Trim With Outer Join in where

Getting an error called Invalid relational Operator
SELECT DISTINCT t1.recv_order_no, t2.reference_no
FROM receiving_order t1, receiver_num t2
WHERE TRIM(t2.reference_no) (+) = TRIM (t1.recv_order_no)
ORDER BY t2.reference_no ASC
What I am doing wrong here ?
Can I use trim fun with outer join ?
Thanks for help.
Srini

Hi Srini,
I have done this with emp and dept
Following is an example:
1 select a.deptno, b.ename
2     from dept a, emp b
3*   where trim(a.deptno) = trim(b.deptno(+))
scott>/
    DEPTNO ENAME
        10 CLARK
        10 KING
        10 GHULAM
        10 MILLER
        20 SMITH
        20 ADAMS
        20 FORD
        20 SCOTT
        20 JONES
        30 ALLEN
        30 BLAKE
        30 MARTIN
        30 JAMES
        30 TURNER
        30 WARD
        40Hope this helps
Ghulam

Similar Messages

Generate a where clause with outer join criteria condition: (+)=

Hi,
In my search page, I use Auto Customization Criteria mode, and I build where clause by using get Criteria():
public void initSrpQuery(Dictionary[] dic, String userName) {
int dicSize = dic.length;
StringBuffer whereClause = new StringBuffer(100);
Vector parameters = new Vector(5);
int clauseCount = 0;
int bindCount = 1;
for(int i=0; i < dicSize; i++){
String itemName = (String)(dic.get(OAViewObject.CRITERIA_ITEM_NAME));
Object value = dic[i].get(OAViewObject.CRITERIA_VALUE);
String joinCondition = (String)dic[i].get(OAViewObject.CRITERIA_JOIN_CONDITION);
String criteriaCondition = (String)dic[i].get(OAViewObject.CRITERIA_CONDITION);
String criteriaDataType = (String)dic[i].get(OAViewObject.CRITERIA_DATATYPE);
String viewAttributename = (String)dic[i].get(OAViewObject.CRITERIA_VIEW_ATTRIBUTE_NAME);
String columnName = findAttributeDef(viewAttributename).getColumnNameForQuery();
if((value != null) /*&& (!("".equals((String).trim())))*/){
if(clauseCount > 0){
whereClause.append(" AND ");
whereClause.append(columnName + " " + criteriaCondition + " :");
whereClause.append(++bindCount);
parameters.addElement(value);
clauseCount++;
If I want to generate following where clause:
select
,emp.name
,emp.email
,emp.salesrep_number
,comp.name
,gs.srp_goal_header_id
,gs.status_code
,gs.start_date
,gs.end_date
from g2c_goal_shr_emp_assignments_v emp
,jtf_rs_salesreps rs
,xxg2c_srp_goal_headers_all gs
,cn_comp_plans_all comp
where 1 = 1
and rs.salesrep_id = gs.salesrep_id (+)
and gs.comp_plan_id = comp.comp_plan_id (+)
and gs.period_year (+) = :1 -- :1 p_fiscal_year
How can I generate a where clause with outer join : gs.period_year (+) = :1 ? Will I get '(+)=' from get(OAViewObject.CRITERIA_CONDITION)?
thanks
Lei

If you are using SQL-Plus or Reports you can use lexical parameters like:
SELECT * FROM emp &condition;
When you run the query it will ask for value of condition and you can enter what every you want. Here is a really fun query:
SELECT &columns FROM &tables &condition;
But if you are using Forms. Then you have to change the condition by SET_BLOCK_PROPERTY.
Best of luck!

Help requried with outer joins

Hi All,
I neeed a query help can any one please help me getting this done,
for the below query
select trunc(assumed_time_sql) AS date1,sum(rp.rebate_due)as sum1 from mn_date_dim dd ,mn_rebate_payment rp,mn_prc_program prc,mn_structured_doc sd
where trunc(assumed_time_sql) in (TO_DATE('01-JUL-10','dd-mon-yy'),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-3),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-6),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-9))----input parameter
AND trunc(dd.assumed_time_sql)=TRUNC(rp.start_date)
AND prc.prc_program_id=rp.tiered_rebate_id
AND sd.struct_doc_id=prc.struct_doc_id
AND sd.struct_doc_id_num='M0000763'----input parameter
group by trunc(assumed_time_sql);
I am getting output as
date1      sum1
01-JAN-10      10
01-APR-10     15
01-JUL-10     20
But i want my output to be as
date1      sum1
01-JAN-10      10
01-APR-10     15
01-JUL-10     20
01-OCT-09 NULL
I have tried with outer joins but this didn't help me
Can any one please give me help in getting this done
Thanks

