Tricky SQL

Hi,
I have a table X that contains data and another table Y that contains user preferences data.
I am trying, without much success so far, to write an sql query which returns all data in table X if there are no preferences in table Y for a specific user and returns only matching data from table X if there are preferences in table Y for a specfic user.
select * from X
where exists (select 1 from Y
where Y.userid = 'aa'
and Y.colA = X.colB)
and X.colD between to_date('20-01-2010', 'dd-mm-yyyy')
and to_date('24-01-2010', 'dd-mm-yyyy');
if the user 'aa' has preferences in table Y then the query works and returns matching data from X but if the user 'aa' has no preferences data in table Y then no data from X is returned at all. I would like to have all the data from X returned in that case.
Any pointers on what i am doing wrong? Pls help as it's urgent.
Thanks.

something like this?
select * from X
where exists (select 1 from Y
where Y.userid = 'aa'
and Y.colA = X.colB)
and X.colD between to_date('20-01-2010', 'dd-mm-yyyy')
and to_date('24-01-2010', 'dd-mm-yyyy')
UNION ALL
select * from X
where not exists (select 1 from Y
where Y.userid = 'aa')

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Tricky sql queries for interview preparation

Hi,
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NKU wrote:
Great Work Kamran....:-)
Regards,
Navneet;)
Kamran Agayev A. (10g OCP)
http://kamranagayev.wordpress.com
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A few tricky SQL statements

I'm trying to do two fairly tricky SQL statements for a class, and been trying for a while and have gotten stuck.
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1.
SQL> WITH T
2       AS (SELECT 'mathematics' course_name, 'john' student_name, 'A' grade FROM DUAL
3           UNION ALL
4           SELECT 'mathematics' course_name, 'john1' student_name, 'A' grade FROM DUAL
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7           UNION ALL
8           SELECT 'mathematics' course_name, 'john3' student_name, 'B' grade FROM DUAL
9           UNION ALL
10           SELECT 'physics' course_name, 'john' student_name, 'A' grade FROM DUAL
11           UNION ALL
12           SELECT 'physics' course_name, 'john1' student_name, 'B' grade FROM DUAL
13           UNION ALL
14           SELECT 'physics' course_name, 'john2' student_name, 'B' grade FROM DUAL
15           UNION ALL
16           SELECT 'physics' course_name, 'john3' student_name, 'B' grade FROM DUAL)
17 SELECT   *
18    FROM   T;
COURSE_NAME STUDE G
mathematics john A
mathematics john1 A
mathematics john2 A
mathematics john3 B
physics     john A
physics     john1 B
physics     john2 B
physics     john3 B
8 rows selected.
SQL> WITH T
2       AS (SELECT 'mathematics' course_name, 'john' student_name, 'A' grade FROM DUAL
3           UNION ALL
4           SELECT 'mathematics' course_name, 'john1' student_name, 'A' grade FROM DUAL
5           UNION ALL
6           SELECT 'mathematics' course_name, 'john2' student_name, 'A' grade FROM DUAL
7           UNION ALL
8           SELECT 'mathematics' course_name, 'john3' student_name, 'B' grade FROM DUAL
9           UNION ALL
10           SELECT 'physics' course_name, 'john' student_name, 'A' grade FROM DUAL
11           UNION ALL
12           SELECT 'physics' course_name, 'john1' student_name, 'B' grade FROM DUAL
13           UNION ALL
14           SELECT 'physics' course_name, 'john2' student_name, 'B' grade FROM DUAL
15           UNION ALL
16           SELECT 'physics' course_name, 'john3' student_name, 'B' grade FROM DUAL)
17 SELECT   *
18    FROM   (SELECT     course_name, COUNT (*) total_cnt, SUM (CASE WHEN grade = 'A' THEN 1 ELSE 0 END) grade_cnt
19                FROM   T
20            GROUP BY   course_name)
21   WHERE   grade_cnt > total_cnt / 2;
COURSE_NAME TOTAL_CNT GRADE_CNT
mathematics          4          3
SQL>
2.
SQL> WITH T
2       AS (SELECT '1' course_id, 'john' student_name FROM DUAL
3           UNION ALL
4           SELECT '2' course_id, 'john' student_name FROM DUAL
5           UNION ALL
6           SELECT '1' course_id, 'peter' student_name FROM DUAL
7           UNION ALL
8           SELECT '2' course_id, 'peter' student_name FROM DUAL
9           UNION ALL
10           SELECT '3' course_id, 'king' student_name FROM DUAL
11           UNION ALL
12           SELECT '4' course_id, 'king' student_name FROM DUAL)
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14    FROM t;
C STUDE
1 john
2 john
1 peter
2 peter
3 king
4 king
6 rows selected.
SQL> WITH T
2       AS (SELECT '1' course_id, 'john' student_name FROM DUAL
3           UNION ALL
4           SELECT '2' course_id, 'john' student_name FROM DUAL
5           UNION ALL
6           SELECT '1' course_id, 'peter' student_name FROM DUAL
7           UNION ALL
8           SELECT '2' course_id, 'peter' student_name FROM DUAL
9           UNION ALL
10           SELECT '3' course_id, 'king' student_name FROM DUAL
11           UNION ALL
12           SELECT '4' course_id, 'king' student_name FROM DUAL),
13       r
14       AS (SELECT     student_name, SUM (POWER ( 2, course_id)) val
15               FROM   T
16           GROUP BY   student_name)
17 SELECT   DISTINCT student_name NAME
18    FROM   r
19   WHERE   EXISTS
20              (SELECT     'x'
21                   FROM   r r1
22                  WHERE   r1.val = r.val
23               GROUP BY   val
24                 HAVING   COUNT (*) > 1);
NAME
john
peterEdited by: G. on Feb 24, 2011 2:09 PM

