What to make root node?

I have a situation with members and clubs where I want (yes I'm a newbie)
club
member
club
member
member
member
club
member
member
I currently have this code which shows my JTree root but I've inadvertently made it a vector...
MyTreeModel t = new MyTreeModel();
              DefaultMutableTreeNode top = new DefaultMutableTreeNode(t.getRoot());
              MyTreeModel treeModel = new MyTreeModel();
              JTree tree = new JTree(treeModel);my question then is what should I be using for root? And if I just use a node called root how do I link my clubs and members to it?
Any advice would be appreciated as I'm a bit clueless on how to proceed.

Any advice would be appreciated as I'm a bit clueless on how to proceed. Read the Swing tutorial on [url http://java.sun.com/docs/books/tutorial/uiswing/components/tree.html]How to Use Trees for a working example.

Similar Messages

How to handle unknown root node type when parsing?

Hello all, hoping someone knows how to accomplish this...
I'm trying to use XMLBeans to parse RIXML 2.0 documents. This schema allows for
multiple root node types, so I don't know when I'm trying to parse a file if the
root node is a Research node or a Product node, for example. If I try to invoke
parse and there is a type mismatch I get the following error:
com.bea.xml.XmlException: D:\RIXML\V2TestDoc.xml:0: error: The document is not
a Research@http://www.rixml.org/2002/6/RIXML: document element local name mismatch
expected Researchgot Product
     at com.bea.xbean.store.Root.verifyDocumentType(Root.java:472)
     at com.bea.xbean.store.Root.autoTypedDocument(Root.java:394)
     at com.bea.xbean.store.Root.loadXml(Root.java:763)
     at com.bea.xbean.schema.SchemaTypeLoaderBase.parse(SchemaTypeLoaderBase.java:286)
     at com.bea.xbean.schema.SchemaTypeLoaderBase.parse(SchemaTypeLoaderBase.java:224)
     at org.rixml.x2002.x6.rixml.ResearchDocument$Factory.parse(Unknown Source)
     at Test.main(Test.java:21)
Exception in thread "main"
So how do I generically handle parsing when I don't know what type of root node
I'm going to get?
Thanks,
Joe

Hello Joe -- You might try parsing the document as XmlObject (which your
schema-generated types extend). Then you could use an XmlCursor to discover
what the root element's local name is. Something like the following code
might be a way to do it. You could also simply re-parse the document after
discovering its root element name, but that would probably be more
expensive.
XmlObject xml = XmlObject.Factory.parse(mydoc.xml);
XmlCursor cursor = xml.newCursor();
cursor.toFirstContentToken();
if (cursor.getName().getLocalPart().equals("Research"))
// cast the XmlObject to your ResearchDocument type and use it.
else if (cursor.getName().getLocalPart().equals("Product"))
// cast the XmlObject to your ProductDocument type and use it.
cursor.dispose();
Steve
"Joe Celentano" <[email protected]> wrote in message
news:[email protected]..
>
Hello all, hoping someone knows how to accomplish this...
I'm trying to use XMLBeans to parse RIXML 2.0 documents. This schemaallows for
multiple root node types, so I don't know when I'm trying to parse a fileif the
root node is a Research node or a Product node, for example. If I try toinvoke
parse and there is a type mismatch I get the following error:
com.bea.xml.XmlException: D:\RIXML\V2TestDoc.xml:0: error: The document isnot
a Research@http://www.rixml.org/2002/6/RIXML: document element local name
mismatch
expected Researchgot Product
at com.bea.xbean.store.Root.verifyDocumentType(Root.java:472)
at com.bea.xbean.store.Root.autoTypedDocument(Root.java:394)
at com.bea.xbean.store.Root.loadXml(Root.java:763)
atcom.bea.xbean.schema.SchemaTypeLoaderBase.parse(SchemaTypeLoaderBase.java:28
6)
atcom.bea.xbean.schema.SchemaTypeLoaderBase.parse(SchemaTypeLoaderBase.java:22
4)
at org.rixml.x2002.x6.rixml.ResearchDocument$Factory.parse(Unknown Source)
at Test.main(Test.java:21)
Exception in thread "main"
So how do I generically handle parsing when I don't know what type of rootnode
I'm going to get?
Thanks,
Joe

