Validate Email by regular Expression... Need Help
Dear All,
Requirement:
validate the email ID entered & throw error message, if it is invalid.
DATA c_mailpattern TYPE c LENGTH 60 VALUE
'[a-zA-Z0-9._%-]+@[a-zA-Z0-9.-]+\.[a-zA-Z]{2,4} '.
** If @ is present, more than once. Error out
find ALL OCCURRENCES OF '@' in P_email
MATCH COUNT v_count.
if v_count > 1.
v_badpattern = 1.
endif.
** If , is present, once, Error out
find ALL OCCURRENCES OF ',' in P_Email
MATCH COUNT v_count.
if v_count > 0.
v_badpattern = v_badpattern + 1.
endif.
FIND REGEX c_mailpattern IN P_Email IGNORING CASE .
IF sy-subrc <> 0 OR v_badpattern > 0.
Write:/ p_EMAIL, 'has invalid Email format'.
ENDIF.
though this works fine, tester needs me to catch, if domain name has "app.com.com" as invalid email id.
above regex fails in such case.
I searched & found
{messageID=3706355}
messageID=1657369}{
https://wiki.sdn.sap.com/wiki/display/Snippets/E-MAIL+Validation
doesn't help.
I found this regex in a perl program.
[a-z0-9!#$%&'{size:14}*+{size:14}/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?
Can I get help to modify this into ABAP String?
1) I can't bypass the boldened text using Escape characters like #* or '' Can some one help me assign this regex-string into a string variable?
2) This regex is longer than allowed length for a literal.
It can be split into 2 strings, then concatenated & checked.
Edited by: Mallikarjuna J on May 16, 2011 8:23 PM
Edited by: Mallikarjuna J on May 16, 2011 8:26 PM
Thanks Sebastian, Pratik & Keshav for the replies.
SX_INTERNET_ADDRESS_TO_NORMAL doesn't validate a wrong email ID. It only splits the internet address into mail & domain.
Prathik,
just .com.com is not the point, Bad input could be .net.ent or .net.com or so....
Amol, Thanks, but I keep receiving Error, not found in the 41 line response I get
I think we need to check not line 2 but line 28.
Taking cue from Prathik, I'm planning to put this
*** ls_inputmail-mail is the email-id entered by user.
************ Check for Valid Regular Expression
***** DOT(.) is allowed more than once,
***** @ is allowed only once,
***** , is not allowed.
** If @ is present, more than once. Error out
find ALL OCCURRENCES OF '@' in ls_input_mail-mail
MATCH COUNT v_count.
if v_count > 1.
v_badpattern = 1.
endif.
** If , is present, once, Error out
find ALL OCCURRENCES OF ',' in ls_input_mail-mail
MATCH COUNT v_count.
if v_count > 0.
v_badpattern = v_badpattern + 1.
endif.
** Find if domain part i.e., after @ has errors.
SPLIT ls_input_mail-mail at '@' into v_mailpart v_domain.
* there's a dot in the domain.
if v_domain Co '.' .
* last 2 char can only be country name, not anything else.
SPLIT v_domain at '@' into v_domain1 v_domain2.
* v_domain2 can only be a country name, else error out
select single landx from t005 into v_country
where landx = v_domain2.
if sy-subrc <> 0.
v_badpattern = v_badpattern + 1.
endif.
ENDIF.
FIND REGEX c_mailpattern IN ls_input_mail-mail IGNORING CASE .
IF sy-subrc <> 0 OR v_badpattern > 0.
Write:/ ls_inputmail-mail, 'has invalid email format'.
ENDIF.
However, I was wondering, if there was a way to use escapae characters & make the beow string as a valid regex variable to check email id.
[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?
Nevertheless, Thanks Friends for all your inputs.
Edited by: Mallikarjuna J on May 17, 2011 2:23 PM
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Pattern.compile("<a\\s+href\\s*=\\s*\"?(.*?)[\"|>]", Pattern.CASE_INSENSITIVE);So is there a way to say look for double quotes OR single quotes?
Many thanks
nullThere's no need to escape the single-quote (or apostrophe) in a regex. The only reason it was necessary to escape the double-quote (or quotation mark) is because the regex was written in the form of a String literal. Neither the single-quote or the double-quote has any special meaning in regexes.
-
Stripping HTML thru regular expression(pls help)
Hi all..
I've been trying to use the regular OROMatcher-1.1 expression package downloaded from apache.org.
it works well with my program but i m having problems building correct regular expression to strip off HTML tags.
can any of u help me build an expression tha strips of ALL html tags including those with funny spaces such as:
<a href = "www.here.com">click me</a>
do help pls. i've tried for ages and its driving me madHi,
Wont go into much details but the simplest way to do that would be using XML technology. Try using SAX or DOX whatever you feel comfortable with. I think SAX would be a better choice. For details visit
http://java.sun.com/xml/?frontpage-spotlight
/khurram -
Regular expression needed to escape dots
Hello
In a file , I might have several times a line like this :
VALOR DESCUENTO ....... 1,505,728.80What is the regular expression to get *1,505,728.80* ? Please note that there are dots ..how do i escape them ?
This is what I use , but it does not work
String descuentoPattern = "VALOR DESCUENTO(?:\\s+?)(?:^\\s+?)(?:\\s+?)(.*)"; cheers,
deibysBigDaddyLoveHandles wrote:
The same way you escape any character -- with a backslash.Remembering to double-up backslashes in Java strings, of course.
@deibys, your regex is wrong. Try this instead:
String foo = "VALOR DESCUENTO ....... 1,505,728.80";
String pattern = "VALOR DESCUENTO\\s*\\.+\\s+(.*)";
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(foo);
if (m.matches()) {
System.out.println("Match found: " + m.group(1));
} -
Forgot email and password. Need help! Newer mind g...
Hello i need to get back my skype account and i dont know wich of my email is on that account becouse its been few years when i created account. Is it possible by using login nick name get back my account. For proof its my account i can tell ewerything what is on it. Please help!
Newer mind got it back...Here are Two Ways to help you get your Gmail back click on both for the Info: http://goo.gl/T9ot6 http://goo.gl/N6Ba0 b33
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