Urgent query on joins --Please Help!!
Hi Experts,
We have two table T1 and T2 with A three columns in T1 as A(uniquie constraint and not null )and in table T2 as X.
We need to find rows in T1 for which no value of A exists in X of T2.Please provide your suggestion on the query we can frame for this requirement.
Thanks and Regards
Debashis
Edited by: user13267825 on Aug 27, 2010 3:08 AM
Maybe something like this then:
SELECT a FROM t1 WHERE b = :something
MINUS
SELECT x FROM t2
/ This is a case where it is always helpful to provide the following:
1. Oracle version (SELECT * FROM V$VERSION)
2. Sample data in the form of CREATE / INSERT statements.
3. Expected output
4. Explanation of expected output (A.K.A. "business logic")
5. Use \ tags for #2 and #3. See FAQ (Link on top right side) for details.
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LP.*
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COLUMN Emp_ID FOR 999999
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COLUMN Leavetype_desc FOR A10
COLUMN Leave_Count FOR 999
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FROM
SELECT *
FROM
SELECT
Emp_ID
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FROM
SELECT ROWNUM RN FROM
USER_OBJECTS
WHERE ROWNUM <= 100
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14210 JUL-2006 2 Sick 0
14210 JUL-2006 3 Casual 0
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TKPROF
call count cpu elapsed disk query current rows
Parse 1 0.00 0.00 0 0 0 0
Execute 68337 10.32 10.32 0 0 0 0
Fetch 68337 229.75 936.36 58819 6743323 1121 68232
total 136675 240.07 946.69 58819 6743323 1121 68232
Misses in library cache during parse: 1
Misses in library cache during execute: 1
Optimizer mode: ALL_ROWS
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Number of plan statistics captured: 1
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0 0 0 INDEX UNIQUE SCAN MTL_PARAMETERS_U1 (cr=0 pr=0 pw=0 time=0 us cost=0 size=4 card=1)(object id 9847)
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1 1 1 TABLE ACCESS BY INDEX ROWID GL_CODE_COMBINATIONS (cr=4 pr=2 pw=0 time=27531 us cost=2 size=57 card=1)
1 1 1 INDEX UNIQUE SCAN GL_CODE_COMBINATIONS_U1 (cr=3 pr=1 pw=0 time=19925 us cost=1 size=0 card=1)(object id 51426)
1 1 1 TABLE ACCESS BY INDEX ROWID MTL_ITEM_LOCATIONS (cr=4 pr=1 pw=0 time=7758 us cost=3 size=24 card=1)
1 1 1 INDEX RANGE SCAN MTL_ITEM_LOCATIONS_U1 (cr=3 pr=0 pw=0 time=51 us cost=2 size=0 card=1)(object id 9761)
1 1 1 TABLE ACCESS BY INDEX ROWID HR_ORGANIZATION_INFORMATION (cr=3 pr=0 pw=0 time=85 us cost=2 size=28 card=1)
1 1 1 INDEX RANGE SCAN HR_ORGANIZATION_INFORMATIO_FK2 (cr=2 pr=0 pw=0 time=29 us cost=1 size=0 card=2)(object id 5379798)
1 1 1 TABLE ACCESS BY INDEX ROWID HR_ORGANIZATION_INFORMATION (cr=3 pr=0 pw=0 time=25 us cost=1 size=25 card=1)
1 1 1 INDEX RANGE SCAN HR_ORGANIZATION_INFORMATIO_FK2 (cr=2 pr=0 pw=0 time=11 us cost=1 size=0 card=1)(object id 5379798)
1 1 1 INDEX FULL SCAN GL_SETS_OF_BOOKS_U2 (cr=1 pr=0 pw=0 time=69 us cost=1 size=4 card=1)(object id 1380842)
1 1 1 BUFFER SORT (cr=2 pr=0 pw=0 time=110 us cost=55 size=0 card=1)
1 1 1 TABLE ACCESS FULL FND_PRODUCT_GROUPS (cr=2 pr=0 pw=0 time=59 us cost=3 size=0 card=1)
Elapsed times include waiting on following events:
Event waited on Times Max. Wait Total Waited
---------------------------------------- Waited ---------- ------------
library cache lock 2 0.00 0.00
library cache pin 2 0.00 0.00
Disk file operations I/O 249 0.00 0.00
db file sequential read 58819 2.61 714.28