PCOLL_CONTROL, PCST_TXN,...What are these objects? JBO-28039:Root node for collection

I've a UIX JSP Application with BC4J developed with JDeveloper RC.
I noted that in my schema there are these "strange" db objects:
PCOLL_CONTROL
PCST_MYPACKAGEMODULE_SEQ
PCST_MyPackageModule
PCST_TXN
PCST_TXN_SEQ
Can anyone explain what are they or where can I find documentation about them ?
When and why Jdev create them ?
Beside some people that use my application got the following Error:
"JBO-28039: Root node for collection TXN of id -1 is invalid......".
I think that it's connected with the objects listed above.
Has someone experienced this problem ?
thank you
Isabella

Could you provide more information regarding this issue:
1. When you mention that some people that use your application receive the exception do you mean that the
exception is thrown from the application and displayed to the user or do you mean that the exception is simply logged
in the Diagnostic output? The latter may be expected in some scenarios.
2. Could you provide a full stack trace for the exception?
3. Could you provide the BC4J diagnostic output generated when the exception occurs (specify the VM switch
-Djbo.debugoutput=console at the command line)?
Thanks,
JR

Root node contains specific attribute could make the XSLT transfrom fail

I have to convert EJB deploy desciptor in my project, but I found that XML format transfrom with Apache Xalan will fail when the root node contants some specific attribute.
Here is an example:
Input XML file:
<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2eehttp://java.sun.com/xml/ns/j2ee/ejb-jar_2_1.xsd"
version="2.1">
<cd>
<title>Empire Burlesque</title>
<artist>Bob Dylan</artist>
<country>USA</country>
<company>Columbia</company>
<price>10.90</price>
<year>1985</year>
</cd>
<cd>
<title>Hide your heart</title>
<artist>Bonnie Tyler</artist>
<country>UK</country>
<company>CBS Records</company>
<price>9.90</price>
<year>1988</year>
</cd>
</catalog>
XSL transfer file:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method='html' version='1.0' encoding='UTF-8' indent='yes'/>
<xsl:template match="/">
<html>
<body>
My CD Collection
<table border="1">
<tr bgcolor="#9acd32">
<th align="left">Title</th>
<th align="left">Artist</th>
</tr>
<xsl:for-each select="catalog/cd">
<tr>
<td><xsl:value-of select="title"/></td>
<td><xsl:value-of select="artist"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
The XML transfrom will fail in this way.
But if I remove the attributes in the input xml's root node, such as this:
<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<cd>
The transform operation will succeed.
Does anyone know the reason?

In your xslt you will have to make sure to reference the elements using the http://java.sun.com/xml/ns/j2ee namespace.
Change your XSLT to be something like this and it should work:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:j2ee="http://java.sun.com/xml/ns/j2ee">
<xsl:output method='html' version='1.0' encoding='UTF-8' indent='yes'/>
<xsl:template match="/">
<html>
<body>
My CD Collection
<table border="1">
<tr bgcolor="#9acd32">
<th align="left">Title</th>
<th align="left">Artist</th>
</tr>
<xsl:for-each select="j2ee:catalog/j2ee:cd">
<tr>
<td><xsl:value-of select="j2ee:title"/></td>
<td><xsl:value-of select="j2ee:artist"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>

Inserting root node to enable 1...n

I am doing IDOC - file scenario
I have a DT already created at the receiver end
what do I have to do inorder to recieve mutliple instances of IDOC in receiver ( 1.... n )?
I am planning to create a root node with 1...1 and make the fileds 0...unbound
is this gonna work ?
if yes, please let me know how do I insert a node in the root level
thanks,
venkat.