Hi,
As SB pointed out, you'd better provide tables and data in order to be helped more efficiently.
Anyway, you may want to investigate the use of NVL and/or DECODE so that you can translate NULL into valid values so they are returned to your select statement.
HTH,
Thierry
Handle: p78
Status Level: Newbie (10)
Registered: Mar 9, 2009
Total Posts: 60
Total Questions: 35 (30 unresolved) Be kind to share your helpful / correct threads with other with marking them as ANSWERED
Edited by: Urgent-IT on Feb 13, 2011 11:00 AM

Group by with outer join

Group by sum doesn't work with outer join. Can anyone please help me to get it right?
I've posted some sample data and queries below:
CREATE TABLE COMPLAINT
CNO     NUMBER,
REASON VARCHAR2(15 BYTE),
TOTAL   NUMBER
Insert into COMPLAINT
   (CNO, REASON, TOTAL)
Values
   (1, 'edge', 250);
Insert into COMPLAINT
   (CNO, REASON, TOTAL)
Values
   (2, 'edge', 250);
Insert into COMPLAINT
   (CNO, REASON, TOTAL)
Values
   (3, 'brst', 300);
Insert into COMPLAINT
   (CNO, REASON, TOTAL)
Values
   (4, 'crea', 400);
COMMIT;
CREATE TABLE SCOTT.COMPLAINTROLL
CNO   NUMBER,
ROLL VARCHAR2(15 BYTE)
SET DEFINE OFF;
Insert into COMPLAINTROLL
   (CNO, ROLL)
Values
   (2, 'roll22');
Insert into COMPLAINTROLL
   (CNO, ROLL)
Values
   (1, 'roll4');
Insert into COMPLAINTROLL
   (CNO, ROLL)
Values
   (1, 'roll3');
Insert into COMPLAINTROLL
   (CNO, ROLL)
Values
   (1, 'roll2');
Insert into COMPLAINTROLL
   (CNO, ROLL)
Values
   (1, 'roll1');
COMMIT;
select * from complaint
CNO     REASON     TOTAL
1     edge     250
2     edge     250
3     brst     300
4     crea     400
select * from complaintroll
CNO     ROLL
1     roll1
1     roll2
1     roll3
1     roll4
2     roll22
-- total of reason code edge is 500
select reason,sum(total)
from complaint c
group by reason
REASON     SUM(TOTAL)
brst     300
crea     400
edge     500
-- total of reason code edge after outer join is 1250
select reason,sum(total)
from complaint c,complaintroll cr
where c.cno=cr.cno(+)
group by reason
REASON     SUM(TOTAL)
brst     300
crea     400
edge     1250
{\code}
Thanks for reading this post.

The problem that you described is simple. The outer join duplicates all the rows from the parent table (complaint). If you want to sum a column from the parent table, then this sum includes all the duplicated rows.
There are several solutions for this problem.
A) One had been shown already by Cenutil. Instead of doing an outer join, you can do a subquery in the select clause that delivers the additional information from the detail table.
SQL> select reason,
   sum(total),
   sum((select count(*) from complaintroll cr where c.cno=cr.cno)) cnt_rolls
from complaint c
group by c.reason;
REASON          SUM(TOTAL) CNT_ROLLS
crea                   400          0
brst                   300          0
edge                   500          5b) sum in two steps. First sum and count including the join criteria, then use this information to calculate the correct total sum.
SQL> select reason, sum(stotal), sum(stotal/scount), sum(scount), sum(cnt_rolls)
2 from (select reason, sum(total) stotal, count(*) scount, count(cr.cno) cnt_rolls
3         from complaint c
4         left join complaintroll cr on c.cno=cr.cno
5         group by reason, c.cno
6         )
7   group by reason;
REASON          SUM(STOTAL) SUM(STOTAL/SCOUNT) SUM(SCOUNT) SUM(CNT_ROLLS)
crea                    400                400           1              0
brst                    300                300           1              0
edge                   1250                500           5              5
sql> c) another option is to do the left join, but do the aggregation only one time for the parent table. Analytic functions are helpful for that. However since analytic fuinctions can't be used inside an aggregation function, we would again need an inline view.
SQL> select reason, sum(case when rn = 1 then total end) sum_total, count(*), count(crcno)
2 from (select row_number() over (partition by c.reason order by c.cno) rn,
3                   c.*, cr.cno crcno
4         from complaint c
5         left join complaintroll cr on c.cno=cr.cno
6         )
7 group by reason;
REASON           SUM_TOTAL   COUNT(*) COUNT(CRCNO)
brst                   300          1            0
crea                   400          1            0
edge                   250          5            5
SQL> Edited by: Sven W. on Feb 10, 2011 1:00 PM - formatting + column added to 2nd option

