item in a tree control

Hello,
I have 2 questions regarding a tree control:
1) Is there any way to specify a parent item tag and get an array of ALL its sub item tags? For example, in the attached vi, specify the Parent#2 parent tag and get an array containing Item#P21 and Item#P22
2) Is there a way to specify a range to the ActiveCell property. For example, all items from line#1 to line number#3
Any ideas?
Attachments:
Tree example.vi ‏6 KB

Mentos wrote:
1) Is there any way to specify a parent item tag and get an array of ALL its sub item tags? For example, in the attached vi, specify the Parent#2 parent tag and get an array containing Item#P21 and Item#P22
Did you try a search? There's no direct way of doing this. You have to navigate the tree and build up an array. You can find an example here: http://forums.ni.com/t5/LabVIEW/get-all-children-of-a-parent-in-tree/td-p/729548
2) Is there a way to specify a range to the ActiveCell property. For example, all items from line#1 to line number#3
No. (It's called ActiveCell, not ActiveCells) Presumably you are trying to perform an operation on multiple items. Unfortunately, you need to use a loop. You should defer panel updates if you're doing this a lot.

Problem with trees(Duplication of the parent node in creation of children)

Hi guys i am experiencing a slight problem with the creation of trees.Here is a clear explanation of my program.I created a program that generates edges from a set of datapoints then use each and every edge that is generated to create multiple trees with the edge as the rootnode for each and every tree.Everything up to so far everything went well but the problem comes when i want the program to pick every single tree and traverse through the set of generated edges to create the children of a tree.What it does at the moment for each tree is returning the a duplication of the parent node as the child nodes and that is a problem.Can anyone related with this problem help.Your help will be appreciated.
The code
TreeNode class
package SPO;
import java.util.*;
public class TreeNode
 Edge edge;
 TreeNode node;
 Vector childrens = new Vector();
 public TreeNode(Edge edge)
 this.edge = edge;
 public synchronized void insert(Edge edge)
 if(edge.fromNode == this.edge.toNode)
 if(node == null )
 node = new TreeNode(edge);
 childrens.add(node);
 else
 node.insert(edge);
 childrens.add(node);
Tree class
package SPO;
import java.util.*;
public class Tree
 TreeNode rootNode;
 public Tree()
 rootNode = null;
 public Tree[] createTrees(Vector initTrees,Vector edges)
 Tree [] trees = new Tree[initTrees.size()];
 for(int c = 0;c < trees.length;c++)
 trees[c] = (Tree)initTrees.elementAt(c);
 for(int i = 0;i < trees.length;i++)
 for(int x = 0;x < edges.size();x++)
 Vector temp = (Vector)edges.elementAt(x);
 for(int y = 0;y < temp.size();y++)
 trees.insertNode((Edge)temp.elementAt(y));
return trees;
public void printTree(Tree tree)
System.out.print("("+tree.rootNode.edge.fromNode.getObjName()+","+tree.rootNode.edge.toNode.getObjName()+")");
Vector siblings = tree.rootNode.childrens;
for(int i = 0; i < siblings.size();i++)
TreeNode node = (TreeNode)siblings.elementAt(i);
System.out.print("("+node.edge.fromNode.getObjName()+","+node.edge.toNode.getObjName()+")");
System.out.println();
public Vector initializeTrees(Vector edges)
Vector trees = new Vector();
for(int i = 0;i < edges.size();i++)
Vector temp = (Vector)edges.elementAt(i);
for(int j = 0;j < temp.size();j++)
Tree tree = new Tree();
tree.insertNode((Edge)temp.elementAt(j));
trees.add(tree);
return trees;
public synchronized void insertNode(Edge edge)
if(rootNode == null)
rootNode = new TreeNode(edge);
else
rootNode.insert(edge);
EdgeGenerator class
package SPO;
import java.util.*;
import k_means.*;
public class EdgeGenerator
 public EdgeGenerator()
public Vector createEdges(Vector dataPoints)
//OrderPair orderPair = new OrderPair();
Vector edges = new Vector();
for(int i = 0;i < dataPoints.size()-1 ;i++)
Vector temp = new Vector();
for(int j = i+1;j < dataPoints.size();j++)
//Create an order of edges
Edge edge = new Edge((DataPoint)dataPoints.elementAt(i),(DataPoint)dataPoints.elementAt(j));
temp.add(edge);
edges.add(temp);
return edges;
Edge class
package SPO;
import k_means.*;
public class Edge
public DataPoint toNode;
public DataPoint fromNode;
public Edge(DataPoint x,DataPoint y)
if (x.getX() > y.getX())
this.fromNode = x;
this.toNode = y;
else
this.fromNode=y;
this.toNode = x;
Entry Point
package SPO;
import java.util.*;
import k_means.*;
public class Tester {
 public static void main(String[] args)
 Vector dataPoints = new Vector();
 dataPoints.add(new DataPoint(140, "Orange"));
 dataPoints.add(new DataPoint(114.2, "Lemmon"));
 dataPoints.add(new DataPoint(111.5, "Coke"));
 dataPoints.add(new DataPoint(104.6, "Pine apple"));
 dataPoints.add(new DataPoint(94.1, "W grape"));
 dataPoints.add(new DataPoint(85.2, "Appletizer"));
 dataPoints.add(new DataPoint(84.8, "R Grape"));
 dataPoints.add(new DataPoint(74.2, "Sprite"));
 dataPoints.add(new DataPoint(69.2, "Granadilla"));
 dataPoints.add(new DataPoint(59, "Strawbery"));
 dataPoints.add(new DataPoint(45.5, "Stone"));
 dataPoints.add(new DataPoint(36.3, "Yam"));