Tricky SQL query to DUMP to flat file

Hi All,
I have used UTL file utility before to dump table data into a comma seperated file but this time I have a tricky problem.
I have a table called customers with the following fields
work_order_no, customer_no, contract_start_date, title, Name, first_name, street, street_no, bank_code, name, liason_name
and have a products table with following fields
work_order_number, material_type, material_number, qty
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A
1001,
1234,
12.01.2004,
Mr. Dr.,
Alphs,
Thomas,
my street,
12,
1112,
Barclays,
Mr. Dr. Alphs Thomas,
<EOH> - is a fixed
1001,
M,
12,
1,
<EOL> is fixed
1001,
M,
12,
1,
<EOL> is fixed
1001,
M,
12,
1,
<EOF> is fixed
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How do i write a Pl/Sql code which can be called from command prompt.
Thanks in advance

You can try this out and see if it works :
CURSOR to fetch the customers data
Loop
- Use a string to concatenate the cursor variables
- Use chr(10) to print the columns in seperate lines
i.e. lResult := x.work_order_no || ',' || chr(10)
|| x.customer_no || ',' || chr(10)
|| x.contract_start_date || ',' || chr(10)
|| x.liason_name || ',' || chr(10)
- Use Utl_File to write the formatted string to
the output file
- Use Utl_File to write constant '<EOH>' to the
output file
- Get all product details
- For each product details
Loop
lResult := x1.material_type || ',' || chr(10)
|| x1.material_number || ',' || chr(10)
|| x1.Qty || ',' || chr(10)
- Use Utl_File to write the formatted
string to the output file
- Use Utl_File to write constant '<EOL>' to
the output file
End Loop
End Loop
- Use Utl_File to write constant '<EOF>' to the output
file
- Use Utl_File to write counters to the output file
You can write the code in a PL/SQL script file called a.sql and save it on the server directory 'c:\a.sql'.
To run from the command prompt type:
c:\> sqlplus userid/pwd@connectstring @c:\a.sql
Hope this helps.
-- Shailender Mehta --

Need help in writing a tricky sql/PL/Sql Procedure

Hi,
I have a Branch table with just two fields in it node1 and Node2, The table looks like this
node1 | node2
-------|---------
1 | 2
3 | 2
3 | 4
4 | 5
1 | 5
1 | 6
5 | 6
in the above data if you draw lines between node_1 and node_2 you will see that there are 3 different paths to get from 1 to 5, as follows
/--------6-------\
1----------------------5
\2------3-------4/
Now I need to Find all the nodes between 1 and 5 or all the possible paths from node 1 to node 5 in this case I have 3 possible paths they are as follows
1-2-3-4-5
1-3-5
1-5
Now I know if this data was stored in a hierarchical manner I can get the results i want by using CONNECT BY and SYS_CONNECT_BY_PATH.
Is there a way to transform this data into a hierarchcal manner so that I can use the CONNECT BY or can somebody give me an Idea as to how to write a PL/SQL procedure to get the result I want.
Any help will be greatly appreciated

