Two BLOBS in a single table

So I have a table:
BLOB_TABLE
BLOB_ID Number (primary sequence key triggered automatically)
BULLETIN BLOB
BULL_FILE VARCHAR(255)
BULL_MIME VARCHAR(255)
BULL_LAST_UPDATE DATE
SUPERFORM BLOB
SUPER_FILE VARCHAR(255)
SUPER_MIME VARCHAR(255)
SUPER_LAST_UPDATE DATE
When I try to display either BLOB, it will only show the last BLOB loaded for that record.
Can I store two BLOB data types in a table? It doesn't seem to matter how I even try to display (even using the "download" link attached to the File Browse).
Or do I need to create two tables and link them together (I would rather not do this if I don't have to).
Please advise.

I'm trying to display the BLOB's image on an Interactive Report and Form but neither are working for me, even though I'm trying to follow the Demo/Sample Application to the letter! Aaagh!
Does this feature have a restriction that the table and field have to be in the same schema as the Apex workspace?
Just limiting it to the Form page, I haven't been able to get my image to display using either the apex_util.get_blob_file_src() function or defining a Number/Date Format.
I've checked my database and the image is stored in the BLOG.
1) The apex_util.get_blob_file_src() function shows a bad image icon in FireFox, nothing in IE8.
2) Trying to simplify, I defined the format as:
IMAGE:AEO_TESTING_BASELINE:ERROR_IMAGE::MIMETYPE:FILENAME:LAST_UPDATE_DATE
Where
:AEO_TESTING_BASELINE is the table name (in another schema, but granted and has public synonym)
:ERROR_IMAGE is the column name with the BLOB
:MIMETYPE is the column holding the mime info
:FILENAME is the column where the file name was stored
:LAST_UPDATE_DATE - date column
But Apex says: "AEO_TESTING_BASELINE" not found
I'm sure I've got the table and column names right.
Help! This is driving me nuts.
Thanks,
Stew

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Two Fields in a Single Table

Hello All,
I'm a newbie to the forum & to Crystal(9), I've searched the forum and ca't exactly find an answer to my question:
My goal is to be able to pull the Company Member Type & the Contact Member Type as part of the same report in the selection criteria.
My problem is: They both reside in the same table...
The question is: "how to be able to pull the info?"
If I need to provide more or clearer info pleasde let me know. Any help is appreciated.
Lost in DC - DJ

If you have a single table datasource record duplication wouldn't be a result of the select expert. In fact, I can't think of a case where a single table datasource could possibly duplicate records.
The duplicates must be the result of a join.
To answer your initial question, the select expert you enter is subjected, in its entirety, to each record in the joined tables.
The problem that I see with the above suggestion relates to precedence.
This:
cond 1 AND cond 2 AND cond 3 OR cond 4
Is not this:
cond 1 AND cond 2 AND (cond 3 OR cond 4)
In the case of the non-paren-ed select statement, it will return records that satisfy ALL of the AND conditions OR just the or condition.
In the second case, it will return all records that satisfy condition 1 and condition 2 AND either condition 3 or condition 4.
Try bracketing the ored conditions from the same table. That should solve your select problem, but not the duplication problem.

TopLink Question - Mutliple Object to Single Table mapping

Just a short question,
Does toplink support mapping feature as such that it can map two distinct objects with single table that when in insertion or selection those two objects can be manipulated, selected in single operation? I know that TopLink mapping supports single object from multiple table mapping, but I'm not sure about multiple objects being associated with single table.
Secondly, does Hibernate has something like what I described above?
Howard.