Update with Outer Join, round 2

Thanks for those of you who helped me out on the first one (I never thought that you could use a one-row SELECT like that).
However, here is a new version of my problem:
I have three tables.
Table_1 has a column that needs to be updated based on values in Table_2 and Table_3.
Both Table_1 and Table_2 have values used to determine which Table_3 row to use.
However, not every Table_1 row has a corresponding Table_3 row, in which case the Table_3 value to use is assumed to be 1.
The tables and corresponding columns are:
TABLE_1
value_1 - the value to be updated
key_2 - a pointer to TABLE_2
key_3a - a pointer to TABLE_3, or a dummy value if there is no corresponding TABLE_3 record
TABLE_2
key_2 - the primary key
key_3b - a secondary pointer to TABLE_3
value_2 - a value to be used in calculating TABLE_1.value_1
TABLE_3
key_3a - the first part of the unique key
ley_3b - the second part of the unique key
value_3 - a value to be used in calculating TABLE_1.value_1
If there is a row in table_3 that matches the table_1.key_3a and table_2.key_3b values (where table_2.key_2 = table_1.key_2):
set table_1.value_1 = table_2.value_2 * table_3.value_3
If there is no such row in table_3:
set table_1.value_1 = table_2.value_2
I want to do something like this:
UPDATE table_1 t1
SET value_1 =
SELECT t2.value_2 * NVL(t3.value_3, 1)
FROM table_2 t2
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
WHERE t2.key_2 = t1.key_2
However, Oracle does not allow t1 to be referenced in the ON clause of the outer join.
(Assume that every key_2 value in table_1 is in table_2 as well - it is only the key_3 value that can be a dummy.)
If I move "t3.key_3 = t1.key_3" to the WHERE clause, then t1.value_1 is null for rows without the corresponding table_3 value.
I can do it with a clone of table_1 using ROWIDs:
UPDATE table_1 t1
SET value_1 =
SELECT t2.value_2 * NVL(t3.value_3, 1)
FROM table_1 t1a
JOIN table_2 t2
ON t2.key_2 = t1a.key_2
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1a.key_3a)
WHERE t1a.row_id = t1.row_id
However, is there an easier way to do this using ANSI joins (i.e. without (+) syntax)?
I have this feeling I am missing something reasonably obvious here.

ddelgran wrote:
Thanks for those of you who helped me out on the first one (I never thought that you could use a one-row SELECT like that).
I want to do something like this:
UPDATE table_1 t1
SET value_1 =
SELECT t2.value_2 * NVL(t3.value_3, 1)
FROM table_2 t2
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
WHERE t2.key_2 = t1.key_2
However, Oracle does not allow t1 to be referenced in the ON clause of the outer join.
(Assume that every key_2 value in table_1 is in table_2 as well - it is only the key_3 value that can be a dummy.)
If I move "t3.key_3 = t1.key_3" to the WHERE clause, then t1.value_1 is null for rows without the corresponding table_3 value.
I can do it with a clone of table_1 using ROWIDs:
UPDATE table_1 t1
SET value_1 =
SELECT t2.value_2 * NVL(t3.value_3, 1)
FROM table_1 t1a
JOIN table_2 t2
ON t2.key_2 = t1a.key_2
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1a.key_3a)
WHERE t1a.row_id = t1.row_id
However, is there an easier way to do this using ANSI joins (i.e. without (+) syntax)?
I have this feeling I am missing something reasonably obvious here.You might want to refer to my post in your original thread how to use join views in updates. You can use ANSI join syntax there, too:
Re: Update with Outer Join
You would end up with something like this (note: untested):
UPDATE
SELECT t1.value_1, t2.value_2 * NVL(t3.value_3, 1) as new_val
FROM table_1 t1
INNER JOIN table_2 t2 ON (t2.key_2 = t1.key_2)
LEFT JOIN table_3 t3
ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
SET value_1 = new_val;And again the same restrictions regarding key-preserved tables apply as described in the post referred to.
Regards,
Randolf
Oracle related stuff blog:
http://oracle-randolf.blogspot.com/
SQLTools++ for Oracle (Open source Oracle GUI for Windows):
http://www.sqltools-plusplus.org:7676/
http://sourceforge.net/projects/sqlt-pp/

