Xsl transformation of xml with wrong namespace

Question

I have xml with wrong namespace:
<PAMStartedNotification xmlns="some site">
<tUser>PLVUSER</tUser>
</PAMStartedNotification>I need to leave this namespace and transform it.
As a result of transformation now I get
<tUser></tUser>
...I.e. XPath is not calculated properly.
If I leave out that namespace then everything is ok.
But I want to leave that namespace as it is.
I use the following code to transform xml:
Templates stylesheet = transformerFactory.newTemplates(new StreamSource(new File(fileName)));
Transformer processor = stylesheet.newTransformer();
java.io.StringWriter resultWriter = new java.io.StringWriter();
StreamResult streamResult = new StreamResult(resultWriter);
processor.transform(new StreamSource(new StringReader(xmlData)), streamResult);
transformedXML = resultWriter.getBuffer().toString();Any ideas how to do that(transform xml with wrong namespace)?
Edited by: prng on Dec 15, 2008 6:43 AM
Edited by: prng on Dec 15, 2008 6:45 AM

Answer 1

prng wrote:
Sorry.
Here is XPath I use to select tUser:
/PAMStartedNotification/tUser
Right. To start out, that selects a PAMStartedNotification element which is in no namespace. But yours isn't. It's in the default namespace, which doesn't have a prefix. You could try this XPath expression:
/*[local-name() = 'PAMStartedNotification']/*[local-name() = 'tUser'](Untested, might have mis-typings and so on.)