Try-catch, new to java

Question

Anyone know how to effectivly exit a try catch statement if the exception is thrown? Heres this code I'm working with:
public void create(){
     textCheck1 = textField1.getText();
     try{
       intCheck = Integer.parseInt(textCheck1);
     catch(IllegalArgumentException nfe) {
       System.out.println("NumberFormatException: Level must be a number between 1-70");
     if(intCheck>70){
         throw new NumberFormatException("NumberFormatException: Level must be a number between 1-70");
     else{
       TextArea.setText("Character Successfully Created");
       if(button1.isSelected()){
       System.out.println("Character: \n"+"Name: "+textField2.getText()+"\n"+"Job: "+box.getSelectedItem()+"\n"+"Level: "+textField1.getText()+"\n"+"Gender: Male"+"\n"+"Heroic: "+checkBox.isSelected()+"\n");
       else if(button2.isSelected()){
       System.out.println("Character: \n"+"Name: "+textField2.getText()+"\n"+"Job: "+box.getSelectedItem()+"\n"+"Level: "+textField1.getText()+"\n"+"Gender: Male"+"\n"+"Heroic: "+checkBox.isSelected()+"\n");
    }the way this is set up, when the catch block throws the exception the if-else executes anyway and the results are printed. If the string isn't formated correctly I want to throw the exception and exit the method. please help. thanks.

Answer 1

cyberjed1 wrote:
try{
intCheck = Integer.parseInt(textCheck1);
catch(IllegalArgumentException nfe) {
System.out.println("NumberFormatException: Level must be a number between 1-70");
}the way this is set up, when the catch block throws the exception the if-else executes anyway and the results are printed. If the string isn't formated correctly I want to throw the exception and exit the method. please help. thanks.Two flaws:
1) You're catching IllegalArgumentException instead of NumberFormatException. The catch would never be entered.
2) You're ignoring/swallowing the exception and doing a 'dumb' sysout instead of throwing the (new) exception.
Fix your code as follows:
try{
    intCheck = Integer.parseInt(textCheck1);
} catch (NumberFormatException nfe) {
    throw new NumberFormatException("NumberFormatException: Level must be a number between 1-70");
} Exactly the way as you did in the subsequent if block.
By the way, if you consider yourself new to Java, why don't you make use of the 'New to Java' forum? Here we expect a bit more from you.