Visibility of paths

Hello everyone,
I'm using the Pen Tool to draw several paths; I need to draw each path with reference to the other, previously drawn, paths. This is where I encountered a problem with Photoshop CS3: whenever I create a new path, the old ones become invisible, and I can only see one path at a time - the one that's selected in the Paths panel.
Is there any way to control the visibility of the different existing paths (as you can, for example, with layers) and to make several (unstroked) paths be visible simultaneously?
Anticipated thanks for any help!

Instead of having several individual paths, you could combine them as sub-paths in a single path.

Similar Messages

How to not show only visible expanded paths in tree?

Hi!
Let's have a tree with next nodes:
R - root
N1.0
N1.1 - child of N1.0
N1.1.1 - child of N1.1
The node N1.1 is expand, but node N1.0 is not expand. How show tree when node N1.1 is expand but it's not visible, because it parent is not expand?
Thank you.

The correct way to do this is to create a separate account for each of you and disable automatic login when prompted. Under Accounts I would also activate Fast User Switching if the two of you use it at the same time. Then each of you will have your own user directory and this will segregate all of your user data into two separate user folders and you can act separately.
If it is just a convenience thing then download another email program, like Thunderbird, and each of you can simply use a separate program and neither will be bothered with the others email.
Also unchecking the "enable this account" in the Mail > Account preferences will cause an account to "disappear" from the Inbox view until the box is rechecked. But this is only a solution if one of you uses the account occasionally like on long weekends or something.
I think the separate accounts option is what you want from your description but there a few less drastic options.
HTH,
=Tod

WPF: Could we simplify path definitions?

We have defined two paths for apply to two different styles.
The only difference between two paths is one path rotates 180 degree of first path.
So far we have to duplicate Path definition code and two paths difference in bold line section.
<Path x:Name="pathChrome" Data="M5.4907628E-15,85.783656 L-1.1796041E-14,15.481527 C-1.1796041E-14,15.481527 0.00046152103,-0.125 15.441696,-0.125 30.82625,-0.125 153.00691,0.12776899 153.00691,0.12776899 169.14967,0.12776899 169.5,15.491538 169.5,15.660051 169.5,27.792962 169.5,67.500033 169.5,85.783656" HorizontalAlignment="Left" Height="74.569" Stretch="Fill" StrokeThickness="1" VerticalAlignment="Top" Width="162" Margin="5,2.6,0,0" ClipToBounds="False" Opacity="1" Visibility="Hidden">
<Path.Stroke>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="White" Offset="1"/>
<GradientStop Color="#FF8D8D8D"/>
</LinearGradientBrush>
</Path.Stroke>
<Path.Fill>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="#FF9E9E9E" Offset="0.004"/>
<GradientStop Color="#FFE2E2E2" Offset="1"/>
</LinearGradientBrush>
</Path.Fill>
</Path>
<Path x:Name="path" Data="M5.4907628E-15,85.783656 L-1.1796041E-14,15.481527 C-1.1796041E-14,15.481527 0.00046152103,-0.125 15.441696,-0.125 30.82625,-0.125 153.00691,0.12776899 153.00691,0.12776899 169.14967,0.12776899 169.5,15.491538 169.5,15.660051 169.5,27.792962 169.5,67.500033 169.5,85.783656" HorizontalAlignment="Left" Height="74.569" Stretch="Fill" StrokeThickness="1" VerticalAlignment="Top" Width="162" Margin="5,2.6,0,0" ClipToBounds="False" Opacity="1" Visibility="Hidden"
RenderTransformOrigin="0.5,0.5">
<Path.Stroke>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="White" Offset="1"/>
<GradientStop Color="#FF8D8D8D"/>
</LinearGradientBrush>
</Path.Stroke>
<Path.Fill>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="#FF9E9E9E" Offset="0.004"/>
<GradientStop Color="#FFE2E2E2" Offset="1"/>
</LinearGradientBrush>
</Path.Fill>
<Path.RenderTransform>
<TransformGroup>
<RotateTransform Angle="180"/>
</TransformGroup>
</Path.RenderTransform>
</Path>
Is it possible that we can make the code simple? Thx!
JaneC

