1d cluster array replace value in a 1d boolean array (without using Loop)

Hi ,
is there a way to replace the values (string , boolean) of a 1D array Cluster with value of 1D boolean array without using loop ?
Regards
Simone
Attachments:
111.png ‏75 KB

Replace Array Subset requires that the array elements are type compatible with the elements that you want to replace. That seems not the case in your example.
And the For Loop is anything but slow. How many billion elements do you expect your array to have to worry about performance of the for loop? With the type definition of your example even a ready made LabVIEW function would have to do internally a for loop too, since the boolean data inside the original array can not be in a continous memory area.
Maybe if you show us what you try to do with the for loop we can understand better what your concerns are. As it is from the front panel image alone it is really hard to understand what your imagined problem might be.
Rolf Kalbermatter
CIT Engineering Netherlands
a division of Test & Measurement Solutions

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w to change a single element in an array without affecting the others by using a reference in case I can use it elsewhere.

> My situation is that I have an array of clusters on the front panel.
> Each element is used for a particular test setup, so if the array size
> is three, it means we have three identical test setups that can be
> used. The cluster contains two string controls and a button: 'device
> ID' string, 'start' button and 'status' string.
>
> In order to keep the diagrams simple, I would like to use a reference
> to the array as input into a subvi. This subvi will then modify a
> particular element in the array (i.e. set the 'status' string).
>
It isn't possible to get a reference to a particular element within an
array. There is only one reference to the one control that represents
all elements in the array.
While it may seem better to use references to update
an element within
an array, it shouldn't really be necessary, and it can also lead to
race conditions. If you write to an element that has the
possibility of the user changing, whether you write with a local, a
reference, or any other means, there is a race condition between the
diagram and the user. LV will help with this to a certain extent,
especially for controls that take awhile to edit like ones that use
the keyboard. In these cases, if the user has already started entering
text, it will not be overwritten by the new value unless the key focus
is taken away from the control first. It is similar when moving a slider
or other value changes using the mouse. LV will write to the other values,
but will not rip the slider out of the user's hand.
To completely avoid race conditions, you can split the array into user
fields and indicators that are located underneath them. Or, if some
controls act as both, you can do like Excel. You don't directly type
into the cell. You choose w
hich cell to edit, but you modify another
location. When the edit is completed, it is incorporated into the
display so that it is never lost.
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How to build a cluster array dynamically from another cluster array?

I'm working on a problem where I seem to be getting lost in a sea of
possibilities, none of which strikes me as optimum. Here's what I need to do.
I've got an input array of clusters (ARR1). Each cluster contains the
following components: an integer (INT1), a ring variable (RING1), a boolean
(BOOL1) and a cluster which itself is simply a bunch of ring variables
(CLUST1) Now, I need to transform that into a set of clusters (CLUST3) each of
which contains an array of characters (CHARARY2), a copy of the ring variable
(RING2), a copy of the boolean variable (BOOL2) and a copy of the cluster
(CLUST2).
To build the CLUST3, I need to find all elements within ARR1 that have the
same unique combination of RING1 and BOOL1, and if BOOL1 is True, then RING1
in addition, build an array of all the INT1 values corresponding to each
unique combination above converted to character, and then bundle this array
plus the unique combination of the other variables into a new cluster. In
general I could have several such clusters.
So if I had the following array to start with:
Index INT1 RING1 BOOL1 CLUST1
0 3 1 F {Values1}
1 2 1 T {Values2}
2 4 0 F {Values1}
3 6 0 F {Values3}
4 1 2 T {Values2}
5 4 2 T {Values2}
6 3 0 T {Values3}
7 4 2 T {Values3}
I should end up with the following clusters:
CHARARY2 RING2 BOOL1 CLUST1
"3" 1 F Don't care
"2" 1 T {Values2}
"4","6" 0 F Don't care
"1","4" 2 T {Values2}
"3" 0 T {Values3}
"4" 2 T {Values3}
What methods would you suggest for accomplishing this easily and efficiently?
Alex Rast
[email protected]
[email protected]