gc cr grant 2-way 5198 0.16 4.52
gc current grant busy 1 0.00 0.00
KJC: Wait for msg sends to complete 517 0.00 0.05
library cache: mutex X 433 0.01 0.04
gc cr grant congested 28 0.08 0.18
latch: ges resource hash list 5 0.00 0.00
gc current block 2-way 513 0.11 0.61
gc current block congested 2 0.00 0.00
latch: gc element 16 0.00 0.01
latch: cache buffers chains 4 0.00 0.00
latch: object queue header operation 3 0.00 0.00
********************************************************************************Explain Plan for the query
SELECT STATEMENT, GOAL = ALL_ROWS Cost=56 Cardinality=1 Bytes=219
MERGE JOIN CARTESIAN Cost=56 Cardinality=1 Bytes=219
NESTED LOOPS Cost=53 Cardinality=1 Bytes=219
NESTED LOOPS Cost=52 Cardinality=1 Bytes=215
NESTED LOOPS Cost=51 Cardinality=1 Bytes=190
NESTED LOOPS Cost=49 Cardinality=1 Bytes=162
NESTED LOOPS Cost=46 Cardinality=1 Bytes=138
NESTED LOOPS Cost=44 Cardinality=1 Bytes=81
NESTED LOOPS Cost=43 Cardinality=1 Bytes=73
NESTED LOOPS Cost=43 Cardinality=2 Bytes=132
VIEW Object owner=APPS Object name=CST_INV_DISTRIBUTION_V Cost=41 Cardinality=2 Bytes=118
UNION-ALL
NESTED LOOPS OUTER Cost=20 Cardinality=1 Bytes=291
NESTED LOOPS Cost=18 Cardinality=1 Bytes=255
NESTED LOOPS Cost=18 Cardinality=1 Bytes=251
MERGE JOIN CARTESIAN Cost=14 Cardinality=1 Bytes=192
NESTED LOOPS OUTER Cost=12 Cardinality=1 Bytes=156
NESTED LOOPS Cost=10 Cardinality=1 Bytes=120
NESTED LOOPS OUTER Cost=9 Cardinality=1 Bytes=113
NESTED LOOPS Cost=8 Cardinality=1 Bytes=106
NESTED LOOPS Cost=6 Cardinality=1 Bytes=93
NESTED LOOPS Cost=4 Cardinality=1 Bytes=83
NESTED LOOPS Cost=4 Cardinality=1 Bytes=80
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_MATERIAL_TRANSACTIONS Cost=4 Cardinality=1 Bytes=76
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_MATERIAL_TRANSACTIONS_U1 Cost=3 Cardinality=1
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_TRANSACTION_TYPES_U1 Cost=0 Cardinality=191 Bytes=764
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_TXN_SOURCE_TYPES_U1 Cost=0 Cardinality=18 Bytes=54
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_SYSTEM_ITEMS_B_U1 Cost=2 Cardinality=73632445 Bytes=736324450
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_SYSTEM_ITEMS_TL_U1 Cost=2 Cardinality=73652390 Bytes=957481070
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_PARAMETERS Cost=1 Cardinality=470 Bytes=3290
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_PARAMETERS_U1 Cost=0 Cardinality=1
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_PARAMETERS Cost=1 Cardinality=470 Bytes=3290
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_PARAMETERS_U1 Cost=0 Cardinality=1
INDEX RANGE SCAN Object owner=APPLSYS Object name=FND_LOOKUP_VALUES_U1 Cost=2 Cardinality=1 Bytes=36
BUFFER SORT Cost=12 Cardinality=1 Bytes=36
INDEX RANGE SCAN Object owner=APPLSYS Object name=FND_LOOKUP_VALUES_U1 Cost=2 Cardinality=1 Bytes=36
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_TRANSACTION_ACCOUNTS Cost=4 Cardinality=1 Bytes=59
INDEX RANGE SCAN Object owner=INV Object name=MTL_TRANSACTION_ACCOUNTS_N1 Cost=3 Cardinality=3
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_PARAMETERS_U1 Cost=0 Cardinality=1 Bytes=4
INDEX RANGE SCAN Object owner=APPLSYS Object name=FND_LOOKUP_VALUES_U1 Cost=2 Cardinality=1 Bytes=36
NESTED LOOPS Cost=21 Cardinality=1 Bytes=288
NESTED LOOPS Cost=19 Cardinality=1 Bytes=275
NESTED LOOPS Cost=17 Cardinality=1 Bytes=265
NESTED LOOPS Cost=17 Cardinality=1 Bytes=261
