Understanding Star Schema Operations

Hi All,
I worked on Oracle Answers and have knowledge on Data Warehousing concepts. I have enough oracle documentation on OLAP, OBIEE, Data Warehousing.
But i 'm not able to understand the star schema concepts in and out. I'm lost on all documents, where i'm getting the simple answer on the following topics:
1. Is it necessary to create dimensions using CREATE DIMENTION or it can be a simple relational table structure with CREATE TABLE statement?
2. What will be the steps to create a very basic/simple star schema using DML statements not using any tool?
3. Where I can get very basic level step by step tutorial to create a very simple star schema by sql -> loading test data by sql commands -> then what queries we can use to get BI reports or using OBIEE to create a simple rpd.
Please give me some idea on this as I have to create a small OBIEE repository where i have to do create the warehouse and ETL process, everything.
Pls advise.
Thanks in Advance.
Sudipta

No my question was on creating the star schema. If i have to create a very simple star schema then can I create the star schema with the following relational tables?
create table dim_products (
product_id number primary key,
product_name varchar2(32),
brand varchar2(32),
category_name varchar(32),
sub_category_name varchar2(32)
create table dim_time (
time_id number primary key,
selling_date date,
selling_day number(2),
selling_month varchar2(12),
selling_Quarter varchar2(6),
year number(4)
create table dim_region (
region_id number primary key,
store_name varchar2(32),
city_name varchar2(32),
state_name varchar2(32),
country_name varchar2(32),
region_name varchar2(32)
create table fact_sales (
sale_id number primary key,
region_id number ,
time_id number ,
product_id number ,
unit_sold number,
constraint fact_sales1 foreign key (region_id) references dim_region (region_id),
constraint fact_sales2 foreign key (time_id) references dim_time (time_id),
constraint fact_sales3 foreign key (product_id) references dim_products (product_id)
Or I have to create the DIMENSIONS explicitly, in order to building the hierarchy levels?
Regards
Sudipta

Similar Messages

  • Star schema question

    Hi,
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    So my understanding is when I have for example 3 dimensions (product dimension, sales dimension, time dimension) and one fact table.
    The realization looks like this:
    product dim ->
    sales dim -> joiner operator = fact table with the IDs of the dims and measure
    time dim ->
    Please correct me if I am wrong.
    If there is something that I can read to this subject of matter it would be very nice if someone could post it.
    Thx

    Hi,
    first you load the dimensions. Every entry has an id (surrogate key) and some business key (coming from the data source).
    When you load the fact, you use the business key from the data source to join (using a joiner or lookup operator) the dimension and get the id (surrogate key) from it. You only load the id and the measures into the fact table.
    Make sure to handle the case that the business key is null or no entry in the dimension can be found.
    If you query the fact table you must always join the dimensions.
    Regards,
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  • What is star schema - pls explain with example

    Hai.
    what is star schema - pls explain with example
    thanks in advance
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    Hi Giri,
    SAP's BIW employs extended star schama
    The extended star schema consists of a fact table (in two parts, E and F - f is the inbound table, E long-term storage). Dimension tables are connected to the fact tables via the DIMID(dimension id) which is a generated value and is stored in both dimension and fact tables. In addition, the dimension tables are connected to tables which hold master data values (or bind the dimension table to tables that hold the values), such as S tables, P, Q, X, Y. These dimension tables hold SIDs, again generated keys which relate values in the dimension table (the DIMIDs) with master data values. Thus, at the time of the query, join operations ensure that the master data values can be merged with the key figure values stored in the fact tables.
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    Also follow the link for more info:
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    Thanks for any points you assign.
    Regards

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    I think (not sure) we join tables in SSAS queries and calculate aggregations in it.
    I think SSAS stores these values and joined tables and we do not need to evaluates those values again and this behavior is like a Data Warehouse.
    Is not it?
    So if I do not need historical data, Can I avoid creating Data Warehouse?
    On the backend SSAS uses queries only to extract the data
    B/w I was not explaining on SSAS. I was explaining on what happens inside datawarehouse  which is a relational database by itself. SSAS is used to built cube (OLAP structures) on top of datawarehouse. star schema is easier for defining relationships
    and buidling aggregations inside SSAS as its simple and requires minimal lookups to be performed. Also data would be held at lowest granularity level which can easily be aggregated to required levels inside OLAP cubes. Cube processing is very resource
    intensive and using OLTP system would really have a huge impact on processing performance as its nnot denormalized and also doing tranformation etc on the fly adds up to complexity. Precreating a layer (data warehouse) having data in required format would
    make cube processing easier and simpler as it has to just cross join tables and aggregate data based on relationships defined and level needed inside the cube.
    Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://visakhm.blogspot.com/ https://www.facebook.com/VmBlogs

