Truncating the leading zeros

Question

hi,
Could anybody pls tell me how do i truncate the leading zeros in the incoming file structure.
Thanks,
Chinna

Answer 1

Hi,
Check this thread, i laready answered it there.
Suppressing leading zeroes during mapping
For you i pasting the solution here.
Write a UDF like this ..
public class test {
public static void main(String[] args) {
System.out.println(args[0].replaceAll("^0*",""));
Also you can use XSLT for this.
Try the XPath function number($string) in your XSLT and see if it does what you want. Since it turns any XPath object into a number, the leading zeros won't appear.
Use it ike this
<xsl:variable name="a">
<xsl:call-template name="removeLeadingZeros">
<xsl:with-param name="phone">
<xsl:value-of select="EVENT/ContactPhone"/>
</xsl:with-param>
</xsl:call-template>
</xsl:variable>
<xsl:template name="removeLeadingZeros">
<xsl:param name="phone"/>
<xsl:message>
<xsl:value-of select="$phone"/>
</xsl:message>
<xsl:choose>
<xsl:when test="starts-with($phone,'0')">
<xsl:call-template name="removeLeadingZeros">
<xsl:with-param name="phone">
<xsl:value-of
select="substring-after($phone,'0' )"/>
</xsl:with-param>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$phone"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Regards
Aashish Sinha
PS : Reward Point if Helpful