Unable to insert record in child block

Dear all,
I am facing a very strange problem.
Actually i have a master-detail form where i need to insert master record as well as child records for the corresponding master item.
For this i have a LOV in master block which populate the master item and execute the coresponding child records.
so first time when i load the form i select a item from master block through a LOV this time :SYSTEM.BLOCK_STATUS is NEW and i populate a item from LOV then :SYSTEM.BLOCK_STATUS is NEW changed to query and i have inserted a next record in child block pressed F10 and it saved very well.
But the problem is when i again select another item from master block through LOV and again tried to insert a record in child record this time it won't saved and the very stragly the cusor moved to master item showing the FRM-40600'Record has already been inserted'
Please help why is it happening ?
Need yours help.

But the problem is when i again select another item from master block through LOV and again tried to insert a record in child record this time it won't saved and the very stragly the cusor moved to master item showing the FRM-40600'Record has already been inserted'When you select a new record in the Master block through the LOV, make sure you clear your form before you query the selected record. Forms thinks you are modifying the same master record and not a new record.
Hope this helps,
Craig B-)
If someone's response is helpful or correct, please mark it accordingly.

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Unable to INSERT record but inserting. Forms 4.5 error through Apps 10.7

Hi All,
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===========
FRM-40508: ORACLE error: unable to INSERT record.
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===========
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================================================
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i          number;
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v_temp      varchar2;
v_user_id NUMBER := 1111; --fnd_global.user_id;
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BEGIN
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END LOOP;
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message('After Insert Child');
COMMIT;
END;
================================================

not sure on the block structure of your forms.
one would question why you seem to be doing a lot of the default insert work on the press of a button (when-button-pressed).
also if you have a master-detail relationship in the form - why you don't let forms handle the master-detail insert.
seems like you have database database blocks but are almost coding as if they are non-base table blocks.

[SOLVED] FRM-40508:ORACLE error: unable to INSERT record

Hi all,
I have migrated this form from 4.5 to 10g (Version 10.1.2.0.2 ). This form inserts a record into the database table when all the fields in the form are filled and a button Save is presed.
At the time when I press the Save button, I get this error. FRM-40508:ORACLE error: unable to INSERT record
So I went on to see the "Display Error" from help and found to be the database error, inserting into a table.
The error message is ORA-00932: inconsistent datatypes: expected DATE got NUMBER
The form where I press Save button has 3 date fields and I checked the properties of them and they are Date only.
I also generated to object list report and tried to find some answer, but no use.
Please help me in debugging this form.
Edited by: Charan on Aug 18, 2011 4:05 PM

I think you need to get a description of the table and compare all the "database" columns in the form with the ones in the database table to see that the types match. Somewhere there's a mismatch. Also check the block(s) "query data source columns" and see if there's any
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Updating detail record and getting multiple 'UNABLE TO INSERT RECORD' msgs

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The UNABLE TO INSERT record will be accompanied by more information if you press the Display Error key. Your form commit processing should stop when it gets an error like this, the fact that it doesn't implies that somewhere in your code you are not checking for FORM_SUCCESS before continuing doing something else.
This sounds quite involved, we would need to have more information about what records are queried and what's being changed on them to cause the commit.

Oracle forms error frm-40508: unable to insert record

Hi Everyone,
I have been having this problem for 2 weeks and I realize that I spent alot of time I couldn't get to fix the problem so I need your help.
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frm 40735:When button pressed trigger raised unhanded exceptionplease help me to solve this>
The FRM-40735 is a generic Unhandled Exception. Please post the full error message so we can better help you.
Craig B-)
If someone's response is helpful or correct, please mark it accordingly.

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Hi
when trying to insert a record in a form builder application I getted the following
error
FRM-40508: ORACLE error: unable to INSERT record.
Is the reason that I have not the authority to enter by by system account althought
I have granted dba to scott and that successed ?
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thanks for adavance

volberg wrote:
in most cases you forget a required field.
Press Shift+F1 to get the error message in detailsql statements in error
INSERT INTO STUDENTS(STUD_ID,STUD_NAME) VALUES (:1,:2)
error
ORA-00001: unique constraint (ELHADI.SYS_C005462) violated
Edited by: VANPERSIE on Aug 29, 2008 5:16 PM

Unable to INSERT record : ERROR

SR # : 3-2184192641
RMS Version 13.1.3
Form : dealmain.fmb
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On looking into detail error the following message is displayed
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create_datetime,last_update_datetime,last_update_id) values(1,:2,:3,:4,:5,:6,:7,:8,:9,:10,:11)."
Please advice.

Are the values for the columns being supplied from the application? If so check the formats of the columns and corresponding values of the same. If they are matching then check whether a null being inserted for a not null column..
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Give the complete details of the columns, their properties and the values being inserted into the table.
Regards,
Sandy.

