XSL Mapping: Get node without complete XPath

Question

Dear all,
I would like to create a generic XSL mapping
In the target structure I would like to insert the value of DOCNUM
<xsl:template match="DOCNUM">
   <xsl:value-of select="/ORDERS/IDOC/EDI_DC40/DOCNUM" />
</xsl:template>
That works.
Now, the mapping should become generic. I would like to use this for ORDERS, DELVRY and so on.
I try tor create it this way.
   <xsl:value-of select="/../IDOC/EDI_DC40/DOCNUM" />
   <xsl:value-of select="/IDOC/EDI_DC40/DOCNUM" />
   <xsl:value-of select="/DOCNUM" />
So I don't want to use ORDERS in the select statement.
How to get this work for all IDOC types?
Regards
Chris

Answer 1

just define this
SOURCE
<?xml version="1.0" encoding="UTF-8"?>
<XXXXXXX>
   <IDOC BEGIN="1">
      <EDI_DC40 SEGMENT="1">
         <TABNAM>EDI_DC40</TABNAM>
         <MANDT>310</MANDT>
         <DOCNUM>0000000001021184</DOCNUM>
         <DOCREL>XX</DOCREL>
         <STATUS>XX</STATUS>
         <DIRECT>1</DIRECT>
</EDI_DC40>
</IDOC>
</XXXXXXX>
XLS
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="IDOC">
<DOCNUM>
<xsl:value-of select="EDI_DC40/DOCNUM" />
</DOCNUM>
</xsl:template>
</xsl:stylesheet>
RESULT
<?xml version="1.0" encoding="UTF-8"?>
<DOCNUM>0000000001021184</DOCNUM>
Thanks
Edited by: Rodrigo Alejandro Pertierra on Feb 3, 2011 2:28 PM