A question about the execution order of java code

Question

I have a question about the order of the execution of java code.
class myclass
String str1 = new String("str1");
static String str2 = new String("str2");
static
String str3 = new String("str3");
myclass( )
String str4 = new String("str4");
static myfuntion()
String str5 = new String("str5");
When I new a myclass object, what is the order of execution about str1,str2.str3 ,str4?
When I run myclass::myfunction( ) instead of new a myclass object what is the execution order about str1, str2, str3, str4, str5?
Thanks

Answer 1

hello,
I think there may be one thing can't use println to make sure.
class myclass
static {  System.out.println("str1");   };
myclass() { System.out.println("str2"); }
then str1 appear before str2
class myclass
static {  String str1 = new String("str1"); };
myclass() { String str2 = new String("str2"); }
then
str1 initilized before str2,
str1 get the value str1----->after<----- str2.
Am I right or wrong?