XML document TO stylesheet

Hi,
Here is my question. I have a XML document. I just want to
convert it into Excel. Do you have any tools for that. If not is
there any method to convert that.
Thanks in advance.
Chan...
null

Jimson K John (guest) wrote:
: Hello,
: : An XSL processor is packaged with the oracle xml parser v2
: : (see oraxsl). You can run this as a command line utility ...
: ^^^^^^
: Can you pls provide the URI for oraxsl. I could not locate
it
: in the documentation set.
: Thanks & Regards,
: Jimson
: Oracle XML Team wrote:
: : I don't know of any such tools, but then I am not much of
: an
: : Excel user. If you fail finding the tool you are looking
for,
: : consider writing a XSL stylesheet to basically flaten the
XML
: : document into space, or tab delimited data columns, e.g.:
: : xml doc:
: : <spreadsheet>
: : <row>
: : <col1>john</col1>
: : <col2>smith</col2>
: : </row>
: : <row>
: : <col1>jim</col1>
: : <col2>hawk</col2>
: : </row>
: : </spreadsheet>
: : resulting text document:
: : john smith
: : jim hawk
: : This I am pretty sure you can import into Excel.
: : ps.: An XSL processor is packaged with the oracle xml
parser
: v2
: : (see oraxsl). You can run this as a command line utility
: which
: : takes as arguments an XSL stylesheet and your XML doc. For
: more
: : info on XSL look at www.w3c.org.
: : Chan (guest) wrote:
: : : Hi,
: : : Here is my question. I have a XML document. I just want
to
: : : convert it into Excel. Do you have any tools for that. If
: not
: : is
: : : there any method to convert that.
: : : Thanks in advance.
: : : Chan...
: : Oracle Technology Network
: : http://technet.oracle.com
There is not a URI to its docs. You can find it and the
associated readme.html in the /bin directory after installing
2.0.2.4.
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
null

Similar Messages

Use 1 stylesheet to translate 2 xml documents(raw data)into one result xml

I have one java application which can generate two xml documents (raw data), now i want to have one result xml which contains contents of these two xml documents(raw data) by using one stylesheet. is it possible?
how to match template in the stylesheet?
how to let the stylesheet know that it should read second raw xml?

Yes it is possible.
You didn't say whether you want to do this by invoking the transformation from a Java program, or with a stand-alone transformer, and which one.
I've done an application where I had a main XML file and a secondary XML file. I invoked the transformation from Java, and passed a parameter to the stylesteet. It winds up looking like a variable ($parm for example).
Here is the declaration of the param in the stylesheet.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="list" />Next, I use the document function to read the file and produce a result tree (like a DOM object, in a sense).
<xsl:variable name="phonemes"
select="document($list)" />Then, you can use code like the following to look for content in the secondary file:
<xsl:if test="$phonemes/phonemes/allsounds[phoneme=$sound]" >This was complex, but it works.
Another approach would be to have a small XML file with the names of the
two XML files you want to process. You could do a for-each to process each of the tags in this little file, use the document function to read in the file and copy th eoutput to where you need it.
So, in that case, you would be processsing 3 files rather than 2. If you are invoking from Java, the third file could be coded in a String rather than having to physically write it out.
You've got a few ideas to consider.
Dave Patterson

Parse and output XML document while preserving attribute order

QUESTION: How can I take in an element with attributes from an XML and output the same element and attributes while preserving the order of those attributes?
The following code will parse and XML document and generate (practically) unchanged output. However, all attributes are ordered a-z
Example: The following element
<work_item_type work_item_db_site="0000000000000000" work_item_db_id="0" work_item_type_code="3" user_tag_ident="Step" name="Work Step" gmt_last_updated="2008-12-31T18:00:00.000000000" last_upd_db_site="0000000000000000" last_upd_db_id="0" rstat_type_code="1">
</work_item_type>is output as:
<work_item_type gmt_last_updated="2008-12-31T18:00:00.000000000" last_upd_db_id="0" last_upd_db_site="0000000000000000" name="Work Step" rstat_type_code="1" user_tag_ident="Step" work_item_db_id="0" work_item_db_site="0000000000000000" work_item_type_code="3">
</work_item_type>As you may notice, there is no difference in these besides order of the attributes!
I am convened that the problem is not in the stylesheet.xslt but if you are not then it is posted bellow.
Please, someone help me out with this! I have a feeling the solution is simple
The following take the XML from source.xml and outputs it to DEST_filename with attributes in a-z order
Code:
private void OutputFile(String DEST_filename, String style_filename){
     //StreamSource stylesheet = new StreamSource(style_filename);
     try{
          File dest_file = new File(DEST_filename);
          if(!dest_file.exists())
              dest_file.createNewFile();
          TransformerFactory tranFactory = TransformerFactory.newInstance();
          Transformer aTransformer = tranFactory.newTransformer();
          aTransformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
          Source src = new DOMSource("source.xml");
          Result dest = new StreamResult(dest_file);
          aTransformer.transform(src, dest);
          System.out.println("Finished");
     catch(Exception e){
          System.err.print(e);
          System.exit(-1);
    }