You could apply the RotateTransform on the element instance to which apply the style or on a ContentControl:
<Path x:Key="pathChrome" x:Shared="false" .... />
<ContentControl Content="{StaticResource pathChrome}">
<ContentControl.LayoutTransform>
<RotateTransform Angle="180"/>
</ContentControl.LayoutTransform>
</ContentControl>
The drawback is of course that you have to this (apply the RotateTransform) every time you want a rotated path.
A better option may be to create two styles and base the second one on the first one:
<Style x:Key="pathChrome" TargetType="{x:Type Path}">
<Setter Property="Height" Value="74.569"/>
<Setter Property="StrokeThickness" Value="1"/>

<Setter Property="Data" Value="M5.4907628E-15,85.783656 L-1.1796041E-14,15.481527 C-1.1796041E-14,15.481527 0.00046152103,-0.125 15.441696,-0.125 30.82625,-0.125 153.00691,0.12776899 153.00691,0.12776899 169.14967,0.12776899 169.5,15.491538 169.5,15.660051 169.5,27.792962 169.5,67.500033 169.5,85.783656"/>
<Setter Property="Stroke">
<Setter.Value>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="White" Offset="1"/>
<GradientStop Color="#FF8D8D8D"/>
</LinearGradientBrush>
</Setter.Value>
</Setter>
<Setter Property="Fill">
<Setter.Value>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="#FF9E9E9E" Offset="0.004"/>
<GradientStop Color="#FFE2E2E2" Offset="1"/>
</LinearGradientBrush>
</Setter.Value>
</Setter>
</Style>
<Style x:Key="path" TargetType="{x:Type Path}" BasedOn="{StaticResource pathChrome}">
<Setter Property="RenderTransform">
<Setter.Value>
<TransformGroup>
<RotateTransform Angle="180"/>
</TransformGroup>
</Setter.Value>
</Setter>
</Style>
Usage:
<Path Style="{StaticResource pathChrome}"/>
<Path Style="{StaticResource path}"/>
Hope that helps.
Please remember to close your threads by marking helpful posts as answer and please start a new thread if you have a new question.

How do I create gradients (only a few steps) that follow the contour of the artwork?

I am creating a 'How to' diagram using illustrations from a previous artist. As such I need to recreate his way of creating image gradients. He seems to do it by using only a small amount of gradient steps creating quite block like gradients. Like this: How would I go about getting my smooth gradients like this? At the moment I am creating a smooth gradient filled object, expanding it then specifying the steps in the dialogue box that then appears. But this does not really recreate the same gradient (please see as follows):So my question is does anybody know how this artist has done this? As the gradients also seem to follow the contours of the object.
Thanks in advance,
Olly

Olly,
If you do wish a more precise recreation, I am afraid you need to approach it some other way.
As I see the original artwork, it has small roundings at the left end, and it has a dark outer stroke and a blend inside from bottom to top, and on top of that it has three slightly shorter parts, the two lower ones abutted. Everything narrower at the left end, except for the stroke which is uniform.
You may recreate all that in this maybe rather silly way:
1) Create a rectangle with the original width and right side height and with the same Stroke Weight and colour as the original and with a solid fill the same colour as the original at the bottom, then create a corresponding rounded rectangle with Corner Radius corresponding to the roundings to the right, and place it on top of the rectangle;
2) Select both and Pathfinder>Divide, then delete the corner paths to the right, then select the rest and Pathfinder>Unite (or whatever it is called in your version to get one path with rounded corners to the right, then scale the H value to the original left side height;
3) Copy 2) to the front, remove the fill, and lock the copy (which holds the stroke), to work on with the fill/nostroke path;
4) Create two copies of 2) and hide the topmost one;
5) With one of the top Reference Points ticked in the Transform palette, select the visible copy path 4) and reduce the H value to a small suitable value (1pt or something, depending on the size);
6) Select 3) and 5) and Object>Blend>Make (with Smooth ticked in Object>Blend>Options), this should give you the background fill;
7) Show the copy hidden in 4) and reduce its height to 1/6 (divide the H value by 6), change the fill to the right (darker) solid colour/shade, move it to a position 1/6 up, and reduce its W value by a small amount so the bottom fill shows at the ends;
8) Move a copy of 7) 1/6 up;
9) Move a copy of 8) 1/3 up;
10) Adjust the colours/shades of 8) and 9), unlock the stroked path from 3), and Group everything, now you should have the whole artwork represented, only rectangular;
Depending on version, you may then:
11a) For the newest version(s) create an Art Brush to be applied to simple paths with decreasing width towards the right, or
11b) For any version, Direct Select the Anchor Points to the far right, and Object>Transform>Scale vertically to get the original height to the right.
Here is an image in greys, indicating the look after 10) and 11) (the stroke should have been wider, eating away more of the height of the bottom fill blend):