Hi!
1.Create another table Branch1 to hold 'transformed data'.
2.Use the following procedure to insert data into branch1 table.
declare
cursor n is select * from branch;
begin
for nrec in n loop
if nrec.node1 = 5 then
     insert into branch1(node1,node2) values(nrec.node2,nrec.node1);
elsif nrec.node2= 5 then
     insert into branch1(node1,node2) values(nrec.node1,nrec.node2);
else
if      nrec.node2> 5      then
     insert into branch1(node1,node2) values(nrec.node1,nrec.node2);
elsif nrec.node1> 5 then
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elsif (nrec.node1 < nrec.node2 ) then
     insert into branch1(node1,node2) values(nrec.node1,nrec.node2);
else
     insert into branch1(node1,node2) values(nrec.node2,nrec.node1);
end if;
end if;
end loop;
commit;
end;
3.Then execute the following connect by query:
SQL> select lpad(' ',level*2,' ')||node1 from branch1
2 start with node1=1
3 connect by prior node2=node1;
Hope this is satisfactory.
Thanks!

Tricky SQL query... how to get all data in a single query?

create table employee_definition (def_id number, def_name varchar(50));
insert into employee_definition values (100, 'EMAIL');
insert into employee_definition values (200, 'MOBILE_PHONE');
insert into employee_definition values (300, 'HOME_PHONE');
SQL> select * from employee_definition;
    DEF_ID DEF_NAME
       100 EMAIL
       200 MOBILE_PHONE
       300 HOME_PHONE
create table employee_data (def_id number, def_value varchar(20), emp_id number);
insert into employee_data values (100, '[email protected]', 123);
insert into employee_data values (200, '01232222', 123);
insert into employee_data values (300, '5555', 123);
insert into employee_data values (100, '[email protected]', 666);
insert into employee_data values (200, '888', 666);
insert into employee_data values (300, '999', 666);
insert into employee_data values (300, '444', 777);
SQL> select * from employee_data;
    DEF_ID DEF_VALUE                EMP_ID
       100 [email protected]              123
       200 01232222                    123
       300 5555                        123
       100 [email protected]              666
       200 888                         666
       300 999                         666
       300 999                         777
7 rows selected.I'm supposed to create a SQL that will return me the email, mobile_phone, and home_phone for a set of employees. The result will be something like this:
EMPLOYEE ID | HOME_PHONE | MOBILE_PHONE | EMAIL
123         | 5555 |    01232222      | [email protected]
666         | 999 |    888      | [email protected]
777         | 444 |    null     | nullThe thing I'm finding difficulty here is that the same column is used to store different values, based on the value in employee_definition table (something like a key/value pair). If I do:
SQL> select emp_id, def_value as email from employee_data, employee_definition
2 where employee_data.def_id = employee_definition.def_id
3 and employee_definition.def_name = 'EMAIL';
    EMP_ID EMAIL
       123 [email protected]
       666 [email protected]'s partially ok.. I'm just getting the definition for 'EMAIL'. But how can I get all the values in a single query, knowing that the column stores different values based on def_name?

Oh no, not again.
Entity attribute models always seem like a great idea to people who have been in the profession for five minutes and lack any kind of fundamental knowledge.
It staggers me that someone with 2,345 posts still believes "you need a 'detail table' for [storing multiple telephone numbers]"
"A person can have multiple telephone numbers" is not an excuse to build a tired person_attribute table. Niether is the bizarre proposal by someone with over 4k posts who should know better in an earlier post that EAV models are necessary to support temporal fidelity.
Taken to it's logical conclusion, EAV modelling leads to just two application tables. THINGS and THING_ATTRIBUTES. And when you consider that a THING_ATTRIBUTE is also a THING, why not roll those two tables up into one also? Hmmm, what does THINGS and THING_ATTRIBUTES look like? I know, TABLES and COLUMNS. Who would've guessed? SQL already provides the completely flexible extensible attribute model the advocates of EAV proscribe. But it also has data types, physical data independence, constraints and an efficient query language which EAV does not.
EAV modelling errodes the semantics of the attributes which are bundled into the "attribute" table.
There is no point in storing 12 different phone numbers with implied functional dependency to unconstrained and often repeating notional attributes like "MOBILE", "LANDLINE", "WORK", err, "WORK2", err, "MOBILE2", err, ... when this phone type attribute has no semantic value. When you want to call someone, you invariably want to retrive the prefered_phone_number which may depend on a time of day, or a call context.
These things need to be modelled properly (i.e normalised to BCNF) within the context of the database.

