Validate cfinput using regular expression

Hi,
can somebody help me valditing an cfinput field using regular expressions?
First digit must be a number or "R".
Digit 2-15 can be everything without special characters. Digit 2-15 can also be empty.
I try this, but it doesn't work (Sorry I'm a beginner using regex).
<cfinput type="text" name="field1" required="yes" validate="regular_expression" pattern="[0-9Rr][0-9a-zA-Z]*" maxlength="15">
Thank you in advice!
Claudia

You haven't told your regex to match the entire string, so it will "pass"
any string that has your match anywhere within it, so like as long as it's
got an R or a digit in it: it's OK.
To tell it to match the entire string, anchor it to the start and end of the
string with ^ and $ respectively.
Regular expression syntax: Using special characters
http://help.adobe.com/en_US/ColdFusion/9.0/Developing/WSc3ff6d0ea77859461172e0811cbec0a38f -7ffb.html#WSc3ff6d0ea77859461172e0811cbec0a38f-7fef
Adam

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How to Validate this using Regular Expressions

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Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:56 AM
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:57 AM

Hopefully someone will still be able to provide a RegEx solution, but until that time here is a working method.
Also, if people have suggestions of other rules for letter capitalization in names, I am interested in those too.
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 workStr = workStr.replaceAll("( mc)", " $1 ");
 // Ensure there is one space after periods and commas
 workStr = workStr.replaceAll("(\\.|,)([^ ])", "$1 $2");
 // Add 2 spaces after periods, commas, hyphens and apostrophes
 workStr = workStr.replaceAll("(\\.|,|-|')", "$1 ");
 // Add a double space to the front of the string
 workStr = " " + workStr;
 // Upshift each character that is preceded by a space and remove double spaces
 // Can't upshift using regular expressions and String methods
 // workStr = workStr.replaceAll("( [^ ])([^ ]+)", "$1"toUpperCase() + "$2");
 StringBuilder titleCase = new StringBuilder();
 for (int i = 0; i < workStr.length(); i++) {
 if (workStr.charAt(i) == ' ') {
 if (workStr.charAt(i+1) == ' ') {
 i += 2;
 while (i < workStr.length() && workStr.charAt(i) == ' ') {
 titleCase.append(workStr.charAt(i++));
 if (i < workStr.length()) {
 titleCase.append(workStr.substring(i, i+1).toUpperCase());
 } else {
 titleCase.append(workStr.charAt(i));
 return titleCase.toString();
{code}

Using regular expressions in java

Does anyone of you know a good source or a tutorial for using regular expressions in java.
I just want to look at some examples....
Thanks

thanks a lot... i have one more query
Boundary matchers
^      The beginning of a line
$      The end of a line
\b      A word boundary
\B      A non-word boundary
\A      The beginning of the input
\G      The end of the previous match
\Z      The end of the input but for the final terminator, if any
\z      The end of the input
if i want to use the $ for comparing with string(text) then how can i use it.
Eg if it is $120 i got a hit
but if its other than that if should not hit.

Using Regular Expressions in Numbers 09?

Is there any way to use regular expressions in Numbers 09 in Find & Replace?

kilowattradio wrote:
Is there any way to use regular expressions in Numbers 09 in Find & Replace?
NO !
_Go to "Provide Numbers Feedback" in the "Numbers" menu_, describe what you wish.
Then, cross your fingers, and wait _at least_ for iWork'10
Yvan KOENIG (VALLAURIS, France) vendredi 25 septembre 2009 14:49:49

Changeparticular characters in a string by using regular expressions ...

Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you

SSU wrote:
Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you
SQL> SELECT
2 regexp_replace('sdfsdf Sdfdfs Sdfd','s|S','X') from dual;
REGEXP_REPLACE('SD
XdfXdf XdfdfX XdfdRegards,
Achyut

Using regular expressions for validating time fields

Similar to my problem with converting a big chunk of validation into smaller chunks of functions I am trying to use Regular Expressions to handle the validation of many, many time fields in a flexible working time sheet.
I have a set of FormCalc scripts to calculate the various values for days, hours and the gain/loss of hours over a four week period. For these scripts to work the time format must be in HH:MM.
Accessibility guidelines nix any use of message box pop ups so I wanted to get around this by having a hidden/visible field with warning text but can't get it to work.
So far I have:
var r = new RegExp(); // Create a new Regular Expression Object
r.compile ("^[00-99]:\\] + [00-59]");
var result = r.test(this.rawValue);
if (result == true){
true;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "visible";
else (result == false){
false;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "hidden";
Any help would be appreciated!

Date and time fields are tricky because you have to consider the formattedValue versus the rawValue. If I am going to use regular expressions to do validation I find it easier to make them text fields and ignore the time patterns (formattedValue). Something like this works (as far as my very brief testing goes) for 24 hour time where time format is HH:MM.
// form1.page1.subform1.time_::exit - (JavaScript, client)
var error = false;
form1.page1.subform1.errorMsg.rawValue = "";
if (!(this.isNull)) {
var time_ = this.rawValue;
if (time_.length != 5) {
    error = true;
else {
    var regExp = /^([01]?[0-9]|2[0-3]):[0-5][0-9]$/;
    if (!(regExp.test(time_))) {
      error = true;
if (error == true) {
form1.page1.subform1.errorMsg.rawValue = "The time must be in the format HH:MM where HH is 00-23 and MM is 00-59.";
form1.page1.subform1.errorMsg.presence = "visible";
Steve

Using Regular Expressions To Remove Characters JDK 1.4

I want to write a regular expression to remove all commas in a string of text.
string is:
1,000
or 1,000,000
I want it to return 1000 and 1000000.
I have tried some but I am just starting with Regular Expressions.
Please Help!

Try this tutorial: Linux : Education : Tutorials
Using regular expressions
David Mertz
President, Gnosis Software, Inc.
September 2000
http://www-105.ibm.com/developerworks/education.nsf/linux-onlinecourse-bytitle/6C2B4863702F592B8625696200589C5B?OpenDocument

Using Regular Expressions to replace Quotes in Strings

I am writing a program that generates Java files and there are Strings that are used that contain Quotes. I want to use regular expressions to replace " with \" when it is written to the file. The code I was trying to use was:
String temp = "\"Hello\" i am a \"variable\"";
temp = temp.replaceAll("\"","\\\\\"");
however, this does not work and when i print out the code to the file the resulting code appears as:
String someVar = ""Hello" i am a "variable"";
and not as:
String someVar = "\"Hello\" i am a \"variable\"";
I am assumming my regular expression is wrong. If it is, could someone explain to me how to fix it so that it will work?
Thanks in advance.

Thanks, appearently I'm just doing something weird that I just need to look at a little bit harder.

Validate cfinput using regular expression

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