Hi,
You cannot directly insert an element at the root level. You have to recreate the whole datatype.
Regards,
Sudheer.

Dynamically rename the root node of XML based on the child elements

Hi Gurus,
Is there any way to rename the root node of the resultant XML after a mapping based on the child elements.
For ex:
consider the following resultant XML after mapping
<result>
<element1> </element1>
<result>
if the element1 is <type> then the output should be
<category>
<type> </type>
</category>
elseif the element1 is <character> then the output should be
<property>
<character> </character>
</property>
Let me know how to do this, either in XSLT or in Graphical mapping.
Thanks,
Prabu

Hi, Prabu:
In this case, I am suggest you have Src and Tar Message.
I am suggesting you create another type of message using key / value pair as I suggested, e.g. called Mid Message.
My solution for you is to have two message mappings:
1. Src -> Mid
2. Mid -> Tar.
In first mapping, you have no control of the structure, but you can map it to Mid structure:
e.g.
if Type node Exist, then map 'Type' to Key, as Key/Value can be creatd under a parent node with 0:1 Occurrence.
saying item.
   in this case, a new item created.
If you think of this way, any xml file can be represted in this way:
   <Employee>
      <Fname>David</Fname>
      <Lname>Miller</Lname>
   </Employee>
   <Employee>
      <Fname>Steve</Fname>
      <Lname>Mai</Lname>
   </Employee>
Can be interpretd as this way:
   <Employee>
      <Element>
         <key>Fname</Key>
         <value>David</Value>
      </Element>
      <Element>
         <key>Lname</Key>
         <value>Miller</Value>
      </Element>
   </Employee>
   <Employee>
      <Element>
         <key>Fname</Key>
         <value>Steve</Value>
      </Element>
      <Element>
         <key>Lname</Key>
         <value>Mai</Value>
      </Element>
   </Employee>
Now you should understand what I mean.
In your case target structure have to desgined as following way:
You need to put Category and Property together with their sub-structure in parallel, make occurence to 0:1
In your second mapping, you can check the key value is "Type" or "Character", based on which one is true,
you create corresponding structure: either Categary or Property.
Regards
Liang
Edited by: Liang Ji on Oct 22, 2010 8:31 PM
Edited by: Liang Ji on Oct 22, 2010 8:35 PM

JTree no root node

how do you create a JTree with no root node?
i just want
Parent
--child
Parent
--child
--child

i think a tree must always have a root node....but I think what u can do is make that root node not visible...i've seen it done before.
good luck

How do i get to display the nodes under the root node in a JTree?

In my JTree there is a root node.This root node has 4 child nodes.Each child node in turn has nodes under it.What i need to do is just display the child nodes under the root node i.e., the four child nodes and keep these child nodes in a collapsed state.How do i go sbout this?

Please try this:
tree.expandRow(0);
SwingUtilities.invokeLater(new Runnable(){
    public void run(){
        tree.setRootVisible(false);
});If you want to show the RootHandles:
tree.setShowsRootHandles(true);If you want to keep nodes in collapsed state (not expandable):
        tel = new TreeWillExpandListener() {
            public void treeWillExpand(TreeExpansionEvent event) throws ExpandVetoException {
                throw new ExpandVetoException( event, "Don't want" );
            public void treeWillCollapse(TreeExpansionEvent event) throws ExpandVetoException {
        tree.addTreeWillExpandListener(tel);Some reading material:
http://java.sun.com/docs/books/tutorial/uiswing/components/tree.html
http://java.sun.com/docs/books/tutorial/uiswing/events/treewillexpandlistener.html
Edited by: Andre_Uhres on Nov 14, 2007 5:17 PM
Edited by: Andre_Uhres on Nov 14, 2007 5:33 PM
Edited by: Andre_Uhres on Nov 14, 2007 5:39 PM