Tricky sql for report purpose

Hi all,
Please see the example and help me out is there any solution to get below Required output.
with t as (select '61527' as cp_Code,'RELEASE SWITCH' as Cp_Des,'88967095' as Part_No,'1800' as List_Price from dual union all
select '61527' as cp_Code,'RELEASE SWITCH' as Cp_Des,'88967095' as Part_No,'909' as List_Price from dual union all
select '61527' as cp_Code,'RELEASE SWITCH' as Cp_Des,'89018180' as Part_No,'4071.53' as List_Price from dual union all
select '61527' as cp_Code,'RELEASE SWITCH' as Cp_Des,'89018180' as Part_No,'5755.25' as List_Price from dual union all
select '61527' as cp_Code,'RELEASE SWITCH' as Cp_Des,'TEST1' as Part_No,'100' as List_Price from dual)
select * from t
Output of the above query
cp_Code          Cp_Des               Part_No          List_Price
61527           RELEASE SWITCH           88967095      1800
61527           RELEASE SWITCH           88967095      909
61527           RELEASE SWITCH           89018180      4071.53
61527           RELEASE SWITCH           89018180      5755.25
61527           RELEASE SWITCH           TEST1      100
Required output like this
cp_Code          Cp_Des               Part_No          List_Price
61527      RELEASE SWITCH      88967095                1800
                                        909
                         89018180                4071.53
                                        5755.25
                         TEST1                100
Thanks in advance .

Hi,
As Karthick said, the Presentation Layer is the best place to handle formatting like this.
For example, in SQL*Plus you can use the BREAK command:
BREAK     ON cp_code NODUPLICATES     ON cp_des NODUPLICATES     ON part_no NODUPLICATES
SELECT       *
FROM       t
ORDER BY cp_code
,       cp_des
,       part_no
,       list_price
;Output:
CP_CO CP_DES         PART_NO LIST_PR
61527 RELEASE SWITCH 88967095 1800
                              909
                     89018180 4071.53
                              5755.25
                     TEST1    100If you want the rows in the order in which you posted them, just change the ORDER BY clause.
This site notmally won't display multiple spaces (or tabs) together.
When posting formatted text (like your output), type these 6 characters:
(all small letters, inside curly brackets) before and after formatted sections.

Tricky SQL - is it possible using just SQL and no PL/SQL

Hello everyone,
Here is my data
create table experience (exp_id number(10), exp_name varchar2(20), root_exp_id number(10));
insert into experience values (642, 'Test', 5172);
create table experience_node (exp_node_id number(10), exp_node_type_id number(2));
insert into experience_node values (5172, 1);
insert into experience_node values (5173, 2);
insert into experience_node values (5174, 2);
create table experience_connector (exp_conn_id number(10), exp_conn_type_id number(2), exp_node_id number(10), parent_exp_node number(10) );
insert into experience_connector values (4287, 1, 5173, 5172);
insert into experience_connector values (4288, 2, 5174, 5173);
insert into experience_connector values (4289, 2, 5175, 5174);
When we run these queries:
select     parent_experience_node_id
from     experience_connector
where     experience_node_id = 5175;
select     parent_experience_node_id
from     experience_connector
where     experience_node_id = 5174;
select     parent_experience_node_id
from     experience_connector
where     experience_node_id = 5173;
select     parent_experience_node_id
from     experience_connector
where     experience_node_id = 5172;
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Thank you so much for you help.
Best,
Lakshmi

We can use "model clause" ;-)
create table T (id number(10), parentID number(10) );
insert into T values (5173, 5172);
insert into T values (5174, 5173);
insert into T values (5175, 5174);
commit;
select parentID
from T
model RETURN UPDATED ROWS
dimension by(id)
measures(parentID)
rules(
parentID[9999] = parentID[5175],
parentID[9999] = parentID[parentID[9999]],
parentID[9999] = parentID[parentID[9999]]);
PARENTID
    5172
or
select parentID
from T
model RETURN UPDATED ROWS
dimension by(id)
measures(parentID)
rules(
parentID[9999] = parentID[parentID[5175]],
parentID[9999] = parentID[parentID[9999]]);

Help me with this tricky sql....

i need a sql querry that displays ename,salary,max(salary) such that max(salary) should be in every column.
it should be like this...
Ename Salary max(Salary)
Smith 12000 18000
robert 8000 18000
frank 14000 18000
walter 18000 18000
stacy 5000 18000
thanks
sankar..

Hi, Sankar,
That's exactly what analytic functions do:
SELECT ename
,       salary
,       MAX (salary) OVER ()   AS max_salary
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You don't need an analytic clause in this case, but syntax still requires the parentheses in "OVER ()".