How to poll a blob using db adapter, with outer joins condition

Hi All,
We are trying to poll tables which contain column types as long and blob, we are using relationships in adapter and kept outer joins. by this we got select distinct t1.document .....etc
distinct keyword cannot be used for blobs.
is there any way to poll these tables having blob column types with outer joins.
thanks a lot in advance,
RR

Hi,
Procedure will be an explicit Invoke not Polling. If you can alter you design such that your BPEL process instead of polling gets triggered by some external entity (Java, PL/SQL, Scheduler, another BPEL etc.), you can put the data fetching logic in the procedure and call this procedure from your BPEL process to get the data. And your BPEL process is called periodically at an interval by an external entity.
Also see if you can restrict the duplicate records at the database level itself. Polling, AFAIK, is limited in terms of customization and wouldn't be easy to customize. However, would like to learn a way if someone has.
Regards,
Neeraj Sehgal

Absolute dynamic select query with dynamic join and where

Has anyone ever tried creating an absolutely dynamic SELECT query with dynamic Join and Where conditions.
I have a requirement of creating such a query in an Utility Class, and i have written the code. But its throwing my sysntax errors.
Please let me know where am I going wrong OR is it really possible to create such a dynamic Query??
    SELECT (FIELDS) INTO TABLE IT_TABLES
      FROM ( (ME->TABLE1) inner join ( me->table2 )
      on ( on_condition ) )
      WHERE (me->where_fields).
Ags.

It worked for me in a following way:
select * into corresponding fields of table <result_table>
        from (join_string)
        where (l_where).
Where the contents of join_string were dynamically build using concatenation. So it will be something like
concatenate ME->TABLE1 'as a INNER JOIN' me->table2 'as b ON (' into join_string separated by space.
<...>
add here matching/reference colums, something like
concatenate 'a~' me->TABLE1_JOIN_COL into temp1.
concatenate 'b~' me->TABLE2_JOIN_COL into temp2.
concatenate join_string temp1 '=' temp2 into join_string separated by space.
<...>
concatenate join_string ')' into join_string separated by space.
And then use similar approach for l_where variable.

How to use common object from two tables with out join.

HI,
I have two tables called A & B In A table i have the following objects
1.weekend
2.S1(measure)
3.S2(measure)
4.S3(measure)
5.S4(measure)
And In B table i have followning columns
1.week end
2.p1(measure)
3.p2(measure)
4.p3(measure)
5.p4(measure)
Now in universe i created all the measure objects i.e.s1,s2,s3,s4,p1,p2,p3,p4 A.weekend,B.weekend.
instead of using week end two times i wnt to use only once because this is common in both table.
if i use join between these tables i am getting values fine
But With out join is there any thing to do in universe level to create common objects to use from both the tables..I tried using aggregate awareness but while reporting it is taking as two SQL.which is not synchronized.
Please help me on this ...

hi,
Although Weekend column is present in both tables, by creating a single Object in Universe, Universe can identify relationship with only table referenced in Object Creation.
So, there will be no identification of relationship with other table measures.
Obviously, you need to create 2 Weekend objects in Universe (in two classes).
Case 1: You need not join these two tables in Universe. When you create 2 Queries in WEBI, automatcially Weekend objects are synchronized (if both are of same datatype)
Case 2: If you join these two tables in Universe, Obviously,
your SQL may contain Weekend from Table1, measures from Table 2
or
your SQL may contain Weekend from Table2, measures from Table 1
Finally, You need to create 2 objects in Universe. But your query may contain a single Object based on Case 2.
Regards,
Vamsee