Issue on deployment: Solution Deployment : Missing one or more of the following attributes from the root node in solution .wsp: assembly '', type ''

Hi,
I have the following issue when deploying:
Solution Deployment : Missing one or more of the following attributes from the root node in solution .wsp: assembly '', type ''
The solution is a farm solution (was never sandbox) and it deploys fine.
It was updated several times with success. We did not see this issue until recently when we had some other issue (unrelated) and looked at the logs. The solution is updated without problem and updates are available for the user. But we can see this error
in the logs at the update time.
Any idea what might cause this?
Pop Anisia

Hi，
This error is wide meaning, as it can come from differences between SP versions, variables types used, bad manifest file, WebConfiguration ...
You can try to redeploy the solution.
retracted the solution,removed all the previous ref, removed dll from GAC and folder from 14\features and reset the iis, deploying it again.
Here are some similar issue post, you can use as a reference:
https://social.technet.microsoft.com/Forums/office/en-US/72ac9a02-3a51-48b8-9e36-3b24a2d4da74/missing-one-or-more-of-the-following-attributes-from-the-root-node-in-solution-alertbdcwsp?forum=sharepointgeneralprevious
https://social.technet.microsoft.com/Forums/office/en-US/331af288-5ba6-48a7-9e9d-ac4e4bc8f8fa/missing-one-or-more-of-the-following-attributes-from-the-root-node-in-solution-xxxwsp-assembly-?forum=sharepointdevelopmentprevious
In additional, you can check the ULS log (C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\14\LOGS) to get the detailed information.
I hope this helpful.
Best Regards，
Lisa Chen
TechNet Community Support
Please remember to mark the replies as answers if they help, and unmark the answers if they provide no help. If you have feedback for TechNet Support, contact
[email protected]

XPath for root node in condition editor

Hi,
I have a HTTP to IDOC scenario. I have to accept any incoming document,(i will know only at runtime whether it is ORDERS or INVOICE or ASN etc) and post it to the respective receiver based on what is the name of the root node. But how do i specify this in the condition editor? if i give /* or name(/*) it does not work.Can anyone suggest a solution for this?
Thanks
Shakthi

Well I have one solution but don't konw if it is worth for you.
First create one mapping called pre_mapping in this mapping map all fields and the root node value to the target structure correspondingly . Now use BPM with simple receive & send steps. BPM should send the message back to XI.
Use the final mapping with this messge retuned from BPM.
Now use the x-path and select the field from source structre (which BPM has sent back to XI) which contains IDOC type. So in this case your sender system will be BPM.

Binding properties of a root node and using fx:include.