NESTED LOOPS OUTER Cost=16 Cardinality=1 Bytes=254
NESTED LOOPS Cost=15 Cardinality=1 Bytes=247
NESTED LOOPS Cost=15 Cardinality=1 Bytes=243
NESTED LOOPS OUTER Cost=15 Cardinality=1 Bytes=240
NESTED LOOPS Cost=13 Cardinality=1 Bytes=204
NESTED LOOPS Cost=9 Cardinality=1 Bytes=131
NESTED LOOPS OUTER Cost=7 Cardinality=1 Bytes=95
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_TRANSACTION_ACCOUNTS Cost=5 Cardinality=1 Bytes=59
INDEX RANGE SCAN Object owner=INV Object name=MTL_TRANSACTION_ACCOUNTS_N1 Cost=4 Cardinality=3
INDEX RANGE SCAN Object owner=APPLSYS Object name=FND_LOOKUP_VALUES_U1 Cost=2 Cardinality=1 Bytes=36
INDEX RANGE SCAN Object owner=APPLSYS Object name=FND_LOOKUP_VALUES_U1 Cost=2 Cardinality=1 Bytes=36
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_MATERIAL_TRANSACTIONS Cost=4 Cardinality=1 Bytes=73
INDEX RANGE SCAN Object owner=INV Object name=MTL_MATERIAL_TRANSACTIONS_N23 Cost=3 Cardinality=1
INDEX RANGE SCAN Object owner=APPLSYS Object name=FND_LOOKUP_VALUES_U1 Cost=2 Cardinality=1 Bytes=36
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_TXN_SOURCE_TYPES_U1 Cost=0 Cardinality=1 Bytes=3
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_TRANSACTION_TYPES_U1 Cost=0 Cardinality=1 Bytes=4
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_PARAMETERS Cost=1 Cardinality=1 Bytes=7
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_PARAMETERS_U1 Cost=0 Cardinality=1
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_PARAMETERS Cost=1 Cardinality=1 Bytes=7
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_PARAMETERS_U1 Cost=0 Cardinality=1
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_PARAMETERS_U1 Cost=0 Cardinality=1 Bytes=4
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_SYSTEM_ITEMS_B_U1 Cost=2 Cardinality=1 Bytes=10
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_SYSTEM_ITEMS_TL_U1 Cost=2 Cardinality=1 Bytes=13
TABLE ACCESS BY INDEX ROWID Object owner=HR Object name=HR_ALL_ORGANIZATION_UNITS Cost=1 Cardinality=1 Bytes=7
INDEX UNIQUE SCAN Object owner=HR Object name=HR_ORGANIZATION_UNITS_PK Cost=0 Cardinality=1
INDEX UNIQUE SCAN Object owner=HR Object name=HR_ALL_ORGANIZATION_UNTS_TL_PK Cost=0 Cardinality=1 Bytes=7
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_PARAMETERS Cost=1 Cardinality=1 Bytes=8
INDEX UNIQUE SCAN Object owner=INV Object name=MTL_PARAMETERS_U1 Cost=0 Cardinality=1
TABLE ACCESS BY INDEX ROWID Object owner=GL Object name=GL_CODE_COMBINATIONS Cost=2 Cardinality=1 Bytes=57
INDEX UNIQUE SCAN Object owner=GL Object name=GL_CODE_COMBINATIONS_U1 Cost=1 Cardinality=1
TABLE ACCESS BY INDEX ROWID Object owner=INV Object name=MTL_ITEM_LOCATIONS Cost=3 Cardinality=1 Bytes=24
INDEX RANGE SCAN Object owner=INV Object name=MTL_ITEM_LOCATIONS_U1 Cost=2 Cardinality=1
TABLE ACCESS BY INDEX ROWID Object owner=HR Object name=HR_ORGANIZATION_INFORMATION Cost=2 Cardinality=1 Bytes=28
INDEX RANGE SCAN Object owner=HR Object name=HR_ORGANIZATION_INFORMATIO_FK2 Cost=1 Cardinality=2
TABLE ACCESS BY INDEX ROWID Object owner=HR Object name=HR_ORGANIZATION_INFORMATION Cost=1 Cardinality=1 Bytes=25
INDEX RANGE SCAN Object owner=HR Object name=HR_ORGANIZATION_INFORMATIO_FK2 Cost=1 Cardinality=1
INDEX FULL SCAN Object owner=GL Object name=GL_SETS_OF_BOOKS_U2 Cost=1 Cardinality=1 Bytes=4
BUFFER SORT Cost=55 Cardinality=1
TABLE ACCESS FULL Object owner=APPLSYS Object name=FND_PRODUCT_GROUPS Cost=3 Cardinality=1 -
A Oracle sql query is needed, please help me out
Hi,