You can't. The reason is, the XML Recommendation explicitly says the order of attributes is not significant. Therefore conforming XML serializers won't treat it as if it were significant.
If you have an environment where you think that the order of attributes is significant, your first step should be to reconsider. Possibly it isn't really significant and you are over-reaching in some way. Or possibly someone writing requirements is ignorant of this fact and the requirement can be discarded.
Or possibly your output is being given to somebody else who has a defective parser which expects the attributes to be in a particular order. You could quote the XML Recommendation to those people but often XML bozos are resistant to change. If you're stuck writing for that parser then you'll have to apply some non-XML processing to your output to fix it up on their behalf.

Is there a way to modify the style sheet so that it transforms an XML document with empty tags as tag / ?

I have extracted some code from codeproject to
reindent an XML document. Does anyone know how I can modify the stylesheet to make it so that the transform of an XML file will result in empty tags showing up as <tag /> instead of <tag></tag>?
// http://www.codeproject.com/Articles/43309/How-to-create-a-simple-XML-file-using-MSXML-in-C
MSXML2::IXMLDOMDocumentPtr FormatDOMDocument(MSXML2::IXMLDOMDocumentPtr pDoc)
LPCSTR const static szStyleSheet =
R"!(<?xml version="1.0" encoding="utf-8"?>)!"
R"!(<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">)!"
R"!( <xsl:output method="xml" indent="yes"/>)!"
R"!( <xsl:template match="@* | node()">)!"
R"!( <xsl:copy>)!"
R"!( <xsl:apply-templates select="@* | node()"/>)!"
R"!( </xsl:copy>)!"
R"!( </xsl:template>)!"
R"!(</xsl:stylesheet>)!";
MSXML2::IXMLDOMDocumentPtr pXmlStyleSheet;
pXmlStyleSheet.CreateInstance(__uuidof(MSXML2::DOMDocument60));
pXmlStyleSheet->loadXML(szStyleSheet);
MSXML2::IXMLDOMDocumentPtr pXmlFormattedDoc;
pXmlFormattedDoc.CreateInstance(__uuidof(MSXML2::DOMDocument60));
CComPtr<IDispatch> pDispatch;
HRESULT hr = pXmlFormattedDoc->QueryInterface(IID_IDispatch, (void**)&pDispatch);
if (SUCCEEDED(hr))
_variant_t vtOutObject;
vtOutObject.vt = VT_DISPATCH;
vtOutObject.pdispVal = pDispatch;
vtOutObject.pdispVal->AddRef();
hr = pDoc->transformNodeToObject(pXmlStyleSheet, vtOutObject);
//By default it is writing the encoding = UTF-16. Let us change the encoding to UTF-8
// <?xml version="1.0" encoding="UTF-8"?>
MSXML2::IXMLDOMNodePtr pXMLFirstChild = pXmlFormattedDoc->GetfirstChild();
// A map of the a attributes (vesrsion, encoding) values (1.0, UTF-8) pair
MSXML2::IXMLDOMNamedNodeMapPtr pXMLAttributeMap = pXMLFirstChild->Getattributes();
MSXML2::IXMLDOMNodePtr pXMLEncodNode = pXMLAttributeMap->getNamedItem(_T("encoding"));
pXMLEncodNode->PutnodeValue(_T("UTF-8")); //encoding = UTF-8
return pXmlFormattedDoc;
Or, if there is some other method for reindenting a MSXML2::IXMLDOMDocumentPtr object where I can specify how I want empty tags to be stored, that would be great too. However, I don't want it to lose its status of an MSXML2::IXMLDOMDocumentPtr object.
I.e. I would like to still perform operations on the result as if it was still an MSXML2::IXMLDOMDocumentPtr object.
Thanks,
A
Adrian