Problem with outer join with filter on join column

Hi,
In physical layer I have one dimension and two facts, and there's an outer join between the facts.
dim_DATE ,
fact_1 ,
fact_2
Joins:
dim_DATE inner join fact_1 on dim_DATE.DATE = fact_1.DATE
fact_1 left outer join fact_2 on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
When I run a report with a date as a filter, OBIEE executes "optimized" physical SQL:
select fact1.X, fact2.Y
from
Fact_1 left outer join on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
where Fact_1.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD' )
and Fact_2.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD')
The filter on Fact_2.DATE effectively replaces outer join with inner.
Is there a way to disable this "optimization", which is actually very good for inner joins, but doesn't allow outer joins?
Thanks in advance,
Alex
Edited by: AM_1 on Aug 11, 2009 8:20 AM

If you want to perform a Fact-based partitioning with OBIEE (two fact with the same dimension), you have to :
* create in your physical layer for each fact table the joins with the dimension
* create in the Business Model layer ONE star schema with ONE logical fact table containing the columns of your two physical fact table
In this way when you choose minimal one column of your fact1 and one column of your fact2, OBIEE will perform two query against each fact table/dimension, join them with an OUTER JOIN and your problem will disappear.
Cheers
Nico

Use of db link in subquery with outer join

I have a query where i am using db link to get data from another database.
I have an outer join where i am using a subquery using the same db link but it fails gives me the error:
ORA-00991: illegal use of LONG datatype.
But the same query with inner join is not giving me the error.
Is this a limitation of Oracle or am I doing something wrong.

This is an example of what i am running. That last outer join does not work c.acad_plan(+).
select count(1)
from ( select a.* from cb001_tbl a where a.strm='1800' ) a ,
( select distinct emplid,national_id,strm, acad_plan, acad_career from ps_uhcb_001@SAPRD where institution='00730') b ,
( select * from ps_acad_plan_tbl@SAPRD a
where a.institution='00730'
and a.eff_status='A'
and a.effdt=(select max(b.effdt) from ps_acad_plan_tbl@SAPRD b
where a.institution=b.institution
and a.acad_plan=b.acad_plan
and b.effdt<=to_date(20100514,'yyyymmdd'))) c
where a.stdnt_id=b.national_id (+)
and a.strm=b.strm (+)
and b.acad_plan=c.acad_plan (+)

Tabular form from query with outer join destroys the universe!

Well, maybe just my app...
At any rate, what I have is a query that pulls RISKS for a project and does a reasonable outer join which joins the latest value from a RISK_HISTORY table. Values for RISK are updated and the value for RISK_HISTORY is changed and a new entry added to the RISK_HISTORY table.
At least that's how it's supposed to be.
I was able to do this with a report-with-a-form region by adding an extra update process to do a new insert into RISK_HISTORY but it seems that the tabular form is a bit more work.
Here's the query I'm using:
select * from(
select
r.RISK_SEQ RISK_SEQ_DISPLAY,
r.RISK_PRIORITY,
r.RISK_INFO,
r.RISK_MITIGATION,
r.ONGOING_FLAG,
r.RISK_DATE,
r.WEEK_GROUP_SEQ,
r.CREATED_ON,
r.CREATED_BY,
r.LAST_MODIFIED_ON,
r.LAST_MODIFIED_BY,
rh.STATUS,
row_number() over (partition by rh.risk_seq order by rh.last_modified_on desc) rn
from RISK r, WEEK_GROUP w, RISK_HISTORY rh
where w.PROJECT_SEQ=43
and r.week_group_seq= w.week_group_seq
and w.week_index=0
and rh.RISK_SEQ = r.RISK_SEQ
) where rn = 1
Clicking "Add Row" gets me this:
Error in mru internal routine: ORA-20001: no data found in tabular form
Running debug doesn't seem to expose much for me either. Is there a better tact for me to take here?
Thanks,
Jon