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Hi,
I am using Jdeveloper 11.1.2.0. I have two master table one child table.
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Thanks in Advance
Edited by: 890233 on Dec 24, 2011 10:40 PM

... And here is the example to insert using sequenceimpl by getting the primary key of the master record and insert master and detail together.
Re: Unable to insert a new row with a sequence generated column id
-Arun

Unable to Insert record In forms: error -ORA-01779 :cannot modify a column

Hi,
I have created one form with two block.
Block-1 : Based on View
Block-2 : Based on table
There is is relationship between Block-1 and Block-2.
Block-1 is populating from LOV.
I just need to insert /update record Block-2 based on data from Block-1
So Block-1 I have made read only at runtime (Inser/update all properties are false).
Now when I insert record in Block-2 based on record from block-1, and getting below error.
"ORA-01779: cannot modify a column which maps to a non key-preserved table"
It is not allowing to insert record.
Please help me.
Subir

The error states that there is some operation on a view, not an a table.
Now when I insert record in Block-2 based on record from block-1What does that mean? How do you insert records in block 2?
When exactly occurs the error?

Unable to insert .flv Template Child Pages

Unable to insert .flv Flash video in template pages
When you attempt to insert a Flash Video file (.flv) into a
child page created from a Dreamweaver template, you see the
following error message: "Making this change would require changing
code that is locked by a template or a translator. The change will
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The Adobe recommended solution: “ 1. Make a parent
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This solution does not work. It doesn’t work because
the checkbox is grayed out - it is impossible to “…
uncheck the "Prompt users to download Flash Player … checkbox
What Can I do?
I want to uncheck that grayed out “Prompt” box.
How can I do that?

I am unable to duplicate what you are describing.
When you go to insert the flv, you Insert/Media/Flash
Video... and the box
is grayed out?
The unchecking of the box solves the problem, why yours is
doing that I dont
understand. I assume you are in an editable region in the
child?
Gary
"AdCracker.com" <[email protected]> wrote in message
news:gdiuj0$86g$[email protected]..
> Unable to insert .flv Flash video in template pages
>
> When you attempt to insert a Flash Video file (.flv)
into a child page
> created
> from a Dreamweaver template, you see the following error
message: "Making
> this
> change would require changing code that is locked by a
template or a
> translator. The change will be discarded."
>
> The Adobe recommended solution: ? 1. Make a parent
template page that
> already
> contains the Flash Player detection code. 2. Insert the
Flash Video into
> the
> child page created from the template, without the Flash
Player detection
> code.
> To do this, uncheck the "Prompt users to download Flash
Player if
> necessary"
> checkbox in the Insert Flash Video dialog box.?
>
> This solution does not work. It doesn?t work because the
checkbox is
> grayed
> out - it is impossible to ?? uncheck the "Prompt users
to download Flash
> Player
> ? checkbox ?
>
> What Can I do?
>
> I want to uncheck that grayed out ?Prompt? box. How can
I do that?
>
>

Unable to insert record in table

Hi,
I want to insert record in database table, but when I execute insert command(at When List changed trigger) as select from query and issue commit, the form trying to insert record from datablock which is obviously having empty items, how can I commit at database level not at form level.
*******************Below the SQL Statement issued by Form******************
INSERT INTO BILL_OF_MATERIALS_TABLE(PROJECTNO,GROUP_,ITEM,STATUS,QUANTITY,UNIT_PRICE,REASON_FOR_CHANGE,REMARKS,AWARD_COPY,LOCKED,VO_COPY) VALUES (:1,:2,:3,:4,:5,:6,:7,EMPTY_CLOB(),:9,:10,:11) RETURNING ROWID,PROJECTNO,GROUP_,ITEM,STATUS,QUANTITY,UNIT_PRICE,REASON_FOR_CHANGE,REMARKS,AWARD_COPY,LOCKED,VO_COPY INTO :12,:13,:14,:15,:16,:17,:18,:19,:20,:21,:22,:23
***************Error Raised by Form********
ORA-01400: cannot insert NULL into ("CAPEX"."BILL_OF_MATERIALS_TABLE"."ITEM")

Remember that when you write "commit;" within your forms code then Forms interprets it as a commit_form statement. That's why the form-level commit is launched as you mentionned.
So if you want to make a database commit then I think that you should create a stored procedure which makes the insert , and you call this stored procedure within your forms code.
Try it.

