Select statement for last day of the last quarter and first quarter

Anybody provide me the single select statement which should result the last day of the last quarter and last day of current quarter?
Ex: Select last date of the last quarter,last day of current quarter from XYZ(DUAL...)
Thanks in Advance

Hi,
Here's one way:
SELECT               TRUNC (SYSDATE, 'Q') - 1     AS prev_qtr_end
,     ADD_MONTHS ( TRUNC (SYSDATE, 'Q') - 1
             , 3
             )                    AS this_qtr_end
FROM    dual;TRUNC (dt, 'Q') returns the first day of the quarter containing dt.
Subtract one day from that, and you have the last day of the previous quarter.
Add 3 months to that, and you have the last day of the current quarter. ADD_MONTHS (dt, n) will always return the last day of a month if its first argument, dt, is the last day of a month.

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Update statement for modifying day of the month

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i hope there is an easy answer to a question i'm probably over thinking. i have a situation where i need to update all the days in a date field to a certain day of the month regardless of the month or year. Here is an example of a small number of dates in the table:
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BI Content Variable on 0Calday for first day of the fiscal year and first day of the current month

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Pls check below link for more.
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SQL select Statement -first day and last day of the month - 1 year from now

Hi,
I need to write a SQL to get the dates in between first day and last day of the month one year from now.
SELECT last_day(add_months(sysdate,12)) as lastday from dual
What could be the Query to get the first day of the month one year from now..
ie ..Sysdate - 3-DEC-2009
Result - 1-DEC-2010
thank you

Hi,
You can use TRUNC with 2 arguments to get the first DATE in a month, year, quarter, week, hour, minute, ISO year, ...
SELECT TRUNC ( ADD_MONTHS ( SYSDATE
                           , 12
              , 'MONTH'
              )     AS first_of_month
FROM    dual
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At that time, I warded about using LAST_DAY as a cutoff point; TRUNC is a much better way.
For example, to find all appointment_dates in the current month next year:
SELECT *
FROM    appointments
WHERE   appointment_date >= TRUNC (ADD_MONTHS (SYSDATE, 12), 'MONTH')
AND     appointment_date < TRUNC (ADD_MONTHS (SYSDATE, 13), 'MONTH')Note that
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How to get the last day of the week?

Hii
i can get the calender week number for any given date using
SELECT to_char(to_date('04/04/2011','MM/DD/YYYY'),'WW') FROM dual
can any body tell me, how to get the last day of that week ?
and the answer should be 04/08/2011(8th april )
thanks
San
Edited by: sandeep9 on Apr 4, 2011 3:50 AM

Hi, San,
Here's one way:
WITH     sample_data     AS
     SELECT DATE '2011-04-04'     AS dt
     FROM     dual
SELECT dt
,     TO_CHAR (dt, 'WW')     AS week_num
,     NEXT_DAY ( dt - 1
           , TO_CHAR ( TRUNC (dt, 'YEAR') - 1
                  , 'Day'
           )          AS end_o_week
FROM     sample_data;Another way is to use date arrithmetic:
WITH     sample_data     AS
     SELECT DATE '2011-04-09'     AS dt
     FROM     dual
SELECT dt
,     TO_CHAR (dt, 'WW')     AS week_num
,     TRUNC (dt, 'YEAR')
      + (7 * CEIL ( (dt - (TRUNC (dt, 'YEAR') - 1))
            / 7
      - 1               AS using_date_arithmetic
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Need to find the last day of the previous month

hi folks,
the code goes like this...
data: xt247 type t247,
      monthn(30) type c,
      monthnumber type i,
      bforwardmonth type i.
call function 'RP_LAST_DAY_OF_MONTHS'
EXPORTING
    day_in            = s_date
IMPORTING
    last_day_of_month = e_date.
write: 'The last day of the month', e_date.
select single * from t247 into xt247
        where spras = sy-langu
          and mnr = e_date+4(2).
monthnumber = xt247-mnr.
write:' The month number', monthnumber.
determine the previous month.
bforwardmonth = monthnumber - 1.
From here I need to determine the last day of the previous month How can I do?
Thanks for your help.
Santhosh

Hi all,
here's the shortest solution:
REPORT z123.
PARAMETERS p_datum LIKE sy-datum DEFAULT sy-datum.
DATA ultimo LIKE sy-datum.
<b>ultimo = p_datum - p_datum+6(2).</b>
WRITE: / p_datum, 20 ultimo COLOR 2.
it's not my solution :
it's from <a href="http://www.abapforum.com/forum/viewtopic.php?t=1434&highlight=ultimo">Andrew_</a>
regards Andreas

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Other wise should i develop custom logic.

