Xml attribute value

Question

I'm having trouble getting a specific attribute value when
parsing the xml tree. I need to get the chidNode that matches
my attribute
request. Is there an easy way to say if the attribute value =
1234 then return
its nodevalue
myXML = new XML();
myXML.load("sample.xml");
myXML.ignoreWhite = true;
myXML.onLoad=feeds;
function feeds(){
myroot = myXML.firstChild;
people = myroot.firstChild;
students = people.childNodes;
if(students.attributes.id == '1234')
trace('yes record found')
the xml at the students level lookss like this
<student id="2214">
<name></name>
</student>
<student id="1234">
<name></name>
</student>
<student id="4567">
<name></name>
</student>
thanks

Answer 1

Well, assuming there is an associated end tag (aka </TEST>) somewhere in your XML, then the XML fragment you show is well-formed XML.
If by "XML functions", you mean something like XMLElement/XMLForest/XMLAgg, then you can be safe to know that it generates well-formed XML.
What is this "xml editor" that you mention but don't name. It sounds as if the issue lies with that tool, based off what little you have provided.
The more details you provide, the better answer you get.