Unpivot taking the last letter from the column name

Hi guys, having
DATE               Period1 Period2 Period3 Period4
01/01/2014       1.02       1.06      1.02      1.03
02/01/2014       1.06       1.05      1.04      1.06
I would like an unptivot as
01/01/2014    1        1.02
01/01/2014    2        1.06
01/01/2014    3        1.02
01/01/2014    4        1.03
02/01/2014    1        1.06
02/01/2014    2        1.05
02/01/2014    3        1.04
02/01/2014    4        1.06
But I'm wondering how can I take the last letter of the column. Maybe I should use a select case...
Any advices? Thank you

DECLARE @Table TABLE
dt DATE,
P1 INT NULL,
P2 INT NULL,
P3 INT NULL,
P4 INt NULL
INSERT INTO @Table(dt, P1, P2, P3, P4)
VALUES('20140101',10,null,20,3);
INSERT INTO @Table(dt, P1, P2, P3, P4)
VALUES('20140102',50,25,15,5);
SELECT dt, row_number() over (partition by dt order by dt) rn,per AS DayMax FROM @Table
UNPIVOT (per FOR DayNumber IN (P1, P2, P3, P4)) AS c
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Message was edited by: sharknca

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Unpivot taking the last letter from the column name

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