Upload a file with an Applet

Hi,
I want to know if it's possible to upload a file with an Applet, but not a signed Applet.
Thanks
Cris

Yes, but you are limited to uploading to the server from where the applet was originating from.
Regards,
Peter Norell

Similar Messages

Upload multiple files WITH correct pairs of form fields into Database

In my form page, I would like to allow 3 files upload and 3 corresponding text fields, so that the filename and text description can be saved in database table in correct pair. Like this:
INSERT INTO table1 (filename,desc) VALUES('photo1.jpg','happy day');
INSERT INTO table1 (filename,desc) VALUES('photo2.jpg','fire camp');
INSERT INTO table1 (filename,desc) VALUES('photo3.jpg','christmas night');
However, using the commons fileupload, http://commons.apache.org/fileupload/, I don't know how to reconstruct my codes so that I can acheieve this result.
if(item.isFormField()){
}else{
}I seems to be restricted from this structure.
The jsp form page
<input type="text" name="description1" value="" />
<input type="file" name="sourcefile" value="" />
<input type="text" name="description2" value="" />
<input type="file" name="sourcefile" value="" />The Servlet file
package Upload;
import sql.*;
import user.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.util.Map;
import java.util.HashMap;
import java.util.Date;
import java.util.List;
import java.util.Iterator;
import java.io.File;
import java.io.PrintWriter;
import java.io.IOException;
import java.text.SimpleDateFormat;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.*;
public class UploadFile extends HttpServlet {
private String fs;
private String category = null;
private String realpath = null;
public String imagepath = null;
public PrintWriter out;
private Map<String, String> formfield = new HashMap<String, String>();
//Initialize global variables
public void init(ServletConfig config, ServletContext context) throws ServletException {
    super.init(config);
//Process the HTTP Post request
public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException, IOException {
    request.setCharacterEncoding("utf-8");
    response.setCharacterEncoding("utf-8");
    response.setContentType("text/html");
    PrintWriter out = response.getWriter();
    Thumbnail thumb = new Thumbnail();
    fs = System.getProperty("file.separator");
    this.SetImagePath();
     boolean isMultipart = ServletFileUpload.isMultipartContent(request);
     if(!isMultipart){
      out.print("not multiple part.");
     }else{
         FileItemFactory factory = new DiskFileItemFactory();
         ServletFileUpload upload = new ServletFileUpload(factory);
         List items = null;
         try{
            items = upload.parseRequest(request);
         } catch (FileUploadException e) {
            e.printStackTrace();
         Iterator itr = items.iterator();
         while (itr.hasNext()) {
           FileItem item = (FileItem) itr.next();
           if(item.isFormField()){
              String formvalue = new String(item.getString().getBytes("ISO-8859-1"), "utf-8");
              formfield.put(item.getFieldName(),formvalue);
              out.println("Normal Form Field, ParaName:" + item.getFieldName() + ", ParaValue: " + formvalue + "<br/>");
           }else{
             String itemName = item.getName();
             String filename = GetTodayDate() + "-" + itemName;
             try{
               new File(this.imagepath + formfield.get("category")).mkdirs();
               new File(this.imagepath + formfield.get("category")+fs+"thumbnails").mkdirs();
               //Save the file to the destination path
               File savedFile = new File(this.imagepath + formfield.get("category") + fs + filename);
               item.write(savedFile);
               thumb.Process(this.imagepath + formfield.get("category") +fs+ filename,this.imagepath + formfield.get("category") +fs+ "thumbnails" +fs+ filename, 25, 100);
               DBConnection db = new DBConnection();
               String sql = "SELECT id from category where name = '"+formfield.get("category")+"'";
               db.SelectQuery(sql);
                while(db.rs.next()){
                  int cat_id = db.rs.getInt("id");
                  sql = "INSERT INTO file (cat_id,filename,description) VALUES ("+cat_id+",'"+filename+"','"+formfield.get("description")+"')";
                  out.println(sql);
                  db.RunQuery(sql);
             } catch (Exception e){
                e.printStackTrace();
        HttpSession session = request.getSession();
        UserData k = (UserData)session.getAttribute("userdata");
        k.setMessage("File Upload successfully");
        response.sendRedirect("./Upload.jsp");
//Get today date, it is a test, actually the current date can be retrieved from SQL
public String GetTodayDate(){
    SimpleDateFormat format = new SimpleDateFormat("yyyyMMdd");
    String today = format.format(new Date());
    return today;
//Set the current RealPath which the file calls for this file
public void SetRealPath(){
    this.realpath = getServletConfig().getServletContext().getRealPath("/");
public void SetImagePath(){
    this.SetRealPath();
    this.imagepath = this.realpath + "images" +fs;
}Can anyone give me some code suggestion? Thx.