I posted a downloadable example of this here:
https://dl.dropboxusercontent.com/u/8788282/binding-test.zip
I've noticed some understandable, but less than perfect behaviour with the way FXML initialization is done when using fx:include. I find it's difficult to bind properties that belong to the root node of the included view without shooting yourself in the proverbial foot. Here is an example of what I mean:
sample.Main
package sample;
import javafx.application.Application;
import javafx.fxml.FXMLLoader;
import javafx.scene.Parent;
import javafx.scene.Scene;
import javafx.stage.Stage;
public class Main extends Application {
    @Override
    public void start(Stage primaryStage) throws Exception {
        Parent root = FXMLLoader.load(getClass().getResource("MainView.fxml"));
        primaryStage.setTitle("Hello World");
        primaryStage.setScene(new Scene(root, 300, 275));
        primaryStage.show();
    public static void main(String[] args) {
        launch(args);
sample.MainController
package sample;
import javafx.fxml.FXML;
public class MainController {
    @FXML
    void initialize() {
        System.out.println("MainController initialized.");
sample.MainView (FXML)
<?xml version="1.0" encoding="UTF-8"?>
<?import javafx.scene.control.Label?>
<?import javafx.scene.layout.*?>
<AnchorPane prefHeight="200.0" prefWidth="200.0"
            xmlns:fx="http://javafx.com/fxml/1"
            xmlns="http://javafx.com/javafx/2.2"
            fx:controller="sample.MainController">
    <children>
        <VBox prefHeight="200.0" prefWidth="200.0" AnchorPane.bottomAnchor="0.0"
              AnchorPane.leftAnchor="0.0" AnchorPane.rightAnchor="0.0"
              AnchorPane.topAnchor="0.0">
            <children>
                <Label text="Main"/>
                <StackPane prefHeight="150.0" prefWidth="200.0"/>
                <fx:include fx:id="sub" source="SubView.fxml" visible="false"/>
            </children>
        </VBox>
    </children>
</AnchorPane>
sample.SubController
package sample;
import javafx.beans.binding.Bindings;
import javafx.fxml.FXML;
import javafx.scene.control.Label;
import javafx.scene.layout.AnchorPane;
public class SubController {
    @FXML
    private AnchorPane anchorPane;
    @FXML
    private Label label;
    @FXML
    void initialize() {
        label.visibleProperty().bind(Bindings.createBooleanBinding(() -> true));
        /* When used as part of an fx:include, this controller's initialize()
         * block is called and the below binding is performed. After that, any
         * property values set via the containing view (MainView) are applied.
         * In this example, the MainView attempts to set the visible property
         * of this included view (fx:id="sub"). Since the visible property of
         * the root node (anchorPane) has already been bound, the error
         * "A bound value cannot be set." is given.
        anchorPane.visibleProperty().bind(Bindings.createBooleanBinding(() -> true));
        System.out.println("SubController initialized.");
sample.SubView (FXML)
<?xml version="1.0" encoding="UTF-8"?>
<?import javafx.scene.control.Label?>
<?import javafx.scene.layout.*?>
<AnchorPane id="AnchorPane" fx:id="anchorPane" maxHeight="-Infinity"
            maxWidth="-Infinity" minHeight="-Infinity" minWidth="-Infinity"
            prefHeight="400.0" prefWidth="600.0"
            xmlns:fx="http://javafx.com/fxml/1"
            xmlns="http://javafx.com/javafx/2.2"
            fx:controller="sample.SubController">
    <children>
        <VBox prefHeight="400.0" prefWidth="600.0" AnchorPane.bottomAnchor="0.0"
              AnchorPane.leftAnchor="0.0" AnchorPane.rightAnchor="0.0"
              AnchorPane.topAnchor="0.0">
            <children>
                <Label fx:id="label" text="sub view"/>
            </children>
        </VBox>
    </children>
</AnchorPane>
The comments in the initialize method of SubController explain what's happening. I found it a bit confusing until I figured out what was going on. Should FXMLLoader be checking to see if a property is already bound before trying to set it, at least for nodes declared via fx:include?

Hi Gaurave,
We need to show the report like this to some users, thats what the requirement is. Using the Posted nodes option does not help.
Thanks.

Lining up root node and child nodes in JTree

I have a JTree that has a root node and n child nodes. There are no sub-levels - it is structured just like AOL instant messenger. What I want to do is have the child node icons line up directly under the root nodes text. For example (if you can read this), where "-" denotes the icon:
- root
- child
- child
Currently it is something like this:
- root
- child
- child
I have been messing with the setLeftChildIndent( int ) and setRightChildIndent( int ), but they are not doing much...they seem to not want to only move the leaf nodes but all of the nodes, so its not doing exactly what I want.
Any ideas? In the meantime I'll be looking more into how exactly those indent mutators work.
Thanks!

What you want is to do a setRootVisible(false) on the JTree.
All your child nodes are then your "root level" folders.
tree.setRootVisible(true):
+root
+--child1
+--child2
+--child3
+----child3a
+----child3btree.setRootVisible(false):
+child1
+child2
+child3
+--child3a
+--child3b

How to make all nodes in a detailed navigation tree open automatically??

