Valodate xml against xsd

Question

Hi ,
I have the below as "position.xml"
<?xml version="1.0" encoding="UTF-8"?>
<position
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="file://c:\wsad\workspace\sma\xml\position.xsd">
<position_number>12345</position_number>
<position_title>Sr. Engr</position_title>
<report_to_position>23456</report_to_position>
<incumbent>23456</incumbent>
<operation>INSERT</operation>
</position>
and
position.xsd is :
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="Root">
<xs:complexType>
<xs:sequence>
<xs:element name="position" type="positionType" maxOccurs="unbounded"/>
</xs:sequence>
</xs:complexType>
</xs:element>
     <xs:complexType name="positionType">
<xs:sequence>
     <xs:element name="position_number" type="xs:string"/>
<xs:element name="position_title" type="xs:string"/>
     <xs:element name="report_to_position" type="xs:string"/>
     <xs:element name="incumbent"           type="xs:string"/>
     <xs:element name="operation"           type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:schema>
When i use the code:
import org.apache.xerces.parsers.DOMParser;
import java.io.File;
public class SchemaTest {
     private String xmlFile = "";
     private String xsdFile = "";
     public SchemaTest(String xmlFile, String xsdFile) {
          this.xmlFile = xmlFile;
          this.xsdFile = xsdFile;
     public static void main(String args[]) {
          for (int i = 0; i < args.length; i++) {
               switch (i) {
                    case 0 :
                         System.out.println("XML File=" + args);
                         break;
                    case 1 :
                         System.out.println("XSD File=" + args);
                         break;
                    default :
                         System.out.println("Unknown=" + args);
                         break;
          if (args.length != 2) {
               System.err.println("Usage: <xml file> <xsd file>");
               System.exit(1);
          SchemaTest testXml = new SchemaTest(args[0], args[1]);
          testXml.process();
     public void process() {
          File docFile = new File(xmlFile);
          try {
               DOMParser parser = new DOMParser();
               parser.setFeature("http://xml.org/sax/features/validation", true);
               parser.setFeature("http://apache.org/xml/features/validation/schema",true);
               parser.setFeature("http://apache.org/xml/features/validation/schema-full-checking", true);
//               parser.setProperty("http://apache.org/xml/properties/schema/external-schemaLocation", xsdFile);
               parser.setProperty(
                    "http://apache.org/xml/properties/schema/external-noNamespaceSchemaLocation",
                    xsdFile);
               ErrorChecker errors = new ErrorChecker();
               parser.setErrorHandler(errors);
               parser.parse(docFile.toString());
          } catch (Exception e) {
               System.out.print("Problem parsing the file.");
               System.out.println("Error: " + e);
I get the following error message:
XML File=[Ljava.lang.String;@45a877
XSD File=[Ljava.lang.String;@45a877
Line 4...
cvc-elt.1: Cannot find the declaration of element 'position'.
Line 4...
cvc-datatype-valid.1.2.1: 'file://c:\wsad\workspace\sma\xml\position.xsd' is not a valid value for 'anyURI'.
Line 4...
cvc-attribute.3: The value 'file://c:\wsad\workspace\sma\xml\position.xsd' of attribute 'xsi:noNamespaceSchemaLocation' on element 'position' is not valid with respect to its type, 'anyURI'.
Can someone help !!!!!!!!
Thanks !

Answer 1

cvc-datatype-valid.1.2.1: 'file://c:\wsad\workspace\sma\xml\position.xsd' is not a valid value for 'anyURI'.I am guessing that's in a place that is supposed to have a URI. Well, if you're going to have backslashes in a URI then you have to escape them as %5C. But if you meant for them to separate directory names, then replace them by slashes as per the URI specification.