Video file name on listbutton label

I'm playing FMS videos from XML. but no need visible filelist path on listbutton.label.
How can i show only video file name on listbutton.label ;
<?xml version="1.0" encoding="utf-8"?>
<XML>
<FileList>files/store1/2013/1/2/15/video1</FileList>
<FileList>files/store1/2013/1/2/15/video2</FileList>
<FileList>files/store1/2013/1/2/15/video3</FileList>
</XML>
AS3
function playlistLoaded(e:Event):void
          xmlPlaylist = new XML(urlLoader.data);
for (var i:int=0; i<xmlPlaylist.FileList.length(); i++)
     listbutton = new Button();
     listbutton.y = i * 19 + 1;
     listbutton.width = 200;
     listbutton.height = 20;
     listbutton.label = xmlPlaylist.FileList[i];

files/store1/2013/1/2/15 this paths are not fixed.
changing daily. But folders are fixed so what can i do...? how to caluculate "/", and remove before filename
like..
files/store1/2013/3/6/23
files/store2/2013/12/30/15
files/store3/2013/8/10/20

Drag & drop from explorer into my application

Hi folks,
I want to drag files or folders from Windows explorer into a tree structure of my LabVIEW application. I did not find any solution or example (and I was not able to install the G-Toolbox, which is mentioned in some old forum boards).
Does anybody have an example? Thank you very much!
Solved!
Go to Solution.

I found this thread searching for a way to drag and drop files from the OS (either Windows Explorer or Mac Finder) onto my VI. I don't want a visible file path control on the front panel--I want the user to be able to drop the file anywhere within the VI's panel.
I've looked at all of the examples linked above in this NI thread and the thread at LAVA, but came up empty for any code examples that does this for both Mac and Windows.
I did eventually find a way to create something that works for Windows. (I might have seen this solution from the JKI guys a few years back--I can't remember.) It relies on the following:
* A transperrent path control set to "fit control to pane" so that it covers the whole pane even if it is resized.
* This path control needs to be the top-most control so that is can always receive the dropped path.
* Create a <This VI>:Mouse Enters event to make the path control inivisble
* Create a <This VI>:Mouse Exits event to make the path control visible
This works in Windows (testing with LV2010 in Win7) because when you drag a file onto the VI panel it DOES NOT fire the Mouse Enters event. You can drop the file and as soon as the path control receives the path the VI can rehide the path control so that the user can manipulate other controls on the panel.
However, the problem is that on Mac (tested with LV2010 in Mac Lion), the Mouse Enters event DOES fire when you drag a file into the VI panel.
I'm posting this example as a working example for Windows folks, but I hoping there is a clever Mac user out there than can figure out a work-around to make this work for the Mac too.
Thanks!
Attachments:
drag and drop file path example.vi ‏18 KB

Fiori Extension Point Question

I am trying to extend the Approve Timesheets app, there is an extension point in the Object header that I would like to add attributes to:
<ObjectHeader
                title="{parts:[{path:'DetailModel>/Cotype'},{path:'DetailModel>/Codesc'}],formatter:'hcm.mgr.approve.timesheet.utility.Parser.projectTitle'}"
                number="{DetailModel>/No_People}"
                numberUnit="{i18n>TSA_PEOPLE}"
                visible="{DetailModel>/CostVisible}">
                <firstStatus>
                    <ObjectStatus text="{path:'DetailModel>Overtime', formatter:'hcm.mgr.approve.timesheet.utility.Parser.parseOverTime'}"></ObjectStatus>
                </firstStatus>
                
                <core:ExtensionPoint name="extS3CostHeader"></core:ExtensionPoint>
            </ObjectHeader>
I used the Add SAP Fiori Extension option in Juno so I am pretty sure I have the component.js part setup right, here is my code for the fragment:
<core:FragmentDefinition xmlns="sap.m" xmlns:core="sap.ui.core">
      <attributes>
      <ObjectAttribute text="Hello World" />
    </attributes>
</core:FragmentDefinition>
Wen I run the app it just hangs?
Thoughts?
Do I need something more in the fragment?