  • Star schema design

    Hi,
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    Now what i don't understand is that instead of having Separate SID tables for linking the dimension and fact tables   why cant we make the DIMENSION table generic and keep them out of the infocube so that we can same the same dimension table for many infocube in this case we wont need SID tables.
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    Your dimension tables are filled based on your transaction data - which is why dimension table design is very important  you decide to group related data for the incoming transaction data into your dimension tables .
    The dimension tables have SIDs which in turn point to master data = in the classic star schema - the dimension tables are outside the cube but the dim tables have the master data within them whhich is overcome using the extended star schema.
    The reason why dimension tables can be reused is that the dim IDs and SIDs in the simension table correspond to the transaction data in the cube - and unless the dim IDs in both your cubes match you cannot reuse the dim tables - which means that you have exactly the same data in both the cubes - which means you need not have two cubes with the same data.
    Example :
    Cube 1 : Fact Table
    Dim1ID | DIM2ID | KF1
    1|01|100
    2|02|200
    Dimension Table : Dim 1 ( Assumin that there are 2 characteristics in this dimension ) - here the DIM1ID is Key
    Dim1ID | SID1 | SID2
    1|20|25
    2|30|35
    Dimension Table Dim 2 - Here the Dim2ID field is key
    Dim2ID| SID1 | SID2| SID3
    01| 30| 45
    02|45|40
    Here the Dim IDs for the cube Fact table are generated at the time of load and this is generated from the NRIV Table ( read material on Number Ranges ) - this meanns that you cannot control DIM ID generation across cubes which means that you cannot reuse Dimension Tables

  • HR Analytics Star Schema Definitions

    All--
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    Apparently on eDelivery they have finally made available the Source to Staging Mappings in spreadsheet form.
    Check that out.
    Bob Murching posted about it a few cycles ago on this forum as well.
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  • Star schema and Infoprovider

    Hello,
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    Thanks in advance

    Hi
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    From your statement, it is clear that you still need to get a better of understanding of the modeling. Instead refer to the link below. It's a fantastic document.
    http://www.sdn.sap.com/irj/scn/index?rid=/library/uuid/6ce7b0a4-0b01-0010-52ac-a6e813c35a84
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  • Need help with an extended star schema.

