Using link button

Hi all
i would like to create a link button which when pressed will show the customer details form for a given customer which appears in a edit text field.
my question is how do i connect the link button to the edit text field so it will show its details?
appreciate the help
Yoav

Dim oItem as SAPbouiCOM.Item
Dim oLink As SAPbouiCOM.LinkedButton
<b>oItem.LinkTo = "TEXTBOX"</b>
Set oLink = oItem.Specific
<b>oLink.LinkedObject = lf_BusinessPartner</b>

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Hi all,
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Hi Manish,
Please refer the following sample code:
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Hi,
I am new to ADF, i am facing 1 issue while implementing ADF mobile browser application.
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the structer of my code is
< iterator1>
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< iterator2>
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</ iterator2>
< /iterator1>
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Thanks
Shyam
Edited by: shyam on Dec 26, 2011 5:40 PM

Hi,
To solve my problem I used a af:foreach instead.
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<af:setActionListener from="#{text.IndCode}" to="#{pageFlowScope.IndicatorCodeParam}" />
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</af:forEach>
By the way you need to convert the iterator to an Array using a ManagedBean.
public Object[] toArray() {
CollectionModel cm = (CollectionModel) getEL("#{bindings.TView1.collectionModel}");
indicators = new Object[cm.getRowCount()];
for(int i=0;i<cm.getRowCount();i++){
indicators[i] = cm.getRowData(i);
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public static Object getEL(String expr) {
FacesContext fc = FacesContext.getCurrentInstance();
return fc.getApplication().evaluateExpressionGet(fc,expr,Object.class);
Hope that helps-
Edited by: JuJuZ on Jan 3, 2012 12:23 AM
Add getEL Method

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