Vista, unrecognized partition table use fdisk to fix?

I have a NTFS Vista partition and when I boot into it I get a lot of white type on black screens telling me there is an unknown partition located and to use fdisk to fix.
Vista comes up and works fine but I'd like to get rid of those screens.
Any ideas appreciated ...
Thanks ... Ken

Two yrs going back to RC1 in Oct '06 and I've never seen, nor do I have any idea, what you did or have, and whether you have altered or touched the GPT or EFI partitions or USB device.
And I've got 4 internal NTFS drives, most with two partitions, some flash devices, FireWire 800, along with native SATA external.
And never even seen fdisk mentioned.
Maybe you should click on properties and schedule chkdsk for every partition you can and look in Computer -> Manage.

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    Last edited by McZ (2008-02-01 20:07:42)

  • Error while creating partition table

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    41>
    42> insert #table1
    43> select "ET00jPzh", "Jan 15 2015", 1
    44> union all
    45> select "ET00jPzh", "Jan 15 2015", 1
    (1 row affected)
    (1 row affected)
    (2 rows affected)
    1>
    2> update partitioned
    3> set    ValidTo = dateadd(dd,-1,FileDate)
    4> from   #table1 t
    5> inner  join partitioned p on (p.PK = t.PK)
    6> where  p.ValidTo = '99991231'
    7> and    t.changed = 1
    Msg 2601, Level 14, State 6:
    Server 'PHILLY_ASE', Line 2:
    Attempt to insert duplicate key row in object 'partitioned' with unique index 'pk'
    Command has been aborted.
    (0 rows affected)
    1>
    2> update unpartitioned
    3> set    ValidTo = dateadd(dd,-1,FileDate)
    4> from   #table1 t
    5> inner  join unpartitioned u on (u.PK = t.PK)
    6> where  u.ValidTo = '99991231'
    7> and    t.changed = 1
    (1 row affected)
    1>
    2> drop table #table1
    1>
    2> drop table partitioned
    3> drop table unpartitioned
    -- duplicating with 'int'
    1> use demo_db
    1>
    2> CREATE TABLE #table1
    3>     (   PK          char(8) null,
    4>         FileDate        date,
    5> --        changed         bit
    6>  changed int
    7>     )
    8>
    9> CREATE TABLE partitioned  (
    10>   PK         char(8) NOT NULL,
    11>   ValidFrom     date DEFAULT current_date() NOT NULL,
    12>   ValidTo       date DEFAULT '31-Dec-9999' NOT NULL
    13>   )
    14>
    15> LOCK DATAROWS
    16>   PARTITION BY RANGE (ValidTo)
    17>   ( p2014 VALUES <= ('20141231') ON [default],
    18>   p2015 VALUES <= ('20151231') ON [default],
    19>   pMAX VALUES <= (MAX) ON [default]
    20>         )
    21>
    22> CREATE UNIQUE CLUSTERED INDEX pk
    23>   ON partitioned(PK, ValidFrom, ValidTo)
    24>   LOCAL INDEX
    25>
    26> CREATE TABLE unpartitioned  (
    27>   PK         char(8) NOT NULL,
    28>   ValidFrom     date DEFAULT current_date() NOT NULL,
    29>   ValidTo       date DEFAULT '31-Dec-9999' NOT NULL,
    30>   )
    31> LOCK DATAROWS
    32>
    33> CREATE UNIQUE CLUSTERED INDEX pk
    34>   ON unpartitioned(PK, ValidFrom, ValidTo)
    35>
    36> insert partitioned
    37> select "ET00jPzh", "Jan  7 2015", "Dec 31 9999"
    38>
    39> insert unpartitioned
    40> select "ET00jPzh", "Jan  7 2015", "Dec 31 9999"
    41>
    42> insert #table1
    43> select "ET00jPzh", "Jan 15 2015", 1
    44> union all
    45> select "ET00jPzh", "Jan 15 2015", 1
    (1 row affected)
    (1 row affected)
    (2 rows affected)
    1>
    2> update partitioned
    3> set    ValidTo = dateadd(dd,-1,FileDate)
    4> from   #table1 t
    5> inner  join partitioned p on (p.PK = t.PK)
    6> where  p.ValidTo = '99991231'
    7> and    t.changed = 1
    Msg 2601, Level 14, State 6:
    Server 'PHILLY_ASE', Line 2:
    Attempt to insert duplicate key row in object 'partitioned' with unique index 'pk'
    Command has been aborted.
    (0 rows affected)
    1>
    2> update unpartitioned
    3> set    ValidTo = dateadd(dd,-1,FileDate)
    4> from   #table1 t
    5> inner  join unpartitioned u on (u.PK = t.PK)
    6> where  u.ValidTo = '99991231'
    7> and    t.changed = 1
    (1 row affected)
    1>
    2> drop table #table1
    1>
    2> drop table partitioned
    3> drop table unpartitioned

  • Partitioned table takes more time to load

    Hi,
    Recently I have been test loading a partition table (Datawarehouse fact table). However, I notice almost 2X to 2.5X jump in timing compared to the non-partitioned table.
    The partition is on the TIME Key on the basis of monthly range. Since this key is not entirely consistent (less than 1% cases) and can change sometimes, I have enabled row movement.
    Is there anything that you can do to improve timing when everything else remains same?
    Regards
    Prem

    Hi,
    When you load data into a partitioned table oracle has to check every record
    to decide in which partition store it.
    When you load data in a heap table oracle hasn't to check it. All records
    are saved in the same segment.
    You can save time when you load in partitioned tables using partition
    clause.
    Regards
    K.Rajkumar

  • Unique key on range-partitioned table

    Hi,
    We are using a composite range-hash interval partitioned table
    Uses index - trying to make this have same tablespace as the partitions i.e. local but not liking it
    alter table RETAILER_TRANSACTION_COMP_POR
    add constraint RETAILER_TRANSACTION_COMP_PK primary key (DWH_NUM)
    using index
    LOCAL
    ora-14039: partitioning columns must form a subset of key columns of a unique index
    Without local then fine but doesn't have same tablespace as the partitions and don't want to make this part of partition key.
    Tbale range partitioned - this is just a UK to prevent duplicates

    [oracle@localhost ~]$ oerr ora 14039
    14039, 00000, "partitioning columns must form a subset of key columns of a UNIQUE index"
    // *Cause:  User attempted to create a UNIQUE partitioned index whose
    //          partitioning columns do not form a subset of its key columns
    //          which is illegal
    // *Action: If the user, indeed, desired to create an index whose
    //          partitioning columns do not form a subset of its key columns,
    //          it must be created as non-UNIQUE; otherwise, correct the
    //          list of key and/or partitioning columns to ensure that the index'
    //          partitioning columns form a subset of its key columns

  • Partition tables replication

    Can anyone let me know how to replicate partitioned tables using goldengate.

    Hi,
    I have enabled replication for one of the partitioned table and inserted few rows which got replicated successfully.
    Then i tried to update the rows at source, and i could see that this change didnt happen at target side. Similarly when i tried to delete rows my replicat process abended with an error.
    Please check this link where i have posted the output and all. Let me know what can be done, we need to move to production implementation asap if this testing goes fine.
    Replicat Abended  while rows are deleted at source
    Thanks,
    Bharat Damarla

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