Why wont my probes read outside of the For Loop?

The problem seems that, for some reason the when I try to line a wait time function outside of a while loop after I have used a boolean function, (subtract). What I am trying to do is to reset the time axis on the graph because it wants to spiral into millions of numbers and to keep counting. I want to just take samples of like 100-1000 milliseconds and graph my data pixels against it. I have tried a while loop, that seems to work sometimes. The thing is really weird, it seems as if it wants to work sometimes and in some places but not in others. I have attached some expamples and the VI I am trying to get to work. Notice the problem places are in Red.
Thanks alot guys, (and girls), for any help that y
ou can give me.
Brian
Attachments:
example_for_analysis_by_engineers.vi ‏40 KB
Brians_Display_Image_not_U8_but_U16.vi ‏102 KB

Could you include the other VIs as well (save with options -> development distribution)? It's not possible to run your VI without the sub-VIs.
I haven't fully understood what you are trying to accomplish, but looking at what I've got there are two things that come to mind:
If you are generating data inside the loop, and only want to sample some of it and send that data to a graph then you must make sure that the data flow works. A loop will not output the data you wire out of it until the loop has terminated.
Thre little grey dot you mention in the code is a "coercion dot", it means that the data you wire into the function/VI does not have the same type as the function expects. LV will use the polymorphism functionality to coerce the data to the correct t
ype, an operation that is best avoided, at least if it's a lot of data involved (requires extra memory to do the coercion) or if it may cause an incorrect value to be passed. In your case the image cluster you have wired to the IMAQ function is not based on the type definition the function is using, just replace the cluster with the type defined one you'll get rid of the dot.
MTO

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Cheers,
I am not 100% sure what your problem is but how about writing the red value into the local variable and reading it outside of the loop? Or enqueue the value into the queue and dequeue it in the other loop (Producer/Consumer Structure (Data))?
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Print a value outside the for loop.

for (int j=0; j< 4; j++)
 String name = "AAAA";
 String add="BBBB";
 LogManager.logStatus(" NAMe.. ............ "+name);
LogManager.logStatus(" Name ;;;;;;;;;;; "+name);I want to how to print the "Name ;;;;;;;;;;; ". after the for loop.

If i declared as
private static String name;
then the output is coming null in 2nd log statement.
But i need the the print of 2nd log should be same as log in 1st .

Why Isn't the for loop executing?

here's the code,the for loop isn't executing,can anyone trouble shoot?
import acm.program.ConsoleProgram;
public class AddIntegerList extends ConsoleProgram {
public void run(){
 for(int c=0;c<5;c++);{
 println("This is a programe to divide 2 numbers");
double i = readDouble("enter num1: ");
double x = readDouble("enter num2: ");
double ans = i/x;
println("The answer to your division Is "+ans+ "");
 } by the way,this Is the first piece of java code that I have written. :D
Edited by: Parastar on Oct 21, 2009 4:20 AM

I dont think there should be a semicolon at the end of this
for(int c=0;c<5;c++); Remove it and try running the program.
Edited by: A.J.Bharanidharan on Oct 21, 2009 4:53 PM

The demand of my application is that i can not replace for loop with a while loop.because i need fixed number of iterations and as far as i know fixed iterations could be only with possible with the for loop.

the demand of my application is that i can not replace for loop with a while loop.because i need fixed number of iterations and as far as i know fixed iterations could be only with possible with the for loop.
your recommended second option that i could add true/false case.
this true/false case must be inside the for loop or outside the for loop?if this case is inside the for
loop, how can i send stop command from outer while
loop?
more over do you have any example for this please?
thanks"

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Ben gave you step-by-step instructions in response to your previous question. Look here for Ben's response.
Ben's response looks pretty good and detailed to me. It certa
inly deserved better than a 1-star rating.

How to code a parallel 'for loop' and 'while loop' where the while loop cannot terminate until the for loop has finished?? (queues also present)

I've attached a sample VI that I just cannot figure out how to get working the way that I want. I've labeled the some sections with black-on-yellow text boxes for clarity during the description that follows in the next few sentences. Here's what I want:
1) overall -- i'm intend for this to be a subVI that will do data acquisition and write the data to a file. I want it to use a producer/consumer approach. The producer construct is the 'parallel for loop' that runs an exact number of times depending on user input (which will come from the mainVI that is not included). For now I've wired a 1-D array w/ 2 elements as a test case. During the producer loop, the data is acquired and put into a queue to be delt with in the consumer loop (for now, i just add a random number to the queue).
2) the consumer construct is the 'parallel while loop'. It will dequeue elements and write them to a file. I want this to keep running continuously and parallel until two conditions are met.
      i. the for loop has finished execution
      ii. the queue is empty.
   when the conditions are met, the while loop will exit, close the queue, and the subVI will finish. (and return stuff to mainVI that i can deal with on my own)
Here's the problems.
1) in the "parallel for loop" I have a flat sequence structure.. I haven't had time to incorporate some data dependency into these two sequential sections, but basically, I just care that the "inner while loop" condition is met before the data is collected and queued. I think I can do this on my own, but if you have suggestions, I'm interested.
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3) for now, I've placed a simple stop button in the 'parallel while loop', but I must be missing something fundamental here, because the stop button is totally unresponsive. i.e. - when I press it, it stays depressed, and nothing happens.
suggestions are totally welcome!
thanks,
-Z
Attachments:
daq01v1.vi ‏59 KB

