Why would this query return an error that mentions an entirely different database being offline?
Trying to get a list of fragmented indexes based on a database name. However,
SELECT COUNT(*) AS TableFragOver80PctCount
FROM sys.dm_db_index_physical_stats (null, null, null, null, null )as ts
INNER JOIN sys.tables t on t.[object_id] = ts.[object_id]
INNER JOIN sys.indexes i on i.[object_id] = ts.[object_id]
INNER JOIN sys.databases db ON ts.database_id = db.database_id
WHERE db.name = 'MY DB NAME'
AND ts.avg_fragmentation_in_percent > 80.00
The error I get back
Msg 942, Level 14, State 4, Line 1
Database 'VERY DIFFERENT DB' cannot be opened because it is offline.
I know there is a database on this server that is offline, actually 2 or 3, but not the one Im trying to get information about. What could cause the above query to have trouble getting index info that is caused by an entirely different database being
offline?
FROM sys.dm_db_index_physical_stats (null, null, null, null, null )as ts
See MSDN sys.dm_db_index_physical_stats
; the first parameter is the database id; if you pass NULL as here, then all databases will be scanned, also your offline one.
Olaf Helper
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Similar Messages
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Why would this query return three rows?
select pc.tour_id,
pcp.project_id,
pc.contr_num,
pc.current_contr_status,
pc.current_contr_substat
from p_contract_lead pcl
left join p_contract pc on pc.contr_num = '2385108'--pcl.contr_num
left join p_contract_purchase pcp on pcp.contr_num ='2385108'-- pc.contr_num
where pcl.lead_id = '179772978'
in this query it returns me 3 rows,
in p_contract there is only 1 row with contr_num = '2385108'
and p_contract_purchase also has 1 row with contr_num = '2385108'
in p_contract_lead the lead_id = '179772978' has 3 records but they dont have contr_num=2385108
im just wondering why is giving me these results?
shouldnt it give me zero results since the pcl.lead_id = '179772978' does not equal contr_num=2385108?
i have version 12.0.0.6, maybe is the way i dont understand the left join works, or could be something else?
sorry for not creating a example , because i really dont know how.
thanks for your helpHi,
FROM l
LEFT OUTER JOIN r ON ...
means include all rows from l whether or not they have a match in r.
If you have 3 rows in l, then there will always be at least 3 rows in the result set, regardless of what's in r (if anything).
natpidgeon wrote:
in p_contract there is only 1 row with contr_num = '2385108'
and p_contract_purchase also has 1 row with contr_num = '2385108'
in p_contract_lead the lead_id = '179772978' has 3 records but they dont have contr_num=2385108
im just wondering why is giving me these results?
shouldnt it give me zero results since the pcl.lead_id = '179772978' does not equal contr_num=2385108? ...
What you just described is basically how an inner join works.
In this case, it doesn't matter in the least whether pcl.lead_id equals anything in pc or not. The join condition between pcl and pc is
pc.contr_num = '2385108'
That is, a row from pcl will match a row in pc if (and only if) pc.contr_num='2385108'. The join condition makes no mention of pcl.lead_id (or any other column in pcl, for that matter), so what's in pcl.lead_id (or any other column of pcl) doesn't play any role in deciding if rows match.
sorry for not creating a example , because i really dont know how.
Post CREATE TABLE statements for all 3 tables. You only need to include the columns that are used in this query.
Post 1 INSERT statement for p_contract, with contr_num = '2385108'. It wouldn't hurt to post an additional row that you know shouldn't appear in the results.
Post 1 INSERT statement for p_contract_purchase, also with contr_num = '2385108'. Again, it wouldn't hurt to post a 2nd row that does not meet the join condition.
Post 3 INSERT statements p_contract_lead with lead_id = '179772978' , but NOT contr_num='2385108'. Again, having another row with a different lead_id would make a better example. -
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check out this query:-
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1
2 -------------------------------------------------------------------------------------
3 | Id | Operation | Name | Rows | Bytes | Cost (%CPU)|
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Please help.
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select
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level as col1
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