Xpath syntax for "a number"

In regex, it's [0-9]+ or \d+.  I'm trying to use xpath to match a number that's any value of 18 digits long.  What's the syntax?

DuckDuckGo: http://www.regular-expressions.info/xpath.html

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  • XPATH Syntax

    Simple question. Can someone please provide the proper syntax for placing an Input Variable into the query-database XPATH statement? I cannot even get this statement to compile (or any variants of it):
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    Here is the detailed error:
    Error(30): [Error ORABPEL-10039]: invalid xpath expression [Description]: in line 30 of "C:\OraBPELPM_1\integration\jdev\jdev\mywork\BPELws\JDBC\JDBC.bpel", xpath expression "orcl:query-database('select ename from emp where empno = bpws:getVariableData('inputVariable')',false(),false(),'jdbc:oracle:thin:scott/tiger@localhost:1521:ORCL')" specified in <from> is not valid, because XPath query syntax error. Syntax error while parsing xpath expression "orcl:query-database('select ename from emp where empno = bpws:getVariableData('inputVariable')',false(),false(),'jdbc:oracle:thin:scott/tiger@localhost:1521:ORCL')", at position "79" the exception is Expected: ). Please verify the xpath query "orcl:query-database('select ename from emp where empno = bpws:getVariableData('inputVariable')',false(),false(),'jdbc:oracle:thin:scott/tiger@localhost:1521:ORCL')" which is defined in BPEL process. . [Potential fix]: Please make sure the expression is valid.
    I have been trying to XSQL to work and it suffers from XPATH issues at runtime.
    Clemens, any suggestions here? I was thinking perhaps of using ora:parseEscapedXML to forceably create the proper expression after concatenating the orcl:query-database together with the EMPNO after it is assigned to a holding String variable. Not sure it would work though. It does not look like you can perform 2 successive COPY TO / FROM in one set of tags.
    Thanks!

    Does anybody have any suggestions for this issue? Has anyone gotten this aspect of XPATH to work correctly? HELP!

  • Syntax for creating foreign key across users in a database

    There are two user present A,B.They are granted all privileges.Now in USER A, there is a table PARENT whose primary key is PARENT_NO.In USER B I have created a table CHILD whose primary key is CHILD_NO.
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    Please post your code. Cut'n'paste from SQL*Plus like this...
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    Connected.
    SQL> desc t1
    Name                                      Null?    Type
    COL1                                               NUMBER
    COL2                                               VARCHAR2(10)
    SQL> grant references on t1 to b;
    Grant succeeded.
    SQL> conn b/b
    SQL> create synonym a_t for a.t1;
    Synonym created.
    SQL> alter table test add constraint fk foreign key (n) references a_t(col1);
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    SQL> Note that Oracle will translate the synonym anyway...
    SQL> select constraint_name, r_owner, r_constraint_name
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    SQL> By the way, this ...
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  • Code to write syntax for JOB submit ( Please answer ASAP)

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    Message was edited by:
            ramana peddu
    Message was edited by:
            ramana peddu

    Hi,
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  • Round up syntax for Formatted Search

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    Hi Too Mui Hwee
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  • SQL Syntax for Access database

    This pertains to LV only due to the fact that LV requires a slightly different syntax for SQL statements for use with Access than what you will see in the Access Queries SQL view.  For instance, I discovered that if you use a  ?  for a character placeholder  (can be any single character) in Access, you need to use an  _  (underscore)  for this feature.  I also discoverd that you use a % sign instead of an *  (asterisk) for any number of characters.
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    Doug
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    Thanks Danubio for the links.  The one for the SQL utility may be helpful as I go forward.
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    Doug
    "My only wish is that I am capable of learning each and every day until my last breath."

  • Flex 3: syntax for populating ArrayCollection by loop

    Hi, I'm a newb. I can't find an example of how to do this. Any examples would be greatl appreciated.
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    Here is an example of adding data points from a simple formula using a random number generator and scaling the randomness up. The process is just to create a new Object for each iteration of the loop and add the object to your ArrayCollection. You can assign as many properties to the object as you need, which can be helpful for using one ArrayCollection that is displayed in multiple charts.
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  • XPath Syntax Query

    Hello,
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    <PRODUCTS>
    <PRODUCT PRD_ID="123" QUANTITY="10">
    <PERIOD></PERIOD>
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    <SUPP>ven1</SUPP>
    <EDITION>ENTERPRISE</EDITION>
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    Thanks

    Hi,
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             100 SY-VLINE,
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             100 SY-VLINE,
             147 SY-VLINE.
            120 SY-VLINE,
            84 'Internal',
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             147 SY-VLINE.
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            120 sy-vline,
            123 'Restricted',
            122 'Page ',
            147 SY-VLINE.
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  • Syntax for DAQmxRepea​tTask

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    Solved!
    Go to Solution.

