Zip.ZipInputStream cannot extract files with Chinese chars in name

Question

Dear friends,
Peace b upon u!
I am trying to read a zip file (~3000 files)containing one
or more files with Chinese, Japanese or Korean names, the
getNextEntry method throws an IllegalArgumentException as below after extracting just ~300 files as below:-
java.lang.IllegalArgumentException
        at java.util.zip.ZipInputStream.getUTF8String(Unknown Source)
        at java.util.zip.ZipInputStream.readLOC(Unknown Source)
        at java.util.zip.ZipInputStream.getNextEntry(Unknown Source)
        at testZipFiles.getZipFiles(testZipFiles.java:65)
        at testZipFiles.main(testZipFiles.java:18) issue:java.util.zip.ZipInputStream cannot extract files with Chinese chars in name
Category java:classes_util_jarzip
Plz let me know 1 of the ways which I can solve this issue.
1)if someone has JAVA DCOMPILER plz send the SOURCE Code
for the ZipInputStream.class to me..I need to edit it using 1 of the solutions as provided below which I googled.
2)If there is an alternate or upgraded java.util.zip.ZipInputStream or any org.apache.tools.zip.* package which can read such files..If yes where I can download the same on net.
3)Any other easier solution, which can let me extract all files (by excluding Chinese files thru CATCH) without the extractor process to fail altogether.
On net I found that the only solution with this is:-
- edit the new ZipEntry, remove the static initializer that calls
the native methods initIDs().
this step seems a bit scary, but it's according to the
workaround
to bug #4244499 (the workaround of Olive64, THU JUN 05
01:55 P.M. 2003),
that handles a similar bug at the ZipOutputStream.
Now you have a ZipInputStream that supports multi-bytes
entry names.
to extract the zip file, using the fixed code that is offered
above,
create a function that gets an "encoding" string, a "destPath"
string
and a "sourceFile" (zipped) and does :
ZipInputStream zipinputstream = null;
ZipEntry zipentry;
zipinputstream = new ZipInputStream(new FileInputStream
(sourceFile),encoding);
zipentry = zipinputstream.getNextEntry();
while (zipentry != null) { //for each entry to be extracted
    String entryName = zipentry.getName();
    int n;
    FileOutputStream fileoutputstream = new FileOutputStream
( destPath + entryName );
    while ((n = zipinputstream.read(buf, 0, 1024)) > -1)
        fileoutputstream.write(buf, 0, n);
    fileoutputstream.close();
    zipinputstream.closeEntry();
    zipentry = zipinputstream.getNextEntry();
}//while
zipinputstream.close();

Answer 1

Hi friend,
We'd better to ask one question in each thread. If you have another issue, you can consider to open up a new thread in this forum.
Now for the first question, do you mean this picture? It throws access exception in archive2.
If so , because your extractPath is a path, not a directory.You should add +"xxx.zip". For more information, please refer to
ZipFile.Open
Method (String, ZipArchiveMode).
For the second question, you can use the following code to skip the error message.
while (true)
try
//do something;
catch (Exception ex)
{ continue; }
Good day!
Kristin
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