Wildcards in type declarations or only methods?

Question

Can you declare wildcards in type declarations such as:
public class ListManager<List<?>> {
}When I try this, I get the following compiler errror:
C:\dev\hcj\tiger\src>c:\j2sdk1.5.0\bin\javac -source 1.5 oreilly/hcj/tiger/*.java
oreilly/hcj/tiger/ListManager.java:21: > expected
public class ListManager<List<?>> {
                             ^
oreilly/hcj/tiger/ListManager.java:31: '{' expected
^
2 errorsWhat am I doing wrong [if anything]?
TIA
-- Kraythe

Answer 1

public class ListManager<List<?>> {
}When I try this, I get the following compiler errror:Hmm .. I was thinking about this. .. What i was trying to declare was a class that would use as a parameter any declaration of a List. So what I want is a class that will take List<Integer> and List<String> and so on. So the result would be to use it like this:
public void someMehtod() {
    ListManager<List<String>> strListMger = ...
    ListManager<List<Integer>> strListMger = ...
}So if not with the wildcard, how is this accoplished (if it can be accomplished at all).
I would also like to do something like:
public class ListManager<Type extends List<?>> {
}In this manner I would at least have access to the type. Except the extends is a misnomer since i want type to be any List<> type.