If anyone is interested, I got an answer on StackOverflow
here.
Adrian

Embedding XSL in XML document

Hi
I am new to this particular forum. I had some query regarding embedding XSL .
Can we embedd the XSL stylesheet in the XML document itself.
I searched this forum and got some similar queries but the output isn't working. Can anyone put a working example.
I have got the following XSL stylesheet:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<body>
<table border="1" width="100%" cellpadding="1">
<tr bgcolor="#FFFF99">
<th style="font-family:arial unicode ms;font-size:100%" align="center">Serial number </th>
<th style="font-family:arial unicode ms;font-size:100%" align="center">Site number </th>
</tr>
<xsl:for-each select="Master/RECORD">
<xsl:if test="SR_NO > 0">
<tr>
<td style="font-family:arial unicode ms;font-size:80%" align="right"><xsl:value-of select="SR_NO"/></td>
<td style="font-family:arial unicode ms;font-size:80%" align="right"><xsl:value-of select="ACR_SNO"/></td>
</tr>
</xsl:if>
</xsl:for-each>
</table>
</body>
</xsl:template>
</xsl:stylesheet>
The XML document is as below:
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="archivingmaster.xsl"?>
<Master>
<RECORD>
<SR_NO>1</SR_NO>
<ACRSNO>1</ACR_SNO>
</RECORD>
<RECORD>
<SR_NO>2</SR_NO>
<ACRSNO>2</ACR_SNO>
</RECORD>
</Master>
Thanks in advance
Ameya.

I have already gone through that link and searched for this on the net. But it doesn't seem to work on my Mozilla Firefox browser.
Can anybody put a working example if possible.
Thanks
Ameya.

Problem displaying arabic text in xml document

Hi ..
I have an xml type coloum where i store an xml document that contains some arabic texts with UTF-8 encoding, m using an xsl file to transform the xml and display it in an html page.
At the database level when i select the xml col to dispaly the document, arabic texts are displayed correctly (DB is set to 1256), however when trying to display the text on html it gives me junk values. XSL sheet's encoding is set to windows-1256. M using Jdeveloper 1012 and BC4J frame work in my application.
How do i solve this problem.?
P.S.it wud b great if u support ur answer with examples .
Regards

You have to do it yourself - I don't have a ready solution. Just look into documentation how StyleSheets are used and see what properties work best for you:
http://livedocs.adobe.com/flash/9.0/ActionScriptLangRefV3/flash/text/TextField.html
http://livedocs.adobe.com/flash/9.0/ActionScriptLangRefV3/flash/text/StyleSheet.html
Also, with embedded fonts you need to play with TextFormat settings and AntiAliasType
http://livedocs.adobe.com/flash/9.0/ActionScriptLangRefV3/flash/text/AntiAliasType.html
In addition, on my machine even if I don't emebed fonts - Arabic works in Arial, TImes and others.

Updating a XML document with a processing instruction

Greetings Guru's
I have a fully functional XML database solution for our new system. The only thing left is for me to update a xml document in the database with a processing instruction to find the style sheet (JAXB strips it out when the XML must go back into the database).
I can update complete nodes and node elements in the xml document using updateXML in a regular update statement, but I do not know how to add the following processing instruction to my documents.
<?xml-stylesheet type="text/xsl" href="/RASWEB/JIT_REPORT.xslt"?>
[pre]
Thanks in advance
Derrick

SQL> var xmltext varchar2(4000)
SQL> --
SQL> begin
2    :xmlText := '<Hello>World</Hello>';
3 end;
4 /
PL/SQL procedure successfully completed.
SQL> drop table t
2 /
drop table t
ERROR at line 1:
ORA-00942: table or view does not exist
SQL> create table t of xmltype
2 /
Table created.
SQL> set long 10000
SQL> --
SQL> insert into t values (xmltype(:xmltext))
2 /
1 row created.
SQL> select *
2    from t
3 /
SYS_NC_ROWINFO$
<Hello>World</Hello>
SQL> update t set object_value = updateXML
2                              (
3                                object_value,
4                                '/',
5                                xmlconcat
6                                (
7                                  xmlpi("xml-stylesheet",'type="text/xsl" href="/RASWEB/JIT_REPORT.xslt"'),
8                                  object_value
9                                )
10                              )
11 /
1 row updated.
SQL> select * from t
2 /
SYS_NC_ROWINFO$
<?xml-stylesheet type="text/xsl" href="/RASWEB/JIT_REPORT.xslt"?>
<Hello>World</Hello>
SQL>