Hi Prazy,
using nvl also didn't solve my problem.Actually my problem is I am having a table a in which I have a column called satus, status has the values like A or I .I have one lookup called MTH_BUYSINESS_FUNCTION in which for lookup_code A I have menaing as Active and for lookup_code I meaning is Inactive.Now in table a for sttaus I have two values one A and one null Now I want to write sql which displayes the meaning for column staus.Result should be Active and null .If I am uisng 1 query which I gave u I am not able to get the 2nd row in my output.If I use 2nd query then I get duplicate rows.
Thanks ,
Amrit

Help with outer joins in Oracle!!

so far this is what i've come up with and the code below does not work. Can anyone please help me on how the sytanx of left joins and how to use multiple left joins in a single query in oracle?
SELECT a.*, b.Position_CD, c.Skill_CD, d.Team_Name, d.Team_Country, d.Club, e.Structure_Name
FROM Roster a, Roster_position b, roster_skill c, Team d, Team_Structure e
where (a.Roster_ID = ((b.Roster_ID= c.Roster_Id(+)) b.roster_id(+)).......
I dont' know how to add more left joins!
Here is the query I'm trying to duplicate (which is a query from Ms Access databaase which works fine).
SELECT a.*, b.Position_CD, c.Skill_CD, d.Team_Name, d.Team_Country, d.Club, e.Structure_Name
from ((Roster a LEFT JOIN (Roster_Position b LEFT JOIN Roster_Skill c ON b.Roster_ID=c.Roster_ID) ON a.Roster_ID=b.Roster_ID) LEFT JOIN Team d ON a.Team_CD=d.Team_CD) LEFT JOIN Team_Structure e ON a.Team_Structure_CD=e.Team_Structure_CD
ORDER BY a.Roster_Id;
Any help or comments are greatly appreciated

First,
I am not one of the leading SQL brains here...but I'm taking a stab, nonetheless.
Second,
Here's my best guess - and it seems to me that it should work as there are not two outer joins between any two tables. I hope I decoded your joins correctly - quite a mess that Access syntax!
SELECT a.*, b.position_cd, c.skill_cd, d.team_name, d.team_country, d.club, e.structure_name
FROM ROSTER a, ROSTER_POSITION b, ROSTER_SKILL c, TEAM d, TEAM_STRUCTURE e
WHERE a.roster_id = b.roster_id(+)
AND b.roster_id = c.roster_id(+)
AND a.team_cd = d.team_cd(+)
AND a.team_structure = e.team_structure(+);Third,
As an architect-dude, it seems to me that you have a serious
modeling problem to need so many outer joins in such a basic
grab of data. In any scale other than minute, the performance
of this model will suffer dramatically. Specifically, why can't
ROSTER have an equijoin with TEAM and with TEAM_STRUCTURE - as they
appear to be lookup tables...
Good Luck
(I'm certain you'll get better SQL from the others),
Michael O'Neill
Publisher of the PigiWiki
clever-idea.com

Update with Outer Join

Is it possible to do an update that involves an outer join on the table being updated?
Here's what I mean - currently, I have something like:
UPDATE table_1 t1
SET col_1 =
SELECT t2.col_2
FROM table_2 t2
WHERE t2.t1_key = t1.t1_key
WHERE EXISTS
SELECT t2.*
FROM table_2 t2
WHERE t2.t1_key = t1.t1_key
UPDATE table_1 t1
SET col_1 = 0
WHERE NOT EXISTS
SELECT t2.*
FROM table_2 t2
WHERE t2.t1_key = t1.t1_key
Yes, I could do set all of the table_1.col_1 values = 0 first, and then do the first update, but it is inefficient given the number of records in the table that would be updated twice.
Is there a way of combining these two updates into a single update statement?

You could simply use your first update and omit the WHERE EXISTS clause since you want to update all the rows in table_1 anyway.
If the subquery finds a match, it will update with the selected value. Normally, a non-match would set the column to a null but you can solve that with NVL:
SQL> select * from table_1;
              T1_KEY                COL_1
                   1                    1
                   2                    1
                   3                    1
                   4                    1
                   5                    1
                   6                    1
                   7                    1
                   8                    1
                   9                    1
9 rows selected.
SQL> select * from table_2;
              T2_KEY                COL_2
                   1                    9
                   3                    9
                   5                    9
SQL> UPDATE table_1 t1
2 SET    col_1 = nvl (
3                       (SELECT t2.col_2
4                        FROM   table_2 t2
5                        WHERE t2.t2_key = t1.t1_key
6                       ),0
7                     )
8 ;
9 rows updated.
SQL> select * from table_1;
              T1_KEY                COL_1
                   1                    9
                   2                    0
                   3                    9
                   4                    0
                   5                    9
                   6                    0
                   7                    0
                   8                    0
                   9                    0
9 rows selected.