 dataPoints.add(new DataPoint(27, "Cocoa"));
 dataPoints.add(new DataPoint(13.8, "Pawpaw"));
EdgeGenerator eg = new EdgeGenerator();
Vector edges = eg.createEdges(dataPoints);
Tree treeMaker = new Tree();
Vector partialTrees = treeMaker.initializeTrees(edges);
Tree [] trees = treeMaker.createTrees(partialTrees,edges);
for(int i = 0;i < trees.length;i++)
treeMaker.printTree(trees[i]);
The program output
Each and every "@" symbol represents the start of a tree
@(Orange,Lemmon)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)
@(Orange,Coke)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)
@(Orange,Pine apple)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)
@(Orange,W grape)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)
@(Orange,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(Orange,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Orange,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Orange,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Orange,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Orange,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Orange,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Orange,Cocoa)(Cocoa,Pawpaw)
@(Orange,Pawpaw)
@(Lemmon,Coke)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)
@(Lemmon,Pine apple)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)
@(Lemmon,W grape)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)
@(Lemmon,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(Lemmon,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Lemmon,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Lemmon,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Lemmon,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Lemmon,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Lemmon,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Lemmon,Cocoa)(Cocoa,Pawpaw)
@(Lemmon,Pawpaw)
@(Coke,Pine apple)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)
@(Coke,W grape)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)
@(Coke,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(Coke,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Coke,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Coke,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Coke,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Coke,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Coke,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Coke,Cocoa)(Cocoa,Pawpaw)
@(Coke,Pawpaw)
@(Pine apple,W grape)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)
@(Pine apple,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(Pine apple,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Pine apple,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Pine apple,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Pine apple,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Pine apple,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Pine apple,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Pine apple,Cocoa)(Cocoa,Pawpaw)
@(Pine apple,Pawpaw)
@(W grape,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(W grape,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(W grape,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(W grape,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(W grape,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(W grape,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(W grape,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(W grape,Cocoa)(Cocoa,Pawpaw)
@(W grape,Pawpaw)
@(Appletizer,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Appletizer,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Appletizer,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Appletizer,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Appletizer,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Appletizer,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Appletizer,Cocoa)(Cocoa,Pawpaw)
@(Appletizer,Pawpaw)
@(R Grape,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(R Grape,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(R Grape,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(R Grape,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(R Grape,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(R Grape,Cocoa)(Cocoa,Pawpaw)
@(R Grape,Pawpaw)
@(Sprite,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Sprite,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Sprite,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Sprite,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Sprite,Cocoa)(Cocoa,Pawpaw)
@(Sprite,Pawpaw)
@(Granadilla,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Granadilla,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Granadilla,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Granadilla,Cocoa)(Cocoa,Pawpaw)
@(Granadilla,Pawpaw)
@(Strawbery,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Strawbery,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Strawbery,Cocoa)(Cocoa,Pawpaw)
@(Strawbery,Pawpaw)
@(Stone,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Stone,Cocoa)(Cocoa,Pawpaw)
@(Stone,Pawpaw)
@(Yam,Cocoa)(Cocoa,Pawpaw)
@(Yam,Pawpaw)
@(Cocoa,Pawpaw)