When one hits the submit button - I then get a 404 page error.What is the apaches(?) error log saying? Mostly you get very useful information when looking into the error log!
In any case you may look at how you are Uploading Multiple Files with mod_plsql.

How to upload a file with a HTML form into a BLOB ?

Hi,
I want to upload a file into a BLOB.
I have created a procedure in PL/SQL whitch generates an html form.
You can upload a file with <input type="file" name="my_file">.
How can I insert this file into my database ?
Thank's for your Help
Estelle

Hi Estelle,
Portal Applications forum is a more apporpriate forum for such questions. Please post your question there.
Thanks,
Ravi

How to upload large file with http via post

Hi guys,
Does anybody know how to upload large file (>100 MB) use applet to servlet with http via post method? Thanks in advance.
Regards,
Mark.

Hi SuckRatE
Thanks for your reply. Could you give me some client side code to upload a large file. I use URL to connect to server. It throws out of memory exception. The part of client code is below:
// connect to the servlet
URL theServlet = new URL(servletLocation);
URLConnection servletConnection = theServlet.openConnection();
// inform the connection that we will send output and accept input
servletConnection.setDoInput(true);
servletConnection.setDoOutput(true);
// Don't used a cached version of URL connection.
servletConnection.setUseCaches (false);
servletConnection.setDefaultUseCaches(false);
// Specify the content type that we will send text data
servletConnection.setRequestProperty("Content-Type",
+"application/octet-stream");
// send the user string to the servlet.
OutputStream outStream = servletConnection.getOutputStream();
FileInputStream filein = new FileInputStream(largeFile);
//BufferedReader in = new BufferedReader(new InputStreamReader
+(servletConnection.getInputStream()));
//System.out.println("tempCurrent = "+in.readLine());
byte abyte[] = new byte[2048];
int cnt = 0;
while((cnt = filein.read(abyte)) > 0)
outStream.write(abyte, 0, cnt);
filein.close();
outStream.flush();
outStream.close();
Regards,
Mark.

Unable to upload a file with Drag and Drop and http

Hello,
I am trying to upload a file through the web interface (Netscape 4.7 and IE 5.0). When I click un upload, Via Drag and Drop, a new window is started, but never completes.
With Netscape, I get a message box: Netscape is unable to locate the server null. Please check the server name and try again.
With IE 5, I get an error: This page can not be displayed.
Are there any files I need to edit on the PC side to get this to work?
Thanks
Scott
PS I think you guys are doing a great job with support on iFS.

WebUI Drag & Drop requires FTP to be running and available.
Drag & Drop is really just uses the browser built in FTP ability.

Error message while upload excel file (with macro) to sap (iw28)

While upload excel file to sap through iw28, i get error message (vb)
u2022 i have to say that the excel file contain macro , with out the macro , work fine .
u2022 The error display just in refresh command.
the error message :
Public Sub ALV_CUS_Exit()
Dim objs As ChartObjects
Dim obj As ChartObject
Dim sheet As Worksheet
Dim r As Range
For Each sheet In Sheets
Set objs = sheet.ChartObjects
For Each obj In objs
Set r = Sheets("RawData").UsedRange
obj.Chart.SetSourceData Source:=r
Next obj
Next sheet
End Sub

hi,
This is releated to the ABAP coding...There might be some ouput problem in the Abap list viewer...Pls check it with the ABAP consultant...
Regards
Priyanka.P

Upload text files with non-english characters

I use an Apex page to upload text files. Then i retrieve the contents of files from wwv_flow_files.blob_content and convert them to varchar2 with utl_raw.cast_to_varchar2, but characters like ò, à, ù become garbage.
What could be the problem? Are characters lost when files are stored in wwv_flow_files or when i do the conversion?
Some other info:
* I see wwv_flow_files.DAD_CHARSET is set to "ascii", wwv_flow_files.FILE_CHARSET is null.
* Trying utl_raw.cast_to_varchar2( utl_raw.cast_to_raw('àòèù') ) returns 'àòèù' correctly;
* NLS_CHARACTERSET parameter is AL32UTF8 (not just english ASCII)

Hi
Have a look at csv upload -- suggestion needed with non-English character in csv file it might help you.
Thanks,
Manish

Upload Csv files with infopackages - Error 1

Hello again,
i'm trying to upload csv file into a infopackage with master data text but the sistem sends a error message "Error 1 uploading external data".
Infopackage settings:
source system: PC
file type: data file
csv file
data separator ;
ESC signal "
a created a txt file with data separated with ; and later converted txt file into a csv file.
can anybody help me pls?
Thanks
Silvia Marques

Hi Silvia,
If the fields are correct in the transfer structure (only 2 fields). Then check whether the field length and type has been defined correctly for both the fields.
If thats not a problem then try to load only upto PSA.
If you are using IDOC as your transfer method then go to the "details" tab of the monitor of the error request and see the details. It will give you the correct picture of the error.
Bye
Dinesh.