    I have the following data in spreadsheet form and I need to transpose this into an extended star schema in order to prdouce my characteristics and key figures, however I'm having a little trouble understanding where to include the Product Group in the star schema and also what to do with the Sales Doc (Invoice Number) in the sales information spreadsheet. 
    I need to summarise the data into the following also:
    1.     Total quantity and revenue for each Channel and product group
    2.     Total quantity and revenue for each Channel and product group (July 2009 to September 2009)
    3.      Total Quantity and Revenue for iphone sales
    So my question in short is what would the star schema look like?  I'm hoping somebody can help me over this hurdle.
    The following are the details from the spreadsheet:
    Product Details (Attributes)
    File Name:  Product_Details.csv
    Structure     FieldName     Length     Description
         ProdID     5     Uniquely identifies a product
         PG_Group     20     Identifies products in specific groups (Navigational field)
    Sample Data
    ProdID,PG_Group
    PDS01,COMPUTER
    PDS02,COMPUTER
    PDS03,COMPUTER
    PDS04,ACCESSORIES
    PDS05,ACCESSORIES
    PDS06,ACCESSORIES
    PDS07,ACCESSORIES
    PDS08,HARDWARE
    Product Description (Text)
    File Name:  Product.csv
    Structure     FieldName     Length     Description
         ProdID     5     Uniquely identifies a product
         Prod_Desc     Medium Text     Represents the product description
    (Navigational field)
         Language     2     Represents the language descriptor
    Sample Data
    ProdID,Prod_Desc,Language
    PDS01,Notebook Speedy I,EN
    PDS02,Notebook Speedy II,EN
    PDS03,PC Thinkbox I,EN
    PDS04,USB Adaptor,EN
    PDS05,iPhones PX2,EN
    PDS06, Stereo Kit,EN
    PDS07,Camera Connector,EN
    PDS08,USB Storage,EN
    Transactional Data
    Sales information
    File Name:  Sales.txt
    Structure     FieldName     Length     Description
         Product     5     Uniquely identifies a product
         Sales Doc     4     Sales Document number (Invoice Number)
         Calendar Year     8     YYYYMMDD format
         Channel     1     Represents the distribution channel the product was sold by
         Quantity     4     Numeric value indicating the number of each product sold on a specific sales document
         Unit     2     Refers the unit specified by the quantity
         Revenue     8     Refers the sales amount of a specific product on a specific sales document
         Currency     3     Relates the revenue currency type
    Sample Data
    Product;Sales Doc ,Calendar Day,Channel,Quantity,Unit;Revenue,Currency
    ZD_PROD,0DOC_NUMBER,0CALDAY,ZD_CHAN,ZD_QTY,0UNIT,ZD_REV,0CURRENCY
    PDS07,7389,20090705,A,95,EA,151905,USD
    PDS08,7389,20090705,A,115,EA,264385,USD
    PDS02,7473,20090706,B,55,EA,3580445,USD
    PDS01,7472,20090706,C,110,EA,604989,USD
    PDS02,7472,20090706,C,43,EA,2799257,USD
    PDS03,7472,20090706,C,75,EA,4507425,USD
    PDS04,7472,20090706,A,339,EA,301032,USD
    PDS06,7472,20090706,A,120,EA,47976,USD
    PDS01,7473,20090718,D,55,EA,3024945,USD
    PDS02,6845,20090806,B,30,EA,195297,USD
    PDS07,6877,20090807,C,800,EA,12792,USD
    PDS08,6877,20090807,C,250,EA,57475,USD
    PDS03,6912,20090812,C,250,EA,1502475,USD
    PDS04,6900,20090812,B,70,EA,6216,USD
    PDS01,6899,20090812,C,12,EA,659988,USD
    PDS04,6899,20090812,D,55,EA,4884,USD
    PDS04,7479,20090815,C,80,EA,7104,USD
    PDS05,7479,20090815,C,300,EA,70497,USD
    PDS05,6809,20090818,A,1000,EA,234990,USD
    PDS06,6809,20090818,A,130,EA,51974,USD
    PDS03,6831,20090822,C,15,EA,901485,USD
    PDS04,6831,20090822,C,500,EA,4440,USD
    PDS03,6830,20090822,C,125,EA,7512375,USD
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    Sample Data
    ChanID, Chan_Desc
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  • EIS and setup of Star Schema

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    Message was edited by: Sudhakar Upadhyaya
    Message was edited by: Sudhakar Upadhyaya

    About you last question:
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    By the way the easier way to solve such a doubts is to read something about MultiDimensional Data Modeling: there's a wide litterature about this topic that can't be summarized in few rows without omitting important notes
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  • Snowflake/Star Schema in OBIEE

    Hi Gurus,
    I would be very glad if you can help me to resolve this problem.
    Before posting, I searched the forum there are similar queries(Circular Join) but I do not get the solution.
    I have fact and dimension tables builded with star schema which I do not have any problem. But there is a fact table which has dimension to dimension relation between them.
    When I tried to connect them which I explained in below I am getting error(Circular join problem) or If I fix the error, In Obiee analysis I am getting another error which says there is no fact table between tables. Let me explain the situation;
    I have 4 dimensions table and a fact table;
    connection between them;
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    Date Dim(1) ---> Fact.A(N)
    Customer Dim(1) ---->Fact.A(N)
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    I can see that there are bunch of circular join in here :(. I did not understand to use Alias to resolve this problem.
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    If you do not understand the question I will try to be more clear.
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    Hi M.S,
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    Hope this helps.
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  • Strange star schema created by tutorial

    Hi, I have a fresh and clean installation of BI SE1.
    I followed the steps for the tutorial (those related to OWB and created the data mart).
    I really don't understand what kind of star schema is the resulting one and I think there might be a bug in OWB.
    In "Sales" table there are no rows referencing those records in dimensions which have negative dimension keys. So why generating those rows in dimensions? They are useless...