Your program description makes no sense. What exactly is it supposed to do?
Your errors make no sense. What is it doing wrong?
Your program output makes no sense. Look up pre-order, in-order, and post-order notation for representing trees. Pick one of those that you think would be best. I would go with pre-order. Because what you are doing isn't understandable.
By the way, I think your concept of a tree is flawed. A node in a tree has 3 things. it has a reference to its parent, it has references to any of its children, and it has some key value that represents the node (if each node were represented by numbers, the value would be an integer or something). In the case of the root, its reference to its parent is null. I don't know what you are doing with your tree, but it is highly confusing.

Af:tree Master child relation ,but showing child id's as parent node vice

Hi ,
Am using adf 11G 11.1.1.5
I have a small requiement .
Am using af:tree , where i display childId's . Onclick of child it i have to show popup with tree structure where i will show parentid as node and childId's as child nodes
i have created view link between child and parent views.
Now isssue is when i selected childId in table (i mean a checkbox is given where user check the child Id and fire button ).On dat action am calling popup with tree structure .BUT here childId's are displaying like Parent nodes and parentId's as child node.
any suggestion . if want i will drop the code

i knew somewhere i was messed up .
There is only viewlink between, Parent and child .NO FK ,these are not related database table (Entity Object.).
simple query's which are made from same table , but base on Parent/Root col i have show data in tree structure way.
Just like
ParentId Chilld id
100 jhon
100 max
100 adam
101 jack
103 jill
103 marven
Now it will show in table like
jhon
max
adam
jack
jill
marven
If i click max i mean check box and fire button , i have to show tree structure like below
100
jhon
max
adam
As max parentid is 100 , i have to show all the childid which have 100 as parentid.
any suggestion plz , me struck here to handel

Insert Parent Node From Tree To Another

Hello
My problem is: haw can I insert or shift Parent Node with its child from tree to another without use SQL query.
I should find the child and if this child has a child to shift with the parent to another tree, there are no tools or function can return the child of the node? Or what is the best procedure to do that?
I will be thankful if there some one can help me
Regards

You can grab the data with ftree.populate_group_from_tree and then use ftree.add_tree_data to put it in another tree.

Is it possible to put two different colors in tree parent node background and child nodes background?

Is it possible to put two different colors in tree parent
node background and child nodes background?
Any help will be very helpful.
Thanks

Hi PanosE,
Yes, you can set up another Standard Edition Server in child domain and then deploy pool pairing.
You need to deploy a new Front End Pool for the new Standard Edition Server.
A similar case for your reference.
https://social.technet.microsoft.com/Forums/office/en-US/eca4299c-8edb-481e-b328-c7deba2a79ba/lync-2013-standard-edition-lync-fe-pools-in-multiple-domain-single-forest-senario?forum=lyncdeploy
Best regards,
Eric
Please remember to mark the replies as answers if they help, and unmark the answers if they provide no help. If you have feedback for TechNet Support, contact [email protected]

ADF Tree setting focus back to parent node after deletion of child node

Hi,
Is there a way to get the focus back to the parent node (or rather any particular node) in a tree?
I have a use case where we need to get the focus back to the parent node after a child node is deleted.
Currently the focus is shifted to the next node in the tree, but the need is to get the focus shifted back to the parent node. Also the parent node should be re-invoked to populate to get the latest status after deletion of the child node.
Any help/pointers?
Thanks

Thanks for the reply Frank.
I saw the link http://sreevardhanadf.blogspot.in/2012/07/showing-next-row-as-current-row-after.html
However the issue is since I am using custom created tree using POJO tree item (composite object).
calling myTree.getWrappedData() doesn't gives me a handle to JUCtrlHierBinding and subsequent access to JUCtrlHierNodeBinding.
my program gives me data like -
List<MyTreeItem> treeData = (List<MyTreeItem>)treeModel.getWrappedData();
because my tree model is build using -
treeModel = new ChildPropertyTreeModel(items, "children");
where items is List of <MyTreeItem>
Hence I am unable to get a handle using -
List nodeParentList = nodeParent .getKeyPath();
I am programmatically able to invoke the parent node to get the fresh data, only issue is the focus/selection of that node is not happening
Is there a way around?
Thanks
Sachin

Tree control parent node label

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