How to handle 2 or more .jar files with an applet

Hey out there
I have created an ftpClient application that uses "jakarta ftpClient". It works fine as an JFrame application � But when I converted the Application into an JApplet I get the following Exception:
java.lang.NoClassDefFoundError: org/apache/commons/net/ftp/FTPClient
I have bundled the main application into a .jar file (Application,jar). But I don't know how to handle the 2 jakarta .jar files with my JApplet??
I Tried to append the 2 jakarta .jar files to the Application,jar with the following code:
jar cvf Application.jar 1.class 2.class�. commons-net-1.4.1.jar jakarta-oro-2.0.8.jar
But with the same result / Exception (I have signed the Jar file!)
Can anyone help me

Hi i have a question with your application can you down- or upload more files at the same time? Because i'm having problems with my ftp application.
Here is the link with my problem maybe you can help me. I will be very pleased when you can help me.
http://forum.java.sun.com/thread.jspa?threadID=5162042&tstart=0
Thx
Satanduvel

Uploading a File with AppleScript via JavaScript

Hi everybody,
being new to AppleScripting and JavaScripting I'm faced with the following problem:
Is it possible to make AppleScript to input the path for a file to be uploaded via JavaScript? If yes, what should be the correct Path Format and how to wrap it up the JavaScript action into AppleScript? I've tried a few comands but to no success.
On the webpage in question, there's a "Choose" button, that is defined as follows:
<input type="file" class="gwt-FileUpload" name="swfFile">
I've been trying to use the following syntax:
do JavaScript "document.getElementsByName('swfFile')[0].value('Macintosh HD:Users:myaccount:Desktop:Scrapbook:!动画.swf')" in document 1
as well as this one, where the Path is definitelly understood by shellscript:
do JavaScript "document.getElementsByName('swfFile')[0].value('/Users/myaccount/Desktop/Scrap book/!动画.swf')" in document 1
The name of the file is (and must remain) in chinese, but for testing purposes I have also tried files with english names, without success.
Currently I'm using a solution with JavaScript comand:
do JavaScript "document.getElementsByName('swfFile')[0].click()" in document 1
to click the finder window to browse for the file, and manipulating keystrokes by using System Events to find the right file, but it's not infallible with a number of files and it's hardly an ellegant sollution.
Any idea what I'm doing wrong?
Cheers!

@twtwtw
the do JavaScript "document.forms[0].submit()" command didn't work, so I kept the original way of submitting by clicking the button. The submitting part works, but not the input file part.
That's the code I used
    tell application "Safari"
        do JavaScript "document.getElementById('gwt-uid-13').value='on'" in document 1
        do JavaScript "document.forms[0].elements['swfFile'].value=" & "'" & SWFFilePath & "'" in document 1
        do JavaScript "document.getElementsByClassName('gwt-SubmitButton')[0].click()" in document 1
        delay 1
    end tell
with SWFFilePath set as the POSIX path as well as the default file format
Macintosh HD:Users:myaccount:Desktop:Scrapbook:!动画.swf'
but it did not work.
If you've got the time, feel free to upload an .swf. The service is free and the server delats uploaded files after 15 min. (if you don't have any, you may try an empty .txt file instead - it won't get converted, but the point is just to get it into the input box).
In the meantime, I'll have a look at adayzdone's suggestion. It's not perfect (the downside being that it requires the window to be active, so I can't run the script in the background or with my screensaver & password on), but it's still more reliable than my sollution with navigating arrowkeyes.

How to delete one existing file before uploading a file with same name?

