Working with LIKE operator

hi,
i have a small confusion in escape clause.
create table products (product_name varchar2(100));
begin
insert into products (product_name) values('A%_WQ123');
insert into products (product_name) values('A%BWQ123');
insert into products (product_name) values('AB_WQ123');
commit;
end;
select * from products where product_name like '%\%_WQ12%' escape '\';
output:
product_name
A%_WQ123
A%BWQ123
can you please tell how this is working, in the above statment the ESCAPE will escape only % or both %and_
thanks,

Are you after this?
select * from products where product_name like '%\%\_WQ12%' escape '\';
Cheers,
Manik.

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DATA: l_doctext type c value ''''.
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Something like this ->
satyaki>select *
2     from v$version;
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - Prod
PL/SQL Release 10.2.0.3.0 - Production
CORE    10.2.0.3.0      Production
TNS for 32-bit Windows: Version 10.2.0.3.0 - Production
NLSRTL Version 10.2.0.3.0 - Production
Elapsed: 00:00:00.26
satyaki>
satyaki>
satyaki>select *
2 from emp
3 where upper(ename) like nvl('%'||upper('&str')||'%',upper(ename));
Enter value for str:
old   3: where upper(ename) like nvl('%'||upper('&str')||'%',upper(ename))
new   3: where upper(ename) like nvl('%'||upper('')||'%',upper(ename))
     EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
      9999 SATYAKI    SLS             7698 02-NOV-08      55000       3455         10
      7777 SOURAV     SLS                  14-SEP-08      45000       3400         10
      7521 WARD       SALESMAN        7698 22-FEB-81       1250        500         30
      7566 JONES      MANAGER         7839 02-APR-81       2975                    20
      7654 MARTIN     SALESMAN        7698 28-SEP-81       1250       1400         30
      7698 BLAKE      MANAGER         7839 01-MAY-81       2850                    30
      7782 CLARK      MANAGER         7839 09-JUN-81       4450                    10
      7788 SCOTT      ANALYST         7566 19-APR-87       3000                    20
      7839 KING       PRESIDENT            17-NOV-81       7000                    10
      7844 TURNER     SALESMAN        7698 08-SEP-81       1500          0         30
      7876 ADAMS      CLERK           7788 23-MAY-87       1100                    20
     EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
      7900 JAMES      CLERK           7698 03-DEC-81        950                    30
      7902 FORD       ANALYST         7566 03-DEC-81       3000                    20
13 rows selected.
Elapsed: 00:00:00.02
satyaki>
satyaki>/
Enter value for str: sa
old   3: where upper(ename) like nvl('%'||upper('&str')||'%',upper(ename))
new   3: where upper(ename) like nvl('%'||upper('sa')||'%',upper(ename))
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      9999 SATYAKI    SLS             7698 02-NOV-08      55000       3455         10
Elapsed: 00:00:00.08Regards.
Satyaki De.

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create table mytestc(x varchar2(10));
insert into mytestc values ('18t');
insert into mytestc values ('4t;8t');
commit;
How do I give a select so I can select all the rows where 8t is present
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gives 18t in result set

Hi,
user650888 wrote:
create table mytestc(x varchar2(10));
insert into mytestc values ('18t');
insert into mytestc values ('4t;8t');
commit;Thanks for posting the CREATE TABLE and INSERT statements; that's very helpful.
Don't forget to post the results you want from that data, an explanation of how you get those results from that data, and the version of Oracle you're using.
How do I give a select so I can select all the rows where 8t is present
select * from mytestc where x like '%8t%'
gives 18t in result setThat's right; '8t' is present in '18t'. That's what you said you wanted. If you would post your desired results and an explanation, then people could help you more.
Did you mean to say that '8t' has to be a complete item in the ;-delimited list, not a subset of some other string, like '18t' or '8td'?
In other words, do you mean that you only want to count '8t' as a match when the character before it is a ';' (or when it is at the beginning of x) qnd the character immediately after it is also ';' (or it comes at the end of x)?
If so:
WHERE     INSTR ( ';' || x || ';'
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WHERE     ';' || x || ';'     LIKE '%;8t;%'This is called the "mother is in chemotherapy" problem.
Edited by: Frank Kulash on May 24, 2011 4:39 PM

Working with LIKE operator

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