ArrayOutOfBound Exception??!!!WHY

Question

Dea Forum Members,
i need some help with my following code -
private void display() {
     int counter = 0;
     for(char letter = 'A'; letter < 'Z'; letter++) {     
     if(counter == tokenCount) {
     break;
     else {
     rows[letter-'A'].rowDisplay(letter);
     counter++;
This is actually a part of a cinema hall booking program where the row and seats will be displayed.tokenCount(an instance variable in this class) is the total number of Rows - row[0] is depicted as row 'A' and row[25] is depcited as row 'Z' for the purpose of display.the number of rows ie. tokenCount is being read from a text file....that may be 1 or 2 or maximum 26.row[i] is an object of a row class and rowDisplay(char) is a method of row class for displaying the seats of a particular row object.
so if the total number of rows(tokenCount) be 2 the for loop should be executed till 'B' only and then it will come out of the for loop as i have issued a break; command.the variable counter is keeping track of the total number of rows processed and if it matches tokenCount,it shud encounter the break; command and come out of the for loop so that further no more array is the loop is processed.so if tokenCount is 2....only row[0] and row[1] will be processed and it will come out of the for loop.but in practise while i am executing the program...i am receing an error as follows -
ArrayIndexOutOfBoundsException:2
at BookingProcess.display<BookingProcess.java:92>
where BookingProcess is the Class containing the method private void display()
pls do help me with ur suggestions......
Regards
RK

Answer 1

ArrayIndexOutOfBoundsException:2
at BookingProcess.display<BookingProcess.java:92>
where BookingProcess is the Class containing the
method private void display()On line 92 in BookingProcess.java, you're trying to access index 2 of an array that has, at most, elements 0 and 1.
Can't say any more than that from the information you've provided.
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