Hello everybody.
I am uploading a file to Tomcat server. But, the problem is:
i want to delete an existing file in the server, if i upload a fresh file with same name. In other words, "First check for the file with the same name in the server. If it exists, then delete existing file in the server and upload fresh one". If such file doesnot exist, then upload the file to server.
I have given deleteonExit()
but, for the first time when user is uploading, i want to check for the file with same name in the server.
i am pasting the code here. please help:

<%
String contentType = request.getContentType();
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0))
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength)
byteRead = in.read(dataBytes, totalBytesRead, formDataLength);
totalBytesRead += byteRead;
String contextRootPath = this.getServletContext().getRealPath("/");
contextRootPath=contextRootPath.concat("uploaded");
String file = new String(dataBytes);
String saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));
// Create a directory; all ancestor directories must exist
File outputFile = new File(contextRootPath, saveFile);
var=outputFile.getPath();
outputFile.createNewFile();
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex + 1,contentType.length());
int pos;
pos = file.indexOf("filename=\"");
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
FileOutputStream fileOut = new FileOutputStream(outputFile);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
outputFile.deleteOnExit();
%>Please help. Thanks for taking time.
Regards,
Ashvini

Thank you MartinHilpert,
I have one more doubt,
I am uploading the file to one folder called "uploaded". Before uploading a fresh file, i want to delete all existing files in that folder. IS that possible ?? If yes, can you please tell me how to do that ??
Regards, Thanks for your time.
Ashlvini

How to upload .csv file with tab as delimiter.

HI,
I want to upload a .csv file with tab as delimiter to unix path in background.
I know there is function module 'GUI_UPLOAD', but in my case data is available in an internal table .
upload the *.CSV :
OPEN DATASET lv_filename
         FOR OUTPUT IN TEXT MODE ENCODING DEFAULT.
    IF sy-subrc = 0.
*     Write file records into file on application server
      LOOP AT gt_datatab INTO gs_datatab.
        TRANSFER gs_datatab TO lv_filename.
      ENDLOOP.
CLOSE DATASET lv_filename.

Bhanu,
Define a local variable of type CL_ABAP_CHAR_UTILITIES=>HORIZONTAL_TAB.
LV_TAB TYPE CL_ABAP_CHAR_UTILITIES=>HORIZONTAL_TAB
LOOP AT GT_DATATAB INTO GS_DATATAB.
CONCATENATE GS_DATATAB-FIELD1
                         GS_DATATAB-FIELD2
                         GS_DATATAB-FIELDN
                         INTO LV_STRING SEPARATED BY LV_TAB.
TRANSFER LV_STRING TO lv_filename.
ENDLOOP.
Thanks,
Vikram.M

Why do I have "broken image" icons after uploading a file with safari 7.0

I have a wesite where I can upload images. We show the directory of uploaded files with an icon that is a thumbnail of the image. This is working fine with all versions of safari except 7.0.
All users with 7.0 see the small blue icon with a "?" in place of the thumbnail (png and jpg). When the full image is displayed it look fine.
The wierd thing is that if I go to Chrome and view my directory and then go back to safari 7.0 and refresh, all thumbnails appear correctly.
I suspect there is a bug in Safari 7.0. Anyone else have this problem?

Has the 1 year limited hardware warranty expired? Apple would only charge to perform a repair or a replacement. If iOS 7.0.3 caused the issue then that would be a software issue, not hardware. Take it into the Genius Bar because the technicians are the only people that will be able to determine the cause. But if the iPhone needs to be replaced and it is not covered then Apple are in the right.

Upload binary files with Developer Forms

Hi all,
I'm newbie with Forms and I don't know if this question is already answered.
I'm deploying an application involved with blob columns (binary files: pdf, doc, gif, etc) I want to let users to choose files from his PCs (typical "Browse files" button) but I don´t know if this is possible and if yes, how to implement it.
Anybody can help me?
My email is [email protected]
Thanks in advance!
Cristina

If you want to upload direct into the database from the client then No you will need a 9i database or above.
If you want to upload a file from the browser client to the middle tier (Application server) then that will be OK no matter what DB version you are using. Bug of course you'll then need to do the last bit yourself if you want the document / image put into the database.

Webutil - issue with uploading text files with client_get_file_name

Hi,
I'm using webutil client_get_file_name to upload files from the client machine to the server.
It works fine for xls,pdf,doc files etc. but not for txt files it seems.
It doesn't display any error at all either.
Has anyone seen this type of issue before?
Kind regards,
Tom
Windows XP
Forms v10.1.2.0.2

Hi Sarah et al,
The code that I'm using to upload any file type format is:
vfilename := client_get_file_name('c:\',file_filter => 'All files (*.*)');
it works for doc/pdf/xls/rtf/csv etc.
but not for text files i.e. .txt
Also, could someone tell me how to open a .msg (Outlook message) file
as it gives the output:
'Cannot read item' upon the opening of the Outlook application.
I'm using the following to try and open it:
CLIENT_HOST( 'cmd /C start '||p_filename);
Your help would be appreciated.
Kind regards,
Tom

Upload a file with an Applet

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