Loading a XML-document into tables

Hi,
I have created a view for the tables below.
Table Book with columns:
- Book_ID
- Book_Name
- Ref_To_Price ( -> is a reference to Table Price (Price_ID))
Table Price with columns:
- Price_ID
- Price_DM
SQL-Syntax:
"create view Bookprice as select Book_ID, Book_Name, Ref_To_Price, Price_ID, Price_DM from Book, Price where Ref_To_Price = Price_ID; "
XML-Document:
<?xml version="1.0" encoding="UTF-16"?>
<!DOCTYPE ANWENDUNGEN SYSTEM "file:/E:/book.dtd">

<ROOTDOC>
<ROW>
<BOOK_ID>66-77</BOOK_ID>
<BOOK_NAME>JavaScript</BOOK_NAME>
<REF_TO_PRICE>12</REF_TO_PRICE>
<PRICE_ID>12</PRICE_ID>
<PRICE_DM>25.50DM</PPRICE_DM>
</ROW>
</ROOTDOC>
If I use the XML SQL Utility to insert the XML-Document, the following error message came up:
" Exception in thread "main" oracle.xml.sql.OracleXMLSQLException: java.sql.SQLException: ORA-01776: cannot modify more than one base table through a join view "
Can anyone help me, please ?
null

Hi,
This is a classic join view problem, where u cannot update two tables in one shot. The main problem is that ur two tables are not normalized correctly. Why can't they be in just one table?
OK, if that is not possible, then the best way out is to create a simple INSTEAD OF trigger on the view which will insert correclty,
e.g.
CREATE TRIGGER bookprice_tr INSTEAD OF INSERT ON Bookprice FOR EACH ROW
BEGIN
insert into Book values (:NEW.Book_id,
:NEW.Book_name, :NEW.Ref_to_Price);
insert into Price
values(:NEW.Price_ID, :NEW.Price_DM);
END;
Hope this helps,
Murali

XML document must have a top level element. Error processing resource

Hi,
I am trying to send a XML file to a web browser from a servlet. I read the contents of the XML file into a string and I am sending it to the brower. Before I do this I set the 'Content-type' header of the httpResponse to "application/xml" . Embedded in the XML file is an xml-stylesheet elemetn indicating which *.xsl stylesheet to use to parse the XML content.
I get the following error:
The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.
XML document must have a top level element. Error processing resource 'http://127.0.0.1:8080/testReplyingXML/xml-to-html.xs...
Now, if I take the stylesheet element out of the XML string I sent, then the browser stores the content into and *.xml file. I manually run the "xml-to-xsl " stylesheet mentioned in the error output above, and there is no problem, the xml content gets successfully transformed in a viewable HTML .
It is only when I embed the "stylesheet" element into the XML content that I get this error.
So the browser is receiveing valid XML.
I am not sure if the above error is complaining about the XML content I send or the stylesshet .
Does anyone have an idea of what am I doing wrong?
For your information here are my servlet code and the XML file:
servlet:-
package webapps.testReplyingXML;
import java.io.BufferedReader;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.FileReader;
import java.util.Enumeration;
import java.util.StringTokenizer;
import java.io.PrintWriter;
public class ReplyXML extends HttpServlet {
          static int transactionCount = 0;
          public void doGet(HttpServletRequest req, HttpServletResponse res) throws ServletException ,IOException {
               String Q_PARAM = "query";
               String requestString = req.getQueryString();
               for ( Enumeration en = req.getParameterNames() ; en.hasMoreElements() ; )
     String k = (String)en.nextElement() ;
     String[] x = req.getParameterValues(k) ;
     String s = null;
     String DATA_PARAM= "";
     for(int i = 0 ; i < x.length ; i++ )
     s = x[i] ;
     //System.out.println("s = " + s);
     if (k.equals("query")){
          try {
                         //res.setHeader("Content-Type", "application/xml");
                         //res.setHeader("Transfer-Encoding", "chunked");
                         //res.setHeader("Cache-Control", "no-cache");
                         //res.setHeader("Server", "Jetty/5.1.10");
                         //res.setHeader("Pragma", "no-cache");
                         //res.setHeader("X-Joseki-Server", "Joseki-3.0-dev");
                         res.setStatus(res.SC_OK);
                         StringBuffer fileData = new StringBuffer(1000);
                    BufferedReader reader = new BufferedReader(new FileReader("sparql_results.xml"));
                    char[] buf = new char[1024];
                    int numRead=0;
                    while((numRead=reader.read(buf)) != -1){
                    String readData = String.valueOf(buf, 0, numRead);
                    fileData.append(readData);
                    buf = new char[1024];
                    reader.close();
                    String xmlMsg= fileData.toString();
                    System.out.println("XMLMSG= " + xmlMsg);
                         PrintWriter outresp = res.getWriter();
                         outresp.println(xmlMsg);
                         outresp.close();
          }catch (Exception e) {
               e.printStackTrace();
          public void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
               doGet(req, res);
XML FILE:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="xml-to-html.xsl"?>
<sparql
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:xs="http://www.w3.org/2001/XMLSchema#"
xmlns="http://www.w3.org/2005/sparql-results#" >
<head>
<variable name="book"/>
<variable name="title"/>
</head>
<results ordered="false" distinct="false">
<result>
<binding name="book">
<uri>http://example.org/book/book6</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Half-Blood Prince</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book5</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Order of the Phoenix</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book4</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Goblet of Fire</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book3</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Prisoner Of Azkaban</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book2</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Chamber of Secrets</literal>
</binding>
</result>
<result>
<binding name="book">
<uri>http://example.org/book/book1</uri>
</binding>
<binding name="title">
<literal>Harry Potter and the Philosopher's Stone</literal>
</binding>
</result>
</results>
</sparql>