    I understand that...But
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    2) the Channels dimension in BISE1_SALESWH is not correct, in fact it is different from that in BISE1_TUTORIALWH.
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  • Star Schema and Oracle 11gR2 ?

    Star Schema and Oracle 11gR2 ?
    I know the star schema (ROLAP) and implemented couple of them. Apart from general design principle of dimension, FACT, surrogate key etc, what are the specific items needed in Oracle 11gR2?
    Some one talked about over 10 conditions/pre-requisits for Star Schema (ROLAP) implementations in Oracle 11gR2. I did some search, but I did not get any hits.
    Do we design Star schema (ROLAP) differently in Oracle 11gR2?
    Any pointer welcome.
    Thanks in helping.

    Hi,
    from my experience there are no specific requirements for the star schema design when using owb 11.2.
    When using the OWB ETL Option (extra license required), one may use the owb dimensions and cubes.
    These make mapping development easier, since support for SCD2 is built into the dimension operators. Loading the cube is simplified because the lookup of the surrogate key from the dimension is built into the cube operator.
    These owb objects will deploy specific dimension and fact tables. If you already have existing ones, you must modify them manually.
    I implemented several projects without these advanced features. Baiscally I did the same in OWB what I would have done using hand-coded SQL and PL/SQL. And it worked just fine.
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    Carsten.

  • Master data sharing using ext. star schema

    Hi,
    I have undetrstood the concept of extended star schema.
    I understand,
    One of the advantages of extended star schema is, that the master data can be shared, meaning, since the master data is stored separately, other star schema's can also share this master data provided it is of the same relevance( with same infoobjects used in this star schema).
    Confirm if my understanding is right and if right,
    Any idea or suggestion how to demonstrate this ?
    Points will be given for good answers.
    thanks.
    bwlearner

    Hey,
    If u could map this with programming.
    MASTER DATA Tables are like GLOBAL declaration and InfoCubes (Fact Tables) are like LOCAL declaration. Any number of IncoCubes can access one particular Master Data Table.
    Assume Sales data coming from 5 regions. Here 0CUSTOMER & its attributes will update the same Master Data Table. The data fields will be stored in the Infocube. So all the 5 InfoCubes access the same Master Data tables using the Dimension & SID tables.
    Clear ?
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  • Star schema in Physical Layer

    Recently, i came across a question from one of colleague. The discussion went as follows:
    He asked me what is star schema and where can you define it? Physical layer or BMM layer?
    I explained about star schema and answered his rest of the doubt that, we define it in BMM layer.
    His immediate question is why can't we define it in Physical layer? Since BMM layer allows to build dimensional models, so, we have to build it in that layer itself is my reply. But, later in the evening, when i started thinking on my way to home, i started thinking about his doubt.
    Here, what am curious to know is since we can join tables in Physical layer too, why can't we define star in Physical layer? and why only in BMM? and what are the difference in the Joins that we made in Physical layer to that of BMM layer?
    I tired getting answers for these in documents and in some other online resources, but, am not succeed. So, am approaching this forum in anticipation. Can anyof you help us understanding these concepts better.

    In OBIEE Server Administration Guide it is written for logical fk join:
    Logical foreign key joins might be needed if the Oracle BI Server is to be used as an ODBC data
    source for certain third-party query and reporting tools. Typically, you should not create logical
    foreign keys. This capability is in the Administration Tool to provide compatibility with previous
    releases.
    And logical complex join:
    The use of logical complex joins is recommended over logical key and foreign key joins.
    And physical complex join:
    In the physical layer of the repository, complex joins are joins over nonforeign key and primary key
    columns. When you create a complex join in the physical layer, you can specify expressions and the
    specific columns on which to create the join. When you create a complex join in the business model
    layer, you do not specify expressions.
    I agree, that always are some special cases, but in general it should be clear when to use which joins.
    So, you should read chapters 4,5 one more time this administration guide [OBIEE server administration guide|http://download.oracle.com/docs/cd/E10415_01/doc/bi.1013/b31770.pdf]

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    Recently reinstalled iTunes. All music files previously recognized by iTunes on my external hard drive are now unrecognized by iTunes when I try to play a song within iTunes. How do I get iTunes to re-recognize all files without doing search to exter