XMLAgg and order by

Question

Hello;
I can't seem to figure out how to use the "order by" syntax of the XMLAgg() function - wondering if someone has a short example they could share.
As specified in the syntax diagram for XMLAgg()(http://otn.oracle.com/docs/products/oracle9i/doc_library/release2/appdev.920/a96620/xdb12gen.htm#1027574), it should be possible to specify an order by clause that lets me sort the nested elements.
Every variation I've tried though doesn't let me do it. Here's a simplified examaple.
What I want to do have the nested <emp> elements sorted by e.name in the produced xml.
Any/all help is appreciated.
Regards,
Brian.
SELECT XMLELEMENT( "Department", XMLATTRIBUTES ( d.dname AS "name" ),
(SELECT XMLAGG(XMLELEMENT ("emp", XMLATTRIBUTES (e.ename AS name) ))
FROM scott.emp e
WHERE e.deptno = d.deptno) ) AS "dept_list"
FROM scott.dept d ;
<Department name="Accounting">
<emp name="Smith"/>
<emp name="Yates"/>
</Department>
<Department name="Shipping">
<emp name="Martin"/>
<emp name="Oppenheimer"/>
</Department>

Answer 1

Hi
Here an example with 9.2.0.2.0...
SQL&gt; SELECT ename, sal
2 FROM emp
3 WHERE deptno = 10;
ENAME SAL
CLARK 2450
KING 5000
MILLER 1300
SQL&gt; SELECT XMLAgg(XMLElement("ename", ename) ORDER BY ename) result
2 FROM emp
3 WHERE deptno = 10;
RESULT
&lt;ename&gt;CLARK&lt;/ename&gt;
&lt;ename&gt;KING&lt;/ename&gt;
&lt;ename&gt;MILLER&lt;/ename&gt;
SQL&gt; SELECT XMLAgg(XMLElement("ename", ename) ORDER BY sal) result
2 FROM emp
3 WHERE deptno = 10;
RESULT
&lt;ename&gt;MILLER&lt;/ename&gt;
&lt;ename&gt;CLARK&lt;/ename&gt;
&lt;ename&gt;KING&lt;/ename&gt;
Chris