Error processing resource http://127.0.0.1:8080/testReplyingXML/xml-to-html.xs...
Well, if one more character had been deleted from that message then you would have a problem. But as it is, the error message says there's an error processing a resouce whose name ends with "xml-to-html.xs" followed by something. That would be the stylesheet if I'm not mistaken. Most likely the browser can't find it at the URL mentioned in the error message.

[JS][CS3] Trying to use XSL to transform a XML document

I´m trying to do a script to format my XML in a particular way. The XSL document is ok because I´ve used this document to format an XML document in Indesign CS3 and works fine.However, when I´m trying to use this document in my scripting method I can´t obtain my XML formatted. I´ve tried it many times but I really don´t know where is the problem.
I´ve changed the XMLExportPreferences (allowTransform,TransformFileName)in my scripting method before exporting my XML in order to obtain a formatted XML.
Anyone have any idea? What are the steps to make this work?
Thank u,
Peter

I'm having a similar problem but with importing XML. When I run this script I get a dialogue saying that "Stylesheet 'Macintosh HD:Users:myFolder:transform.xsl, specified in the XSLT processing instruction can not be found." But this is the location of the stylesheet??
Here's the entire script (a combination of Adobe samples):
main();
function main(){
mySetup();
mySnippet();
function mySetup(){
var myDocument = app.documents.add();
var myRootXMLElement = myDocument.xmlElements.item(0);
var myXMLTag = myDocument.xmlTags.add("body");
var myXMLElement = myDocument.xmlElements.item(0).xmlElements.add(myXMLTag);
myDocument.select(myXMLElement);
//Sets XML import options.
var myXMLImportPreferences = myDocument.xmlImportPreferences;
myXMLImportPreferences.createLinkToXML = false;
myXMLImportPreferences.ignoreUnmatchedIncoming = false;
myXMLImportPreferences.ignoreWhitespace = true;
myXMLImportPreferences.importCALSTables = true;
myXMLImportPreferences.importStyle = XMLImportStyles.mergeImport;
myXMLImportPreferences.importTextIntoTables = false;
myXMLImportPreferences.importToSelected = true;
myXMLImportPreferences.removeUnmatchedExisting = false;
myXMLImportPreferences.repeatTextElements = true;
myXMLImportPreferences.allowTransform = true;
myXMLImportPreferences.transformFilename = File("/Users/myFolder/transform.xsl");
myDocument.importXML(File("/Users/myFolder/document.xml"))
function mySnippet(){
var myDocument = app.documents.item(0);
myDocument.viewPreferences.horizontalMeasurementUnits = MeasurementUnits.points;
myDocument.viewPreferences.verticalMeasurementUnits = MeasurementUnits.points;
myDocument.viewPreferences.rulerOrigin = RulerOrigin.pageOrigin;
myDocument.xmlElements.item(0).xmlElements.item(0).placeIntoFrame(myDocumen pages.item(0), [35, 35, 758, 576]);

