Unreported exception; java.sql.SQLException; must be caught or declared to

Question

Hi everyone,
For my Java course assignment we need to make a small application that uses a MS Access database. But de code below gives me a "Unreported exception; java.sql.SQLException; must be caught or declared to be thrown at line xx" error.
public class ConnectieBeheer
  private static Connection con;
  private static Statement stmt;
  private static ResultSet res;
  private static ResultSetMetaData md;
  private ConnectieBeheer(){}
  public static void openDB() {
    Driver driver = new JdbcOdbcDriver();
    Properties info = new Properties();
    String url = "jdbc:odbc:theater";
    con = driver.connect(url, info);       <--- Error here
    if (con != null)
      stmt =  con.createStatement();      <--- Error here
      DatabaseMetaData dma = con.getMetaData();      <--- Error here
  }So I tried this :
public static void openDB() throws SQLException {Now I do not get an error.
The OpenDB method is called from a different class like this :
  public static void test1(){
    ConnectieBeheer.openDB();
    System.out.println("DB opened");
  }But now it gives the same "Unreported exception; java.sql.SQLException; must be caught or declared to be thrown at line xx" error but now at the line ConnectieBeheer.openDB();
Why is this? And what can I do to correct this?
Thanks!
Steven.

Answer 1

you should read the sun tutoriel about exceptions handling ;
there are two ways to handle an exception : either you redirects it (using "throws" statement, what you did for the openDB method), or you catch it using a try { ... } catch (Exception exc) {}
if you want to get rid of the error what you can do is :
  public static void test1(){
    try {
        ConnectieBeheer.openDB();
    } catch (java.sql.SQLException sqle) {
        sqle.printStackTrace();
    System.out.println("DB opened");
  }