Issue with Outer Join (Possible Bug)

Hi,
I am using Toplink 10.3.3 with oracle as db. I noticed that if I use outer joins with collections, then toplink doesnt add (+) sign to the where clause of the collection.
For e.g. for a relationship - Employee has projects, if I do an outer join on projects and also provide a where clause for projects collection, the query doesnt include the (+) sign in it.
Expression expr = builder.anyOfAllowingNone("projects").getAllowingNull("anotherOne-OneMapping").get("attr").equal("Value")
This expr goes in the where clause and TopLink does not generate (+) in the query alongside attr = "Value"
I have tried this from workbench as well as Java. Could anyone please confirm that the above scenario works? May be this is a bug in toplink !
TIA
Ani

I too have found a few bugs with full outer joins. Many of them have been fixed in 9iR2 though.
Like this one simple one on unpatched 9iR1: select foo1.x, foo2.x
from foo1 full outer join (select * from foo2 where x = :bindx) foo2 on (foo1.y = foo2.y)
ERROR at line 2:
ORA-00600: internal error code, arguments: [qctcte1], 0], [], [], [], [], [], []Fixed here: Hdr: 2458655 9.0.1.3.0 RDBMS 9.0.1.3.0 SQL LANGUAGE PRODID-5 PORTID-453
Abstract: ORA-600 [QCTECTE1] ON QUERY WITH FULL OUTER JOIN AND BIND VARIABLES

View with outer join results wrong number of rows

Hi,
When i run a query on a view it returns 2 rows(2 distinct rows), when i run the same query with the select statement which the view is created , it returns only 1 row. According to data the 1 row result is correct, how come twi results. A coding sample as follows. Any help is most appreciated.
I have a view created based on a outer join of two views in the format;
create or replace view view1 as
select ord.order_no order_no,
ord.del_type del_type,
det.qty qty
from detail_view det, order_view ord
where det.site(+) = ord.site
and det.part(+) = ord.part
and nvl(ord.del_type,'_NULL_') <> 'F'
with read only;
detail_view & order_view themselves have several group by/sum and union Alls.
When i run the query on this view
[Select * from View1 where order_no = 'A30' And del_type = 'B']
it returns 2 distinct rows. But when i run the select statement which created the View1 with the query it returns only one row!!
What did i do wrong?
Thanks
Sanjeewa

I cannot reproduce this :
SCOTT@LSC01> create table detail_view(qty number,site number,part number);
Table created.
SCOTT@LSC01> create table order_view(order_no varchar2(10), del_type varchar2(1), site number,part number);
Table created.
SCOTT@LSC01>
SCOTT@LSC01> create or replace view view1 as
2 select ord.order_no order_no,
3 ord.del_type del_type,
4 det.qty qty
5 from detail_view det, order_view ord
6 where det.site(+) = ord.site
7 and det.part(+) = ord.part
8 and nvl(ord.del_type,'_NULL_') <> 'F'
9 with read only;
View created.
SCOTT@LSC01>
SCOTT@LSC01> insert into order_view values ('A30','B',1,2);
1 row created.
SCOTT@LSC01> insert into order_view values ('A30','B',1,2);
1 row created.
SCOTT@LSC01>
SCOTT@LSC01> Select * from View1 where order_no = 'A30' And del_type = 'B';
ORDER_NO   D        QTY
A30        B
A30        B
SCOTT@LSC01>
SCOTT@LSC01> select ord.order_no order_no,
2 ord.del_type del_type,
3 det.qty qty
4 from detail_view det, order_view ord
5 where det.site(+) = ord.site
6 and det.part(+) = ord.part
7 and nvl(ord.del_type,'_NULL_') <> 'F' ;
ORDER_NO   D        QTY
A30        B
A30        Bwhat is your version?

Trim With Outer Join in where

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