Hi Howard,
You can map two objects to a single table if the objects are related by aggregation.
In TopLink, two objectsa source (parent or owning) object and a target (child or owned) objectare related by aggregation if there is a strict one-to-one relationship between them, and all the attributes of the target object can be retrieved from the same data source representation as the source object. This means that if the source object exists, then the target object must also exist, and if the source object is destroyed, then the target object is also destroyed.
http://www.oracle.com/technology/products/ias/toplink/doc/1013/main/_html/tutbuild004.htm#sthref2325
-Blaise

Problem with inserting two BLOBs into a table using setBinaryStream

DBMS 9.2.0.1.0, Oracle JDBC driver 10.1.0.2.0
The following code insert in one INSERT two BLOBs
into two columns using PreparedStatement.setBinaryStream(). When the size of the of at least one blob exceeds
some limit (? 2k, 4k ?), the values are swapped and
inserted into wrong columns.
Please, is this a problem in JDBC driver?
====================================================
import java.io.ByteArrayInputStream;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.SQLException;
import java.sql.Statement;
* Test - two BLOBs swapped problem.
* If size of the blob is larger that some treshold, they are swapped in the database.
public class BlobSwapTest {
private static Connection getConnection() throws SQLException {
try {
Class.forName("oracle.jdbc.driver.OracleDriver");
} catch (ClassNotFoundException cnfe) {
throw new SQLException("ClassNotFoundException: " + cnfe.getMessage());
return DriverManager.getConnection("jdbc:oracle:thin:@//HOST:1521/DB", "USER", "PSWD");
private static void createTable() throws SQLException {
Connection conn = getConnection();
Statement stmt = null;
try {
stmt = conn.createStatement();
try {
stmt.execute("DROP TABLE BlobTest2");
} catch (SQLException e) {
System.err.println("Table BlobTest2 was not deleted: " + e.getMessage());
stmt.execute(
"CREATE TABLE BlobTest2 ("
+ " pk VARCHAR(512), "
+ " blob BLOB, "
+ " blobB BLOB, "
+ " PRIMARY KEY (pk)"
+ ")"
} finally {
try {
if (stmt != null) stmt.close();
} finally {
conn.close();
public static void main(String[] args) throws SQLException {
createTable();
Connection conn = getConnection();
PreparedStatement pstmt = null;
try {
conn.setAutoCommit(false);
pstmt = conn.prepareStatement("INSERT INTO BlobTest2 VALUES (?,?,?)");
final int size = 5000; // change the value to 500 and the test is OK
byte[] buf = new byte[size];
byte[] buf2 = new byte[size];
for (int i = 0; i < size; i++) {
buf = 66;
buf2 = 88;
pstmt.setString(1, "PK value");
pstmt.setBinaryStream(2, new ByteArrayInputStream(buf), size);
pstmt.setBinaryStream(3, new ByteArrayInputStream(buf2), size);
pstmt.executeUpdate();
conn.commit();
} finally {
if (pstmt != null) pstmt.close();
conn.close();
====================================================

See my response in the JVM forum.

How to get space between two values in a single cell of a table.

hello,
how to get space between two values in a single cell of a table.
thanks a lot.
kailash.

sorry i got the answer.

Taking data from two different server in a single table

Hi All,
can u plz tell me i want take a data from a two different server in a single table
Thanks,
Bell.

Again, you have written the same sentence. I have 2 servers Server1 and Server2 and one table called my_table (You or God knows where this table is).
Now tell us what you want to do ?
Sidhu
http://amardeepsidhu.blogspot.com

How to get two tansaction data's in a single table.

hi experts,
               I have 2 transaction data's:
Eg:
Transaction data 1:
ID       C1      C2     C3
101     10      20      30
102     11      21      31
103     12      22      32
Transaction data 2:
ID       C1      C4     C5
101     10      40      50
102     11      41      51
103     12      42      52
my question is, when i am trying to loading the data into the infocube, i should get both data's in a single table. that means it should be like:
ID    C1 C2   C3   C4   C5
101 10   20    30   40   50
102 11   21    31   41   51
103 12   22    32   42   52
Note: C1 object contains same data in both trandata's

Venkata,
In this case you should first load to ODS and then to Infocube. But both the data should have common key fields. Data fields can vary.
In your case suppoe ID be the key field. Both the dat should have ID, as the ODS will have ID as key field.
Now you can have two infosources and two update rules to the same ODS.
So the ODS strcuture will be:
ID C1 C2 C3 C4, C5
First data and second data as you gave. But the C1 in second dat should have an extra field as it will be overwritten if it is not a key field and will add a new record if the value of C1 is not same as that of data1.
First decide upon teh key fields of ODS. In update rules you can map only required fields from the respective tran data only. Like in first update rules you can map ID C1, C2, C3 only and in second you can map ID C4, C5. Now we need to evaluate only C1 for which I need some sample records and data relation
By this way you can get a single record in ODS after loading both data.