[Solved] Unable to insert records, trigger is showing mutating error

Friends,
I created a procedure
===>>
SQL> CREATE OR REPLACE PROCEDURE PO_RECEIVINGS_ASSETS_TR_P
2 IS
3 CURSOR CUR_LAST_DAY_RCV IS
4 SELECT * FROM PO_RECEIVINGS_INSTANT_V WHERE TRANSACTION_ID = (SELECT MAX(TRANSACTION_ID) FROM PO_RECEIVINGS_INSTANT_V);
5 BEGIN
6 FOR REC_LAST_DAY_RCV IN CUR_LAST_DAY_RCV
7 LOOP
8 FOR i IN 1 .. REC_LAST_DAY_RCV.QUANTITY
9 LOOP
10 INSERT INTO ND_TEST VALUES(REC_LAST_DAY_RCV.TRANSACTION_ID, REC_LAST_DAY_RCV.CREATION_DATE, REC_LAST_DAY_RCV.QUANTITY,
11 REC_LAST_DAY_RCV.PO_LINE_ID);
12 END LOOP;
13 END LOOP;
14 END;
15 /
Procedure created.
<<===
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===>>
SQL> CREATE OR REPLACE TRIGGER PO_RECEIVINGS_INTO_ASSETS_TR
2 AFTER INSERT ON RCV_TRANSACTIONS_ND
3 FOR EACH ROW
4 BEGIN
5 IF :NEW.TRANSACTION_TYPE = 'ACCEPT' THEN
6 PO_RECEIVINGS_ASSETS_TR_P;
7 END IF;
8 END;
9 /
Trigger created.
<<===
when I try to insert record in RCV_TRANSACTIONS_ND, I get below lines.
===>>
SQL> INSERT INTO RCV_TRANSACTIONS_ND (TRANSACTION_ID,LAST_UPDATE_DATE,LAST_UPDATED_BY,CREATION_DATE,
2 CREATED_BY,TRANSACTION_TYPE,TRANSACTION_DATE, QUANTITY, UNIT_OF_MEASURE, SHIPMENT_HEADER_ID,
3 SHIPMENT_LINE_ID,USER_ENTERED_FLAG, PO_HEADER_ID, PO_LINE_ID)
4 VALUES(1001001,SYSDATE,3572,SYSDATE,3572,'ACCEPT',SYSDATE,1,'Nos',199999,199099,'Y',133032,1679
29);
INSERT INTO RCV_TRANSACTIONS_ND (TRANSACTION_ID,LAST_UPDATE_DATE,LAST_UPDATED_BY,CREATION_DATE,
ERROR at line 1:
ORA-04091: table RCV_TRANSACTIONS_ND is mutating, trigger/function may not
see it
ORA-06512: at "PO_RECEIVINGS_ASSETS_TR_P", line 4
ORA-06512: at "PO_RECEIVINGS_ASSETS_TR_P", line 6
ORA-06512: at "PO_RECEIVINGS_INTO_ASSETS_TR", line 3
ORA-04088: error during execution of trigger
'PO_RECEIVINGS_INTO_ASSETS_TR'
<<===
Using Database 9i.

Well, I tried to solve it and it worked.
SQL> CREATE OR REPLACE PROCEDURE PO_RECEIVINGS_ASSETS_TR_P(VAL1 IN NUMBER, VAL2 IN DATE, VAL3 IN NUMBER, VAL4 IN NUMBER)
2 IS
3 BEGIN
4 FOR i IN 1 .. VAL3
5 LOOP
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7 END LOOP;
8 END;
9 /
Procedure created.
===
SQL> CREATE OR REPLACE TRIGGER PO_RECEIVINGS_INTO_ASSETS_TR
2 AFTER INSERT ON RCV_TRANSACTIONS_ND
3 FOR EACH ROW
4 BEGIN
5 IF :NEW.TRANSACTION_TYPE = 'ACCEPT' THEN
6 PO_RECEIVINGS_ASSETS_TR_P(:NEW.TRANSACTION_ID, :NEW.CREATION_DATE, :NEW.QUANTITY, :NEW.PO_LINE_ID);
7 END IF;
8 END;
9 /
Trigger created.
===
SQL> INSERT INTO RCV_TRANSACTIONS_ND (TRANSACTION_ID,LAST_UPDATE_DATE,LAST_UPDATED_BY,CREATION_DATE,
2 CREATED_BY,TRANSACTION_TYPE,TRANSACTION_DATE, QUANTITY, UNIT_OF_MEASURE, SHIPMENT_HEADER_ID,
3 SHIPMENT_LINE_ID,USER_ENTERED_FLAG, PO_HEADER_ID, PO_LINE_ID)
4 VALUES(1001001,SYSDATE,3572,SYSDATE,3572,'ACCEPT',SYSDATE,1,'Nos',199999,199099,'Y',133032,1679
29);
1 row created.
===
Thanks everyone

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hi there
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Hi
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wdContext.nodeOutput().invalidate();
}catch(Exception ex)

try
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Unable to insert record in child block

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