I have a table similar to scott.emp table and i should get first three recently joined employees salaries according to their joined date from each deptno
output should like this:
deptno firstempsalary secondemplsal thirdemploysalary
10 xxx xxx xxxx
20 xx xx
30 xx xxx xxxx
40 xx
50 xx xxxx xxx
60 xx xx
70 xx
it means that 70 dept having only one employee and 20 dept having only two employees and 10 dept having more than three employees but we should get only three recently joined employees salaries from 10 dept.
Hope this is clear .. please give me a query to get this info ..
oracle is 10g version
great thanks in advance.select deptno,
max(case jd_rank when 1 then salary end) firstempsal,
max(case jd_rank when 2 then salary end) secondempsal,
max(case jd_rank when 3 then salary end) thirdempsal
from
(select salary, deptno, row_number() over(partition by deptno order by join_date desc) jd_rank from emp)
group by deptno
Problem here is what to do when employees have the same join date? This example will arbitrarily choose their order and if, for example, three employees share the same (most recent) join date then they will arbitrarily be classed as "first", "second" and "third". If four employees join at the same time, one of them will be ignored at random!
Edited by: user10548434 on 03-Dec-2008 06:27 -
Regarding ECC 6.0- CRM and BW. URGENT....Please help!!
Dear All,
I have a small query- Are CRM and BW an integral part of ECC 6.0? I mean, if I install ECC 6.0, will CRM and BW also get installed OR Do I need to explicitly install CRM and BW after installing ECC 6.0?
If CRM and BW are an integral part of ECC 6.0, Do I need to carry out some additional steps/install add-on components(while installing ECC 6.0), to activate CRM and BW OR will it be activated by default once I am through with the normal installation process of ECC 6.0?
Thanks in anticipation!!CRM-Customer Relationship Management
General Settings in CRM
Use
This section describes the general settings necessary for BW Integration in CRM.
If CRM is not involved in your scenario skip this section.
This step has to be carried out in the CRM system:
Integration with Other mySAP Components  Data Transfer to the SAP Business Information Warehouse  Business Content DataSources  Transfer Application Component Hierarchy
RSA9-Tcode
Confirm the security check: Do you want the content application Transfer Component Hierarchy? with YES.
If a dialog box appears requesting the user to enter a development class, enter a development class in the customers namespace and choose Save or choose Local object.
If no error message is sent the application component hierarchy has been transferred successfully.
Cross Connectivity:
It describes all settings that are necessary to connect the components of the SAP.system landscape with each other. The settings for each combination of two components to be connected are described in a separate structure node. The separate section headings make it possible to identify the activities required to connect certain components with each other. The section headings for components that are not part of the installation can be skipped
Connecting SAP BI with SAP ERP, SAP CRM
Procedure
To carry out the activity, choose one of the following navigation options in the SAP BI system:
Transaction Code RSA1
SAP BI Menu Modeling  Data Warehousing Workbench: Modeling
Connecting SAP BI with SAP ERP, SAP CRM
Procedure
To carry out the activity, choose one of the following navigation options in the SAP BI system:
Transaction Code RSA1
SAP BI Menu Modeling  Data Warehousing Workbench: Modeling
1. Choose Modeling.
2. Choose Source Systems.
3. Select SAP in the window on the right.
4. Choose the Context menu (right mouse click).
5. Choose Create.
6. Make the following entries:
Field Entry
Target computer (server) Server of the SAP ERP, SAP CRM or SAP SRM system
System ID System ID of the SAP ERP, SAP CRM or SAP SRM system
System number System number of the SAP ERP, SAP CRM or SAP SRM system
Background user in source system RFCUSER
Password for source system welcome
Background user in BI RFCUSER (can not be changed in this activity)
Password for BI user welcome
9. On the dialog box Please log on as an administrator in the following screen choose Continue.
10. Log on to the Source System with your administrator user. Choose the correct client.
11. On the dialog box New Source System Connection choose Continue.
12. On the Replicate Metadata dialog box, choose Only Activate.
The building block CRM Lead Analysis describes the all the required activities to analyze the Marketing Lead Analysis data from SAP CRM in SAP Business Information Warehouse.
The analysis is carried out with the following queries of the InfoCube 0MKTG_C01 CRM - Lead Management (SAP BW Business Content).
The Lead Management InfoCube contains all the characteristics and data used for the administration of leads. This InfoCube enables you to execute the following standard queries available in SAP BW:
1. Channel Analysis: This query is used to determine the best channels by which business partners are contacted in the context of a marketing campaign. Following each marketing campaign, the lead manager can compare the success of a given channel to those of others.
2. Efficiency Reporting: This query is used to analyze the efficiency with which leads are qualified. By navigating to the sales organizations and the responsible employees for the leads, it is possible to assess how efficiently lead teams are working and to identify areas for improvement.
3. Historical Evaluation: Use to help analyze and compare leads over different intervals (comparison of different quarters or years for example) to see if general characteristics in the processing of leads can be identified for these periods.
4. Lost Leads: Provides an overview of the number of lost leads in a particular period and the reasons (implemented as a navigation characteristic) for the loss of the leads. This query is used to analyze the main reasons why leads might be lost, with a view to developing new strategies for overcoming these weaknesses.
5. Channel Mgmt.: Top-n Lost Leads (Current Year): In a Channel Manager Portal, this query provides an analysis of the leads lost by a Channel Manager over the past 12 months. Channel Managers can also view the leads lost by their Channel Partners. In a Partner Portal, this query shows the top-n unsuccessful leads distributed by a Channel Manager to a Channel Partner. Partner Manager can see the lost leads of the Partner Employees over the year. Partner Employee can view his lost leads over the year.
InfoSources
0CRM_LEAD_H - Lead Header (Transactional Data)
0CRM_LEAD_I - Lead Item (Transactional Data)
0CRM_MIG - Mail GUID
Before starting activities in this building block, you need to perform or check the following steps:
1. From the BW Connectivity building block the following activities have to be completed:
a. Local Settings è SAP CRM: all activities have to be completed.
b. Local Settings è SAP BW: all activities have to be completed.
c. Cross Connectivity è Connecting SAP BW with SAP R/3, SAP CRM, SAP SRM: Connect your CRM System.
2. From the General Settings for BW Integration building block the following activities have to be completed:
a. In section General Settings in CRM all activities have to be completed.
b. In section General Settings in SAP BW all activities have to be completed. -
Need SQL query using View - Please help
Hi,
I have similar requirement like below.
I have two tables DEPT and EMP and some departments may not have employees. I have created below view, which displays all DEPT records, even though there are no emplyees.
CREATE OR REPLACE VIEW dept_emp_vw AS
SELECT deptno, empid, 0 AS selected
FROM dept d, emp e
WHERE d.deptno = e.deptnno (+);
Ex.
DEPTNO EMPID SELECTED
10 101 0
10 102 0
20 103 0
30 103 0
40 104 0
50 <null> 0
Application will pass "empid" to the view (for ex. empid = 103) and I want result like below.
Ex.
DEPTNO EMPID SELECTED
10 101 0
10 102 0
20 103 1
30 103 1
40 104 0
50 <null> 0
Can you please let me know the query using "dept_emp_vw" view. We have Oracle 11g Release 2.