One insert creates two calls in def$_aqcall table .

Want to know if the following is a normal behaviour.
We use SQL*loader to load data into our database which is replicated via multi-master. Every row inserted into the database creates two rows in the def$_aqcall table. One call is rep_insert and the other is BLOB_UPDATE. We do have a column as BLOB datatype in the table .The LOB is *** not *** stored IN ROW. In effect, every row insert is translated into two calls and i am sure that it is also propagated to the replicated site as two calls. Is this a normal behaviour?, if so can you please explain why oracle does it that way?.
Regards
Rajesh
null

If I created two triggers on the same table and event
(before insert), which of them will be triggered
first ?...As already mentioned, prior to 11g the order of firing is undetermined.
The problem from the beginning is that I created the
second one as after insert and in the body of the
trigger I wrote (:new.xxx:= value) ... then an error
(that it should be before insert trigger or update
trigger), so I created it as before update ,,, but I
have already before update trigger (for primary
key)..... and the problem -I think- which of them
start first...If there is a conflict of interest inside the code then you will have to alter your design principle around this to cater for it. Also consider combining the code into a single before insert trigger to prevent any confusion.
Can make the second one as after insert and make
update statement instead of assigning (:new.xxx:=
value).....Attempting to update or query the same table as is causing the trigger to fire will result in a mutating table error. You can't do this.

How to display data from 2 different groups in a single table

Hi,
Following is the requirement:
The XML Content is below
ListOf_ssAssetMgmtAsset>
-<ssAssetMgmtAsset>
<ssAccountName>1-1D09-83031</ssAccountName>
<ssAccountPrimaryCountry>USA</ssAccountPrimaryCountry>
<ssAssetNumber>13111027</ssAssetNumber>
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<ssNaiGrantNumber>ABC</ssNaiGrantNumber>
<ssNaiProductType>System Security Software</ssNaiProductType>
<ssNaiSuperceded>123</ssNaiSuperceded>
<ssProductDescription>Upgrade extract local DB</ssProductDescription>
<ssProductName>1-1M5H-296</ssProductName>
<ssStatus>ABC</ssStatus>
<ssId>1X-ZY</ssId>
<ssCreated>01/01/1980</ssCreated>
<ssUpdated>01/01/1980</ssUpdated>
<ssCreatedBy>1X-ZY</ssCreatedBy>
<ssUpdatedBy>1X-ZY</ssUpdatedBy>
-<ListOf_ssAgreementEntitlement>
-<ssAgreementEntitlement>
<ssEntitlementEndDate>16/12/2009</ssEntitlementEndDate>
<ssEntitlementStartDate>16/11/2009</ssEntitlementStartDate>
<ssEntitlementType>Services</ssEntitlementType>
<ssNaiQuantity>2</ssNaiQuantity>
</ssAgreementEntitlement>
</ListOf_ssAgreementEntitlement>
-<ListOf_ssAgreementEntitlement>
-<ssAgreementEntitlement>
<ssEntitlementEndDate>10/12/2009</ssEntitlementEndDate>
<ssEntitlementStartDate>10/11/2009</ssEntitlementStartDate>
<ssEntitlementType>ServicePortal</ssEntitlementType>
<ssNaiQuantity>1</ssNaiQuantity>
</ssAgreementEntitlement>
</ListOf_ssAgreementEntitlement>
</ssAssetMgmtAsset>
</ListOf_ssAssetMgmtAsset>
The data needs to be displayed in the below manner where first grouping is by Account Country, then by Account Name. Then the table with 9 columns where in the first 5 columns are from first group and the next 4 are from second group.
Account Country
Account Name
ProductType Grant # Asset # Product SKU Product Name Entitlement Type Quantity /Nodes EntitlementStart Date Entitlement EndDate
I have the coding as
first for loop: <?for-each-group:ssAssetMgmtAsset;./ssAccountPrimaryCountry?>
second for loop: <?for-each-group:current-group();./ssAccountName?>
third which is for the table : <?for-each:current-group()?>
I close the above grp after product description.
One table with the first 5 columns and below second table is placed adjacent to the first to display the 4 columns with the grp <?for-each:ssAgreementEntitlement?>
how do I get all the 9 columns in a single row in a single table.
Any help is appreciated.
thanks