Tricky SQL statement

Hi,
I've got 3 columns X,Y & Z.
Each column can have the values 'A', 'B' or NULL.
If 2 out of 3 have an 'A' I want to get 'TEXT1', if 2 out of 3 have a 'B' I want to get 'TEXT2' in all other cases I want to 'TEXT3'.
I'm using 8.1.7.0.0 and only direct SQL is allowed (so no own functions or procedure's).
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create table test(x varchar2(1), y varchar2(1), z varchar2(1));
delete from test ;
insert into test values('A', 'A', 'A');
insert into test values('A', 'A', 'B');
insert into test values('A', 'A', null);
insert into test values('A', 'B', 'A');
insert into test values('A', 'B', 'B');
insert into test values('A', 'B', null);
select
min(decode (zcount,2,decode(zcol,'A','TEXT1','B','TEXT2','TEXT3') ,'TEXT3'))
from
(select zcol, count(*) zcount, zrowid
from
(select x zcol , rowid zrowid from test
union all
select y zcol , rowid zrowid from test
union all
select z zcol , rowid zrowid from test
group by zcol, zrowid
) AAA
group by zrowid
TEXT3
TEXT1
TEXT1
TEXT1
TEXT2
TEXT3

Help with a tricky sql

** Consider the following table; we'll name this 'entities' for
the following discussion.
ENTITY FORM DEPTH EQUIV SOURCE
100012802307W502 DVNU 1458 14399 GOVT
100012802307W502 DVNU 1458 14399 IPL
100012802307W502 PLSR 1455 14399 GOVT
100012802307W502 PLSR 4238 14399 wayrig
100012802307W502 PLSR 4450.4 14399 GOVT
100012802307W502 PLSR 4788.3 14399 GOVT
101070403227W300 BGVL 800 14399 GOVT
101070403227W300 DVNU 855.3 14390 IPL
101070403227W300 DVNU 855.6 14399 GOVT
** The goal
For each unique ID (only 2 in the above example table: 100012802307W502
and 101070403227W300)
We need to get a single 'formation pick'.
Without going into details, 'formation pick' is an industry term and
in our example, a formation pick is identified by the FORM attribute.
** The Problem
Given the above, the question which I need to answer is
for each unique ENTITY, I want to get the PLSR formation pick.
If for any ENTITY, there is not a PLSR pick, but there is
an EQUIVALENT pick then for that ENTITY, we want that equivalent pick
(in our example above, all FORM which have the same EQUIV value are
considered equivalent; thus for 100012802307W502, there are PLSR picks
while for 101070403227W300, there are not but there are equivalent
picks (DVNU and BGVL)
The picks are to be selected based on a priority
top priority is given to SOURCE wayrig
If a given pick does not have a wayrig, SOURCE, then accept IPL
Finally, if neither the wayrig, or IPL SOURCE are available,
accept the GOVT pick
Thus, for 100012802307W502, where there are multiple PLSR picks, we
want the one with the highest available priority
(the 100012802307W502 PLSR 4238 14399 wayrig)
row
For 101070403227W300, which does not have a PLSR pick, we need to consider
the qualifying equivalent picks and the highest applicable priority for
these picks is where SOURCE = GOVT -> rows
101070403227W300 BGVL 800 14399 GOVT
101070403227W300 DVNU 855.6 14399 GOVT
Thus, the final condition that
should there be 2 or more picks whose priority is the same, then we
want the one with the shallowest DEPTH
row
101070403227W300 BGVL 800 14399 GOVT
Thus the desired final results
ENTITY FORM DEPTH EQUIV SOURCE
100012802307W502 PLSR 4238 14399 wayrig
101070403227W300 BGVL 800 14399 GOVT
** Constraints
It is most desireable to achieve this without having to create
physical tables and/or views as the query(ies) must run against
a public database where users do not have create table privileges.
If anyone has solutions that include physical tables, please submit
these anyways as they may help us devise the ultimate approach that
we are seeking.
More info (in case this is helpful)
I have been working on this and variations of this problem for
a little while.
Here is a query that was submitted to me via this discussion group
sometime ago on a similar problem
select ENTITY, FORM, MIN(DECODE ( SOURCE,'wayrig',1,'IPL',2, 3)) PICK_PRIORITY
from entities
where EQUIV = '14399'
GROUP BY ENTITY, FORM
ENTITY FORM PICK_PRIORITY
100012802307W502 DVNU 2
100012802307W502 PLSR 1
101070403227W300 BGVL 3
101070403227W300 DVNU 3
as you can see, the above query gets me partially where I need to go.
Unfortunately, I have not been able to adapt the above query in such a
way as to get the rest of the information related to the selected ENTITY;
that is, the DEPTH, EQUIV, and SOURCE values are not present in the
selected data.
And of course, the above is only a piece of the puzzle as it does not
get me a single row per selected ENTITY.
Thanks for your consideration
null

