Using all days in a month

Question

Hi, how I make to use all days in a select that has only a few days.
e.g.: in a select return 5 days (01-02-08, 01-04-08, 01-12-08, 01-21-08, 01-25-08) but i need all days 01-01-08 .. 01-31-08 as a table.
Days..........Production
01-01-08....0
01-02-08....150
01-03-08....0
01-04-08....201
01-05-08....0
01-06-08....0
01-07-08....0
01-08-08....0
01-09-08....0
01-10-08....0
01-31-08....0
Edited by: user622983 on 28/01/2009 02:44
Edited by: user622983 on 28/01/2009 02:45

Answer 1

SELECT   v.newdt, NVL (z.production, 0)
    FROM (WITH d AS
               (SELECT   TRUNC (TO_DATE ('jan-2009', 'MON-YYYY'), 'MM')
                       - 1 AS dt
                  FROM DUAL)
          SELECT     dt + LEVEL newdt
                FROM d
          CONNECT BY LEVEL <= ADD_MONTHS (dt, 1) - dt) v,
         (SELECT *
            FROM (WITH t AS
                       (SELECT TO_DATE ('01-jan-2009', 'dd-mon-yyyy') dt,
                               10 production
                          FROM DUAL
                        UNION
                        SELECT TO_DATE ('05-jan-2009', 'dd-mon-yyyy') dt,
                               20 production
                          FROM DUAL)
                  SELECT *
                    FROM t)) z
   WHERE v.newdt = z.dt(+)
ORDER BY 1;