Tedious but not conceptually difficult.
ARR1 goes into a for loop, auto indexed on the FOR loop. The for loop has a
shift register which will be used to build the output array. Nested within
the for loop is another for loop, which the shift register array goes into,
again auto indexed, along with the element that has been auto-indexed from
ARR1. This for loop has a shift register, initialised with a boolean "true".
The inner loop compares the current element of ARR1 with the output array
and if an element in the output array is already present which matches the
input by your criteria, then the boolean register is set false; otherwise it
is left alone.
After the nested FOR loop you have a case fed from the boolean shift
register; if the boolean is true, the new element is unique and should be
added to the array. If it is false then a previous element has been found
making the present one redundant, and the array should be passed through
without adding the element.
In the true case, you simply unbundle the original element into its
components and build the new element, using "build array".
Notes for if the above is easy for you;
1) if handling lots of data then pre-initialise the shift register of your
outer loop with the same number of elements as your input array. Use
"Replace Array Subset" instead of "Build Array" to insert the current
element into the pre-allocated memory rather than having to create a new
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the elements you've used, removing the unused ones at the end.
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for loop is more efficient since you can halt the while loop as soon as a
duplicate is found. With the described approach you have to go through the
whole array even if the first element turns out to be a duplicate- much
wasted computer time.
Alex Rast wrote in message
news:[email protected]...
> I'm working on a problem where I seem to be getting lost in a sea of
> possibilities, none of which strikes me as optimum. Here's what I need to
do.
>
> I've got an input array of clusters (ARR1). Each cluster contains the
> following components: an integer (INT1), a ring variable (RING1), a
boolean
> (BOOL1) and a cluster which itself is simply a bunch of ring variables
> (CLUST1) Now, I need to transform that into a set of clusters (CLUST3)
each of
> which contains an array of characters (CHARARY2), a copy of the ring
variable
> (RING2), a copy of the boolean variable (BOOL2) and a copy of the cluster
> (CLUST2).
>
> To build the CLUST3, I need to find all elements within ARR1 that have the
> same unique combination of RING1 and BOOL1, and if BOOL1 is True, then
RING1
> in addition, build an array of all the INT1 values corresponding to each
> unique combination above converted to character, and then bundle this
array
> plus the unique combination of the other variables into a new cluster. In
> general I could have several such clusters.
>
> So if I had the following array to start with:
>
> Index INT1 RING1 BOOL1 CLUST1
> ---------------------------------------------------
> 0 3 1 F {Values1}
> 1 2 1 T {Values2}
> 2 4 0 F {Values1}
> 3 6 0 F {Values3}
> 4 1 2 T {Values2}
> 5 4 2 T {Values2}
> 6 3 0 T {Values3}
> 7 4 2 T {Values3}
>
> I should end up with the following clusters:
>
> CHARARY2 RING2 BOOL1 CLUST1
> -----------------------------------------------------
> "3" 1 F Don't care
> "2" 1 T {Values2}
> "4","6" 0 F Don't care
> "1","4" 2 T {Values2}
> "3" 0 T {Values3}
> "4" 2 T {Values3}
>
> What methods would you suggest for accomplishing this easily and
efficiently?
>
> Alex Rast
> [email protected]
> [email protected]

Scrollable cluster arrays as control, writing programmatically at the same time?

I would like to have a cluster array (just an example, you may suggest better solution), where each row (cluster-element) contains signal selection from combobox, and its value and unit.
I would like to have a signal list, where in each row, I can select which signal I want to show e.g. "motor speed", "motor torque", "motor power". And when signals are selected, the value of the
signals are automatically updated elsewhere. So basicly, I want to select which signals I monitor, and then watch them change over time. I use single cluster array because I want it to be scrollable. The problem is:
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First suggestion is to post the code you have.
But that being said what you want to do can be done. I think the problem you are having is a race condition between the user and the software. Where the user chagnes the value and the software changes it back. I suggest reading the value of the control and replacing its value but keep the signal names the user entered, then write that back to the control.
Another suggestion is to have two separate arrays, one that is signal selection, and one is values. Then you only need to update the values table with the new data and the signal names never get overwritten. You'll likely want to couple the two arrays so when one index value changes the other changes with it. This can be done with an independent scrollbar control.
Unofficial Forum Rules and Guidelines - Hooovahh - LabVIEW Overlord
If 10 out of 10 experts in any field say something is bad, you should probably take their opinion seriously.

Set Colors of a part of a booelan cluster array

I put an example of a cluster boolean array. Now i a want that a certain part (see the red arae) has another color.
Not the colors as set by 1 or 0. And keep the rest of the array in the other (white) color.
I put the attached example ColorArray.vi (labVIEW2010).
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Attachments:
ColorArray.vi ‏11 KB

Hi Ben,
simple rule in LabVIEW: in an array all elements share the same properties, they only differ in value!
So you cannot color some elements different to the other (using properties).
But:
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Best regards,
GerdW
CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
Kudos are welcome

1d cluster array replace value in a 1d boolean array (without using Loop)

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