XPath - How to get only second matching node?

Hello,
withs this XPath expression:
//td[contains(@name, 'FirstColumn')]on this XML:
<html>
     <table>
          <tr>
               <td name="MyFirstColumnInRow">A11 - skip me!</td>
               <td name="MySecondColumnInRow">A12</td>
          </tr>
          <tr>
               <td name="MyFirstColumnInRow">A21 - find me!</td>
               <td name="MySecondColumnInRow">A22</td>
          </tr>
          <tr>
               <td name="MyFirstColumnInRow">A31 - skip me!</td>
               <td name="MySecondColumnInRow">A32</td>
          </tr>
     </table>
</html>I have got three matching nodes: A11, A21, A31 .
How to expand this XPath expression to get only the second node: A21 ?
I can't find appropriate solution.
Thanks in advance.

Why don't you get all the nodes and than you can do whatever you want? You can even get an iterator (here commented out) or write your rule in a loop.
    public static Document parseXmlIntoDOM(File xmlFile,boolean validating,boolean spaceAware) throws XMLException{
        Document document = null;
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        factory.setValidating(validating);
        factory.setNamespaceAware(spaceAware);
        try {
           DocumentBuilder builder = factory.newDocumentBuilder();
           document = builder.parse(xmlFile);
        catch (SAXException sxe) {throw new XMLException("An error in parsing the input source",sxe);}
        catch (ParserConfigurationException pce) {throw new XMLException("An error in parsing the input source",pce);}
        catch (IOException ioe) {throw new XMLException("An error in parsing the input source",ioe);}
        return document;
    public static void main(String args[]){
        Document dom;
        try{
            File file = new File("C:\\Documents and Settings\\diego\\xml\\newXMLDocument.xml");
            dom = parseXmlIntoDOM(file,false,true);
            XPath xpath = XPathFactory.newInstance().newXPath();
            String expression = "/html/table/tr/td";
            DTMNodeList tdNodes = (DTMNodeList)xpath.evaluate(expression, dom, XPathConstants.NODESET);
            //DTMIterator iterator=tdNodes.getDTMIterator();
            Node secondinstance = tdNodes.item(2);
            System.out.println(secondinstance.getTextContent());
            }catch(Exception e){
                e.printStackTrace();
    }This works just fine for me and that is my output (in the standard):
compile:
run:
A21 - find me!
BUILD SUCCESSFUL (total time: 1 second)Sorry the code I wrote is awful, but working. P.S. is there a way for not using the "DTM" api?

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XPath - How to get only second matching node?

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