Why is there no error ????

Hi,
This is from my sourcecode:
public aj_List mergeSort (aj_List l){
     int m=l.size()/2;
     if(l.size()>2){
     aj_List l1=divide(l,0,m-1);
     aj_List l2=divide(l,m,l.size()-1);
     mergeSort(l1);
     mergeSort(l2);
     }else{ ...........................
The function has the return type "aj_List", but I can call the funktion without doing this:
a1,a2 are from type aj_List:
a1 = mergeSort(l1);
a2 = mergeSort(l2);
this works too!
Normally I get a error when trying to compile this. But there not. I do not why both implementations are allowed. Should be not, or ?

Hard to understand the question but I think you want to know why both of the following are legal
mergeSort(l1);
a1 = mergeSort(l1);
Basically because java allows the return value to be thrown away. It still exists for a short time, but you just don't use it.

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Please do not post the same question more than once!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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