Xml document converting to pdf

Hi,
I have a question regarding the convertion of xml document to pdf document.
Below is the scenario.
I have an xml document stored in the table in a CLOB format. I would like to convert the xml document stored in a table to pdf document and display in a Web browser.
I have written the stylesheet to convert the xml document to the xsl fo(XSL Formatting object xml) type document. I need to apply FOP Processor to convert into pdf document.
How do i do that in PL/ SQL ?
Any thoughts ??

1. Generate a XSL-FO document by applying an XSLT to the XML document in the database.
2. Convert the XSL-FO document to a PDF document.

Can I append an XML Document into another?

I have a large xml document which I open into coldfusion (mx
7), and then a smaller group of files that are opened into thier
own xml objects. After some customization of xml text values, I
want to append the smaller xml documents into the larger document
at specific positions within the document tree.
I have the code that I thought would do this, using an
arrayappend function, but what happens is that only the root
element of the smaller (inserted) xml document is placed into the
main document.
Is this possible, or do I need to modify the code so that the
entire tree of xml data that I am appending is created on the
fly?

Personally I do this with XSLT.
<cfxml variable="doc1">
<root>
<member id="10">
<name>Ian</name>
<sex>male</sex>
</member>
</root>
</cfxml>
<cfxml variable="doc2">
<root>
<member id="1">
<name>Joe</name>
<sex>male</sex>
</member>
<member id="2">
<name>John</name>
<sex>male</sex>
</member>
<member id="3">
<name>Sue</name>
<sex>female</sex>
</member>
</root>
</cfxml>
<cffile action="write" file="#expandPath("/")#\doc2.xml"
output="#ToString(doc2)#" nameconflict="overwrite">

<cfset newNode = doc1.root.member.cloneNode(true)>
<cfset doc2.changeNodeOwner(newNode)>
<cfset doc2.root.appendChild(newNode)>
<cfdump var="#doc2#" label="Merged by hidden functions"
expand="no">


<cfoutput>
<cfsavecontent variable="transformer">
<xsl:stylesheet xmlns:xsl="
http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml"/>

<xsl:variable name="emps"
select="document('#expandPath("/")#\doc2.xml')"/>


<xsl:template match="/">
<root>

<xsl:for-each select="root/child::*">

<xsl:copy-of select="."/>
</xsl:for-each>

<xsl:for-each select="$emps/root/child::*">

<xsl:copy-of select="."/>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>
</cfsavecontent>
</cfoutput>

<cfset doc2 = XMLparse(XMLtransform(doc1,transformer))>
<cfdump var="#doc2#" label="Merged by XSLT"
expand="no">

