Count Occurrences of String in Cell Range
I have a column like this:
Header 1
AA
AA, BB
BB
BB, AA
AA
I need to count how many times "AA" appears throughout this column, so in this case the answer should be 4. I've tried searching for hours, but can't find anything. Anyone have any ideas?
Thanks!
Hi G,
COUNTIF, using wildcards can count the number of cells containing the specific string.
The example below shows the results where a cell contains AA more than once. C2 contains the same formula as above. C4 contains =SUM(B). Cells in column B use LEN() and SUBSTITUTE to calculate the number of times AA appears in each row of column A.
A2, and filled down: =(LEN(A2)-LEN(SUBSTITUTE(A2,B$1,"")))/LEN(B$1)
Regards,
Barry
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In my reports, I count the number of tests of one of our products and another count on the number of failures. I then use a simple formula to give me the defect rate percentage (DR%)
The universe objects used in the calculation are:
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NOTE: There is a "not equal to sign" between [Test Code Description] and "FUNCTIONAL..." above, but the forum is blanking it when I preview the message. Not a big deal, but it may be important for someone looking to help...
I then have a third variable called [DR%] that divides [Failed Count] into the number of [Count Assys], which yields a number formatted as a percentage.
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The problem is: when I have a zero defect count (everything passes), the cell is blank, so the percentage variable remains blank. I want a zero (0) to appear if nothing failed so the percentage appears as 0%
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Edited by: Charles Norman on Dec 9, 2008 12:44 PM
Edited by: Charles Norman on Dec 9, 2008 12:47 PMHi Charles,
Use [Dr%] Variable formula as =if(IsNull([Dr%]);0;[DR%])
Here IsNull returns the Boolean value of variable [Dr%] if its true then inserts 0 else the percentage values of failed tests based on the total number of assembly tests performed.
I Hope this is what you want to achieve....
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How do I use variables to define a cell range?
I have a series of data elements that are organized by date. I need to find a list of dates when specific events have occurred (each event is marked by a flag value of 1). I'm using VLOOKUP to find the first date when the event occurs. For the next date I need to adjust the cell range I'm searching so that it won't pick up the first occurence of the flag value (1).
Example:
1st query =VLOOKUP(1,G3..G223,51,0)
The first query returns a date that is in row 12. I now need to make the second query look for rows 13 through 223.
Overall I need to create over 500 such queries (50 columns of data and 10 events in each row), so typing in each query individually is not an appealing option.
Thanks!Hi Dad,
I'm having some trouble with your description of the data table. If I read it correctly, the cells in column G contain either a 1 or are empty (or contain a zero). If this is correct, and you are using column G to hold the compare range, then, as the VLOOKUP description in AppleWorks Help states, "If the values in the compare range are not in strict ascending or descending order, or the compare range does not contain an inclusive range from the highest to lowest possible value, the results can be unpredictable." It's very difficult to place the values 0 and 1 into 221 individual cells in "strict ascending order."
VLOOKUP(v,cr,os,m) looks for a specific value (v) in a strictly ordered list of values (cr), and when that value is found*, returns the value in the cell that is in the same row and offset a specific number of columns (os) to the right.
*The method of comparison (m) determines whether an exact match is necessary or if the comparison can be <=v or >=v.
•From the Compare range in your formula, your table has 221 rows (3 through 223). My assumption is that you are recording data for 221 specific dates.
•From the offset value in the formula (51) the table has 52 columns—a compare range column, a result column, and 50 others between them.
•From your formula, it appears that only one column of the chart is being used as a compare range for a particular search (event?).
•You state you have 50 columns of data and that there are 10 events in each row (of 52? cells).
From the last statement, I infer that there are 50 distinct possible events (one for each column), and that 10 of these 50 events occur on each date. Is that correct?
If I understand the description, then my impression is that VLOOKUP is not an effective tool for this job.
Instead, I would suggest a larger table and a set of formulas which will construct a list of the dates on which each event occurs. (Note that the maximum length of a formula, and the maximum length of data for a single cell are both 255 characters. This may necessitate some adjustment to the formulas if one event occurs a great number of times.)
The larger table will consist of two (or three) sections:
•a data entry section much like my understanding of your current table. One column will contain a list of dates. Fifty other columns will each represent a single type of event. Each cell in that column will contain a 1 if the event occurred on the date listed in that row, or will be empty if the event did not occur on that date. for illustration purposes, the dates will be listed in F3..F223, and the events in columns G..BD, with the occurence of Event 1 reported in G3..G223.
•A calculated section which copies the contents of the data block, substituting the correct date for each occurrence of a 1 in the data. In this block (BF3..DC223), column BF will list the dates on which event 1 occurred, column DC the dates on which event 50 occurred. Row 2 (or Rows 1 and 2) in this secton will repeat the headers in the data entry section.
Formulas:
BF1: =G1
Fill this formula Down and Right to DC2
BF3: =IF(G3=1,=DATETOTEXT($F3),"")
Fill this formula Down and Right to DC223
Collecting the dates:
Open a new Word Processor document.
For EACH event, switch back to the spreadsheet document, select the full column containing the dates for that event (eg. BF1..BF223 for Event 1) and Copy.
Switch to the word processor document and Paste, then press shift-return twice (This enters a visual separation that will not be removed in the next step.)
Save the (temporary) WP document. You will have to name it the first time. After that, just press command-S. (This gives you a fall back if you make—and notice—an error along the way.
Repeat these three steps until you have transfered all 50 columns of data (including the empty cells in each column) into a single list in the WP document.
Now use Find/Change to remove all of the empty lines in the list.