What is the lnk between the two
ssAssetMgmtAsset and ssAgreementEntitlement ?
you want to display all the ssAgreementEntitlement for every ssAssetMgmtAsset group ?
there shud be a link between them, you have link them and display.

Merging two records in a single record for the same matnr,werks and bwart.

Hi I have a requirement to merge two records into one single record using the quantity field from MSEG table.
I am selecting two records from the table MSEG. Now for these two records i have to add the quantity values into one variable.
Then there should be only one record for the same matnr,werks,bwart.
Any suggestion would be appreciated.
Regards,
Amit

hi,
You can COLLECT statement only if all non key fields are numeric.
This statement Adds all such fields and give us a single record.
Regards
Sumit Agarwal

Why do we create multiple aliases to a single table?

<h4>{color:#0000ff}Hi,{color}</h4>
<h4></h4>
<h4></h4>
<h4>{color:#0000ff} Why do we create multiple aliases to a single table in the same query?{color}</h4>
<h4></h4>
<h4></h4>
<h4>{color:#0000ff}{color:#000000}For Ex: {color}{color}</h4>
<h4>
{color:#000000}select name,address,phone, from emp e, emp e1{color}</h4>
<h4></h4>
<h4>{color:#000000}where e.empid = e1.empid;{color}</h4>
<h4>
{color:#0000ff}ofcourse the above query's where condition is not correct, but i am giving as an example only{color}</h4>
<h4>{color:#0000ff}I have seen similar kind of queries where a single table name is aliased 10 times in the same query{color}</h4>
<h4>{color:#0000ff}can someone help me to understand the logic behind it?{color}</h4>
<h4>{color:#0000ff}Thanks in advance{color}</h4>
<h4>{color:#0000ff}greddy.{color}</h4>
Edited by: greddy on Oct 24, 2008 2:46 AM

Hi,
When you say
FROM    emp e
,       emp e1you are using two copies of the same table.
Can you imagine using two copies of the same book at the same time?
Say you see a word (like "hyrax") that you don't know. You might look up that word in the dictionary.
The English sentence "Open the dictionary to the page containing the new word." is like this SQL query:
FROM    dictionary
WHERE   :unknown_word BETWEEN low_guide_word and high_guide_wordWhat if you saw that word while reading a book (let's call it book_a).
You might want to leave book_a open, and place the dictionary beside book_a, so you can easily compare how the word is used in book_a with the definition in the dictionary.
This corresponds to joining two tables in SQL:
FROM    book_a
JOIN    dictionary ON unknown_word BETWEEN low_guide_word AND high_guide_word
WHERE   book_a.page = whatever -- NOTE: both tables have a column called pageor you can use aliases for one or both of the tables
FROM    book_a      a
JOIN    dictionary d ON a.unknown_word BETWEEN d.low_guide_word AND d.high_guide_word
WHERE   a.page = whatever -- NOTE: both tables have a column called pageNow, imagine that book_a is itself the dictionary. Say you saw the word "hyrax" while you were looking up another word, "ibex".
You can do a side-by-side comparison, as above, if you have two copies of the dictionary. Leave one copy open to "ibex", and open the other copy to "hyrax".
This corresponds to a self-join in SQL:
FROM    dictionary a
JOIN    dictionary d ON a.unknown_word BETWEEN d.low_guide_word AND d.high_guide_word
WHERE   a.page = whatever -- NOTE: both tables have a column called pageNotice that this last bit of code is identical to the previous one, except that book_a is replaced with dictionary.
In this case, you must you a table alias, at least for one copy. It wouldn't make any sense to say "Leave the dictionary open to "ibex" and open the dictionary to "hyrax". You have to have some unique way of referring to each copy, such as "Leave the dictionary on my left open to "ibex" and open the dictionary on my right to "hyrax"."