Thanks a lot for the help.Not possible using normal SQL - as SQL is not a procedure language and does not support variable declaration and use (e.g. passing empid as a variable and using it both as a predicate and as a condition in the SQL projection).
That said - SQL can be "+parameterised+". An approach that is ugly and contrary to the basic design and use of SQL. But it can support the (very weird) view definition of yours.
E.g.
SQL> create or replace procedure SetVariable( name varchar2, value varchar2 ) is
2 begin
3 DBMS_SESSION.set_context( 'MyVariables', name, value );
4 end;
5 /
Procedure created.
SQL>
SQL>
SQL> create or replace context MyVariables using SetVariable;
Context created.
SQL>
SQL> create or replace view my_funky_weird_view as
2 select
3 e.empno,
4 e.ename,
5 e.job,
6 case e.empno
7 when to_number(sys_context( 'MyVariables', 'empid' )) then
8 0
9 else
10 1
11 end as "SELECTED"
12 from emp e
13 /
View created.
SQL>
SQL> exec SetVariable( 'empid', 7499 )
PL/SQL procedure successfully completed.
SQL>
SQL> select * from session_context where namespace = 'MYVARIABLES';
NAMESPACE ATTRIBUTE VALUE
MYVARIABLES EMPID 7499
SQL>
SQL> select * from my_funky_weird_view order by selected;
EMPNO ENAME JOB SELECTED
7499 ALLEN SALESMAN 0
7521 WARD SALESMAN 1
7566 JONES MANAGER 1
7654 MARTIN SALESMAN 1
7698 BLAKE MANAGER 1
7934 MILLER CLERK 1
7788 SCOTT ANALYST 1
7839 KING PRESIDENT 1
7844 TURNER SALESMAN 1
7876 ADAMS CLERK 1
7900 JAMES CLERK 1
7902 FORD ANALYST 1
7369 SMITH CLERK 1
7782 CLARK MANAGER 1
14 rows selected.
SQL>But I will N\OT recommend doing it this way. It is not natural SQL as PL/SQL is needed to "+inject+" name-value pairs into the context for the SQL view to use. It is ugly. It is not standard. It cannot scale. It is complex to use. Etc.
Yes, there are instances when this approach is exactly what one needs - when for example dealing with a trusted context and using the contents for implementing a security layer. But in the above case - I would rather want to see the actual business requirement first, as I think you're barking up the wrong tree with the view solution you have imagined. -
URGENT!!! PLEASE HELP - CAN'T SEND OR RECEIVE EMAI...
All of a sudden this morning my email account (on web mail) will not send or receive any emails? My friend has a bt mail account and theirs is working fine. Any clues? This is most urgent as this is my only email address and I am awaiting an urgent email and confirmation emails as currently booking flights. Any help would be so much appreciated.
Hi guys,
Thanks all for posting. Are you having problems with the Yahoo or BT Mail service? Are you getting any error messages? Can you give me as much detail as possible and I’ll look into it.
Cheers
David
BTCare Community Mod
If we have asked you to email us with your details, please make sure you are logged in to the forum, otherwise you will not be able to see our ‘Contact Us’ link within our profiles.
We are sorry but we are unable to deal with service/account queries via the private message(PM) function so please don't PM your account info, we need to deal with this via our email account :-) -
Urgent and typical issue- Please help!!
Dear All,
I have a BOM material(say M) which is made up of 3 components(say A, B and C).
I procure component A from 3 different countries(T1, T2 andT3), component B from 2 different countries(T4 and T5) and component C from 4 different countries(T6, T7, T8 and T9).I process them and prepare a finished good M(as mentioned above) and export it. I want to track the country of origin of each of the components of this BOM.How can I achieve this?
To make my question more clear ..If I am exporting material M, I should be able to track all the 9 countries(T1 ..T9) because M is made up of 3 components procured from 9 countries(in all).
Since the problem is critical, I would appreciate your urgent help on this.Thanks!!Hi Venkat,
Thankyou so much for your response.I came to know about you beforehand, from one of your students whom you are grooming on GTS.As the problem was really critical I tried to contact you, to seek your help, but couldn't reach you.Can you please mail me your contact number on [email protected]
I need to talk to you for a few minutes to discuss this.
Thanks again!!
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