Press command-F to open the Find/Change dialogue.
Type "\p\p" into Find and "\p" into Change (both without the quotes).
Repeat the next three steps until AppleWorks reports "0" occurences were changed.
Click Change All.
Click OK to acknowledge the warning that this action is irreversible.
Read the number of changes that occurred, then Click OK to close this alert.
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Message was edited by: Un-decided -
Count integers in String array
String[] s= {"xx","yy","34","35","46"};
i want to count the integers in that String array.
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Can any one suggest me how to get that one.Try it again with this String in your
array:"2147483648"
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String[] array = {"xx","yy","34","35","46", "2147483648"};
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for (String s : array) {
boolean numericOnly = true;
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All,
Does anyone know the syntax or algorithm to count the occurrences of matched words that where compared from two separate columns or tables? Below is a simple example of the type of comparison I would like to perform. I found the function regexp_count, but it only works in 11g. Unfortunately, I have Oracle 10g. Any help would be greatly appreciated. Thanks
i.e.
drop table compare_matched_words;
create table compare_matched_words (
query_id number,
query_string1 varchar2(80),
query_string2 varchar2(80)
insert into compare_matched_words values (1, 'oracle 255','oracle1 255');
insert into compare_matched_words values (2, 'larry or ellison','larry or');
insert into compare_matched_words values (3, 'oracle and text','and');
insert into compare_matched_words values (4, 'market1 share','market share');
insert into compare_matched_words values (5, 'larry or',' larry or ellison');
insert into compare_matched_words values (6, 'oracle1 255','oracle 255');Issue is not in 11g. Before you can solve the task you need to split QUERY_STRING1 and QUERY_STRING2 into words and then compare words for same QUERY_ID. To split string into words use something like:
select query_id,
regexp_substr(query_string1,'\w+',1,column_value) query_string1_word
from compare_matched_words t,
table(
cast(
multiset(
select level
from dual
connect by level <= length(regexp_replace(regexp_replace(QUERY_STRING1,'\w+','A'),'[^A]'))
) as sys.OdciNumberList
SQL> /
QUERY_ID QUERY_STRING1_WORD
1 oracle
1 255
2 larry
2 or
2 ellison
3 oracle
3 and
3 text
4 market1
4 share
5 larry
QUERY_ID QUERY_STRING1_WORD
5 or
6 oracle1
6 255
14 rows selected.
SQL> Now:
select t1.query_id,
t1.query_string1,
t2.query_string2,
count(*) matchin_word_count
from (
select query_id,
query_string1,
regexp_substr(query_string1,'\w+',1,column_value) query_string1_word
from compare_matched_words t,
table(
cast(
multiset(
select level
from dual
connect by level <= length(regexp_replace(regexp_replace(query_string1,'\w+','A'),'[^A]'))
) as sys.OdciNumberList
) t1,
select query_id,
query_string2,
regexp_substr(query_string2,'\w+',1,column_value) query_string2_word
from compare_matched_words t,
table(
cast(
multiset(
select level
from dual
connect by level <= length(regexp_replace(regexp_replace(query_string2,'\w+','A'),'[^A]'))
) as sys.OdciNumberList
) t2
where t2.query_id = t1.query_id
and t2.query_string2_word = t1.query_string1_word
group by t1.query_id,
t1.query_string1,
t2.query_string2
order by t1.query_id
QUERY_ID QUERY_STRING1 QUERY_STRING2 MATCHIN_WORD_COUNT
1 oracle 255 oracle1 255 1
2 larry or ellison larry or 2
3 oracle and text and 1
4 market1 share market share 1
5 larry or larry or ellison 2
6 oracle1 255 oracle 255 1
6 rows selected.
SQL> SY. -
How can i count the word in a cell.
Dear Experts,
i want to count the word in cell how can i do this ?
Isthere any function ?
plz give logic or command.You can ty :
SQL> var text varchar2(50)
SQL> exec :text := 'How do I count the number of words in my cell?'
PL/SQL procedure successfully completed.
SQL> select text,
2 sum(case when substr(text,rownum,1)=' '
3 and substr(text,rownum-1,1)!=' '
4 then 1
5 else 0 end) nb_word
6 from (select rownum,:text||' ' text,length(:text) ln from dual)
7 connect by level <= ln+1
8 group by text
9 /
TEXT
NB_WORD
How do I count the number of words in my cell?
11
SQL> exec :text := 'How do I count the number of words in my cell? '
BEGIN :text := 'How do I count the number of words in my cell? '; END;
ERROR at line 1:
ORA-06502: PL/SQL: numeric or value error: character string buffer too small
ORA-06512: at line 1
SQL> var text varchar2(1000)
SQL> exec :text := 'How do I count the number of words in my cell? '
PL/SQL procedure successfully completed.
SQL> select text,
2 sum(case when substr(text,rownum,1)=' '
3 and substr(text,rownum-1,1)!=' '
4 then 1
5 else 0 end) nb_word
6 from (select rownum,:text||' ' text,length(:text) ln from dual)
7 connect by level <= ln+1
8 group by text
9 /
TEXT
NB_WORD
How do I count the number of words in my cell?
11
SQL> select * from v$version where rownum=1;
BANNER
Oracle9i Enterprise Edition Release 9.2.0.7.0 - Production
SQL> Nicolas.
Well, we can discuss about what limit a word : here space, but there is point, double-point, and so on... And about what is a word : do the punctuation is a word ?
For example :
"It's a word !"=>how many words are in this sentence ?
http://en.wikipedia.org/wiki/Word
Message was edited by:
N. Gasparotto
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