I'd actually like to add a little more, since I thought about it a bit and I'm still not quite certain I understand the sequence of events...
altenbach wrote:
zskillz wrote:
So i read a bit more about the 'dequeue element' function, and as I understand it, since there is no timeout wired to the dequeue element function, it will wait forever, thus the race condition I suggested above can never happen!
Yes, you got it!
As I've thought about it a bit more, there's a few things that surprise me... first, the reason the 'dequeue element while loop' errors is not because there's nothing in the queue, it's becaues the queue has been released and it's trying to access that released queue... However the problem I have is this --- Even though there's no timeout wired to the dequeue element, I still would think that the while loop that contains it would continue to run at whatever pace it wanted -- and as i said before.. most of the time, it would find that there is nothing to dequeue, but once in a while, something is there. however, it seems that this loop only runs when something has been enqueued. the reason I say this is illustrated in the next code sample MODv2 that's attached below. I've added a stop button to the "queue size while loop" so the program runs until that is pressed. I've also added a simple conditional in the "dequeue while loop" that generates a random number if it a button is pressed... but this button is totally non-responsive... which means to me that the "dequeue while loop" isn't actually continuously running, but only when an element is added to the queue. this still seems almost like the 'dequeue while loop" waits for a notifier from the queue telling it to run. can you explain this to me? because it is different from what I expect to be happening.
rasputin wrote:
I tried to open your VIs but it doesn't work. LV
is launched, the dialog box (new, open, configure...) opens and then...
nothing. Not even an error message. I guess it isn't a problem of LV
version or a dialog box would appear saying this. Could you, please,
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Thanks,
Hi Rasputin, I'm using LV8. I assume that was your problem, but who knows. I've attached a pic of of altenbach's solution since it's what I needed.
thanks
-Z
Message Edited by zskillz on 10-20-2006 11:49 AM
Attachments:
daq01v1MODv2.vi ‏63 KB
daq01v1MODpic.JPG ‏116 KB

Need help with the for loop

Hello,
I hope someone can point me in the right direction for my next assignment. I am very new at Java programming. For my next assignment for class I will need expand my previous program which was a mortgage calculator. The first assignment we wrote a program to show the monthly payments of a $200,000 loan at 5.75% for 30 years. Now we have to output all 360 monthly payments with pauses in between so it doesnt scoll off the page. The calculation that we use is:
month_payments = (principle * monthlyinterest) / (1-Math.pow(1 + monthlyinterest, - months));
My question is how do I get the correct calculation outputed 360 times. I would like to use the "for loop" to do this. Also what is the correct way to do the pause command? I do not want someone to write the code, I just want some help to where I need to start off, I want to learn this on my own.
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for (int i ; i < 10 ; i ++ ) { System.out.println("Come sail away"); }
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Less or less than equal in the for loop condition

Hi,
What do you prefer, what is more common, which one is more easily readable, less or less than equal in the for loop condition?
for (int i = 0; i < arr.lenght; i++){..}
//or
for (int i = 0; i <= arr.lenght - 1 ; i++){..}I know this is basic programming and nothing to do with Java, so if this forum is not for this purpose, could you please suggest a general programming forum?
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Thanks in advance,
lemonboston

lemonboston wrote:
Hi,
What do you preferPersonal preference, which is useless to you
, what is more common,Based on years of reading open source code, the first
which one is more easily readable, less or less than equal in the for loop condition?Personal opinion, which is useless to you
I would really appreciate it as I have many general questions :)If you don't want to think about it yourself (which you should be doing in stead of asking general questions), simply attack it lazily. Both examples achieve exactly the same, but the first one is less to type and to read.

[svn:bz-trunk] 21048: moving the locking of MessageService. subscribeLock one level up in the for loop.

Revision: 21048
Revision: 21048
Author:   [email protected]
Date:     2011-04-08 06:47:21 -0700 (Fri, 08 Apr 2011)
Log Message:
moving the locking of MessageService.subscribeLock one level up in the for loop.
in case of multiple subscribers, we only lock once
checkintests pass
Modified Paths:
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How to control the looping time of the for loop in 10 microseconds in labview?

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The speed of the "for loop iteration"

Hi all:
I have written a short mini program just to test out the speed of a "for loop iteration"
package generator;
* Title: 
* Description: 
* Copyright: Copyright (c) 2004
* Company: 
* @author not attributable
* @version 1.0
private static long tmp = 0;
public static int count=0;
public synchronized long getValue(){
 long value = 0;
 value = 10 * System.currentTimeMillis();
 if(value == tmp){
 value++;
 count++;
 tmp = value;
 return value;
public static void main(String[] args) {
 for (int i=0;i<1000;i++){
 getValue();
 System.out.println("count is " + count);
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Also, anybody know exactly how System.currentTimeMillis works? For example, how does it get the current time from the OS, etc. let me know.
Again, Many many thanks...

Hi all:
I have written a short mini program just to test out the speed of a "for loop iteration"You will find the overhead of the getValue() call, the increments and most importantly the System.currentTimeMillis() is what you are timing.
 public static void main(String args[]) {
 int ITER = 1000000000;
 long start = System.currentTimeMillis();
 for(int i=0;i<ITER;i++);
 long end = System.currentTimeMillis();
 System.out.println("Iterations per sec="+ITER*1000L/(end - start));
 }Prints the following Iterations per sec=576368876Running on a 1.8 GHz Intel/Windows2000

Why wont my probes read outside of the For Loop?

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