"bounoe",
I am a little bit confused, because what you are asking for and the sample result seem to be in slight conflict. What you ask for does not require that equiv = '14399', but your results seem to.
So, if equiv must equal '14399', then
SELECT DISTINCT entity, form, depth, equiv, source
FROM entities
WHERE equiv = '14399'
AND (entity,
DECODE(form,'PLSR',1,2),
depth,
DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4)) IN
(SELECT entity,
DECODE(form,'PLSR',1,2),
MIN(depth),
DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4)
FROM entities
WHERE equiv = '14399'
AND (entity,
DECODE(form,'PLSR',1,2),
DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4)) IN
(SELECT entity,
DECODE(form,'PLSR',1,2),
MIN(DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4))
FROM entities
WHERE equiv = '14399'
AND (entity,DECODE(form,'PLSR',1,2)) IN
(SELECT entity,
MIN(DECODE(form,'PLSR',1,2))
FROM entities
WHERE equiv = '14399'
GROUP BY entity)
GROUP BY entity,DECODE(form,'PLSR',1,2))
GROUP BY entity,
DECODE(form,'PLSR',1,2),
DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4));
ENTITY FORM DEPTH EQUIV SOURCE
100012802307W502 PLSR 4238 14399 wayrig
101070403227W300 BGVL 800 14399 GOVT
If equiv need not equal '14399':
SELECT DISTINCT entity, form, depth, equiv, source
FROM entities
WHERE (entity,
DECODE(form,'PLSR',1,2),
depth,
DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4)) IN
(SELECT entity,
DECODE(form,'PLSR',1,2),
MIN(depth),
DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4)
FROM entities
WHERE (entity,
DECODE(form,'PLSR',1,2),
DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4)) IN
(SELECT entity,
DECODE(form,'PLSR',1,2),
MIN(DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4))
FROM entities
WHERE (entity,DECODE(form,'PLSR',1,2)) IN
(SELECT entity,
MIN(DECODE(form,'PLSR',1,2))
FROM entities
GROUP BY entity)
GROUP BY entity,DECODE(form,'PLSR',1,2))
GROUP BY entity,
DECODE(form,'PLSR',1,2),
DECODE(source,'wayrig',1,'IPL',2,'GOVT',3,4));
ENTITY FORM DEPTH EQUIV SOURCE
100012802307W502 PLSR 4238 14399 wayrig
101070403227W300 DVNU 855 14390 IPL
If neither of these is exactly what you need, please let me know.
Barbara
null