Error XSQL-017 Running XML Document Demo

Environment: Oracle 8.1.6 (NT 4.0)
XSQL 1.0.4.1
JDK 1.1.8
While running the XML Document Demo, I enter the Author, Title, Stylesheet and XML Document fields, and click the "Validate and Insert" button. Then I get the messages shown below. Any ideas? Thanks.
===== ===== Start Of Messages ===== =====
XSQL-017: Unexpected Error Occurred
java.lang.NoClassDefFoundError: java/sql/Clob
at
oracle.jdbc.driver.OracleStatement.get_clob_value(OracleStatement.java:4447)
at
oracle.jdbc.driver.OracleStatement.getCLOBValue(OracleStatement.java:3025)
at
oracle.jdbc.driver.OracleCallableStatement.getCLOB(OracleCallableStatement.java:439)
at
oracle.xml.sql.dml.OracleXMLSave.createTempCLOBFromString(Compiled
Code)
at
oracle.xml.sql.dml.OracleXMLSave.getLobVal(OracleXMLSave.java:765)
at
oracle.xml.sql.dml.OracleXMLSave.getObjectVal(OracleXMLSave.java:690)
at oracle.xml.sql.dml.OracleXMLSave.getStructVal(Compiled
Code)
at
oracle.xml.sql.dml.OracleXMLSave.setBindValue(OracleXMLSave.java:1206)
at oracle.xml.sql.dml.OracleXMLSave.saveNodeVal(Compiled
Code)
at
oracle.xml.sql.dml.OracleXMLSave.saveNode(OracleXMLSave.java:2146)
at oracle.xml.sql.dml.OracleXMLSave.saveNodes(Compiled
Code)
at
oracle.xml.sql.dml.OracleXMLSave.saveXML(OracleXMLSave.java:1954)
at
oracle.xml.sql.dml.OracleXMLSave.insertXML(OracleXMLSave.java:1060)
at
oracle.xml.xsql.actions.XSQLInsertRequestHandler.handleAction(XSQLInsertRequestHandler.java:126)
at oracle.xml.xsql.XSQLDocHandler.getDocument(Compiled
Code)
at oracle.xml.xsql.XSQLPageProcessor.process(Compiled Code)
at oracle.xml.xsql.XSQLServlet.doGet(XSQLServlet.java:60)
at oracle.xml.xsql.XSQLServlet.doPost(XSQLServlet.java:81)
at
javax.servlet.http.HttpServlet.service(HttpServlet.java:760)
at
javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
at oracle.lite.web.JupServlet.service(JupServlet.java:186)
at oracle.lite.web.MimeServletHandler.handle(Compiled Code)
at oracle.lite.web.JupApplication.service(Compiled Code)
at oracle.lite.web.JupHandler.handle(Compiled Code)
at oracle.lite.web.HTTPServer.process(Compiled Code)
at oracle.lite.web.HTTPServer.handleRequest(Compiled Code)
at oracle.lite.web.JupServer.handle(Compiled Code)
at oracle.lite.web.SocketListener.process(Compiled Code)
at oracle.lite.web.SocketListener$ReqHandler.run(Compiled
Code)
===== ===== End Of Messages ===== =====
null

Using JDK 1.1.8 you must use the JDBC 1.x driver in classes111.zip and the companion version of the XML SQL Utility xsu111.jar.
You'll need to download these from OTN from http://otn.oracle.com/tech/xml and then replace them in your classpath for the classes12.zip and xsu12.jar that you're using.

How to Create an XML document from XSQL servlet which follows a particular DTD struct

how to Create an XML document from XSQL servlet which follows a particular DTD structure.Could anyone send me a sample code for this.

You'll need to associate an XSLT transformation with your XSQL page that transforms the canonical result into your DTD-valid format.
For example, given an XSQL page like:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="rss.xsl" ?>
<xsql:query max-rows="3" connection="demo" xmlns:xsql="urn:oracle-xsql">
select title,id,description,url,to_char(timestamp,'Mon DD') timestamp
from site_entry
order by id desc
</xsql:query>and an "rss.xsl" stylesheet that looks like this:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes" doctype-system="rss-0.91.dtd"/>
<xsl:template match="/">
<xsl:for-each select="ROWSET/ROW">
<rss version="0.91">
<channel>
<title>Do You XML?</title>
<link>http://xml.us.oracle.com</link>
<description>Oracle XML Website Demo</description>
<language>en-us</language>
<xsl:for-each select="ITEM">
<item>
<title><xsl:value-of select="TITLE"/></title>
<link><xsl:value-of select="URL"/></link>
<description><xsl:value-of select="DESCRIPTION"/></description>
</item>
</xsl:for-each>
</channel>
</rss>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>You produce DTD-valid output against the rss-0.91.dtd DTD that looks like:
<?xml version = '1.0' encoding = 'UTF-8'?>
<!DOCTYPE rss SYSTEM "rss-0.91.dtd">
<rss version="0.91">
<channel>
<title>Do You XML?</title>
<link>http://xml.us.oracle.com</link>
<description>Oracle XML Website Demo</description>
<language>en-us</language>
</channel>
</rss>
<rss version="0.91">
<channel>
<title>Do You XML?</title>
<link>http://xml.us.oracle.com</link>
<description>Oracle XML Website Demo</description>
<language>en-us</language>
</channel>
</rss>
<rss version="0.91">
<channel>
<title>Do You XML?</title>
<link>http://xml.us.oracle.com</link>
<description>Oracle XML Website Demo</description>
<language>en-us</language>
</channel>
</rss>