Hi Mike (& Jason),
I am having exactly the same issue trying to add an extension point to the Wave 2 PO Approval app.
Like your example, the ExtensionPoint is placed in the standard view within an open construct (in your case <ObjectHeader>     ....     </ObjectHeader>; in my case for the MM_PO_APV app S2 view it is within <ObjectListItem>   ...   </ObjectListItem>).
It seems that the core code that inserts the extension point fragment code into the standard code at the insertion point does not understand that the fragment is a sub-element of the open object definition at that point and goes looking for a javascript file of the sub-element name.
I have searched through every Fiori and SAPUI5 document I can find for an example of a working view extension fragment where the extension point is located within an open definition like these, but have not been able to find one. I assume there is some syntax required in the fragment to give the right context to the extension point handler, but being a long time abaper and not a JS or XML programmer I have not been able to crack it. All the short documents on extensibility just give the basics and assume the code fragment will just work, and the long documents (like the SAPUI5 developers guide and the Hana SDK site) also do not cover this exact scenario with an example of the fragment code. However I have seen posts here by people saying that they have implemented these same view extensions successfully.
It is possible that it is an XML namespace issue but I have seen it written that the code fragments should inherit all bindings from the view where the extension point is, so that should be taken care of and the JS library resolution worked out based on the view being extended.
I have got a controller extension working on the S3 view of the PO Approval app so I am not a complete SAPUI5 dolt (well, until proven otherwise ).
Mike - did you get it to work? If so can you post the code? I invite anyone with a working view extension, where the insertion point is located within an open object definition, to post the code fragment here (please).
For reference, the extension point in the PO Approval S2 view is located just before the </ObjectListItem> tag in the following SAP-standard view code (posted after my signature below)
Regards,
Mark
<List
     id="list"
     mode="{device>/listMode}"
     select="_handleSelect">
     <ObjectListItem
          id="MAIN_LIST_ITEM"
          type="{device>/listItemType}"
          press="_handleItemPress"
          title="{SupplierName}"
          number="{parts:[{path : 'Value'}], formatter : 'ui.s2p.mm.purchorder.approve.util.Conversions.lazyRoundNumber'}"
          numberUnit="{Currency}">
          <firstStatus>
               <ObjectStatus
                    text="{parts:[{path:'WiCreatedAt'}], formatter:'ui.s2p.mm.purchorder.approve.util.Conversions.formatDaysAgo'}">
               </ObjectStatus>
          </firstStatus>
          <attributes>
               <ObjectAttribute text="{ItemDescriptions}" />
               <ObjectAttribute text="{CreatedByName}" />
               <ObjectAttribute text="{parts:[{path : 'ForwardedByName'}], formatter : 'ui.s2p.mm.purchorder.approve.util.Conversions.forwardedBy'}"
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               visible="{parts:[{path : 'SubstitutingForName'}], formatter : 'ui.s2p.mm.purchorder.approve.util.Conversions.commonFieldVisibilityTrigger'}" />
               </attributes>
               <core:ExtensionPoint name="extListItemInfo" />
     <ObjectListItem>
</List>

How to open a terminal window in a path currently visible in the Finder?

I often need to open a terminal window with the current visible folder (a long, deep path) as the working directory.
In Windows I used to have the little "Open command window here..." hack available in the context menu in Explorer.
How can I achieve the same on OS X to avoid tediously typing the path?

open a finder window and navigate to one-level above
this visible folder.
open a terminal window.
drag the folder of interest from the finder window
into the terminal window. now you see the whole path
to that folder has been typed out for you....
so, if you wanted to 'cd' into that folder in
terminal, you'd type cd, then a space, into the
terminal window, then drag that folder in there from
the finder, then hit return.... viola!
If the folder you want is already open, you can drag the icon at the top of the Finder window. You don't have to go one level up.

Mouse Path Not Visible - Why?

Hi, all. I'm editing a Captivate demo using Captivate 3 and
for some reason the paths for the mouse movement aren't visible. I
can't select or move the mouse and when I right-click on it I'm not
offered an option to align it's movement to the previous slide. I
added a slide at the head of the show and added a mouse cursor
manually, which affords me all of these options. Did I do something
during the capture that would make the mouse movements
uneditable?

