Varification Number Generation and showing it as popup

Question

I want to show a popup of varification number when user inserts a form.
let say there are 3 fields in a form, first two are visible and can have any info. third one is hidden and it generates auto numbers, first i need that it must generate some random numbers upon each submission of form. Second i want this randam generated number to be shown to the user as popup and tells user that it is his/her verification number. and in future if he/she wants to check what they entered, they will be able to fetch with that verification number.
Any help will be appriciated
Thanks in Advance
Mazahir Abbas

Answer 1

If its hidden you don't need to prefetch it as users don't get to see it. You can assign it from the Submit PLSQL process itself and set that hidden item(say P100_VERIFICATION_NUMBER) with the value.
Then add an onload Javascript that displays the message when the hidden item not null(so that it runs only after submit process)
alert(' Your Verification Number is :'+ $v('P100_VERIFICATION_NUMBER') );You can also do that directly from the PLSQL process
BEGIN
  --process
  :P100_VERIFICATION_NUMBER := <new verification number>;
  htp.p('<script>');
  htp.p('alert("Your Verification Number is :'||:P100_VERIFICATION_NUMBER||'")');
  htp.p('</script>');
END;Random numbers needn't be unique and might not be good idea in the long run. You should be using sequences in these situations. However if you want it to generate random values you can use
FLOOR(DBMS_RANDOM.value(0,1)*99999999999999999999) generating a 20 digit random no.