Large XML Document Error

We are using Oracle's XSQL servlet engine 9.0.2.0.0A to query an Oracle Database using xsql:include-owa. This xsql document uses a custom serializer to write the resulting XML to a file on the webserver. We have run into a problem with writing XML documents larger than approximatly 7MB. The file is written but just contains a Malformed XML Document error. We have tried tracking down the problem and it seems to be occuring before the custom serializer is given control of the document. Attached below is the xsql document and the Java source of our serializer if it would be of any help.
-Eric Dalquist
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="simple_transform_xml.xsl" serializer="XMLWriter"?>
<BASE_TAG connection="XXXXXXXX" xmlns:xsql="urn:oracle-xsql">
    <xsql:set-page-param name="save-file" value="XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX/applInfo.xml"/>
    <xsql:include-owa >
        STUDEV.STUADMSDSET.P_GET_RECRUIT_INFO('A','C');
    </xsql:include-owa>
</BASE_TAG>-----------------------------------------
* Author:        Eric Dalquist
* E-Mail:        [email protected]
* Date Created: 10-03-2001
* Last Modified: 10-03-2001
* Modified By:   Eric Dalquist
* Description:   This class writes out the contents of the final document produced by the xsql servlet.
package com.mtu.XSQLSerializers;
import java.io.FileOutputStream;
import oracle.xml.xsql.*;
import oracle.xml.parser.v2.XMLDocument;
import org.w3c.dom.Document;
* <P>
*    XMLWriter is an implementation of the abstract XSQLDocumentSerializer class. It is passed a refrence to a DOM Document
*    and the servlet environment. The XMLWriter takes the document and writes it out to the servlet's output stream. There
*    is also the option that the saveFile xsql page parameter can be set to a fully qualified path and file name to write the
*    document to.
* </P>
* <P>
*    Here is an example of setting the saveFile page paramter. This line would be the first tag inside the root xsql servlet tag.
* </P>
* <PRE>
*    <xsql:set-page-param name="save-file" value="/u01/oracle/ias10210/xdk/java/xsql/Repository/Course_List/XMLDocument.xml"/>
* </PRE>
* @author Eric B. Dalquist
* @version 1.0 10/03/2001
public class XMLWriter implements XSQLDocumentSerializer
    /** the header we send if we are returning XML */
    private static final String MIME_XML = "text/xml";
    /** the name of the page parameter we look for to get the path and name to save the XML document to */
    private static final String ATTR_FILE = "save-file";
     * The serialize is called by the servlet engine and is passed the DOM Docuement result
     * from the XSLT transformation if there was one and a refrence to the XSQL servlet environment
     * @param doc The document representation of the XML output of the xsql servlet.
     * @param env A refrence to the servlet's environment.
     * @throws Throwable Any unhandled error is handled by the servlet by default.
    public void serialize(Document doc, XSQLPageRequest env) throws Throwable
        System.out.print("start ... ");
        FileOutputStream fos = null;
        String reqType = env.getRequestType();
        String saveFile = env.getParameter(ATTR_FILE);
        if (!reqType.equals("Command Line"))
            env.setContentType(MIME_XML);
            ((XMLDocument)doc).print(env.getOutputStream());
            env.getOutputStream().close();
        if (saveFile != null && !saveFile.equals("") && saveFile.indexOf("..") == -1 && saveFile.indexOf("~") == -1)
            fos = new FileOutputStream(saveFile);
            ((XMLDocument)doc).print(fos);
            fos.close();
        System.gc();
        System.out.println("end");
}

Technically DBMS_XMLSAVE and it's alter ego DBMS_XMLQUERY are not considered part of XML DB. DBMS_XMLSAVE and DBMS_XMLQUERY are legacy Java implementations.
In 9.2.x these routines were replaced by DBMS_XMLSTORE and DBMS_XMLGEN which are written in 'C' and should be much faster in most cases and address a number of limitations inherant in the older implementations. DBMS_XMLSTORE and DBMS_XMLGEN are part of XML DB and the minimum supported release for XML DB is 9.2.0.3.0.
DBMS_XMLSAVE issues are addressed in the TECH/XML forum
http://forums.oracle.com/forums/category.jspa?categoryID=51

XML document TO stylesheet

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