Using shear to emulate 3D rotation

Hello peeps
I'm trying to use X and Y shear to make a noise generator fit nicely on top of a background image which sits at an angle.
You'll see exactly what I mean in this image, the one at the top left doesn't quiote sit right.
http://www.kmillar.tv/images/image1.gif
(Sorry, I can't figure out how to embed images in these posts).
Anyway, how can I scale/skew/shear the noise generator to fit nicely within the frame of the background image?
The full project files are also here:
http://www.kmillar.tv/sheartest.html
Maybe this kind of 3D compositing just isn't possible to simulate in motion?

You don't want shear, you want corner pin.
See this thread for a way to simulate animated 3D with Motion 1...
http://discussions.apple.com/click.jspa?searchID=-1&messageID=2345359
Patrick

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Hi. I am relatively new to Illustrator.
I am trying to create a simple 3D map, but not with the default iso settings. It's actually a remake of a map made many years ago on a squar grid using a rise of 1 and a run of 2 (all done by hand on graph paper). This creates an angle that is 26.5651°.
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I am trying to create a simple 3D map, but not with the default iso settings....made many years ago on a squar grid using a rise of 1 and a run of 2...
You are confusing actual orthographic projection from an actual 3D model (3D Effect), with an archaic 2D "cheat" that is really not a correctly proportioned orthographic projection at all.
This creates an angle that is 26.5651°.
Yes, but more significantly it is simply the projected angle that results from vertically scaling a true-length 45° line by an arbitrary 50% (the 1:2 ratio). In orthographic projection, that amount of foreshortening would mean that you are viewing the top plane of your coordinate system as if it is tilted upward toward you 30°[arcsine (.5 )= 30°], not the isometric angle of 35°16".
For iso, [scale: H=100%, V=86.602%] [shear: hoizontal axis -30°] [rotate: -30°]
Contrary to the misconception perpetuated by many of those who use the 1:2 cheat, that is not isometric. It's just an arbitrary 2D oblique. By definition, in isometric (read "same measure") drawing, all three axes are of the same length. Using the 1:2 ratio, the length of your left and right axes (the hypoteneuse of a 1x2 rectangle) measures 2.2361. If your vertical axis measures .86602, then obviously your three axes are not of equal length, and the drawing is not isometric. The corresponding lengths/angles of the axes in axonometric (isometric, dimetric, trimetric) drawing are not arbitrary. For any given set of axis angles, there is but one correct set of forshortened lengths.
So from where are you getting the 86.602% figure? I'll tell you: That's the cosine of 30°. Now, if the 1:2 ratio did, in fact, result in a vertical axis of that measure, then the 1:2 cheat would result in a proper dimetric (not isometric) projection. That is, if the top of a cube is tilted upward from your line of sight by 30°, then the front of that cube is necessarily tilted away from perpendicular to your line of sight by 30°. The top would be foreshortened by a factor of .5, and the front would be foreshortened by a factor of .866.
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[One instance of] dimetric:
Left and right axes angled your desired 26.57° from horizontal
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Vertical axis foreshortened length: .866
1:2 cheat:
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Left and right axes foreshortened length: .7906
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Now do the same thing again, but just distort the extrusion depth by the same proportion of a correct dimetric vertical axis length to that of the 1:2 cheat:
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Message was edited by: CtDave
Message was edited by: CtDave

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