Tricky SQL*Loader

Does anyone have any suggestions on how to load a text file with the following layout:
1SYSTEM:   TMS1                                         STATE OF DISMAY                                     DATE: 10/23/06
REPORT:   B155A761                                    DEPARTMENT OF CONFUSION                                         TIME: 15:05
EMPL ID: AAF***                              ACTUAL FTE'S/TOTAL COSTS BY EMPL NAME                                   PAGE:     1
SPR IDX: F****                                    FOR PERIOD 07/06 THRU 08/06
JOB/TASK: F****/F****
0PROGRAM (F00) DEPARTMENT OF CONFUSION                                            ACTUALS THRU 08/06
0SUPER                        EMPL                    ---- MONTHS 07/06 THRU 08/06 ------   ---------- BIENNIUM TO DATE -----------
INDEX        NAME            ID      JOB    TASK     REG       OT STAFF MO      COST        REG         OT STAFF MO      COST
0F1150 XYZ, KELLY J.         123454 FJO1A FTO5A    284.0             1.63     6,688.22     735.0               4.23    17,296.52
                                      FJO1A FTO5D     38.0              .22       893.91      90.0                .52     2,128.73
                                      FJO1A FTW5T      6.0              .03       135.07       6.0                .03       135.07
0 *     XYZ, KELLY J.         123456                  328.0             1.88     7,717.20     831.0               4.78    19,560.32
0       ABC, ALICE M.         234567 FJB1A FTB5A      3.0              .02       107.83       3.0                .02       107.83
                                      FJB1A FTB5B                                             21.5                .14       881.81
                                      FJB1A FTB5D                                              5.5                .03       194.37
                                      FJB1A FTB5G      5.5              .03       192.11      22.0                .11       790.06
                                      FJB1A FTW5U                                              1.0                .01        41.20
                                      FJG1N FTG5C                                             17.0                .11       700.26
                                      FJG1N FTG5E     15.5              .09       557.19      15.5                .09       557.19
                                      FJG1N FTW5A      1.0                         35.95       1.0                           35.95
                                      FJG1N FTW5G                                              1.5                .01        61.79
                                      FJG1N FTW5H                                              1.0                .01        41.20
                                      FJG1N FTW5T      1.0                         35.95       3.0                .01       118.34
                                      FJG1N FTW5U                                              5.0                .03       205.96
                                      FJG1Q FTG5C                                              2.0                .01        70.69
                                      FJG1V FTG5E     64.0              .33     2,140.75      64.0                .33     2,140.75
                                      FJG2A FTG5C                                              2.0                .01        70.69
                                      FJG2A FTW5E                                              1.0                .01        41.20
                                      FJG2A FTW5J                                              9.0                .05       370.75
                                      FJG2A FTW5T      5.5              .03       197.72       5.5                .03       197.72
                                      FJO1A FTO5D    219.0             1.14     7,587.85     432.0               2.34    15,578.73
                                      FJO1A FTW5E                                              1.0                .01        41.20
                                      FJO1A FTW5G      1.0                         35.95       1.0                           35.95
                                      FJO1A FTW5T                                             65.5                .37     2,507.55
                                      FJO1A FTW5U                                              3.0                .02       106.00
                                      FJO1A FTW5V     34.5              .19     1,203.74      84.5                .49     3,103.17
                                      FJO1A FTW5W      2.0              .01        66.30       6.0                .04       219.51
0 *     ABC, ALICE M.       234567                    352.0             1.84    12,161.34     773.5               4.28    28,219.87
0       CDE, GEORGE         345678    FJB1A FTB5B    145.0              .82     5,390.09     536.0               3.05    19,574.79
0       EFG, MARGARET       456789    FJB1A FTB5B                                            138.0                .86     4,259.44
                                      FJG1N FTG5E                                              7.0                .04       191.76
                                      FJG1N FTW5G                                              1.0                           27.38
                                      FJG1N FTW5V                                              1.0                           27.38
                                      FJG1Q FTG5E                                              2.0                .01        54.78
                                      FJG1Q FTG5F                                              4.0                .02       109.56
                                      FJG1Q FTW5B                                              1.0                .01        31.48
1SYSTEM:   TMS1                                         STATE OF DISMAY                                              DATE: 10/23/06
REPORT:   B155A761                                    DEPARTMENT OF CONFUSION                                       TIME: 15:05
EMPL ID: AAF***                              ACTUAL FTE'S/TOTAL COSTS BY EMPL NAME                                 PAGE:     2
SPR IDX: F****                                    FOR PERIOD 07/06 THRU 08/06
JOB/TASK: F****/F****
0PROGRAM (F00) DEPARTMENT OF CONFUSION                                            ACTUALS THRU 08/06
0SUPER                        EMPL                    ---- MONTHS 07/06 THRU 08/06 ------   ---------- BIENNIUM TO DATE -----------
INDEX        NAME            ID      JOB    TASK     REG       OT STAFF MO      COST        REG         OT STAFF MO      COST
0F1150 EFG, MARGARET         456789 FJG1Q FTW5G                                              9.0                .05       279.29
                                      FJG1Q FTW5V                                              6.0                .03       180.76
0 *     EFG, MARGARET         456789                                                          169.0               1.02     5,161.83
0       HIJ, KEN H.           567890 FJG1B FTW5F    120.0              .71     4,226.34     324.0               1.86    10,868.58As you can guess, the first 5 lines need to be skipped everytime they appear. I am sure there is a fairly simple approach to this, but it is escaping me at this time.
I thought about loading the table into a single column table and then trying to write a query that ignores these lines and then parse out the remaining text into columns. But that seems a little convoluted and prone to inconsistencies.

Yeah, I figured I would just use this technique to fill in the data. I knew that part of the challenge ahead of time. Apparently this file comes from a mainframe and getting the output changed isn't an option.
I thought about the skip=n option, but as you stated, that doesn't help me with the subsequent headers.
I was hoping to avoid scripting an additional parser, but it is looking more and more unlikely that I will be able to skip that part.

