Type 1 and Type 2 dimension in the same table
Assuming a table with both Type 1 and Type 2 dimensions how do you engineer an ETL load?
Please correct my options below if I am wrong
Option 1: Inside a Slowly changing dimension set all 3, fixed attributes, Historical attributes and changing attributes. Since historical attributes is Type 2 and changing attributes is Type 1. We get what we want, Correct?
Option 2: writing a merge statement, but not sure how exactly i would be code that.
Please suggest a way if you think both the options are wrong. Thanks in advance.
svk
Hi, Please refer to the
msdn blog.
Hope this helps..............
Ione
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SPEC_CODE,
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SESSION_DOM_MODE,
PRESTYPE_CODE,
PRESTYPE_DOM_TYPE,
DIA_CODE,
VISIT_TIME_START_RESP,
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VISIT_CODE_CRE_USER,
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APPOI_PAYRESP_CODE,
APPOI_DT_ACCIDENT,
PATIENT_LAST_NAME,
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CLINIC.CLINIC_CODE,
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VISIT.VISIT_TIME_DISCHARGE,
VISIT.APPOI_NB_DURATION,
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VISIT.VISIT_DATE_ACCIDENT,
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CLINIC.CLINIC_CODE_DISPL,
CLINIC.CLINIC_DESC,
SPECIALTY.SPEC_CODE,
SPECIALTY.SPEC_CODE_DISPL,
SPECIALTY.SPEC_DESC,
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APPOINTMENT.APPOI_TIME AS VISIT_TIME,
'' AS VISIT_TIME_ARRIVAL,
APPOINTMENT.APPTYPE_CODE,
APPOINTMENT.SESSION_DOM_MODE,
0 AS PRESTYPE_CODE,
'' AS PRESTYPE_DOM_TYPE,
0 AS DIA_CODE,
'' AS VISIT_TIME_START_RESP,
'' AS VISIT_TIME_DISCHARGE,
APPOINTMENT.APPOI_NB_DURATION,
APPOINTMENT.APPOI_TX_REASON AS VISIT_TX_REASON,
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DECODE(APPOINTMENT_GROUP.PAT_SEQ,NULL,0,1) AS VISIT_IND_GROUP,
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0 AS VISIT_IND_COMPLETE,
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'' AS VISIT_TX_DIAGNOSIS,
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0 AS CST_CODE_2,
0 AS CST_CODE_3,
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APPOINTMENT.APPOI_CODE_CRE_USER AS APPOI_CODE_CRE_USER,
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SYSDATE AS VISIT_DH_CRE,
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Hi Steve,
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user623359
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select e.*
from emp e
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(select 'x' from es1
where es1.rating >= 5
and es1.skill_code = 'SQL'
and es1.empno = e.empno)
and
exists
(select 'x' from es1
where es1.rating >= 6
and es1.skill_code = 'PLSQL'
and es1.empno = e.empno)
and
exists
(select 'x' from es1
where es1.rating >= 7
and es1.skill_code = 'JAVA'
and es1.empno = e.empno)
-- Addition (Another example)
with es1 as(
select s.skill_code, es.empno, es.rating
from skills s, emp_skills es
where s.skill_id = es.skill_id
/* main */
select e.*
from emp e
where
(select count(distinct es1.skill_code) from es1
where
((es1.rating >= 5 and es1.skill_code = 'SQL')
or
(es1.rating >= 6 and es1.skill_code = 'PLSQL')
or
(es1.rating >= 7 and es1.skill_code = 'JAVA')
and es1.empno = e.empno)
=3;
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