Displaying two blocks in a single screen

Hi all,
I want to dispaly two screens in a single with as-usual properties.
Please give your suggestions with steps.
Thansk in advance,
Regards,
Balaaji.

hi balaji ,
create a main screen and in which create two sub screens . like this .
REPORT ZSUBSCREEN.
TABLES: USR02,       "Logon data
         SSCRFIELDS. "FIELDS ON SELECTION SCREENS
SUBSCREEN 1
SELECTION-SCREEN BEGIN OF SCREEN 100 AS SUBSCREEN.
SELECTION-SCREEN BEGIN OF BLOCK B1 WITH FRAME TITLE TEXT-010.
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SELECTION-SCREEN END OF BLOCK B1.
SELECTION-SCREEN END OF SCREEN 100.
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SELECTION-SCREEN BEGIN OF SCREEN 200 AS SUBSCREEN.
SELECTION-SCREEN BEGIN OF BLOCK B2 WITH FRAME TITLE TEXT-020.
    SELECT-OPTIONS: LASTLOGI FOR USR02-TRDAT.
SELECTION-SCREEN END OF BLOCK B2.
SELECTION-SCREEN END OF SCREEN 200.
SUBSCREEN 3
SELECTION-SCREEN BEGIN OF SCREEN 300 AS SUBSCREEN.
SELECTION-SCREEN BEGIN OF BLOCK B3 WITH FRAME TITLE TEXT-030.
    SELECT-OPTIONS: CLASSTYP FOR USR02-CLASS.
SELECTION-SCREEN END OF BLOCK B3.
SELECTION-SCREEN END OF SCREEN 300.
STANDARD SELECTION SCREEN FOR SCROLLING LEFT AND RIGHT
SELECTION-SCREEN: FUNCTION KEY 1,
                   FUNCTION KEY 2.
SELECTION-SCREEN: BEGIN OF TABBED BLOCK SUB FOR 15 LINES,
                   END OF BLOCK SUB.
START-OF-SELECTION.
     SELECT * FROM USR02 WHERE BNAME IN USERNAME
                           AND ERDAT IN LASTLOGI
                           AND CLASS IN CLASSTYP.
        WRITE: / 'User ', USR02-BNAME,
                 'Last Login Date ', USR02-TRDAT,
                 'Last Login Time ', USR02-LTIME,
                 'CLASS ', USR02-CLASS.
     ENDSELECT.
END-OF-SELECTION.
INITIALIZATION.
SCREEN ICON LEFT AND RIGHT
   SSCRFIELDS-FUNCTXT_01 = '@0D@'.
   SSCRFIELDS-FUNCTXT_02 = '@0E@'.
   SUB-PROG = SY-REPID.
   SUB-DYNNR = 100.
AT SELECTION-SCREEN.
   CASE SY-DYNNR.
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       IF SSCRFIELDS-UCOMM = 'FC01'.
         SUB-DYNNR = 300.
       ELSEIF SSCRFIELDS-UCOMM = 'FC02'.
         SUB-DYNNR = 200.
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     WHEN 200.
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         SUB-DYNNR = 100.
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         SUB-DYNNR = 300.
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         SUB-DYNNR = 200.
       ELSEIF SSCRFIELDS-UCOMM = 'FC02'.
         SUB-DYNNR = 100.
       ENDIF.
   ENDCASE.
regard,
sandeep patel
reward point if helpful