Hi there
Two questions here.
1. Do the slides in the Film strip have the mouse icon on
them? Or do they instead have a Camcorder icon on them?
If they have a Camcorder icon, this means they are full
motion recording (FMR) slides. You may not edit the mouse movements
in a FMR.
2. Assuming the Film Strip slides actually have a Mouse icon
on them, look in your Timeline area. Look to the left of the Mouse
object. Do you see a simple dot or do you see a padlock icon or
possibly an X in the other field? If so, it means you have either
hidden or locked that object on the slide. Click the X or the
padlock icon to unlock or un-hide the mouse.
Cheers... Rick

Motion paths not wholly visible

I'm trying to simply move a solid with a motion path. I copy/pasted a mask path into the Position property of the solid layer.
Initially everything looks right after I paste the path -- however if I move the position keyframes apart (to make the motion slower) the motion path is no longer visible from beginning to end. As I scrub the time slider the solid is sliding along the path correctly, however I only see about 20% of the path at any one time. It's almost like the anchor point is providing 'light' and I can only see about 10% of the path in front and behind of my current location.
I don't get it.

> It certainly doesn't help that After Effects help file makes NO mention of it on the motion path pages.
"Show motion path controls"

Pen Path not visible - Illustrator CS4

Hello all,
I am a relatively comfortable user of Illustrator - but just now I have encountered a problem whereby my pen path tool is not visible as I draw. When objects are selected with either the selection tool or direct selection tool the path outline is not made available to select. All I get is a generic bounding box with the selection tool - with the direct selection tool I get nothing.
I have scoured the user preferences for some hidden setting - all I can think is that I've mashed the keypad in some wierd and wonderful way that has made this suddenly happen.
Any pointers or help would be much appreciated.

Thank you, that sorts it! In all my years I have never needed that function - I did not know it existed.

Visibility of clipping paths

Whilst CS 6 has some great improvements, I find running clipping paths in it very difficult. That is because in earlier versions of photoshop, clipping paths showed up in the complementary colour of the underlaying colour and were very visible. Now they are a darkish grey, which makes it often impossible to see them. You can go blind trying to see where you are clipping.
Any solutions to this?

I only have CC installed at the moment, and paths work really nicely on that, flipping from black to white according to the colour behind them. It always used to be a problem, and I have seen many discussions and moans on the subject, so you might have to grin and bear - or get a CC subscription

SAP standard Menu : few menu paths not visible in Production but dev

Hi All,
We have a problem where in we can see the following menu path visible in standard menu in developement system; while the same menu path ( and few others also ) not visible in production system for same user ( i.e. having similar authorizations )
the path is : SAP Menu --> Accounting --> Financial Supply Chain Management --> Cash and Liquidity Management
Our system is : ECC 6.0
Every user should be able to view SAP standard menu inspite of the fact that he might have authorization to certain transactions only; hence this should not be an authorization issue ( as per my view ).
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Thanks.
Regards,
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Hi Alex,
I had that option in front of me ( we actually tried it also with no result ). But before that I would like to know, why this might have happened. Why there is difference between standard menu on both servers?
Regards,
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Visible Paths

I am working in Illustrator CS6 on a Mac (10.7.5) and on some (but not all) of the objects in my document, the paths (not strokes) are visible as light grey lines. This occurs in objects that are stroked, filled or both. I can make a stroke thicker, but the 'path' is still visible in the center of it. The Appearences panel gives no indication of what's going on. I've used Illustrator for over 10 years and this has me stumped - any ideas?

Preview is on for this layer. Outline view appears as it normally does. The paths are visible at the same time as the object. There are 2 objects on the same layer and regardless of which object is in front of the other object, the paths of both objects are visble. I created another object on that layer and placed it above the other 2 objects - the paths were visible through this new object as well as it's own path. The path color is the same regardless of the stroke or fill colors of the object. The problem seems to exist on this particular layer.

Defining virtual path for images to be visible without specifiying path(AS)

Hi,
I am running a report (Version 10g) which have an image (Read from file = yes) item with source "Function column" that returns an image name. Ex. "11.gif"
I am recieving an error that the applications server cannot find the image "11.gif"
Image 11.gif is stored in a directory on the Applications server "D:\photos".
Where should I add the directory path "D:\photos" so that the reports will view the image?
Thanks

No need to define a virtual path similar to what's done in forms 10g. An entry in the registry key 'REPORTS_PATH' is enough!

Visibility of paths

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