Dear All,
I have added some iViews to two folders and add these two folders to a workset "Time" and then add "Time" to the role of Employee portal user.
How to make all nodes expanded automatically when this workset is clicked in EP??
thanks,
Zita

Not surprising...it does not work even if you follow the exact way...
Role ->
         Workset 1
                      -> Page 1
                      -> Workset 2
                                       -> Page 2
                      -> Workset 3
                                       -> Page 3
When the user clicks on Role which is the Entry Point, I want the user to see Page1 (works alright) and want the tree node Workset 2 open (doesn't work)...I want tree node Workset 3 closed (which is what happens...)
The thing is Workset 2 has to be open...
This is what I've done...I've made the Initial State of Navigation Panel set to "Open"...
What else is to be done????
Thanks a lot.
JP

Ldif2db command fails to import data and deletes the root node

ldif2db command fails to import data into LDAP.
The command used was
ldif2db -n userRoot -s "dc=example,dc=com" -i test.ldif
The test.ldif conains the nodes under dc=example,dc-com
eg: ou=test,dc=example,dc=com
But on executing the command the root node "dc=example,dc=com" itself got deleted. The console output was like "Skipping entry uid=test001,ou=test,dc=example,dc=com" for all the entries present in ldif.
What might be the reason for this ? Any clues ?
The reason y i am trying to do this ldif2db is to preserve the createtimestamp and modifytimestamp while migrating data from one Directory Server to another. Any other ways of doing it ?

ldif2db is the right command to migrate data and preserve those attributes like createtimestamp and modifytimestamp.
However, when this command is used, it will first remove everthing before it load whatever you want. So you need to be very careful. I got this terrible problem as well.
In my experience, if you use this command, don't use "-s". You can just use:
ldif2db -n suffixName -i test.ldif
If you only have one suffix (database), then you can use "-n userRoot".
Also, if you migrate your data from server A to server B, you'd better dump the data using db2ldif -n userRoot -a test.ldif from server A. Then load it into server B using ldif2db -n userRoot -i test.ldif.

How to disable selection of root node in JTree

Hi all! Thanks for taking a minute to read my post!
I am writing a really basic JTree for showing a list of items.
Here is some of the code:
/** Create a basic tree **/
DefaultMutableTreeNode rootNode = new DefaultMutableTreeNode("Title");
DefaultTreeModel treeModel = new DefaultTreeModel(rootNode);
JTree tree = new JTree(treeModel);
/** Method to return the string of the current highlighted selection **/
public String getSelectionString()
DefaultMutableTreeNode node =
tree.getSelectionPath().getLastPathComponent();
return (String)node.getUserObject();
I would like to disable selection of the root node of my JTree.
Thus, if I make a call to getSelectionString() above, it would return null instead of the string that represents the root label.
I have read the following forum on disabling various TreePaths and TreeNodes in a JTree:
http://forum.java.sun.com/thread.jsp?forum=57&thread=224691
This forum suggests implementing the TreeSelectionListener interface and the TreeSelectionModel class and over-riding the addSelectedPath() methods. I tried this suggestion, and I was able to enable and disable the different children of the Jtree, but the root of the JTree would not disable.
I suppose that I could just simply remove the visibility of the root node, but I really want to avoid that option if possible.
Wait --- let me be clear ---- I want to disable the selection of the root node only - still allowing selection of all its children.
Any suggestions?
Am I missing something really simple here?
Did I explain my problem clearly?
Thanks in advance!
jewels

simply try this..
in the
public void valueChanged(javax.swing.event.TreeSelectionEvent event);
method of TreeSelectionListener impelentation get the
TreePath tp = event.getPath();
from TreePath get the component and then remove the selection from the treePath if it is the node u were checking/root node in this case
tree.getSelectionModel().removeSelectionPath(tp);
Try out....

What to make root node?

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