Where condition in select query

Question

my requirement is this. I want to fetch some records
from DB table. The field objnr has 12 characters.
i will supply a substring of this field. the substring
starts at the 3rd location of field.
SELECT objnr FROM cosp INTO TABLE gt_itab
              WHERE objnr like srch_str.
how to do this? could u give me a possible solution?

Answer 1

Then you're going to have to go at it this way
TABLES: cosp.
DATA:
  BEGIN OF gt_itab OCCURS 0,
    objnr      LIKE cosp-objnr,
  END OF gt_itab.
DATA:
  wk_objnr      LIKE cosp-objnr,
  srch_str(22) VALUE '1000',
  ss_len       TYPE i.
START-OF-SELECTION.
  ss_len = strlen( srch_str ).
  SELECT objnr FROM cosp INTO gt_itab-objnr.
    CHECK gt_itab-objnr+2(ss_len) = srch_str.
    APPEND gt_itab.
  ENDSELECT.
Or this way.
TABLES: cosp.
DATA:
  BEGIN OF gt_itab OCCURS 0,
    objnr      LIKE cosp-objnr,
  END OF gt_itab.
DATA:
  cntlarea(22)  TYPE c  VALUE '1000',
  wk_objnr      LIKE cosp-objnr,
  srch_str(50),
  ss_len       TYPE i.
START-OF-SELECTION.
  CONCATENATE '%' cntlarea '%' INTO srch_str.
  ss_len = strlen( cntlarea ).
  SELECT objnr FROM cosp INTO gt_itab-objnr
    WHERE objnr LIKE srch_str.
    CHECK gt_itab-objnr+2(ss_len) = cntlarea.
    APPEND gt_itab.
  ENDSELECT.
Edited by: Paul Chapman on May 29, 2008 8:33 AM