    Hi Jos,
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    > This does NOT work unless I insert in this DoneCallback DAQmxStopTask before start the task. This is not what I has expected because the callback function is called because the task has finished.
    The callback function is called because the task is finite and the final sample has been acquired. Acquiring the final sample doesn't automatically transition the task from the "running" state to the "committed" state, so you still have to stop the task before you can start it again. See the section of the NI-DAQmx Help entitled "Task State Model" for an explanation of the different states.
    > And this is not what I prefer, because the CVI manual reports that stopping and starting a task will reduce the performance.
    Yes, but in this case I think stopping is necessary. In other cases, it's not necessary. For example, you wouldn't want to stop and start the task between every sample.
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    Anyway, does the performance meet your requirements? If not, what are your performance requirements?
    Brad
    Brad Keryan
    NI R&D

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  • Syntax for commiet  for sales order creation from VB

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  • Can't figure out the correct syntax for this select statement

    Hello,
    The following statement works great and gives the desired results:
    prompt
    prompt Using WITH t
    prompt
    with t as
       select a.proj_id,
              a.proj_start,
              a.proj_end,
              case when (
                         select min(a.proj_start)
                           from v b
                          where (a.proj_start  = b.proj_end)
                            and (a.proj_id    != b.proj_id)
                        is not null then 0 else 1
              end as flag
         from v a
        order by a.proj_start
    select proj_id,
           proj_start,
           proj_end,
           flag,
           -- the following select statement is what I am having a hard time
           -- "duplicating" without using the WITH clause
            select sum(t2.flag)
              from t t2
             where t2.proj_end <= t.proj_end
           ) s
      from t;As an academic exercise I wanted to rewrite the above statement without using the WITH clause, I tried this (among dozens of other tries - I've hit a mental block and can't figure it out):
    prompt
    prompt without with
    prompt
    select c.proj_id,
           c.proj_start,
           c.proj_end,
           c.flag,
           -- This is what I've tried as the equivalent statement but, it is
           -- syntactically incorrect.  What's the correct syntax for what this
           -- statement is intended ?
            select sum(t2.flag)
              from c t2
             where t2.proj_end <= c.proj_end
           ) as proj_grp
      from (
            select a.proj_id,
                   a.proj_start,
                   a.proj_end,
                   case when (
                              select min(a.proj_start)
                                from v b
                               where (a.proj_start  = b.proj_end)
                                 and (a.proj_id    != b.proj_id)
                             is not null then 0 else 1
                   end as flag
              from v a
             order by a.proj_start
           ) c;Thank you for helping, much appreciated.
    John.
    PS: The DDL for the table v used by the above statements is:
    drop table v;
    create table v (
    proj_id         number,
    proj_start      date,
    proj_end        date
    insert into v values
           ( 1, to_date('01-JAN-2005', 'dd-mon-yyyy'),
                to_date('02-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           ( 2, to_date('02-JAN-2005', 'dd-mon-yyyy'),
                to_date('03-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           ( 3, to_date('03-JAN-2005', 'dd-mon-yyyy'),
                to_date('04-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           ( 4, to_date('04-JAN-2005', 'dd-mon-yyyy'),
                to_date('05-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           ( 5, to_date('06-JAN-2005', 'dd-mon-yyyy'),
                to_date('07-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           ( 6, to_date('16-JAN-2005', 'dd-mon-yyyy'),
                to_date('17-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           ( 7, to_date('17-JAN-2005', 'dd-mon-yyyy'),
                to_date('18-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           ( 8, to_date('18-JAN-2005', 'dd-mon-yyyy'),
                to_date('19-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           ( 9, to_date('19-JAN-2005', 'dd-mon-yyyy'),
                to_date('20-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           (10, to_date('21-JAN-2005', 'dd-mon-yyyy'),
                to_date('22-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           (11, to_date('26-JAN-2005', 'dd-mon-yyyy'),
                to_date('27-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           (12, to_date('27-JAN-2005', 'dd-mon-yyyy'),
                to_date('28-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           (13, to_date('28-JAN-2005', 'dd-mon-yyyy'),
                to_date('29-JAN-2005', 'dd-mon-yyyy'));
    insert into v values
           (14, to_date('29-JAN-2005', 'dd-mon-yyyy'),
                to_date('30-JAN-2005', 'dd-mon-yyyy'));