Hi,
Try this way.
Selection-screen
PARAMETERS: p_bldat LIKE bsis-bldat .
INITIALIZATION.
DATA: v_end_date LIKE sy-datum.
CALL FUNCTION 'LAST_DAY_OF_MONTHS'
    EXPORTING
      day_in            = sy-datum
    IMPORTING
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    EXCEPTIONS
      day_in_no_date    = 1
      OTHERS            = 2.
IF sy-subrc <> 0.
    MESSAGE ID sy-msgid TYPE sy-msgty NUMBER sy-msgno
            WITH sy-msgv1 sy-msgv2 sy-msgv3 sy-msgv4.
ENDIF.
p_bldat = v_end_date.
Thanks,
Anitha

Last day from the list of dates

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the query
(select distinct to_date(substr(batch_id,1,6),'DDMMRR') batch_id from gcon_mst_v0)
order by batch_id desc
i want last day from each month from the list of dates listed from the query.
Help would be higly appriciated
Thanks in advance

The column is a varchar but i am convering it to get
the list od dates as you can see in the query. i want
all the last dates of every month from that list of
dates for eg. below is the list of the dates i am
getting from the query.
7/11/2007
7/10/2007
7/9/2007
7/8/2007
7/6/2007
7/5/2007
7/4/2007
7/3/2007
7/2/2007
7/1/2007
6/29/2007
6/28/2007
6/27/2007
6/26/2007
6/25/2007
6/24/2007
6/22/2007
6/21/2007
6/20/2007
6/19/2007
6/18/2007
6/17/2007
6/15/2007
6/14/2007
6/13/2007
6/12/2007
6/11/2007
6/10/2007
6/8/2007
6/7/2007
6/6/2007
6/5/2007
6/4/2007
6/3/2007
6/1/2007
5/31/2007
5/30/2007
5/29/2007
5/28/2007
5/27/2007
5/25/2007
5/24/2007
5/23/2007
5/22/2007
5/21/2007
5/20/2007
5/18/2007
5/17/2007
5/16/2007
5/15/2007
5/14/2007
5/13/2007
5/11/2007
5/10/2007
5/9/2007
5/8/2007
5/7/2007
5/6/2007
5/4/2007
5/3/2007
5/2/2007
5/1/2007
4/30/2007
4/29/2007
4/27/2007
4/26/2007
4/25/2007
4/24/2007
4/23/2007
4/22/2007
4/20/2007
4/19/2007
4/18/2007
4/17/2007
4/16/2007
4/15/2007
4/14/2007
4/12/2007
4/11/2007
4/10/2007
4/9/2007
4/8/2007
4/6/2007
4/5/2007
4/4/2007
4/3/2007
4/2/2007
4/1/2007
3/30/2007
3/29/2007
3/28/2007
3/27/2007
3/26/2007
i want the last date for all the months listed. that
would be
6/29/2007 -- last day for june
5/31/2007-- last day for may
4/30/2007-- last day for april
3/30/2007-- last day for march and so on
thankswrite query as
SELECT LAST_DAY(TO_DATE(SUBSTR(COLUMN_NAME,X),'MM/DD/YYYY'))
FROM TABLE_NAME

Generating the last day of the week

HI All,
I have the Year value (for eg 2002, 2006) and the week number value in the year ( for eg : 32, 52) . Based on this information, how can I get the last day of the particular week.
for eg What is the last day of the week - 2002,32
Any pointer would be great.
Thanks and Regards
Venkat

Or try this:
SQL> WITH t AS
     (SELECT 2006 YEAR, 1 week
        FROM DUAL
      UNION ALL
      SELECT 2002 YEAR, 32 week
        FROM DUAL
      UNION ALL
      SELECT 2005 YEAR, 52 week
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      UNION ALL
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Have a Daily transaction fact where unit cost of product is stored at a day/part num /business unit level.
When we drag and drop date column and unit cost in the report like below we will have
Date      cost
Sep29     $10
sep30     $12
Oct1       $12
Oct2       $14
..........ans so on
The source sustem program runs on last day of the month around 8pm for setting up cost to reflect on 1st of every month
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But actually speaking, on Sep30 the cost was $10.
There is no way of running the ERP program to run afer OBI load. Hence we need an expression in the RPD (not answers) saying
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Is this possible without impacting report performance ?
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sep29     $10
sep30     $10
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Oct2       $14
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The solution requires to have a union report
First part of the report will have Date and Cost fields with a report level date filter, Date NOT IN (TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_MONTH , 1, TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE))))
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Change the column formula for Date to display only Current_Date
Change the column formula for Cost field with FILTER(Cost USING Date = Current_Date-1)
Pls mark if correct/helpful.

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Dear all,
Request to help me in understanding how we can calculate the currency translation rate as per the last day if the acquistion month..
For Example if the Acquistion date : 01/01/2008 (mm/dd/yyyy) the currency translation should happend based on the rate maintained as on 31/01/2008.
Thanks
Pavan Kumar Prakhya

First, you will need to convert the actual acquisition date to the end date of the Fiscal Period. This can be done by using two separate Function Modules. First, get the actual Fiscal Period by entering the date and Fiscal Year Variant into the DATE_TO_PERIOD_CONVERT Function Module. Use the Fiscal Year and Fiscal Period from this and determine the end date of the Fiscal Period by using Function Module LAST_DAY_IN_PERIOD_GET with Fiscal Year, Fiscal Period and Fiscal Year Variant as your inputs.
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How to get the last day of the next month?

Hi all.
I need to get the last day of the next month. E.g. if the date is 20.03.2008 I need to get 30.04.2008.
Is there any FM for it?
TIA, Nikolai.

hi Nikolai,
pls. have a look athe following piece of code:
PARAMETERS : p_date TYPE sy-datum.
DATA : gv_res TYPE sy-datum.
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EXPORTING
*   DAYS              = '0'
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