Tricky SQL helpDates between dates

hi,
I need to return all months that fall between a date range. So for example,
Date range = 01-JAN-1999 to 01-JUN-1999
Should return JAN,FEB,MAR,APR,MAY,JUN
Any ideas on this one folks ?
Yhanks.
N

You can use BETWEEN
where col_date between to_date('01-JAN-1999','DD-MON-YYYY') and to_date('30-JUN-1999','DD-MON-YYYY')
hi,
I need to return all months that fall between a date range. So for example,
Date range = 01-JAN-1999 to 01-JUN-1999
Should return JAN,FEB,MAR,APR,MAY,JUN
Any ideas on this one folks ?
Yhanks.
N

Tricky SQL Query.. help

Hi all,
I am new with this forum, will be here often. i have a question about sq query that i need to run here.
OK. the table
customer
CID_ID CREATE_DT
0000000029003242 10-JUN-12
0000000029003074 10-JUN-12
0000000029003191 10-JUN-12
0000000029002097 09-JUN-12
0000000029004443 12-JUN-12
0000000028975367 10-JUN-12
0000000029004178 11-JUN-12
0000000028998641 07-JUN-12
0000000029003191 10-JUN-12
0000000028998641 07-JUN-12
10 rows selected
the question :
ok, for the result i wanted 2 column which is [cid_id, count(cid_id)] and it must be ordered by create_dt. i know it need group by and order by. i'm ok with using group by or order by them self, but i couldn't get these running at the same time beautifully.
anybody please help me, i have workied on this for 3 days already still i cannot see how i can do this.

/* Formatted on 8/16/2012 2:51:53 PM (QP5 v5.139.911.3011) */
WITH tmp
        AS (SELECT '0000000029003242' cid_id, '10-JUN-12' create_dt FROM DUAL
            UNION ALL
            SELECT '0000000029003074', '10-JUN-12' FROM DUAL
            UNION ALL
            SELECT '0000000029003191', '10-JUN-12' FROM DUAL
            UNION ALL
            SELECT '0000000029002097', '09-JUN-12' FROM DUAL
            UNION ALL
            SELECT '0000000029004443', '12-JUN-12' FROM DUAL
            UNION ALL
            SELECT '0000000028975367', '10-JUN-12' FROM DUAL
            UNION ALL
            SELECT '0000000029004178', '11-JUN-12' FROM DUAL
            UNION ALL
            SELECT '0000000028998641', '07-JUN-12' FROM DUAL
            UNION ALL
            SELECT '0000000029003191', '10-JUN-12' FROM DUAL
            UNION ALL
            SELECT '0000000028998641', '07-JUN-12' FROM DUAL)
SELECT cid_id, create_dt, cnt
FROM (SELECT cid_id,
               create_dt,
               COUNT (
                  cid_id)
               OVER (PARTITION BY cid_id
                     ORDER BY TO_DATE (create_dt, 'dd-Mon-yy'))
                  cnt,
               ROW_NUMBER ()
               OVER (PARTITION BY cid_id
                     ORDER BY TO_DATE (create_dt, 'dd-Mon-yy'))
                  rn
          FROM tmp)
WHERE rn = 10000000028975367     10-JUN-12     1
0000000028998641     07-JUN-12     2
0000000029002097     09-JUN-12     1
0000000029003074     10-JUN-12     1
0000000029003191     10-JUN-12     2
0000000029003242     10-JUN-12     1
0000000029004178     11-JUN-12     1
0000000029004443     12-JUN-12     1
Edited by: Indra Budiantho on Aug 16, 2012 12:53 AM

Tricky SELECT

Hi all,
I have a tricky SQL statement below:
SELECT field_x FROM TABLE B WHERE field_y=0;
will generate result = ABC. ABC is a field IN TABLE A
However WHEN I try TO USE the below query:
SELECT (SELECT field_x FROM TABLE B WHERE field_y=0) FROM TABLE A;
it gives me a different result (All records is ABC), compare to the below query result that I want:
SELECT (ABC) FROM TABLE A;
Please advise.
Thanks.

> I appreciate if you please give the some dos and
donts which i have to keep in mind ( except from the
business requirement) while designing database
structure for an application.
My 2c's.
Relational design works. It is mature. It is well documented. It works. Thus if you step outside the bounds of relational design, you must question WHY and make sure that answers are sound and logical. (obviously I do not refer to OLAP designs here, before someone jumps on my case ;-) )
That was the 1st cent. Logical design.
The 2nd cent says that know Oracle. Physical implementation of the logical design. Know Oracle concepts and fundamentals and features. E.g. a partitioned table can make the difference between a system that still works next year because it was able to scale with volumes.
It should be this simple.

Tricky SQL

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