    Hi, John,
    Not that you asked, but as you proabably know, analytic functions are much better at doing this kind of thing.
    You may be amazed (as I continually am) by how simple and efficient these queries can be.
    For example:
    WITH     got_grp          AS
         SELECT     proj_id, proj_start, proj_end
         ,     proj_end - SUM (proj_end - proj_start) OVER (ORDER BY  proj_start)     AS grp
         FROM     v
    SELECT       ROW_NUMBER () OVER (ORDER BY grp)     AS proj_grp
    ,       MIN (proj_start)                         AS proj_start
    ,       MAX (proj_end)               AS proj_end
    FROM       got_grp
    GROUP BY  grp
    ORDER BY  proj_start
    ;Produces the results you want:
      PROJ_GRP PROJ_START  PROJ_END
             1 01-Jan-2005 05-Jan-2005
             2 06-Jan-2005 07-Jan-2005
             3 16-Jan-2005 20-Jan-2005
             4 21-Jan-2005 22-Jan-2005
             5 26-Jan-2005 30-Jan-2005This is problem is an example of Neighbor-Defined Groups . You want to GROUP BY something that has 5 distinct values, to get the 5 rows above, but there's nothing in the table itself that tells you to which group each row belongs. The groups are not defined by any column in hte table, but by relationships between rows. In this case, a row is in the same group as its neighbor (the row immediatly before or after it when sorted by proj_start or proj_end) if proj_end of the earlier row is the same as proj_start of the later row. That is, there is nothing about 03-Jan-2005 that says the row with proj_id=2 is in the first group, or even that it is in the same group with its neighbor, the row with proj_id=3. Only the relation between those rows, the fact that the earlier row has end_date=03-Jan-2005 and the later row has start_date=03-Jan-2003, that says these neighbors belong to the same group.
    You're figuring out when a new group starts, and then counting how many groups have already started to see to which group each row belongs. That's a prefectly natural procedural way of approaching the problem. But SQL is not a procedural language, and sometimes another approach is much more efficient. In this case, as in many others, a Constant Difference defines the groups. The difference between proj_end (or proj_start, it doesn't matter in this case) and the total duratiojn of the rows up to that date determines a group. The actual value of that difference means nothing to you or anybody else, so I used ROW_NUMBER in the query above to map those distinct values into consecutive integers 1, 2, 3, ... which are a much simpler way to identify the groups.
    Note that the query above only requires one pass through the table, and only requires one sub-query. It does not need a WITH clause; you could easily make got_grp an in-line view.
    If you used analytic functions (LEAD or LAG) to compute flag, and then to compute proj_grp (COUNT or SUM), you would need two sub-queries, one for each analytic function, but you would still only need one pass through the table. Also, those sub-queries could be in-line views; yiou would not need to use a WITH clause.

  • Syntax for linear gradient

    I'm getting:
    WARNING: com.sun.javafx.css.parser.CSSParser linearGradient Using deprecated syntax for linear gradient at <filename & line #>. Refer to the CSS Reference Guide.
    But I'm copying the syntax from the only reference guide I can find (no reference is included in the JDK)
    http://download.oracle.com/javafx/2.0/api/javafx/scene/doc-files/cssref.html

    The docs in the SDK have the correct reference. You can find the ref by following the link from the class doc for Node. Here is the relevant section.
    Linear Gradients <linear-gradient>
    linear-gradient( [ [from <point> to <point>] | [ to <side-or-corner>], ]? [ [ repeat | reflect ], ]? <color-stop>[, <color-stop>]+)
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    This example will create a gradient from top left to bottom right of the filled area with red at the top left corner and black at the bottom right.
    linear-gradient(to bottom right, red, black)
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    radial-gradient([ focus-angle <angle>, ]? [ focus-distance <percentage>, ]? [ center <point>, ]? radius [ <length> | <percentage> ] [ [ repeat | reflect ], ]? <color-stop>[, <color-stop>]+)
    If neither repeat nor reflect are given, then the CycleMethod defaults "NO_CYCLE".
    Stops are per W3C color-stop syntax and are normalized accordingly.
    Following are examples of the use of radial-gradient:
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    radial-gradient(focus-angle 45deg, focus-distance 20%, center 25% 25%, radius 50%, reflect, gray, darkgray 75%, dimgray)
    The following syntax for radial gradient does not conform to the CSS grammar and is deprecated in JavaFX 2.0. The JavaFX 2.0 CSS parser supports the syntax but this support may be removed in later releases.
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  • What is the setVariable syntax for AS3

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    Jusclark-Oracle wrote:
    What is the correct syntax for referencing a page item (P23_ID, for example) in a PL/SQL page process, after submit?
    See "About Referencing Session State" in the documentation.
    Within an anonymous block in an APEX page process, use the standard bind variable syntax:
    :P23_ID
    In general, use bind variable syntax when referencing session state values in SQL or DML:
    select
        ename
    into
        :p23_name
    from
        emp
    where
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    PL/SQL function references v('p23_id') and nv('p23_id') [for number values] must be used to access values in stored program units called from APEX, although it's usually better to pass the values as parameters: foo(:p23_id).

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