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Hi Experts,
I want to display two graphs in a single screen. It should be a pie chart.
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It is working fine.
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Hi Vimal,
Go throungh the following code. it will help you.
REPORT Z_3DGRAPH.*structure declaration for performance measurementTYPES: BEGIN OF ty_performance,
      company(15) TYPE c,
      q1 TYPE i,
      q2 TYPE i,
      q3 type i,
      q4 type i,
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types : BEGIN OF ty_opttable,
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        END OF ty_opttable.*Internal table and work area declarations
DATA: it_performance TYPE STANDARD TABLE OF ty_performance,
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INITIALIZATION.*start of selection event
START-OF-SELECTION.*clearing the work areas
CLEAR WA_PERFORMANCE.
CLEAR wa_opttable.*appending values into the performance internal table
wa_performance-company = 'Company A'.
wa_performance-q1      = 78.
wa_performance-q2      = 68.
wa_performance-q3      = 79.
wa_performance-q4      = 80.append wa_performance to it_performance.wa_performance-company = 'Company B'.
wa_performance-q1      = 48.
wa_performance-q2      = 68.
wa_performance-q3      = 69.
wa_performance-q4      = 70.append wa_performance to it_performance.wa_performance-company = 'Company C'.
wa_performance-q1      = 78.
wa_performance-q2      = 48.
wa_performance-q3      = 79.
wa_performance-q4      = 85.append wa_performance to it_performance.*appending values into the options internal tablewa_opttable-options = 'P3TYPE = TO'.
APPEND wa_opttable TO it_opttable.wa_opttable-options = 'P2TYPE = VB'.
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CALL FUNCTION 'GRAPH_MATRIX_3D'
    EXPORTING
      col1      = 'Quarter 1'
      col2      = 'Quarter 2'
      col3      = 'Quarter 3'
      col4      = 'Quarter 4'
       dim1      = 'In Percentage%'
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      titl      = 'Company Performances'
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Regards,
Rajesh Kumar

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Hi,
I have two hiearchyes on two master data objects, How best can i customise to view this two hiearchies in a single report.

Hi Nagendra,
Find the below links and blogs..
May be this will helps you
A BW hierarchy has the following properties:
Hierarchies are created for basic characteristics
Hierarchies are stored in special master data tables. They behave in a similar way to master data,
and can therefore be used and modified in all Info Cubes.
You can define several hierarchies for a single characteristic.
A hierarchy can have a maximum of 98 levels.
http://help.sap.com/saphelp_nw70/helpdata/EN/80/1a670fe07211d2acb80000e829fbfe/frameset.htm
https://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/b07849c7-3a5b-2b10-7586-c431d300a578
https://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/20a709c1-0a8e-2a10-21b4-f779728c63bf
/people/vijay.vijayasankar/blog/2008/03/13/crm2007-who-gets-to-see-what--some-strategies-for-managing-internal-and-external-users-part-1
/people/shafiq.rehman3/blog/2008/01/22/hr-interface-toolbox--pu12
/people/kamal.khanna/blog/2008/07/09/managing-data-of-most-valuable-asset-of-an-organization-employees
Regards
Sudheer

How to call two RFC in a single JAVA method.

Dear all,
I just want to know that how to call two RFC in a single java method which is defined in CRM implementation file. I'm using NWDS as the customization IDE & working on ISA 7.0.

Hi Sunil,
In the Backend Implementation class, in any method you can call multiple RFCs.
It will be the same way as you do for the single RFC call.
Following syntax is for your reference.
Get the JCO connection
JCoConnection connection = getDefaultJCoConnection();
JCO.Function func = connection.getJCoFunction("ZXXXXXXX");
set the import parameters
Execute it.
connection.execute(func);
get the data from export / table parameters
Now call the second RFC
func = connection.getJCoFunction("ZYYYYYYYYYY");
set the import parameters
Execute it.
get the data from export / table parameters
close the connection
Hope this will help you.
-Chandra.
Edited by: Chandra Sekhar Seeli on Jan 13, 2011 2:04 PM

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